How can I create minimal OOBB for given points? Creating AABB or sphere is very easy, but I have problems creating minimal OOBB.
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First answer didn't get me good results. I don't have huge cloud of points. I have little amount of points. I am doing collision geometry generation. For example, cube has 36 points (6 sides, 2 triangles each, 3 points for each triangle). And algorithm from first post gave bad results for cube. Example points for cube: http://nopaste.dk/download/3382 (should return identity axis)
The PCA/covariance/eigenvector method essentially finds the axes of an ellipsoid that approximates the vertices of your object. It should work for random objects, but will give bad results for symmetric objects like the cube. That's because the approximating ellipsoid for a cube is a sphere, and a sphere does not have well defined axes. So you're not getting the standard axes that you expect.
Perhaps if you know in advance that an object is, for example, a cube you can use a specialized method, and use PCA for everything else.
On the other hand, if you want to compute the true OBB there are existing implementations you can use e.g. http://www.geometrictools.com/LibMathematics/Containment/Containment.html
(archived at https://web.archive.org/web/20110817024344/geometrictools.com/LibMathematics/Containment/Containment.html and https://github.com/timprepscius/GeometricTools/blob/master/WildMagic5/LibMathematics/Containment/Wm5ContMinBox3.cpp). I believe this implements the algorithm alluded to in the comments to your question.
Quoting from that page:
The ContMinBox3 files implement an
algorithm for computing the
minimum-volume box containing the
points. This method computes the
convex hull of the points, a convex
polyhedron. The minimum-volume box
either has a face coincident with a
face of the convex polyhedron or has
axis directions given by three
mutually perpendicular edges of the
convex polyhedron. Each face of the
convex polyhedron is processed by
projecting the polyhedron to the plane
of the face, computing the
minimum-area rectangle containing the
projections, and computing the
minimum-length interval containing the
projections onto the perpendicular of
the face. The minimum-area rectangle
and minimum-length interval combine to
form a candidate box. Then all triples
of edges of the convex polyhedron are
processed. If any triple has mutually
perpendicular edges, the smallest box
with axes in the directions of the
edges is computed. Of all these boxes,
the one with the smallest volume is
the minimum-volume box containing the
original point set.
If, as you say, your objects do not have a large number of vertices, the running time should be acceptable.
In a discussion at http://www.gamedev.net/topic/320675-how-to-create-oriented-bounding-box/ the author of the above library casts some more light on the topic:
Gottschalk's approach to OBB construction is to compute a covariance matrix for the point set. The eigenvectors of this matrix are the OBB axes. The average of the points is the OBB center. The OBB is not guaranteed to have the minimum volume of all containing boxes. An OBB tree is built by recursively splitting the triangle mesh whose vertices are the point set. A couple of heuristics are mentioned for the splitting.
The minimum volume box (MVB) containing a point set is the minimum volume box containing the convex hull of the points. The hull is a convex polyhedron. Based on a result of Joe O'Rourke, the MVB is supported by a face of the polyhedron or by three perpendicular edges of the polyhedron. "Supported by a face" means that the MVB has a face coincident with a polyhedron face. "Supported by three perpendicular edges" means that three perpendicular edges of the MVB are coincident with edges of the polyhedron.
As jyk indicates, the implementations of any of these algorithms is not trivial. However, never let that discourage you from trying :) An AABB can be a good fit, but it can also be a very bad fit. Consider a "thin" cylinder with end points at (0,0,0) and (1,1,1) [imagine the cylinder is the line segment connecting the points]. The AABB is 0 <= x <= 1, 0 <= y <= 1, and 0 <= z <= 1, with a volume of 1. The MVB has center (1,1,1)/2, an axis (1,1,1)/sqrt(3), and an extent for this axis of sqrt(3)/2. It also has two additional axes perpendicular to the first axis, but the extents are 0. The volume of this box is 0. If you give the line segment a little thickness, the MVB becomes slightly larger, but still has a volume much smaller than that of the AABB.
Which type of box you choose should depend on your own application's data.
Implementations of all of this are at my www.geometrictools.com website. I use the median-split heuristic for the bounding-volume trees. The MVB construction requires a convex hull finder in 2D, a convex hull finder in 3D, and a method for computing the minimum area box containing a set of planar points--I use the rotating caliper method for this.
First you have to compute the centroid of the points, in pseudcode
mu = sum(0..N, x[i]) / N
then you have to compute the covariance matrix
C = sum(0..N, mult(x[i]-mu, transpose(x[i]-mu)));
Note that the mult performs an (3x1) matrix multiplication by (1x3) matrix multiplication, and the result is a 3x3 matrix.
The eigenvectors of the C matrix define the three axis of the OBB.
There is a new library ApproxMVBB in C++ online which computes an approximation for the minimum volume bounding box. Its released under MPL 2.0 Licences, and written by me.
If you have time look at: http://gabyx.github.io/ApproxMVBB/
The library is C++11 compatible and only needs Eigen http://eigen.tuxfamily.org.
Tests show that an approximation for 140Million points in 3D can be computed in reasonable time (arround 5-7 seconds) depending on your settings for the approximation.
Related
In my current c++ program I am dealing with a plane that is intersected by several other planes. I want to find the polygon formed by the lines that define the intersections of the planes. For simplicity and computation speed, it seems like my best bet is to get the lines that form the intersections and then work out the polygon in 2d on the surface of the plane. Does anyone have an idea how to translate the lines(represented by a position and a direction vector) onto the plane and the final polygon back into 3d?
In general, this isn't possible to do. The simplest counterexample is the intersection of two planes where the two centers overlap. Viewing it edge-on, it would look like a plus sign. There is no polygon that results from this intersection; a line segment, yes, but no polygon. If you want to draw the resulting polygon, then it needs to be convex, as well which puts more constraints on the allowable intersection configurations.
