displayContacts :: Contact ->[String]
displayContacts [] = []
displayContacts (x :xs) = [show (x)] ++ displayContacts (xs)
after performing above function following result showing with exta "\" why is that and how to overcome this
["(\"Fazaal\",\"Naufer\",7712345678)","(\"Tharanga\",\"Chandasekara\",779876543)","
(\"Ruaim\",\"Mohomad\",7798454545)","(\"Yasitha\",\"Lokunarangoda\",7798121212)","
(\"Rochana\",\"Wimalasena\",779878787)","(\"Navin\",\"Dhananshan\",77987345678)","
( \"Akila\",\"Silva\",7798123123)","(\"Sudantha\",\"Gunawardana\",779812456)"]
i want to display this as "Fazaal" "Naufer" 7712345678 likewise
in my function contact is list of tupples :- [("Isuru","Ranaisnghe",123)]
When you show a string, show "hello", the show instance for String adds in quotes, which are escaped when GHCi prints out a data structure.
There are a few solutions, depending on what your goal is. If you just want cleaner output in GHCi then:
putStrLn $ unlines $ displayContacts contact
Related
I wanted to utilize the print function inside an SML program for sort of debugging purposes to print integer list type data, inside the function and during execution, e.g. inside a let block. However, as I saw, print can only print string type data. I cannot wait for the result to return to print what I want, because the function I created branches during execution and creates many different lists, and I want to see what is the resulting list at the end of each branch.
Therefore, is there a way to print a list inside of a function, as I would print a string?
If it is an int list you can do something like this:
fun printIntList ints = app (fn i => print(Int.toString i ^" ")) ints;
Then printIntList [1,2,3] will print 1 2 3
You can do similar things for other types.
On edit: This is the best you can do with straight SML. SML/NJ has its own extensions including "access to compiler internals" and "user-customizable pretty printing" which sounds promising -- though I have little experience with their extensions to the standard library.
Simple function for turning a list of ints into a string:
fun intlistToString [] = ""
| intlistToString [x] = Int.toString x
| intlistToString (x::xs) = Int.toString x ^ ", " ^ intlistToString xs
Then you can use print (intlistToString myList) instead of print myList. It won't print the square brackets around the list, not without a little more code, but I'll leave that as an exercise because I'm lazy.
I'm trying to add an int list list with another int list list using the append function, but I can't get it to work the way I want.
Say that I want to append [[1,2,3,4,5]] with [6,7] so that I get [[1,2,3,4,5,6,7]].
Here's my attempt: [1,2,3,4,5]::[]#[6,7]::[], but it just gives me the list I want to append as a list of its own instead of the two lists combined into one, like this: [[1,2,3,4,5],[6,7]].
How can I re-write the operation to make it return [[1,2,3,4,5,6,7]]?
Your question is too unspecific. You are dealing with nested lists. Do you want to append the second list to every inner list of the nested list, or only the first one? Your example doesn't tell.
For the former:
fun appendAll xss ys = List.map (fn xs => xs # ys) xss
For the latter:
fun appendHd [] ys = raise Empty
| appendHd (xs::xss) ys = (xs # ys)::xss
However, both of these should rarely be needed, and I somehow feel that you are trying to solve the wrong problem if you end up there.
I have a list of coordinates that I need to put on map. Is it possible in julius to iterate the list ? Right now I am creating an hidden table in hamlet and accessing that table in julius which does not seem to be an ideal solution.
Could some one point to a better solution ? Thanks.
edit: Passing a JSON string for the list (which can be read by julius) seems to solve my problem.
As far as I know, you can't directly iterate over a list in julius. However, you can use the Monoid instance for the Javascript type to accomplish a similar effect. For example:
import Text.Julius
import Data.Monoid
rows :: [Int] -> t -> Javascript
rows xs = mconcat $ map row xs
where
row x = [julius|v[#{show x}] = #{show x};
|]
Then you can use rows xs wherever you'd normally put a julius block. For example, in ghci:
> renderJavascript $ rows [1..5] ()
"v[1] = 1;\nv[2] = 2;\nv[3] = 3;\nv[4] = 4;\nv[5] = 5;\n"
I need to scan through a document and accumulate the output of different functions for each string in the file. The function run on any given line of the file depends on what is in that line.
