I was wondering why the code below only returns "Test" four times, instead of five?
#include <iostream>
#include <cassert>
using namespace std;
class CountDown
{
public: //Application Programmer Interface
CountDown(int start); // it is set to start
void next(); // subtracts one from it
bool end()const; //
private:
int it;
};
CountDown::CountDown(int start)
{
it = 0;
it = start;
}
void CountDown::next()
{
it = it - 1;
}
bool CountDown::end() const
{
if (it <= 0)
cout << "The countdown is now over" << endl;
}
int main()
{
for( CountDown i = 5 ; ! i.end(); i.next())
std::cerr << "test\n";
}
There is no point in doing this double initialization:
CountDown::CountDown(int start)
{
it = 0;
it = start;
}
This is enough:
CountDown::CountDown(int start)
{
it = start;
}
Or even this, using the initialization list:
CountDown::CountDown(int start):it(start)
{
}
As for end() you don't return any value from it. The method should probably look like this:
bool CountDown::end() const
{
return it <= 0;
}
try this.
bool CountDown::end() const
{
if (it > 1) return false;
return true;
}
Related
I'm trying to count vowels in a book "War and Peace" by Lev Tolstoi with 4 different methods:
Using Count_if/find
Using Count_if/for
for/find
4.for/for
The programm also calculates time it takes for every method to get the number of vowels. I'm using a russian version of the book as a reference so all the vowels are taken from cyrillic alphabet. Here is the code:
#include <chrono>
#include <iostream>
#include <vector>
#include <algorithm>
#include <cmath>
#include <Windows.h>
#include <string>
#include <fstream>
#include <iterator>
class Timer
{
private:
using clock_t = std::chrono::high_resolution_clock;
using second_t = std::chrono::duration<double, std::ratio<1> >;
std::string m_name;
std::chrono::time_point<clock_t> m_beg;
double elapsed() const
{
return std::chrono::duration_cast<second_t>(clock_t::now()
- m_beg).count();
}
public:
Timer() : m_beg(clock_t::now()) { }
Timer(std::string name) : m_name(name), m_beg(clock_t::now()) { }
void start(std::string name) {
m_name = name;
m_beg = clock_t::now();
}
void print() const {
std::cout << m_name << ":\t" << elapsed() * 1000 << " ms" << '\n';
}
};
const std::string vowels = "аеёиоуыэюяАЕЁИОУЫЭЮЯ";
bool containVowel(const std::string& s, const char& a)
{
for (size_t i = 0; i < s.size(); i++)
{
if (a == s[i])
{
return true;
}
return false;
}
}
void ForFor(std::ifstream& ifs, std::string& ww)
{
size_t count = 0;
Timer t1("for for");
while (ifs >> ww)
{
for (size_t i = 0; i < ww.size(); i++)
{
if (containVowel(vowels, ww[i]))
{
count++;
}
}
}
t1.print();
std::cout << count << std::endl;
}
//bool findVowel(char c)
//{
// return vowels.find(c) != std::string::npos;
//}
void CountIfFind(std::ifstream& ifs, std::string& ww) // not sure what is the way to cout count here...
{
Timer t("count_if/find");
while (ifs >> ww)
{
size_t count = std::count_if(ww.begin(), ww.end(), [&](char c) {return vowels.find(c) != std::string::npos; });
}
t.print();
}
void CountIfFor(std::ifstream& ifs, std::string& ww) // not sure what is the way to cout count here...
{
Timer t("count_if/for");
while (ifs >> ww)
{
for (size_t i = 0; i < vowels.size(); i++)
{
auto count = std::count_if(ww.begin(), ww.end(), [&](char c) {return c == vowels[i]; });
}
}
t.print();
}
void ForFind(std::ifstream& ifs, std::string& ww)
{
char c{};
int count = 0;
Timer t("for/find");
while (ifs >> ww)
{
for (size_t i = 0; i < ww.size(); i++)
{
if (vowels.find(c) != std::string::npos)
{
count++;
}
}
}
t.print();
std::cout << count << std::endl;
}
int main()
{
setlocale(LC_ALL, "ru");
SetConsoleCP(1251);
SetConsoleOutputCP(1251);
std::ifstream ifs;
ifs.open("Толстой Лев. Война и мир. Книга 1 - royallib.ru.txt");
if (ifs.is_open())
{
std::string ww;
ForFor(ifs, ww);
CountIfFind(ifs,ww);
CountIfFor(ifs,ww);
ForFind(ifs, ww);
ifs.close();
}
else
{
std::cout << "Can't open the file!" << std::endl;
}
}
Function ForFor works just fine but 3 other don't work (they don't show count but show time though). I'm guessing there is a problem with parsing the file, though I'm not sure because of my inexperience.
