Convenient C++ struct initialisation [duplicate] - c++

This question already has answers here:
C++ Structure Initialization [duplicate]
(17 answers)
Closed 3 months ago.
I'm trying to find a convenient way to initialise 'pod' C++ structs. Now, consider the following struct:
struct FooBar {
int foo;
float bar;
};
// just to make all examples work in C and C++:
typedef struct FooBar FooBar;
If I want to conveniently initialise this in C (!), I could simply write:
/* A */ FooBar fb = { .foo = 12, .bar = 3.4 }; // illegal C++, legal C
Note that I want to explicitly avoid the following notation, because it strikes me as being made to break my neck if I change anything in the struct in the future:
/* B */ FooBar fb = { 12, 3.4 }; // legal C++, legal C, bad style?
To achieve the same (or at least similar) in C++ as in the /* A */ example, I would have to implement an annoying constructor:
FooBar::FooBar(int foo, float bar) : foo(foo), bar(bar) {}
// ->
/* C */ FooBar fb(12, 3.4);
Which feels redundant and unnecessary. Also, it is pretty much as bad as the /* B */ example, as it does not explicitly state which value goes to which member.
So, my question is basically how I can achieve something similar to /* A */ or better in C++?
Alternatively, I would be okay with an explanation why I should not want to do this (i.e. why my mental paradigm is bad).
EDIT
By convenient, I mean also maintainable and non-redundant.

Since style A is not allowed in C++ and you don't want style B then how about using style BX:
FooBar fb = { /*.foo=*/ 12, /*.bar=*/ 3.4 }; // :)
At least help at some extent.

Designated initializes will be supported in c++2a, but you don't have to wait, because they are officialy supported by GCC, Clang and MSVC.
#include <iostream>
#include <filesystem>
struct hello_world {
const char* hello;
const char* world;
};
int main ()
{
hello_world hw = {
.hello = "hello, ",
.world = "world!"
};
std::cout << hw.hello << hw.world << std::endl;
return 0;
}
GCC Demo
MSVC Demo
Update 2021
As #Code Doggo noted, anyone who is using Visual Studio 2019 will need to set /std:c++latest  for the "C++ Language Standard" field contained under Configuration Properties -> C/C++ -> Language.

You could use a lambda:
const FooBar fb = [&] {
FooBar fb;
fb.foo = 12;
fb.bar = 3.4;
return fb;
}();
More information on this idiom can be found on Herb Sutter's blog.

Extract the contants into functions that describe them (basic refactoring):
FooBar fb = { foo(), bar() };
I know that style is very close to the one you didn't want to use, but it enables easier replacement of the constant values and also explain them (thus not needing to edit comments), if they ever change that is.
Another thing you could do (since you are lazy) is to make the constructor inline, so you don't have to type as much (removing "Foobar::" and time spent switching between h and cpp file):
struct FooBar {
FooBar(int f, float b) : foo(f), bar(b) {}
int foo;
float bar;
};

Your question is somewhat difficult because even the function:
static FooBar MakeFooBar(int foo, float bar);
may be called as:
FooBar fb = MakeFooBar(3.4, 5);
because of the promotion and conversions rules for built-in numeric types. (C has never been really strongly typed)
In C++, what you want is achievable, though with the help of templates and static assertions:
template <typename Integer, typename Real>
FooBar MakeFooBar(Integer foo, Real bar) {
static_assert(std::is_same<Integer, int>::value, "foo should be of type int");
static_assert(std::is_same<Real, float>::value, "bar should be of type float");
return { foo, bar };
}
In C, you may name the parameters, but you'll never get further.
On the other hand, if all you want is named parameters, then you write a lot of cumbersome code:
struct FooBarMaker {
FooBarMaker(int f): _f(f) {}
FooBar Bar(float b) const { return FooBar(_f, b); }
int _f;
};
static FooBarMaker Foo(int f) { return FooBarMaker(f); }
// Usage
FooBar fb = Foo(5).Bar(3.4);
And you can pepper in type promotion protection if you like.

Many compilers' C++ frontends (including GCC and clang) understand C initializer syntax. If you can, simply use that method.

Yet another way in C++ is
struct Point
{
private:
int x;
int y;
public:
Point& setX(int xIn) { x = Xin; return *this;}
Point& setY(int yIn) { y = Yin; return *this;}
}
Point pt;
pt.setX(20).setY(20);

Option D:
FooBar FooBarMake(int foo, float bar)
Legal C, legal C++. Easily optimizable for PODs. Of course there are no named arguments, but this is like all C++. If you want named arguments, Objective C should be better choice.
Option E:
FooBar fb;
memset(&fb, 0, sizeof(FooBar));
fb.foo = 4;
fb.bar = 15.5f;
Legal C, legal C++. Named arguments.

