show children nodes depending on selected parent - django

Question

Hi i've been looking all over and can't find the answer to this. I have only 3 months experience in using python/django so excuse my dummy quesion!
Im using django mptt to display a simple nested set navigation.
<ul class="root">
{% recursetree nodes %}
<li>
{{ node.name }}
{% if not node.is_leaf_node %}
<ul class="children">
{{ children }}
</ul>
{% endif %}
</li>
{% endrecursetree %}
this works fine - however i would like to show only children of the selected category (based on slug) and not all of them.
Any ideas ???
i finally did it like this:
{% recursetree nodes %}
<li>
<a href='/{{ node.get_absolute_url}}'>{{ node.name }}</a>
</li>
{% if not node.is_leaf.node %}
{% for c in child %}
{% if c in node.get_children %}
{% if forloop.first %}
<ul class="children">
{{ children }}
</ul>
{% endif %}
{% endif %}
{% endfor %}
{% endif %}
{% endrecursetree %}
in views
category = get_object_or_404(Category, slug=slug)
child = category.get_children()
if not child :
child = category.get_siblings()
but it is a hack. has anyone got better idea?

Answer 1

You need to send down some information about what node you're in, and then it's a simple if statement.
Regarding how to send down the node information universally, there are a couple ways to do this in Django, and none of them are perfect. My preferred method is context processors: http://docs.djangoproject.com/en/1.3/ref/templates/api/#writing-your-own-context-processors

Answer 2

{% recursetree nodes %}
<li>
{{ node.name }}
{% if node.name == category.name %}
<ul>
{{ children }}
</ul>
{% endif %}
<li>
{% endrecursetree %}

Answer 3

You can try this:
{% recursetree nodes %}
#check if the node is a child node
{% if node.is_child_node %}
<a href="{{ node.get_absolute_url }}" >{{ node.name }}</a>
{% endif %}
#check if a root node is the current category
{% if node.is_root_node and node.name == category.name %}
{{ children }}
{% endif %}
{% endrecursetree %}