Will be hoping for your help!) Thank you all, in advance.
EDIT:Ok so now I'm sure the issue is in while(ifs>>ww). ForFor was the first function in the main so it worked, I tried commenting it and the next one CountIfFind started working. But when I delete while in every function and use it in main like: while(ifs>>ww) {ForFor(ww); CountIfFind(ww); CountIfFor(ww); ForFind(ww);} It doesn't work at all... How do I fix it?
So here is the correct way to do it:
class Timer
{
private:
using clock_t = std::chrono::high_resolution_clock;
using second_t = std::chrono::duration<double, std::ratio<1> >;
std::string m_name;
std::chrono::time_point<clock_t> m_beg;
double elapsed() const
{
return std::chrono::duration_cast<second_t>(clock_t::now()
- m_beg).count();
}
public:
Timer() : m_beg(clock_t::now()) { }
Timer(std::string name) : m_name(name), m_beg(clock_t::now()) { }
void start(std::string name) {
m_name = name;
m_beg = clock_t::now();
}
void print() const {
std::cout << m_name << ":\t" << elapsed() * 1000 << " ms" << '\n';
}
};
const std::string vowels = "аеёиоуыэюяАЕЁИОУЫЭЮЯ";
size_t ForFor(std::string& ww)
{
size_t count = 0;
Timer t1("for for");
for(const auto& ch : ww)
{
for (const auto& vow : vowels)
{
if (ch == vow)
{
++count;
break;
}
}
}
t1.print();
return count;
}
size_t CountIfFind(std::string& ww)
{
Timer t("count_if/find");
size_t count = std::count_if(ww.begin(), ww.end(), [ & ](char c) {return vowels.find(c) != std::string::npos; });
t.print();
return count;
}
size_t CountIfFor(std::string& ww)
{
Timer t("count_if/for");
size_t count = std::count_if(ww.begin(), ww.end(), [&](const char& c1)
{
for (const auto& ch : vowels)
{
if (c1 == ch)
{
return true;
}
}
return false;
});
t.print();
return count;
}
size_t ForFind(std::string& ww)
{
char c{};
size_t count = 0;
Timer t("for/find");
for (const auto& ch :ww)
{
if (vowels.find(ch) != std::string::npos)
{
++count;
}
}
t.print();
return count;
}
int main()
{SetConsoleCP(1251);
SetConsoleOutputCP(1251);
std::ifstream file("Толстой Лев. Война и мир. Книга 1 - royallib.ru.txt");
file.seekg(0, std::ios::end);
size_t size = file.tellg();
file.seekg(0);
std::string s(size, ' ');
file.read(&s[0], size);
std::cout << CountIfFind(s) << std::endl;
std::cout << ForFor(s) << std::endl;
std::cout << ForFind(s) << std::endl;
std::cout << CountIfFor(s) << std:: endl;
}
I have to finish a prompt tonight for my coding class, and I believe I am writing this incorrectly. I have reviewed other stackoverflow answers, but I still lack the understanding necessary to correctly solve this. This is part of a bigger project, so I have included all code in case another function is causing this error, but in my testing only the Ballot class is giving me errors.
In getVote, if the parameter is within the used portion of the array,
return the Voter pointer that corresponds with that position.