I know this question is old, but there is a way to solve this until C++20 finally brings this feature from C to C++. What you can do to solve this is use preprocessor macros with static_asserts to check your initialization is valid. (I know macros are generally bad, but here I don't see another way.) See example code below:
#define INVALID_STRUCT_ERROR "Instantiation of struct failed: Type, order or number of attributes is wrong."
#define CREATE_STRUCT_1(type, identifier, m_1, p_1) \
{ p_1 };\
static_assert(offsetof(type, m_1) == 0, INVALID_STRUCT_ERROR);\
#define CREATE_STRUCT_2(type, identifier, m_1, p_1, m_2, p_2) \
{ p_1, p_2 };\
static_assert(offsetof(type, m_1) == 0, INVALID_STRUCT_ERROR);\
static_assert(offsetof(type, m_2) >= sizeof(identifier.m_1), INVALID_STRUCT_ERROR);\
#define CREATE_STRUCT_3(type, identifier, m_1, p_1, m_2, p_2, m_3, p_3) \
{ p_1, p_2, p_3 };\
static_assert(offsetof(type, m_1) == 0, INVALID_STRUCT_ERROR);\
static_assert(offsetof(type, m_2) >= sizeof(identifier.m_1), INVALID_STRUCT_ERROR);\
static_assert(offsetof(type, m_3) >= (offsetof(type, m_2) + sizeof(identifier.m_2)), INVALID_STRUCT_ERROR);\
#define CREATE_STRUCT_4(type, identifier, m_1, p_1, m_2, p_2, m_3, p_3, m_4, p_4) \
{ p_1, p_2, p_3, p_4 };\
static_assert(offsetof(type, m_1) == 0, INVALID_STRUCT_ERROR);\
static_assert(offsetof(type, m_2) >= sizeof(identifier.m_1), INVALID_STRUCT_ERROR);\
static_assert(offsetof(type, m_3) >= (offsetof(type, m_2) + sizeof(identifier.m_2)), INVALID_STRUCT_ERROR);\
static_assert(offsetof(type, m_4) >= (offsetof(type, m_3) + sizeof(identifier.m_3)), INVALID_STRUCT_ERROR);\
// Create more macros for structs with more attributes...
Then when you have a struct with const attributes, you can do this:
struct MyStruct
{
const int attr1;
const float attr2;
const double attr3;
};
const MyStruct test = CREATE_STRUCT_3(MyStruct, test, attr1, 1, attr2, 2.f, attr3, 3.);
It's a bit inconvenient, because you need macros for every possible number of attributes and you need to repeat the type and name of your instance in the macro call. Also you cannot use the macro in a return statement, because the asserts come after the initialization.
But it does solve your problem: When you change the struct, the call will fail at compile-time.
If you use C++17, you can even make these macros more strict by forcing the same types, e.g.:
#define CREATE_STRUCT_3(type, identifier, m_1, p_1, m_2, p_2, m_3, p_3) \
{ p_1, p_2, p_3 };\
static_assert(offsetof(type, m_1) == 0, INVALID_STRUCT_ERROR);\
static_assert(offsetof(type, m_2) >= sizeof(identifier.m_1), INVALID_STRUCT_ERROR);\
static_assert(offsetof(type, m_3) >= (offsetof(type, m_2) + sizeof(identifier.m_2)), INVALID_STRUCT_ERROR);\
static_assert(typeid(p_1) == typeid(identifier.m_1), INVALID_STRUCT_ERROR);\
static_assert(typeid(p_2) == typeid(identifier.m_2), INVALID_STRUCT_ERROR);\
static_assert(typeid(p_3) == typeid(identifier.m_3), INVALID_STRUCT_ERROR);\

The way /* B */ is fine in C++ also the C++0x is going to extend the syntax so it is useful for C++ containers too. I do not understand why you call it bad style?
If you want to indicate parameters with names then you can use boost parameter library, but it may confuse someone unfamiliar with it.
Reordering struct members is like reordering function parameters, such refactoring may cause problems if you don't do it very carefully.

What about this syntax?
typedef struct
{
int a;
short b;
}
ABCD;
ABCD abc = { abc.a = 5, abc.b = 7 };
Just tested on a Microsoft Visual C++ 2015 and on g++ 6.0.2. Working OK.
You can make a specific macro also if you want to avoid duplicating variable name.

For me the laziest way to allow inline inizialization is use this macro.
#define METHOD_MEMBER(TYPE, NAME, CLASS) \
CLASS &set_ ## NAME(const TYPE &_val) { NAME = _val; return *this; } \
TYPE NAME;
struct foo {
METHOD_MEMBER(string, attr1, foo)
METHOD_MEMBER(int, attr2, foo)
METHOD_MEMBER(double, attr3, foo)
};
// inline usage
foo test = foo().set_attr1("hi").set_attr2(22).set_attr3(3.14);
That macro create attribute and self reference method.

For versions of C++ prior to C++20 (which introduces the named initialization, making your option A valid in C++), consider the following:
int main()
{
struct TFoo { int val; };
struct TBar { float val; };
struct FooBar {
TFoo foo;
TBar bar;
};
FooBar mystruct = { TFoo{12}, TBar{3.4} };
std::cout << "foo = " << mystruct.foo.val << " bar = " << mystruct.bar.val << std::endl;
}
Note that if you try to initialize the struct with FooBar mystruct = { TFoo{12}, TFoo{3.4} }; you will get a compilation error.
The downside is that you have to create one additional struct for each variable inside your main struct, and also you have to use the inner value with mystruct.foo.val. But on the other hand, it`s clean, simple, pure and standard.

I personally have found that using constructor with struct is the most pragmatic way to ensure struct members are initialized in code to sensible values.
As you say above, small downside is that one does not immediatelly see what param is which member, but most IDEs help here, if one hovers over the code.
What I consider more likely is that new member is added and in this case i want all constructions of the struct to fail to compile, so developer is forced to review. In our fairly large code base, this has proven itself, because it guides developer in what needs attention and therefore creates self-maintained code.

Related

Is there a way to select between two macros depending on the number of parameters on a function sent as the macro parameter?