I could do this very inefficiently by making a complete pass through the file for every list I wanted to collect. Example pseudo-code:
at :: B.ByteString -> Maybe Atom
at line
| line == ATOM record = do stuff to return Just Atom
| otherwise = Nothing
ot :: B.ByteString -> Maybe Sheet
ot line
| line == SHEET record = do other stuff to return Just Sheet
| otherwise = Nothing
Then, I would map each of these functions over the entire list of lines in the file to get a complete list of Atoms and Sheets:
mapper :: [B.ByteString] -> IO ()
mapper lines = do
let atoms = mapMaybe at lines
let sheets = mapMaybe to lines
-- Do stuff with my atoms and sheets
However, this is inefficient because I am maping through the entire list of strings for every list I am trying to create. Instead, I want to map through the list of line strings only once, identify each line as I am moving through it, and then apply the appropriate function and store these values in different lists.
My C mentality wants to do this (pseudo code):
mapper' :: [B.ByteString] -> IO ()
mapper' lines = do
let atoms = []
let sheets = []
for line in lines:
| line == ATOM record = (atoms = atoms ++ at line)
| line == SHEET record = (sheets = sheets ++ ot line)
-- Now 'atoms' is a complete list of all the ATOM records
-- and 'sheets' is a complete list of all the SHEET records
What is the Haskell way of doing this? I simply can't get my functional-programming mindset to come up with a solution.
First of all, I think that the answers others have supplied will work at least 95% of the time. It's always good practice to code for the problem at hand by using appropriate data types (or tuples in some cases). However, sometimes you really don't know in advance what you're looking for in the list, and in these cases trying to enumerate all possibilities is difficult/time-consuming/error-prone. Or, you're writing multiple variants of the same sort of thing (manually inlining multiple folds into one) and you'd like to capture the abstraction.
Fortunately, there are a few techniques that can help.
The framework solution
(somewhat self-evangelizing)
First, the various "iteratee/enumerator" packages often provide functions to deal with this sort of problem. I'm most familiar with iteratee, which would let you do the following:
import Data.Iteratee as I
import Data.Iteratee.Char
import Data.Maybe
-- first, you'll need some way to process the Atoms/Sheets/etc. you're getting
-- if you want to just return them as a list, you can use the built-in
-- stream2list function
-- next, create stream transformers
-- given at :: B.ByteString -> Maybe Atom
-- create a stream transformer from ByteString lines to Atoms
atIter :: Enumeratee [B.ByteString] [Atom] m a
atIter = I.mapChunks (catMaybes . map at)
otIter :: Enumeratee [B.ByteString] [Sheet] m a
otIter = I.mapChunks (catMaybes . map ot)
-- finally, combine multiple processors into one
-- if you have more than one processor, you can use zip3, zip4, etc.
procFile :: Iteratee [B.ByteString] m ([Atom],[Sheet])
procFile = I.zip (atIter =$ stream2list) (otIter =$ stream2list)
-- and run it on some data
runner :: FilePath -> IO ([Atom],[Sheet])
runner filename = do
resultIter <- enumFile defaultBufSize filename $= enumLinesBS $ procFile
run resultIter
One benefit this gives you is extra composability. You can create transformers as you like, and just combine them with zip. You can even run the consumers in parallel if you like (although only if you're working in the IO monad, and probably not worth it unless the consumers do a lot of work) by changing to this:
import Data.Iteratee.Parallel
parProcFile = I.zip (parI $ atIter =$ stream2list) (parI $ otIter =$ stream2list)
The result of doing so isn't the same as a single for-loop - this will still perform multiple traversals of the data. However, the traversal pattern has changed. This will load a certain amount of data at once (defaultBufSize bytes) and traverse that chunk multiple times, storing partial results as necessary. After a chunk has been entirely consumed, the next chunk is loaded and the old one can be garbage collected.
Hopefully this will demonstrate the difference:
Data.List.zip:
x1 x2 x3 .. x_n
x1 x2 x3 .. x_n
Data.Iteratee.zip:
x1 x2 x3 x4 x_n-1 x_n
x1 x2 x3 x4 x_n-1 x_n
If you're doing enough work that parallelism makes sense this isn't a problem at all. Due to memory locality, the performance is much better than multiple traversals over the entire input as Data.List.zip would make.