This is supposed to be tested with:
Ballot ballot1("WI-643UWO");
const Vote *vote3 = ballot1.getVote(2);
cout << vote3 << "\n";
//header file
pragma once
#include <string>
using namespace std;
class Election {
private:
string office;
string firstCanidiateName;
string secondCanidiateName;
public:
Election(string office2, string firstCanidiateName2, string secondCanidiateName2);
string getOffice() const;
string getCandidate1() const;
string getCandidate2() const;
};
class Vote {
private:
string vOffice;
string canidiateName;
bool voteMadeInPerson;
public:
Vote(string vOffice2, string canidiateName2, bool voteMadeInPerson2);
string getOffice() const;
string getCandidate() const;
bool wasInPerson() const;
};
class Ballot {
private:
string voterID;
int votesStored;
Vote* votePointer[6];
public:
Ballot();
Ballot(string voterID2);
~Ballot();
string getVoterId() const;
int getVoteCount() const;
const Vote* getVote(int votePosition) const;
void recordVote(string office, string candidateName, bool voteInPerson);
int countInPersonVotes();
int findVote(string office) const;
};
//functions file
#include "p3.h"
#include <string>
using namespace std;
Election::Election(string office2, string firstCanidiateName2, string secondCanidiateName2) {
office = office2;
firstCanidiateName = firstCanidiateName2;
secondCanidiateName = secondCanidiateName2;
}
string Election::getOffice() const {
return office;
}
string Election::getCandidate1() const {
return firstCanidiateName;
}
string Election::getCandidate2() const {
return secondCanidiateName;
}
string Vote::getOffice() const {
return vOffice;
}
string Vote::getCandidate() const {
return canidiateName;
}
bool Vote::wasInPerson() const {
return voteMadeInPerson;
}
Vote::Vote(string vOffice2, string canidiateName2, bool voteMadeInPerson2) {
if (vOffice2.empty() == true) {
vOffice2 = "Unknown";
}
vOffice = vOffice2;
if (canidiateName2.empty() == true) {
canidiateName2 = "Write In";
}
canidiateName = canidiateName2;
voteMadeInPerson = voteMadeInPerson2;
}
string Ballot::getVoterId() const {
return voterID;
}
int Ballot::getVoteCount() const {
return votesStored;
}
const Vote* Ballot::getVote(int votePosition) const {
Vote* out;
if (votePosition > -1 && votePosition < votesStored) {
//unsure if this is proper syntax -- will need testing
out = votePointer[votePosition];
return out;
}
else {
out = nullptr;
return out;
}
}
void Ballot::recordVote(string office, string candidateName, bool voteInPerson) {
if ((votesStored + 1) < 6) {
int x = findVote(office);
if (x != -1) {
Vote* z = new Vote(office, candidateName, voteInPerson);
votePointer[votesStored] = z;
++votesStored;
}
}
}
int Ballot::countInPersonVotes() {
int count = 0;
for (int i = 0; i < votesStored; ++i) {
bool x = false;
x = votePointer[i]->wasInPerson();
if (x == true) {
count++;
}
}
return count;
}
int Ballot::findVote(string office) const {
//test to make sure this logically works
int i = 0;
bool matchCheck = false;
for (i = 0; i < votesStored; ++i) {
if (votePointer[i]->getOffice() == office) {
matchCheck = true;
return i + 1;
}
}
if (matchCheck == false) {
return -1;
}
}
Ballot::Ballot(string voterID2) {
voterID = voterID2;
votesStored = 0;
}
Ballot::Ballot() {
voterID = "Invalid ID";
votesStored = 0;
}
Ballot::~Ballot() {
/**this is what the prompt asks for, technically.
the book details that this can be achieved in a more simple matter --
using the delete[] operator.
*/
for (int i = 0; i < 6; ++i) {
delete votePointer[i];
}
}
Any help would be appreciated - I am unsure where I am messing up here. I seem to be getting a lot of read access violation errors, but we haven't touched on debugging, so I'm not necessarily sure how to identify what I did wrong. Furthermore, my functions did seem to work initially until I tried fixing it, and now it gives me a read-error almost instantly, which is concerning. And lastly - I am new to pointers, so there is a very high chance I messed up there. Thanks for any advice.
I have a list of {a,b} and i need all possible combinatations where say n=3.
so:
[a,b,a],
[b,a,b]
[a,a,a]
[b,b,b]
etc.
Is there a name of such a problem
My current solution just uses random sampling and is very inefficient:
void set_generator(const vector<int>& vec, int n){
map<string, vector<int>> imap;
int rcount = 0;
while(1){
string ms = "";
vector<int> mset;
for(int i=0; i<n; i++){
int sampled_int = vec[rand() % vec.size()];
ms += std::to_string(sampled_int);
mset.emplace_back(sampled_int);
}
if(rcount > 100)
break;
if(imap.count(ms)){
rcount += 1;
//cout << "*" << endl;
continue;
}
rcount = 0;
imap[ms] = mset;
cout << ms << endl;
}
}
set_generator({1,2},3);
Let us call b the size of the input vector.
The problem consists in generating all numbers from 0 to b^n - 1, in base b.
A simple solution increments the elements of an array one by one, each from 0 to b-1.
This is performed by the function increment in the code hereafter.