I realize the title of the question is very confusing, but I cannot think of a better way to word this, so I'll explain it better with code.
I know you can select macros based on the number of parameters it receives using macro expansion and __VA_ARGS__ like in this dumb example:
#define EXP(x) x
#define SELECT_MACRO(_1, _2, macro) macro
#define FOO1(str) printf(#str);
#define FOO2(str, num) printf(#str, num);
#define SELECT_FOO(...) EXP(SELECT_MACRO(__VA_ARGS__, FOO2, FOO1)(__VA_ARGS__))
int main()
{
int a = 5;
SELECT_FOO("Hello\n");
SELECT_FOO("Number %d \n", 5);
return 0;
}
I am interested in the usability of this method, since it means the user only needs to remember one macro, instead of two. I would like to do something similar, but for macros receiving functions, something that allows c and d to compile:
void PrintNumber(int n)
{
printf("%d\n", n);
}
void PrintHello()
{
printf("Hello\n");
}
#define BIND_FN_DATA(fn) [](int& num) { fn(num); }
#define BIND_FN(fn) [](int& num) { (void)num; fn(); }
#define SELECT_BIND(...) // What should this look like?
int main()
{
auto a = BIND_FN_DATA(PrintNumber);
auto b = BIND_FN(PrintHello);
// auto c = SELECT_BIND(PrintNumber);
// auto d = SELECT_BIND(PrintHello);
return 0;
}
This code is obviously simplified for the question, but essentially I'd like to check if the PrintXXX functions passed to the macro have 1 or 0 parameters. The different lambdas call the functions with or without the parameter, but their signatures need to be kept the same on both methods (in BIND_FN and BIND_FN_DATA). Can anyone think of a way to do this without adding any runtime cost?
Godbolt link: https://godbolt.org/z/cWqWPrvWj
Macros operate on a level of only tokens. They can't know anything about parameters of functions. Therefore it is rather pointless to use macros. In the end the relevant mechanism must be implemented in actual C++.
It is rather simple to write SELECT_BIND as a function template with C++20:
constexpr auto SELECT_BIND(auto fn) noexcept {
return [=](int& num){
if constexpr(requires { fn(num); }) {
fn(num);
} else {
fn();
}
};
}
However, you need to choose which of the two you want to prefer if both fn() and fn(num) are valid. In the above I chose to prefer the latter.
With C++17, in auto fn, auto has to be replaced with F from a template<typename F> and required { fn(num); } must be replaced with std::is_invocable_v<F&, int&>.
Before C++17 this is a bit trickier, requiring e.g. partial specialization.

