I have 2000 page website and it contains over 500 acronyms. What Regular expression could I use to find all the acronyms in the text only? I'm using dream-weaver. Some examples would be AFD, GTDC, IJQW and so on.. these are 2 or more capitals might be bounded or surround by other characters. Such example would be (DFT) or l'WQF - any ideas??
If dreamweaver has search via grep capability, you could just search for any string of letters with all capitals, including whatever necessary punctuation you need, e.g. [A-Z'-]{3,}. The 3 is the minumum number of letters in the acronym... you can change that as needed.
This would probably be better done via shell script, though, just for speed's sake. Let us know what OS you're using and someone else can leave a comment as to how to script that, as I probably don't know.
Related
Hi i'm doing some infosec research and searching through text bins.
I'm using a text editor to search files and I'm wanting to search for email addresses with certain conditions. Text is comma-separated.
Say for example i know the email is 20 chars long and I know that the domain is gmail.com, and I also know it starts with t.
[tT](.{9})#gmail.com
If it was correct it should pick up for example: tqwertyuio#gmail.com and tzxcvb1234#gmail.com. Right?
I'm using emEditor which uses Boost Regex engine I think. This regex is just not working as it also returns anything that has that expression in it.
I've tried to use anchors, but they are not working. Perhaps its this engine. I would of thought i would go:
^[tT](.{9})#gmail.com$
But it's not working. Any help?? Thanks SO much i really just want to learn why i cant do this.
I believe you are looking for 20 characters long email which are NOT surrounded by alphabets or numbers. In that case, you can search for:
(?<!\w)[tT](.{9})#gmail.com(?!\w)
where \w is an alphabet or a number, (?<!\w) is negative lookbehind, and (?!\w) is negative lookahead.
In the Find dialog box, you can enter this regular expression, and make sure you select the "Regular Expressions" option.
You might also want to try the Filter toolbar with the same regular expression.
So I read a lot about Negation in Regex but can't solve my problem in MS Word 2016.
How do I exclude a String, Word, Number(s) from being found?
Example:
<[A-Z]{2}[A-Z0-9]{9;11}> to search a String like XY123BBT22223
But how to exclude for example a specefic one like SEDWS12WW04?
Well it depends on what you need to achieve or is this a matter of curiosity... RegEx is not the same as the built-in Advanced Find with Wildcards; for that you need VBA.
Depending on your need, without using VBA, you could make use of space and return characters - something like this will work for the strings provided: [ ^13][A-Z]{2}[0-9]{1,}[A-Z]{1,}[0-9]{1,}[ ^13] (assuming you use normal carriage returns and spaces in your document)
Anyway, this is a good article on wildcard searches in MS Word: https://wordmvp.com/FAQs/General/UsingWildcards.htm
EDIT:
In light of your further comments you will probably want to look at section 8 of the linked article which explains grouping. For my proposed search you can use this to your advantage by creating 3 groups in your 'find' and only modifying the middle group, if indeed you do intend to modify. Using groups the search would look something like:
([ ^13])([A-Z]{2}[0-9]{1,}[A-Z]{1,}[0-9]{1,})([ ^13])
and the replace might look like this:
\1 SOMETHING \3
Note also: compared to a RegEx solution my suggestion is kinda lame, mainly because compared to RegEx, MS-Words find and replace (good as it is, and really it is) is kinda lame... it's hacky but it might work for you (although you might need to do a few searches).
BUT... if it really is REGEX that you want, well you can get access to this via VBA: How to Use/Enable (RegExp object) Regular Expression using VBA (MACRO) in word
And... then you will be able to use proper RegEx for find and replace, well almost - I'm under the impression that the VBA RegEx still has some quirks...
As already noted by others, this is not possible in Microsoft Word's flavor of regular expressions.
Instead, you should use standard regular expressions. It is actually possible to use standard regular expressions in MS Word if you use a special tool that integrates into Microsoft Word called Multiple Find & Replace (see http://www.translatortools.net/products/transtoolsplus/word-multiplefindreplace). This tool opens as a pane to the right of the document window and works just like the Advanced Find & Replace dialog. However, in addition to Word's existing search functionality, it can use the standard regular expressions syntax to search and replace any text within a Word document.
In your particular case, I would use this:
\b[A-Z]{2}[A-Z0-9]{9,11}\b(?<!\bSEDWS12WW04)
To explain, this searches for a word boundary + ID + word boundary, and then it looks back to make sure that the preceding string does not match [word boundary + excluded ID]. In a similar vein, you can do something like
(?<!\bSEDWS12WW04|\bSEDWS12WW05|\bSEDWS12WW05)
to exlude several IDs.