The beautiful solution
If a single-traversal solution really does make the most sense, you might be interested in Max Rabkin's Beautiful Folding post, and Conal Elliott's followup work (this too). The essential idea is that you can create data structures to represent folds and zips, and combining these lets you create a new, combined fold/zip function that only needs one traversal. It's maybe a little advanced for a Haskell beginner, but since you're thinking about the problem you may find it interesting or useful. Max's post is probably the best starting point.
I show a solution for two types of line, but it is easily extended to five types of line by using a five-tuple instead of a two-tuple.
import Data.Monoid
eachLine :: B.ByteString -> ([Atom], [Sheet])
eachLine bs | isAnAtom bs = ([ {- calculate an Atom -} ], [])
| isASheet bs = ([], [ {- calculate a Sheet -} ])
| otherwise = error "eachLine"
allLines :: [B.ByteString] -> ([Atom], [Sheet])
allLines bss = mconcat (map eachLine bss)
The magic is done by mconcat from Data.Monoid (included with GHC).
(On a point of style: personally I would define a Line type, a parseLine :: B.ByteString -> Line function and write eachLine bs = case parseLine bs of .... But this is peripheral to your question.)
It is a good idea to introduce a new ADT, e.g. "Summary" instead of tuples.
Then, since you want to accumulate the values of Summary you came make it an istance of Data.Monoid. Then you classify each of your lines with the help of classifier functions (e.g. isAtom, isSheet, etc.) and concatenate them together using Monoid's mconcat function (as suggested by #dave4420).
Here is the code (it uses String instead of ByteString, but it is quite easy to change):
module Classifier where
import Data.List
import Data.Monoid
data Summary = Summary
{ atoms :: [String]
, sheets :: [String]
, digits :: [String]
} deriving (Show)
instance Monoid Summary where
mempty = Summary [] [] []
Summary as1 ss1 ds1 `mappend` Summary as2 ss2 ds2 =
Summary (as1 `mappend` as2)
(ss1 `mappend` ss2)
(ds1 `mappend` ds2)
classify :: [String] -> Summary
classify = mconcat . map classifyLine
classifyLine :: String -> Summary
classifyLine line
| isAtom line = Summary [line] [] [] -- or "mempty { atoms = [line] }"
| isSheet line = Summary [] [line] []
| isDigit line = Summary [] [] [line]
| otherwise = mempty -- or "error" if you need this
isAtom, isSheet, isDigit :: String -> Bool
isAtom = isPrefixOf "atom"
isSheet = isPrefixOf "sheet"
isDigit = isPrefixOf "digits"
input :: [String]
input = ["atom1", "sheet1", "sheet2", "digits1"]
test :: Summary
test = classify input
If you have only 2 alternatives, using Either might be a good idea. In that case combine your functions, map the list, and use lefts and rights to get the results:
import Data.Either
-- first sample function, returning String
f1 x = show $ x `div` 2
-- second sample function, returning Int
f2 x = 3*x+1
-- combined function returning Either String Int
hotpo x = if even x then Left (f1 x) else Right (f2 x)
xs = map hotpo [1..10]
-- [Right 4,Left "1",Right 10,Left "2",Right 16,Left "3",Right 22,Left "4",Right 28,Left "5"]
lefts xs
-- ["1","2","3","4","5"]
rights xs
-- [4,10,16,22,28]
hi i have a problem, i have a list of items, for a simple understanding i have a [String] list
now there are several items, but not all items should be in there, so i need to do some things:
print the list to the user in the console (easy with map putStrLn list)
i need to let the user select items which should be used/deleted, how to do this?
then i can work on the selected items and use/delete it
i need help to do the selection. i can't use a GUI and have only the console.
have somebody a idea?
For the first, I'd suggest to use the module Text.Printf for formatting. We also need Data.Functor for <$>:
import Text.Printf (printf)
import Data.Functor ((<$>))
Print out the list and some indices:
putList = mapM (printf "%2d: %s\n") . zipWith [1..]
Print a prompt:
prompt = putStr "Enter a whitespace-separated list of entries to delete.\n> "
Read in the indices:
readIndices = map read . words <$> getLine
get a filtered list:
filtered ix = map snd . filter (flip notElem ix . fst) . zipWith [1..]
And put the blocks together:
filterList ls = do putList ls
prompt
ix <- readIndices
return $! filtered ix ls
That's all! If you have any further question, please ask.