Write a function that only accepts literal `0` or literal `1` as argument

Sometimes for algebraic types it is convenient to have a constructor that takes a literal value 0 to denote the neutral element, or 1 to denote the multiplicative identity element, even if the underlying type is not an integer.
The problem is that it is not obvious how to convince the compiler only to accept, 0 or 1 without accepting any other integer.
Is there a way to do this in C++14 or beyond, for example combining literals, constexpr or static_assert?
Let me illustrate with a free function (although the idea is to use the technique for a constructor that take a single argument. Contructors cannot take template parameters either).
A function that accepts zero only could be written in this way:
constexpr void f_zero(int zero){assert(zero==0); ...}
The problem is that, this could only fail at runtime. I could write f_zero(2) or even f_zero(2.2) and the program will still compile.
The second case is easy to remove, by using enable_if for example
template<class Int, typename = std::enable_if_t<std::is_same<Int, int>{}> >
constexpr void g_zero(Int zero){assert(zero==0);}
This still has the problem that I can pass any integer (and it only fails in debug mode).
In C++ pre 11 one had the ability to do this trick to only accept a literal zero.
struct zero_tag_{};
using zero_t = zero_tag_***;
constexpr void h_zero(zero_t zero){assert(zero==nullptr);}
This actually allowed one to be 99% there, except for very ugly error messages.
Because, basically (modulo Maquevelian use), the only argument accepted would be h_zero(0).
This is situation of affairs is illustrated here https://godbolt.org/z/wSD9ri .
I saw this technique being used in the Boost.Units library.
1) Can one do better now using new features of C++?
The reason I ask is because with the literal 1 the above technique fails completely.
2) Is there an equivalent trick that can be applied to the literal 1 case? (ideally as a separate function).
I could imagine that one can invent a non-standard long long literal _c that creates an instance of std::integral_constant<int, 0> or std::integral_constant<int, 1> and then make the function take these types. However the resulting syntax will be worst for the 0 case. Perhaps there is something simpler.
f(0_c);
f(1_c);
EDIT: I should have mentioned that since f(0) and f(1) are potentially completely separate functions then ideally they should call different functions (or overloads).
In C++20 you can use the consteval keyword to force compile time evaluation. With that you could create a struct, which has a consteval constructor and use that as an argument to a function. Like this:
struct S
{
private:
int x;
public:
S() = delete;
consteval S(int _x)
: x(_x)
{
if (x != 0 && x != 1)
{
// this will trigger a compile error,
// because the allocation is never deleted
// static_assert(_x == 0 || _x == 1); didn't work...
new int{0};
}
}
int get_x() const noexcept
{
return x;
}
};
void func(S s)
{
// use s.get_x() to decide control flow
}
int main()
{
func(0); // this works
func(1); // this also works
func(2); // this is a compile error
}
Here's a godbolt example as well.
Edit:
Apperently clang 10 does not give an error as seen here, but clang (trunk) on godbolt does.
You can get this by passing the 0 or 1 as a template argument like so:
template <int value, typename = std::enable_if_t<value == 0 | value == 1>>
void f() {
// Do something with value
}
The function would then be called like: f<0>(). I don't believe the same thing can be done for constructors (because you can't explicitly set template parameters for constructors), but you could make the constructor(s) private and have static wrapper functions which can be given template parameters perform the check:
class A {
private:
A(int value) { ... }
public:
template <int value, typename = std::enable_if_t<value == 0 || value == 1>>
static A make_A() {
return A(value);
}
};
Objects of type A would be created with A::make_A<0>().
Well... you have tagged C++17, so you can use if constexpr.
So you can define a literal type when 0_x is a std::integral_constant<int, 0> value, when 1_x is a std::integral_constant<int, 1> and when 2_x (and other values) gives a compilation error.
By example
template <char ... Chs>
auto operator "" _x()
{
using t0 = std::integer_sequence<char, '0'>;
using t1 = std::integer_sequence<char, '1'>;
using tx = std::integer_sequence<char, Chs...>;
if constexpr ( std::is_same_v<t0, tx> )
return std::integral_constant<int, 0>{};
else if constexpr ( std::is_same_v<t1, tx> )
return std::integral_constant<int, 1>{};
}
int main ()
{
auto x0 = 0_x;
auto x1 = 1_x;
//auto x2 = 2_x; // compilation error
static_assert( std::is_same_v<decltype(x0),
std::integral_constant<int, 0>> );
static_assert( std::is_same_v<decltype(x1),
std::integral_constant<int, 1>> );
}
Now your f() function can be
template <int X, std::enable_if_t<(X == 0) || (X == 1), bool> = true>
void f (std::integral_constant<int, X> const &)
{
// do something with X
}
and you can call it as follows
f(0_x);
f(1_x);
For the case of Ada, you can define a subtype, a new type, or a derived type that is constrained only for the values of Integer 0 and 1.
with Ada.Text_IO; use Ada.Text_IO;
with Ada.Integer_Text_IO; use Ada.Integer_Text_IO;
procedure two_value is
-- You can use any one of the following 3 declarations. Just comment out other two.
--subtype zero_or_one is Integer range 0 .. 1; -- subtype of Integer.
--type zero_or_one is range 0 .. 1; -- new type.
type zero_or_one is new Integer range 0 .. 1; -- derived type from Integer.
function get_val (val_1 : in zero_or_one) return Integer;
function get_val (val_1 : in zero_or_one) return Integer is
begin
if (val_1 = 0) then
return 0;
else
return 1;
end if;
end get_val;
begin
Put_Line("Demonstrate the use of only two values");
Put_Line(Integer'Image(get_val(0)));
Put_Line(Integer'Image(get_val(1)));
Put_Line(Integer'Image(get_val(2)));
end two_value;
upon compiling you get the following warning message, although compiles successfully :
>gnatmake two_value.adb
gcc -c two_value.adb
two_value.adb:29:40: warning: value not in range of type "zero_or_one" defined at line 8
two_value.adb:29:40: warning: "Constraint_Error" will be raised at run time
gnatbind -x two_value.ali
gnatlink two_value.ali
And executing it gives the runtime error as specified by the compiler
>two_value.exe
Demonstrate the use of only two values
0
1
raised CONSTRAINT_ERROR : two_value.adb:29 range check failed
So, basically you can constrain the values by defining the new types, derived types or subtypes, you don't need to include the code to check the range, but based on your data type the compiler will automatically warn you.
This isn't a modern solution, but adding on to Zach Peltzer's solution, you can keep your syntax if you use macros...
template <int value, typename = std::enable_if_t<value == 0 | value == 1>>
constexpr int f_impl() {
// Do something with value
return 1;
}
#define f(x) f_impl<x>()
int main() {
f(0); //ok
f(1); //ok
f(2); //compile time error
}
Though, with the constructor problem you could just make the class templated instead of trying to have a templated constructor
template<int value, typename = std::enable_if_t<value == 0 | value == 1>>
class A {
public:
A() {
//do stuff
}
};
int main() {
A<0> a0;
auto a1 = A<1>();
// auto a2 = A<2>(); //fails!
}
The best solution to accept literal 0 that I've found to date is to use std::nullptr_t as the function's input:
struct math_object
{
real x,y,z;
math_object(std::nullptr_t) : x(0), y(0), z(0) {}
};
This has conversion advantages over some of the other solutions. For example, it allows syntax such as.. void MyFunc(const math_object &obj=0); I've been using this for years, and haven't found any trouble. However, I do not have a similar solution for literal 1. For that, I created a construct::id structure that has a global IDENTITY variable.
There's a basic problem. How can you do that in the compiler to be done for a parameter, and at the same time be efficient? Well, what do you need exactly?
That is included in strong typed languages like Pascal, or Ada. The enumerated types have only a couple of values, and the types are normally checked at development, but otherwise, the checks are eliminated by some compiler option at runtime, because just everything goes well.
A function interface is a contract. It is a contract between a seller (the writer of the function) and a buyer (the user of that function). There's even an arbiter, which is the programming language, that can act upon if someone tries to cheat the contract. But at the end, the program is being run in a machine that's open to make arbitraryness like modifying the set of enumerated values and put in the place a completely (and not permitted value).
The problem comes also with separate compilation. Separate compilation has its drawbacks, as it must face a compilation, without having to recheck and retest all previous compilations you have made. Once a compilation is finished, everything you have put in the code is there. If you want the code to be efficient, then the tests are superfluous, because caller and implementer both cope with the contract, but if you want to catch a lyer, then you have to include the test code. And then, it is better to do once for all cases, or is it better to let the programmer decide when and when not we want to catch a lyer?
The problem with C (and by legacy with C++) is that they were inspired by very good programmers, that didn't mistakes, and that have to run their software in big and slow machines. They decided to make both languages (the second was for interoperability purposes) weak typed... and so they are. Have you tried to program in Ada? or Modula-2? You'll see that, over the time, the strong typing thing is more academic than otherwise, and finally what you want, as a professional, is to have the freedom to say: now I want to be safe (and include test code), and now I know what I'm doing (and please be most efficient as you can)
Conclusion
The conclussion is that you are free to select the language, to select the compiler, and to relax the rules. The compilers have the possibility to allow you that. And you have to cope with it, or invent (this is something that todays happens almost each week) your own programming language.
This is the answer to my question, based on #IlCapitano answer for a wrapper class.
This wrapper class can be made private an used only on the construction.
class Matrix {
struct ZeroOROne {
/*implicit*/ consteval ZeroOROne(int n) : val_{n} {
if (n != 0 and n != 1) {throw;} // throw can produce an error at compile time
}
int val_;
};
public:
constexpr Matrix(ZeroOROne _0_or_1) {
if(_0_or_1.val_ == 0) { // this cannot be if constexpr, but that is ok
a00 = a01 = a10 = a11 = 0.0;
new int{0}; // allocation could is ok here
} else {
a00 = a11 = 1.0;
a10 = a01 = 0.0;
new int{0}; // allocation could is ok here
}
}
double a00; double a01;
double a10; double a11;
};
In this way, only Matrix A(0) or Matrix A(1) are allowed.
(Although it works with constant variables as well, but that is ok.)
int main() {
// ZeroOROne(0);
// ZeroOROne(1);
// ZeroOROne(2); // compilation error
Matrix A(0);
Matrix B(1);
// Matrix C(2); // compilation error
int const d = 0; // this works because the compiler can "see" the 0.
Matrix D(d);
constexpr int e = 0;
Matrix E(e);
// int f = 0;
// Matrix F(f); // compile error
return B.a00;
}
Here it is shown that the "runtime" if in the constructor is not a problem and can be elided by the compiler: https://godbolt.org/z/hd6TWY6qW
The solution needs C++20 and it works in recent version of GCC and clang.