Output:
111
211
121
221
112
212
122
222
The code:
#include <iostream>
#include <vector>
#include <string>
#include <map>
void set_generator_op (const std::vector<int>& vec, int n){
std::map<std::string, std::vector<int>> imap;
int rcount = 0;
while(1){
std::string ms = "";
std::vector<int> mset;
for(int i=0; i<n; i++){
int sampled_int = vec[rand() % vec.size()];
ms += std::to_string(sampled_int);
mset.emplace_back(sampled_int);
}
if(rcount > 100)
break;
if(imap.count(ms)){
rcount += 1;
//cout << "*" << endl;
continue;
}
rcount = 0;
imap[ms] = mset;
std::cout << ms << "\n";
}
}
// incrementation of a array of int, in base "base"
// return false if max is already attained
bool increment (std::vector<int>& cpt, int base) {
int n = cpt.size();
for (int i = 0; i < n; ++i) {
cpt[i]++;
if (cpt[i] != base) {
return true;
}
cpt[i] = 0;
}
return false;
}
void set_generator_new (const std::vector<int>& vec, int n){
int base = vec.size();
std::vector<int> cpt (n, 0);
while (true) {
std::string permut = "";
for (auto &k: cpt) {
permut += std::to_string (vec[k]);
}
std::cout << permut << "\n";
if (!increment(cpt, base)) return;
}
}
int main() {
set_generator_op ({1,2},3);
std::cout << "\n";
set_generator_new ({1,2},3);
}
Following advices of Jarod42, I have
suppressed the useless conversion to a string
used a more elegant do ... while instead of the while true
inversed the iterators for printing the result
Moreover, I have created a templated version of the program.
New output:
111
112
121
122
211
212
221
222
aaa
aab
aba
abb
baa
bab
bba
bbb
And the new code:
#include <iostream>
#include <vector>
#include <string>
#include <map>
// incrementation of a array of int, in base "base"
// return false if max is already attained
bool increment (std::vector<int>& cpt, int base) {
int n = cpt.size();
for (int i = 0; i < n; ++i) {
cpt[i]++;
if (cpt[i] != base) {
return true;
}
cpt[i] = 0;
}
return false;
}
template <typename T>
void set_generator_new (const std::vector<T>& vec, int n){
int base = vec.size();
std::vector<int> cpt (n, 0);
do {
for (auto it = cpt.rbegin(); it != cpt.rend(); ++it) {
std::cout << vec[*it];
}
std::cout << "\n";
} while (increment(cpt, base));
}
int main() {
set_generator_new<int> ({1,2}, 3);
std::cout << "\n";
set_generator_new<char> ({'a','b'}, 3);
}
Besides the concrete answer for integer usage, I want to provide a generic way I needed during test case construction for scenarios with a wide spread of various parameter variations. Maybe it's helpful to you too, at least for similar scenarios.
#include <vector>
#include <memory>
class SingleParameterToVaryBase
{
public:
virtual bool varyNext() = 0;
virtual void reset() = 0;
};
template <typename _DataType, typename _ParamVariationContType>
class SingleParameterToVary : public SingleParameterToVaryBase
{
public:
SingleParameterToVary(
_DataType& param,
const _ParamVariationContType& valuesToVary) :
mParameter(param)
, mVariations(valuesToVary)
{
if (mVariations.empty())
throw std::logic_error("Empty variation container for parameter");
reset();
}
// Step to next parameter value, return false if end of value vector is reached
virtual bool varyNext() override
{
++mCurrentIt;
const bool finished = mCurrentIt == mVariations.cend();
if (finished)
{
return false;
}
else
{
mParameter = *mCurrentIt;
return true;
}
}
virtual void reset() override
{
mCurrentIt = mVariations.cbegin();
mParameter = *mCurrentIt;
}
private:
typedef typename _ParamVariationContType::const_iterator ConstIteratorType;
// Iterator to the actual values this parameter can yield
ConstIteratorType mCurrentIt;
_ParamVariationContType mVariations;
// Reference to the parameter itself
_DataType& mParameter;
};
class GenericParameterVariator
{
public:
GenericParameterVariator() : mFinished(false)
{
reset();
}
template <typename _ParameterType, typename _ParameterVariationsType>
void registerParameterToVary(
_ParameterType& param,
const _ParameterVariationsType& paramVariations)
{
mParametersToVary.push_back(
std::make_unique<SingleParameterToVary<_ParameterType, _ParameterVariationsType>>(
param, paramVariations));
}
const bool isFinished() const { return mFinished; }
void reset()
{
mFinished = false;
mNumTotalCombinationsVisited = 0;
for (const auto& upParameter : mParametersToVary)
upParameter->reset();
}
// Step into next state if possible
bool createNextParameterPermutation()
{
if (mFinished || mParametersToVary.empty())
return false;
auto itPToVary = mParametersToVary.begin();
while (itPToVary != mParametersToVary.end())
{
const auto& upParameter = *itPToVary;
// If we are the very first configuration at all, do not vary.