Multiple Find & Replace is quite powerful: you can add any number of expressions (either using regular expressions or using Word's standard search syntax) to a list and then search the document for all of them, replace everything, display all matches in a list and replace only specific matches, and a few more things.
I created this tool for translators and editors, but it is great for any advanced search/replace operations in Word, and I am sure you will find it very useful.
Best regards, Stanislav
I'm using TextWrangler, the free version of BBEdit on the Mac, which I understand uses the PCRE engine.
What I want to do is match a specific number of lines and replace as well.
After a lot of searching I came up with this:
(^(.*\r)){25}
This lets me match up to 25 lines. It works great, but the problem comes when I want to actually replace something. I can't figure out how to do it.
For example, I would like to replace all of the returns "\r" with tabs "\t".
Hopefully this is actually possible. I'd appreciate any help. Thanks!
Regexp domain is searching. You cannot replace using regexp; a programming language or editor can use regexp as the search part of its search-and-replace function. Thus, the way to do 25 replacements is purely in the domain of said programming language or editor. If it does not provide such capability, either directly in search-and-replace or as a macro/loop/other, then you cannot do it automatically.
I have a rather complicating data file with many rows of many different types. For the particular column I'm interested in I have a pattern that looks like this:
12.6 \pm 0.8
^^ The number of digits before and after the decimal in each of those pieces of the entry may vary.
I'm hoping I can use regular expressions to replace that column entry to:
[12.6,-0.8,+0.8]
What I am requesting help on is how I should go about replacing once I've found entries like what I had earlier. All of the examples I've found so far are for when you want to replace static strings with other static strings, but for each line I'm necessarily going to have different numbers (and different digits perhaps). The regular expression I've attempted so far to find entries like "12.6 \pm 0.8" is the following:
\d*\.\d*\s\\\w{2})\s\d*\.\d*
I would also appreciate if I could get a check on that, too. At the moment I'm just manipulating the datafile in my text editor, but I'm also open to Python solutions, too.
Thanks!
Your expression is close. Are there any conditions where this won't work?
(\d*\.\d*)\s\\\w{2}\s(\d*\.\d*)
with the replace pattern being (for JS)
[$1, -$2, $2]
or for emacs (according to http://www.emacswiki.org/emacs/RegularExpression)
[\1, -\2, \2]
Using a regex, I am able to find a bunch of numbers that I want to replace. However, I want to replace the number with another number that is calculated using the original - captured - number.
Is that possible in notepad++ using a kind of expression in the replacement-part?
Edit: Maybe a strange thought, but could the calculation be done in the search part, generating a second captured number that would effectively be the result?
Even if it is possible, it will almost certainly be "messy" - why not do the replacements with a simple script instead? For example..
#!/usr/bin/env ruby
f = File.new("f1.txt", File::RDWR)
contents = f.read()
contents.gsub!(/\d+/){|m|
m.to_i + 1 # convert the current match to an integer, and add one
}
f.truncate(0) # empty the existing file
f.seek(0) # seek to the start of the file, before writing again
f.write(contents) # write modified file
f.close()
..and the output:
$ cat f1.txt
This was one: 1
This two two: 2
$ ruby replacer.rb
$ cat f1.txt
This was one: 2
This two two: 3
In reply to jeroen's comment,
I was actually interested if the possibility existed in the regular expression itself as they are so widespread
A regular expression is really just a simple pattern matching syntax. To do anything more advanced than search/replace with the matches would be up to the text-editors, but the usefulness of this is very limited, and can be achieved via scripting most editors allow (Notepad++ has a plugin system, although I've no idea how easy it is to use).
Basically, if regex/search-and-replace will not achieve what you want, I would say either use your editors scripting ability or use an external script.
Is that possible in notepad++ using a kind of expression in the replacement-part?
Interpolated evaluation of regular-expression matches is a relatively advanced feature that I probably would not expect to find in a general-purpose text editing application. I played around with Notepad++ a bit but was unable to get this to work, nor could I find anything in the documentation that suggests this is possible.
Hmmm... I'd have to recommend AWK to do this.
http://en.wikipedia.org/wiki/AWK
notepad++ has limited regular expressions built in. There are extensions that add a bit more to the regular expression find and replace, but I've found those hard to use. I would recommend writing a little external program to do it for you. Either Ruby, Perl or Python would be great for it. If you know those languages. I use Ruby and have had lots of success with it.