C++ function argument safety

In a function that takes several arguments of the same type, how can we guarantee that the caller doesn't mess up the ordering?
For example
void allocate_things(int num_buffers, int pages_per_buffer, int default_value ...
and later
// uhmm.. lets see which was which uhh..
allocate_things(40,22,80,...
A typical solution is to put the parameters in a structure, with named fields.
AllocateParams p;
p.num_buffers = 1;
p.pages_per_buffer = 10;
p.default_value = 93;
allocate_things(p);
You don't have to use fields, of course. You can use member functions or whatever you like.
If you have a C++11 compiler, you could use user-defined literals in combination with user-defined types. Here is a naive approach:
struct num_buffers_t {
constexpr num_buffers_t(int n) : n(n) {} // constexpr constructor requires C++14
int n;
};
struct pages_per_buffer_t {
constexpr pages_per_buffer_t(int n) : n(n) {}
int n;
};
constexpr num_buffers_t operator"" _buffers(unsigned long long int n) {
return num_buffers_t(n);
}
constexpr pages_per_buffer_t operator"" _pages_per_buffer(unsigned long long int n) {
return pages_per_buffer_t(n);
}
void allocate_things(num_buffers_t num_buffers, pages_per_buffer_t pages_per_buffer) {
// do stuff...
}
template <typename S, typename T>
void allocate_things(S, T) = delete; // forbid calling with other types, eg. integer literals
int main() {
// now we see which is which ...
allocate_things(40_buffers, 22_pages_per_buffer);
// the following does not compile (see the 'deleted' function):
// allocate_things(40, 22);
// allocate_things(40, 22_pages_per_buffer);
// allocate_things(22_pages_per_buffer, 40_buffers);
}
Two good answers so far, one more: another approach would be to try leverage the type system wherever possible, and to create strong typedefs. For instance, using boost strong typedef (http://www.boost.org/doc/libs/1_61_0/libs/serialization/doc/strong_typedef.html).
BOOST_STRONG_TYPEDEF(int , num_buffers);
BOOST_STRONG_TYPEDEF(int , num_pages);
void func(num_buffers b, num_pages p);
Calling func with arguments in the wrong order would now be a compile error.
A couple of notes on this. First, boost's strong typedef is rather dated in its approach; you can do much nicer things with variadic CRTP and avoid macros completely. Second, obviously this introduces some overhead as you often have to explicitly convert. So generally you don't want to overuse it. It's really nice for things that come up over and over again in your library. Not so good for things that come up as a one off. So for instance, if you are writing a GPS library, you should have a strong double typedef for distances in metres, a strong int64 typedef for time past epoch in nanoseconds, and so on.
(Note: post was originally tagged 'C`)
C99 onwards allows an extension to #Dietrich Epp idea: compound literal
struct things {
int num_buffers;
int pages_per_buffer;
int default_value
};
allocate_things(struct things);
// Use a compound literal
allocate_things((struct things){.default_value=80, .num_buffers=40, .pages_per_buffer=22});
Could even pass the address of the structure.
allocate_things(struct things *);
// Use a compound literal
allocate_things(&((struct things){.default_value=80,.num_buffers=40,.pages_per_buffer=22}));
You can't. That's why it is recommended to have as few function arguments as possible.
In your example you could have separate functions like set_num_buffers(int num_buffers), set_pages_per_buffer(int pages_per_buffer) etc.
You probably have noticed yourself that allocate_things is not a good name because it doesn't express what the function is actually doing. Especially I would not expect it to set a default value.
Just for completeness, you could use named arguments, when your call becomes.
void allocate_things(num_buffers=20, pages_per_buffer=40, default_value=20);
// or equivalently
void allocate_things(pages_per_buffer=40, default_value=20, num_buffers=20);
However, with the current C++ this requires quite a bit of code to be implemented (in the header file declaring allocate_things(), which must also declare appropriate external objects num_buffers etc providing operator= which return a unique suitable object).
---------- working example (for sergej)
#include <iostream>
struct a_t { int x=0; a_t(int i): x(i){} };
struct b_t { int x=0; b_t(int i): x(i){} };
struct c_t { int x=0; c_t(int i): x(i){} };
// implement using all possible permutations of the arguments.
// for many more argumentes better use a varidadic template.
void func(a_t a, b_t b, c_t c)
{ std::cout<<"a="<<a.x<<" b="<<b.x<<" c="<<c.x<<std::endl; }
inline void func(b_t b, c_t c, a_t a) { func(a,b,c); }
inline void func(c_t c, a_t a, b_t b) { func(a,b,c); }
inline void func(a_t a, c_t c, b_t b) { func(a,b,c); }
inline void func(c_t c, b_t b, a_t a) { func(a,b,c); }
inline void func(b_t b, a_t a, c_t c) { func(a,b,c); }
struct make_a { a_t operator=(int i) { return {i}; } } a;
struct make_b { b_t operator=(int i) { return {i}; } } b;
struct make_c { c_t operator=(int i) { return {i}; } } c;
int main()
{
func(b=2, c=10, a=42);
}
Are you really going to try to QA all the combinations of arbitrary integers? And throw in all the checks for negative/zero values etc?
Just create two enum types for minimum, medium and maximum number of buffers, and small medium and large buffer sizes. Then let the compiler do the work and let your QA folks take an afternoon off:
allocate_things(MINIMUM_BUFFER_CONFIGURATION, LARGE_BUFFER_SIZE, 42);
Then you only have to test a limited number of combinations and you'll have 100% coverage. The people working on your code 5 years from now will only need to know what they want to achieve and not have to guess the numbers they might need or which values have actually been tested in the field.
It does make the code slightly harder to extend, but it sounds like the parameters are for low-level performance tuning, so twiddling the values should not be perceived as cheap/trivial/not needing thorough testing. A code review of a change from
allocate_something(25, 25, 25);
...to
allocate_something(30, 80, 42);
...will likely get just a shrug/blown off, but a code review of a new enum value EXTRA_LARGE_BUFFERS will likely trigger all the right discussions about memory use, documentation, performance testing etc.