const bool variedSomething = mNumTotalCombinationsVisited == 0 ? true : upParameter->varyNext();
++mNumTotalCombinationsVisited;
if (!variedSomething)
{
// If we were not able to vary the last parameter in our list, we are finished.
if (std::next(itPToVary) == mParametersToVary.end())
{
mFinished = true;
return false;
}
++itPToVary;
continue;
}
else
{
if (itPToVary != mParametersToVary.begin())
{
// Reset all parameters before this one
auto itBackwd = itPToVary;
do
{
--itBackwd;
(*itBackwd)->reset();
} while (itBackwd != mParametersToVary.begin());
}
return true;
}
}
return true;
}
private:
// Linearized parameter set
std::vector<std::unique_ptr<SingleParameterToVaryBase>> mParametersToVary;
bool mFinished;
size_t mNumTotalCombinationsVisited;
};
Possible usage:
GenericParameterVariator paramVariator;
size_t param1;
int param2;
char param3;
paramVariator.registerParameterToVary(param1, std::vector<size_t>{ 1, 2 });
paramVariator.registerParameterToVary(param2, std::vector<int>{ -1, -2 });
paramVariator.registerParameterToVary(param3, std::vector<char>{ 'a', 'b' });
std::vector<std::tuple<size_t, int, char>> visitedCombinations;
while (paramVariator.createNextParameterPermutation())
visitedCombinations.push_back(std::make_tuple(param1, param2, param3));
Generates:
(1, -1, 'a')
(2, -1, 'a')
(1, -2, 'a')
(2, -2, 'a')
(1, -1, 'b')
(2, -1, 'b')
(1, -2, 'b')
(2, -2, 'b')
For sure, this can be further optimized/specialized. For instance you can simply add a hashing scheme and/or an avoid functor if you want to avoid effective repetitions. Also, since the parameters are held as references, one might consider to protect the generator from possible error-prone usage via deleting copy/assignement constructors and operators.
Time complexity is within the theoretical permutation complexity range.
We have been restricted us to not use a loop in a program as a programming challenge.
Restrictions:
You can not use while, for, goto and recursion.
The restrictions are pretty daunting. I couldn't really think of any proper solution.
So I opted for this one which is achieved by modifying the return address.
Could this be any better?
#include <unistd.h>
#include <sys/mman.h>
#include <iostream>
#include <cstring>
void the__(){}
void magic__(){}
void loop__(){}
void function__(){}
void here__(){}
template <typename T>
struct for_
{
bool started = false;
void* fix = nullptr;
void(*body)(T&) = nullptr;
for_(void(*body)(T&))
: body(body)
{
auto do_for__ = uintptr_t(do_for_);
uint64_t magic[] = {5243466812662057800, 6135086863767628931ull, 10416984888688609608ull, 144};
mprotect((void*)(do_for__-do_for__%4096), 4096, 7);
std::memcpy((void*)(do_for__+135), magic, 25);
}
static void do_for_(T& ctx)
{
void** p = (void**)((char*)&p+16);
if (!ctx.started)
{
if (!ctx) return;
ctx.started = true;
ctx.fix = *p;
*p = (void*)do_for_;
}
ctx.body(ctx);
ctx.next();
if (ctx)
{
the__();
magic__();
loop__();
function__();
here__();
}
else
{
*p = ctx.fix;
}
}
};
struct For0ToN : for_<For0ToN>
{
For0ToN(int N, void(*f)(For0ToN&))
: for_<For0ToN>(f)
, N(N)
{
do_for_(*this);
}
operator bool() {return i < N;}
operator int() {return i;}
void next() {i++;}
int count() {return i;}
int i = 0, N = 0;
};
int main()
{
For0ToN(10, +[](For0ToN& i)
{
std::cout << int(i) << ": ";
For0ToN(i.count(), +[](For0ToN& i)
{
std::cout << int(i) << ". ";
});
std::cout << "\n";
});
std::cout << "done\n";
return 0;
}
The code is demonstrated here: https://coliru.stacked-crooked.com/a/3dd77ade501ac748
You could use longjmp. Here's an example from cppreference:
#include <csetjmp>
#include <iostream>
std::jmp_buf jump_buffer;
[[noreturn]] void a(int count)
{
std::cout << "a(" << count << ") called\n";
std::longjmp(jump_buffer, count+1); // setjmp() will return count+1
}
int main() {
// loop from 0-9
volatile int count = 0; // local variables must be volatile for setjmp
if (setjmp(jump_buffer) != 10) {
a(count++); // This will cause setjmp() to exit
}
}
Question is unclear but 1 alternative of the loop is std::transform()
Template metaprogramming is common way of avoiding writing explicit loop in code. This work gets done by compiler. Check this for examples of factorial and bubble sort implementation without writing explicit loops. You can check this stack overflow post as well.