I'm trying to convert a polygonal 3D mesh into a series of topographic curves that represent the part of the mesh at a specific height for every interval. So far, I've come up with the idea to intersect a horizontal plane with the mesh and get the intersection curve(s). So for this mesh:
I'd intersect a plane repeatedly at a set interval of precision:
and etc.
While this is straightforward to do visually and in a CAD application, I'm completely lost doing this programmatically. How could I achieve calculating this in a programming environment/ what algorithms can I look into to achieve this?
I'm programming in an STL C++ environment (with Boost), loading .obj meshes with this simple loader, and need simple cartesian 2D points to define the output curve.
An option is to process all the faces in turn and for every face determine the horizontal planes that traverses them. For a given plane and face, check all four vertexes in turn and find the changes of sign (of Zvertex - Zplane). There will be exactly two such changes, defining an edge that belongs to a level curve. (Exceptionally you can find four changes of sign, which occurs when the facet isn't planar - join the points in pairs.)
Every time you find an intersection point, you tag it with the (unique) index of the plane and the (unique) index of the edge that was intersected; you also tag it with the index of the other edge that was intersected in that face.
By sorting on the plane index, you can group the intersections per plane.
For a given plane, using a hash table, you can follow the chain of intersections, from edge to edge.
This gives you the desired set of curves.
I need an algorithm that fills a 2D non-convex polygon that may have holes with points randomly, and then constructs a voronoi diagram on them. The diagram should be bounded with the polygon and the algorithm should run in O(n log n).
My idea was to fill the poly by testing random points inside the polys bounding box and taking only the points inside the poly, and than building voronoi on them, and than clipping the edges of the diagram that exit the polygon.
The problem is, testing random points and clipping the edges is O(n^2).
Can this be done in boost, or is there another small library, or anything else really?
I guess with "holes" you man self-intersections of a single, closed polygon.
Do a Delaunay triangulation of your polygon first:
Calculate section points between segments; add these points, split the segments and rearrange the input so that "inside" is always on the same side of the edge when traversing the polygon's points.
Trangulate all points in your polygon.
Delete the triangles that lie outside your polygon. These will be the concavities and holes created by self-intersections. You can identify them by walking along your polygon and deleting all triangles that lie outside an edge. You need the connectivity of the edges, but that's a byproduct of the triangulation.
You now have the starting point for further triangulation with the Bowyer-Watson algorithm, which triangulates by successively adding points to a parent triangle. So, to add a random point, we can pick a point and update the triangulation in one go:
Pick a random triangle, where the probability for each triangle to be picked is proportional to its area.
Chose a random location inside that riangle by picking barycentric coordinates s in [0, 1], t in[0, 1]and withs + t < 1`. Your new point is then:
{P} = s * ({N2} - {N1}) + t * ({N3} - {N1})
Add your point and retriangulate the parent triangle and other triangles whose circumcircle contains the new point.
The set of triangles to pick has now changed.
You now have a Delaunay triangulation, but you want a Voronoi diagram, which you can easily obtain by connecting the centres of all circumcircles of adjacent triangles. Again, the Delaunay triangulation provides you with the information on the circumcircles and on which triangles are adjacent.
You can use the Bowyer-Watson algorithm on your initial triangulation when you create a large dummy triangle that encloses all your points.
I'm not aware of any triangulation libraries for C++, but this question might get you started.
Here is another geometric problem:
I have created an 3-dimensional triangulated iso-surface of a point cloud using the marching cubes algorithm. Then I intersect this iso-surface with a plane and get a number of line segments that represent the contour lines of the intersection.
Is there any possibility to sort the vertices of these line segments clockwise so that I can draw them as a closed path and do a flood fill?
Thanks in advance!
It depends on how complex your isosurface is, but the simplest thing I can think of that might work is:
For each point, project to the plane. This will give you a set of points in 2d.
Make sure these are centered, via a translation to the centroid or center of the bounding box.
For each 2d point, run atan2 and get an angle. atan2 just puts things in the correct quadrant.
Order by that angle
If your isosurface/plane is monotonically increasing in angle around the centroid, then this will work fine. If not, then you might need to find the 2 nearest neighbors to each point in the plane, and hope that that makes a simple loop. In face, the simple loop idea might be simpler, because you don't need to project and you don't need to compute angles - just do everything in 3d.
I have a need to calculate the minimum area rectangle (smallest possible rectangle) around the polygon.
The only input i have is the number of points in polygon.
I have the co-ordinates of the points also.
This is called Minimum Bounding Box, it's most basic algorithm used in OCR packages. You can find an implementation using Rotating Calipers from the OpenCV package. Once you get the source code, check out this file,
cv/src/cvrotcalipers.cpp
The method you need is cvMinAreaRect2().
Use the rotating calipers algorithm for a convex polygon, or the convex hull otherwise. You will of course need the coordinates of the points in the polygon, not just the number of points.
First do a grahm-scan and get the convex hull of the set of points. Then you can use something like minimum rectangle discussed here
Follow the following algorithm
Rotate the polygon onto the XY plane
Pick 1 edge and align this edge with the X axis(use arctan). Use the min/max x,y to find the bounding rectangle. Compute Area and store in list
Do the same for remaining edges in clipped polygon.
Pick the rectangle with the minimum Area.
Rotate Bounding Rectangle back for Coplanar reverse rotation of Step 1 and step 2
for more detail check link Minimum-Area-Rectangle
Obviously, you'll need the coordinates of the points to get the answer. If the rectangle is aligned to the X and Y aces, then the solution is trivial. If you want the smallest possible rectangle, at any angle, then you'll need to do some sort of optimization process.