Fixing initialization of structs for which constructors have been added

A while ago I wrote code resembling this:
struct Thing
{
int a,b;
};
struct Junk
{
double x;
Thing things[10];
};
Junk myjunk[] =
{
{ 23.4, { {10,20}, {30,40} } },
{ 45.6, { {55,66}, {77,88} } }
};
Originally Thing had no constructors - just a flat simple struct to hold a couple integers. myjunk[] is meant to be special hand-written data to feed into something. In real life it has dozens of lines not just two. This code compiled fine.
Then this morning I added constructors to Thing, useful elsewhere in the great scheme of things, for example, to call functions like blarf(Thing(123,456)); and create huge arrays on the heap with 'new'.
struct Thing
{
int a,b;
Thing();
Thing(int _a, int _b);
};
Now it doesn't compile. I get
Error 1 error C2552: 'Junk::things' : non-aggregates cannot be initialized with initializer list
Yes, class with constructors cannot be made this way. What is the quickest simplest fix to get this compiling?
I know C++11 allows some new ways to initialize variables, but it's not clear in this case what's best. I'm not creating a lone Thing, but an array, and that within another struct. 'Junk' will never have a constructor.
Note that there aren't any virtual methods anywhere, and never will be for Thing and Junk. I'm using Visual Studio 2010, and not sure if it's taking source to be C++11 or older C++.
Change {10, 20} to Thing(10, 20) and so forth.
If you make the constructors constexpr conditional on language version then once you upgrade to a modern compiler you will be able to have the objects initialized at compile-time again:
#if __cplusplus >= 201103L
constexpr
#endif
Thing() : a(0), b(0) {}
#if __cplusplus >= 201103L
constexpr
#endif
Thing(int a, int b) : a(a), b(b) {}
Your code is valid since C++11, so your compiler must not support that. What you can do is initialize the arrays like this:
Junk myjunk[] =
{
{ 23.4, { Thing(10,20), Thing(30,40) } },
{ 45.6, { Thing(55,66), Thing(77,88) } }
};
You can add constructor for Junk with follows
Junk(double _x, initializer_list<Thing> tl) : x(_x){
int i = 0;
for (auto & t : tl) {
things[i] = t;
++i;
if (i >= 10) {
break;
}
}
}

C++ similar behavior to java.lang.Enum<E> [duplicate]