Does it count if I hide recursion into function objects and create a finite state machine?
struct state
{
size_t current_column;
size_t current_row;
size_t max_column;
size_t max_row;
};
typedef function<void(state&)> action_t;
struct do_item
{
do_item(ostream& ss, action_t* move_next)
: ss_(ss), move_next_(move_next) {}
void operator()(state& s)
{
if (s.current_row == s.max_row)
{
ss_ << "done";
return;
}
if (0 == s.current_column)
{
ss_ << s.current_row << ':';
}
if (s.max_column == s.current_column)
{
ss_ << '\n';
s.current_column = 0;
++s.current_row;
s.max_column = s.current_row;
}
else
{
ss_ << ' ' << s.current_column << '.';
++s.current_column;
}
(*move_next_)(s);
}
ostream& ss_;
action_t* move_next_;
};
static string no_loops_challenge(size_t n)
{
stringstream ss;
state s = {0, 0, 0, n};
action_t move_next;
do_item action(ss, &move_next);
move_next = action;
action(s);
return ss.str();
}
Here's a solution using range-v3 that should satisfy all the constraints:
namespace rv = ranges::views;
ranges::for_each(rv::iota(0, 10), [](int i) {
std::cout << i << ": ";
ranges::copy(rv::iota(0, i),
ranges::ostream_iterator<int>(std::cout, ". "));
std::cout << "\n";
});
Here's a demo.
I can't seem to iterate through all the nodes. It goes through only 1 or two nodes and fails to return true for any case. I want the program to iterator through the node multiple times to get all possible outcome, but still be Eulerian circuit. This is just a small example. To determine if it is Eulerian Circuit, it must pass through the edge only once. Whenever i tried the recursive function DFSUtil, it will stop at the first node or the 2nd node.
Example:
start = A
End = C
A connect to B
A connect to C
B connect to A
B connect to C
C connect to B
Result: 2 path
A -> B -> C -> B -> A -> C
A -> B -> A -> C -> B -> C
#include <iostream>
#include <string>
#include <string.h>
#include <sstream>
#include <stdio.h>
#include <stack>
#include <vector>
using namespace std;
unsigned int V;
class node
{
public:
string Enzyme;
vector<node> connection;
node(string Enzyme)
{
this->Enzyme = Enzyme;
}
bool isEulerCircuit();
bool isConnected();
string DFSUtil(unsigned int v,bool visited[]);
void add_edge(node &n)
{
connection.push_back(n);
cout << Enzyme << " connected to " << n.Enzyme << endl;
}
};
string node::DFSUtil(unsigned int v,bool visited[])
{
visited[v] = true;
vector<node>::iterator it;
string res;
for(it = connection.begin(); it != connection.end(); it++)
{
cout << (*it).Enzyme << endl;
if(!visited[v])
{
res+= (*it).Enzyme;
DFSUtil(v,visited);
}
}
return res;
}
bool node::isEulerCircuit()
{
if (isConnected() == false)
{
return false;
}
return true;
}
bool node::isConnected()
{
bool visited[V];
for(int i = 0; i < V; i++)
{
visited[i] = false;
}
int n=3;
DFSUtil(n,visited);
for (int i = 0; i < V; i++)
{
if (visited[i] == false)
{
return false;
}
}
return true;
}
int main()
{
vector<node> nod;
string A = "A";
string B = "B";
string C = "C";
nod.push_back(A);
nod.push_back(B);
nod.push_back(C);
for(int i = 0; i < nod.size(); i++)
{
V = i;
}
cout << endl;
nod[0].add_edge(nod[1]);
nod[0].add_edge(nod[2]);
nod[1].add_edge(nod[0]);
nod[1].add_edge(nod[2]);
nod[2].add_edge(nod[1]);
if(nod[0].isEulerCircuit())
{
cout << "HI" << endl;
}
else
{
cout << "BYE" << endl;
}
return 0;
}