It is common knowledge that built-in enums in C++ are not typesafe.
I was wondering which classes implementing typesafe enums are used out there...
I myself use the following "bicycle", but it is somewhat verbose and limited:
typesafeenum.h:
struct TypesafeEnum
{
// Construction:
public:
TypesafeEnum(): id (next_id++), name("") {}
TypesafeEnum(const std::string& n): id(next_id++), name(n) {}
// Operations:
public:
bool operator == (const TypesafeEnum& right) const;
bool operator != (const TypesafeEnum& right) const;
bool operator < (const TypesafeEnum& right) const;
std::string to_string() const { return name; }
// Implementation:
private:
static int next_id;
int id;
std::string name;
};
typesafeenum.cpp:
int TypesafeEnum::next_id = 1;
bool TypesafeEnum::operator== (const TypesafeEnum& right) const
{ return id == right.id; }
bool TypesafeEnum::operator!= (const TypesafeEnum& right) const
{ return !operator== (right); }
bool TypesafeEnum::operator< (const TypesafeEnum& right) const
{ return id < right.id; }
Usage:
class Dialog
{
...
struct Result: public TypesafeEnum
{
static const Result CANCEL("Cancel");
static const Result OK("Ok");
};
Result doModal();
...
};
const Dialog::Result Dialog::Result::OK;
const Dialog::Result Dialog::Result::CANCEL;
Addition:
I think I should have been more specific about the requirements. I'll try to summarize them:
Priority 1: Setting an enum variable to an invalid value should be impossible (a compile-time error) with no exceptions.
Priority 2: Converting an enum value to/from an int should be possible with a single explicit function/method call.
Priority 3: As compact, elegant and convenient declaration and usage as possible
Priority 4: Converting enum values to and from strings.
Priority 5: (Nice to have) Possibility to iterate over enum values.
I'm currently playing around with the Boost.Enum proposal from the Boost Vault (filename enum_rev4.6.zip). Although it was never officially submitted for inclusion into Boost, it's useable as-is. (Documentation is lacking but is made up for by clear source code and good tests.)
Boost.Enum lets you declare an enum like this:
BOOST_ENUM_VALUES(Level, const char*,
(Abort)("unrecoverable problem")
(Error)("recoverable problem")
(Alert)("unexpected behavior")
(Info) ("expected behavior")
(Trace)("normal flow of execution")
(Debug)("detailed object state listings")
)
And have it automatically expand to this:
class Level : public boost::detail::enum_base<Level, string>
{
public:
enum domain
{
Abort,
Error,
Alert,
Info,
Trace,
Debug,
};
BOOST_STATIC_CONSTANT(index_type, size = 6);
Level() {}
Level(domain index) : boost::detail::enum_base<Level, string>(index) {}
typedef boost::optional<Level> optional;
static optional get_by_name(const char* str)
{
if(strcmp(str, "Abort") == 0) return optional(Abort);
if(strcmp(str, "Error") == 0) return optional(Error);
if(strcmp(str, "Alert") == 0) return optional(Alert);
if(strcmp(str, "Info") == 0) return optional(Info);
if(strcmp(str, "Trace") == 0) return optional(Trace);
if(strcmp(str, "Debug") == 0) return optional(Debug);
return optional();
}
private:
friend class boost::detail::enum_base<Level, string>;
static const char* names(domain index)
{
switch(index)
{
case Abort: return "Abort";
case Error: return "Error";
case Alert: return "Alert";
case Info: return "Info";
case Trace: return "Trace";
case Debug: return "Debug";
default: return NULL;
}
}
typedef boost::optional<value_type> optional_value;
static optional_value values(domain index)
{
switch(index)
{
case Abort: return optional_value("unrecoverable problem");
case Error: return optional_value("recoverable problem");
case Alert: return optional_value("unexpected behavior");
case Info: return optional_value("expected behavior");
case Trace: return optional_value("normal flow of execution");
case Debug: return optional_value("detailed object state listings");
default: return optional_value();
}
}
};
It satisfies all five of the priorities which you list.
A nice compromise method is this:
struct Flintstones {
enum E {
Fred,
Barney,
Wilma
};
};
Flintstones::E fred = Flintstones::Fred;
Flintstones::E barney = Flintstones::Barney;
It's not typesafe in the same sense that your version is, but the usage is nicer than standard enums, and you can still take advantage of integer conversion when you need it.
I use C++0x typesafe enums. I use some helper template/macros that provide the to/from string functionality.
enum class Result { Ok, Cancel};
I don't. Way too much overhead for little benefit. Also, being able to caste enumerations to different data types for serialization is a very handy tool. I have never seen an instance where a "Type safe" enumeration would be worth the overhead and complexity where C++ offers a good enough implementation already.
My take is that you're inventing a problem and then fitting a solution onto it. I see no need to do an elaborate framework for an enumeration of values. If you are dedicated to having your values only be members of a certain set, you could hack up a variant of a unique set datatype.
I'm personally using an adapted version of the typesafe enum idiom. It doesn't provide all the five "requirements" that you've stated in your edit, but I strongly disagree with some of them anyway. For example, I don't see how Prio#4 (conversion of values to strings) has anything to do with type safety. Most of the time string representation of individual values should be separate from the definition of the type anyway (think i18n for a simple reason why). Prio#5 (iteratio, which is optional) is one of the nicest things I'd like to see naturally happening in enums, so I felt sad that it appears as "optional" in your request, but it seems it is better addressed via a separate iteration system such as begin/end functions or an enum_iterator, which makes them work seamlessly with STL and C++11 foreach.
OTOH this simple idiom nicely provides Prio#3 Prio#1 thanks to the fact that it mostly only wraps enums with more type information. Not to mention it is a very simple solution that for the most part doesn't require any external dependency headers, so it's pretty easy to carry around. It also has the advantage of making enumerations scoped a-la-C++11:
// This doesn't compile, and if it did it wouldn't work anyway
enum colors { salmon, .... };
enum fishes { salmon, .... };
// This, however, works seamlessly.
struct colors_def { enum type { salmon, .... }; };
struct fishes_def { enum type { salmon, .... }; };
typedef typesafe_enum<colors_def> colors;
typedef typesafe_enum<fishes_def> fishes;
The only "hole" that solution provides is that it doesn't address the fact that it doesn't prevent enums of different types (or an enum and an int) from being directly compared, because when you use values directly you force the implicit conversion to int:
if (colors::salmon == fishes::salmon) { .../* Ooops! */... }
But so far I've found such problems can be solved by simply offering a better comparison to the compiler - for example, explicitly providing an operator that compares any two different enum types, then forcing it to fail:
// I'm using backports of C++11 utilities like static_assert and enable_if
template <typename Enum1, typename Enum2>
typename enable_if< (is_enum<Enum1>::value && is_enum<Enum2>::value) && (false == is_same<Enum1,Enum2>::value) , bool >
::type operator== (Enum1, Enum2) {
static_assert (false, "Comparing enumerations of different types!");
}
Though it doesn't seem to break code so far, and it does to explicitly deal with the specific problem without doing something else, I'm not sure it such thing is a thing one "should" do (I suspect it will interfere with enums already taking part in conversion operators declared elsewhere; I'd gladly receive commentary about this).
Combining this with the above typesafe idiom gives something that is relatively close to C++11 enum class in humanibility (readability and maintainability) without having to do anything too obscure. And I have to admit it was fun to do, I had never thought to actually ask the compiler if I was dealing with enums or not...
I think the Java enum would be a good model to follow. Essentially, the Java form would look like this:
public enum Result {
OK("OK"), CANCEL("Cancel");
private final String name;
Result(String name) {
this.name = name;
}
public String getName() {
return name;
}
}
What's interesting about the Java approach is that OK and CANCEL are immutable, singleton instances of Result (with the methods that you see). You cannot create any further instances of Result. Since they're singletons, you can compare by pointer/reference---very handy. :-)
ETA: In Java, instead of doing bitmasks by hand, instead you use an EnumSet to specify a bit set (it implements the Set interface, and works like sets---but implemented using bitmasks). Much more readable than hand-written bitmask manipulation!
I gave an answer to this here, on a different topic. It's a different style of approach which allows most of the same functionality without requiring modification to the original enum definition (and consequently allowing usage in cases where you don't define the enum). It also allows runtime range checking.
The downside of my approach is that it doesn't programmatically enforce the coupling between the enum and the helper class, so they have to be updated in parallel. It works for me, but YMMV.
I am currently writing my own typesafe enum library at https://bitbucket.org/chopsii/typesafe-enums
I am not the most experienced C++ developer ever, but I am writing this due to the shortcomings of the BOOST vault enums.
Feel free to check it out and use them yourself, but they have some (hopefully minor) usability issues, and are probably not at all cross-platform.
Please contribute if you want to. This is my first open source undertaking.
Use boost::variant!
After trying a lot of the above ideas and finding them lacking I hit upon this simple approach:
#include <iostream>
#include <boost/variant.hpp>
struct A_t {};
static const A_t A = A_t();
template <typename T>
bool isA(const T & x) { if(boost::get<A_t>(&x)) return true; return false; }
struct B_t {};
static const B_t B = B_t();
template <typename T>
bool isB(const T & x) { if(boost::get<B_t>(&x)) return true; return false; }
struct C_t {};
static const C_t C = C_t();
template <typename T>
bool isC(const T & x) { if(boost::get<C_t>(&x)) return true; return false; }
typedef boost::variant<A_t, B_t> AB;
typedef boost::variant<B_t, C_t> BC;
void ab(const AB & e)
{
if(isA(e))
std::cerr << "A!" << std::endl;
if(isB(e))
std::cerr << "B!" << std::endl;
// ERROR:
// if(isC(e))
// std::cerr << "C!" << std::endl;
// ERROR:
// if(e == 0)
// std::cerr << "B!" << std::endl;
}
void bc(const BC & e)
{
// ERROR:
// if(isA(e))
// std::cerr << "A!" << std::endl;
if(isB(e))
std::cerr << "B!" << std::endl;
if(isC(e))
std::cerr << "C!" << std::endl;
}
int main() {
AB a;
a = A;
AB b;
b = B;
ab(a);
ab(b);
ab(A);
ab(B);
// ab(C); // ERROR
// bc(A); // ERROR
bc(B);
bc(C);
}
You can probably come up with a macro to generate the boilerplate. (Let me know if you do.)
Unlike other approaches this one is actually type-safe and works with old C++. You can even make cool types like boost::variant<int, A_t, B_t, boost::none>, for example, to represent a value that could be A, B, an integer or nothing which is almost Haskell98 levels of type safety.
Downsides to be aware of:
at-least with old boost -- I'm on a system with boost 1.33 -- you are limited to 20 items in your variant; there is a work-around however
affects compile time
insane error messages -- but that's C++ for you
Update
Here, for your convenience is your typesafe-enum "library". Paste this header:
#ifndef _TYPESAFE_ENUMS_H
#define _TYPESAFE_ENUMS_H
#include <string>
#include <boost/variant.hpp>
#define ITEM(NAME, VAL) \
struct NAME##_t { \
std::string toStr() const { return std::string( #NAME ); } \
int toInt() const { return VAL; } \
}; \
static const NAME##_t NAME = NAME##_t(); \
template <typename T> \
bool is##NAME(const T & x) { if(boost::get<NAME##_t>(&x)) return true; return false; } \
class toStr_visitor: public boost::static_visitor<std::string> {
public:
template<typename T>
std::string operator()(const T & a) const {
return a.toStr();
}
};
template<BOOST_VARIANT_ENUM_PARAMS(typename T)>
inline static
std::string toStr(const boost::variant<BOOST_VARIANT_ENUM_PARAMS(T)> & a) {
return boost::apply_visitor(toStr_visitor(), a);
}
class toInt_visitor: public boost::static_visitor<int> {
public:
template<typename T>
int operator()(const T & a) const {
return a.toInt();
}
};
template<BOOST_VARIANT_ENUM_PARAMS(typename T)>
inline static
int toInt(const boost::variant<BOOST_VARIANT_ENUM_PARAMS(T)> & a) {
return boost::apply_visitor(toInt_visitor(), a);
}
#define ENUM(...) \
typedef boost::variant<__VA_ARGS__>
#endif
And use it like:
ITEM(A, 0);
ITEM(B, 1);
ITEM(C, 2);
ENUM(A_t, B_t) AB;
ENUM(B_t, C_t) BC;
Notice you have to say A_t instead of A in the ENUM macro which destroys some of the magic. Oh well. Also, notice there's now a toStr function and a toInt function to meet OPs requirement of simple conversion to strings and ints. The requirement I can't figure out is a way to iterate over the items. Let me know if you know how to write such a thing.
Not sure if this post is too late, but there's an article on GameDev.net which satisfies all but the 5th point (ability to iterate over enumerators):
http://www.gamedev.net/reference/snippets/features/cppstringizing/
The method described by the article allows string conversion support for existing enumerations without changing their code. If you only want support for new enumerations though, I'd go with Boost.Enum (mentioned above).