C++ quick sort algorithm - c++

Question

I'm not looking to copy a qsort algorithm. I'm practicing writing qsort and this is what I've come up with and I'm interested in what part of my code is wrong. Please don't tell me that this is homework cause I could just use the code in the link below.
Reference: http://xoax.net/comp/sci/algorithms/Lesson4.php
When this runs I get this in the console:
Program loaded.
run
[Switching to process 10738]
Running…
Current language: auto; currently c++
Program received signal: “EXC_ARITHMETIC”.
void myQSort(int min, int max, int* myArray)
{
// Initially find a random pivot
int pivotIndex = rand() % max;
int pivot = myArray[pivotIndex];
int i = 0 , j = max-1;
// Pointer to begining of array and one to the end
int* begin = myArray;
int* end = &myArray[max-1];
// While begin < end
while( begin < end )
{
// Find the lowest bound number to swap
while( *begin < pivot )
{
begin++;
}
while( *end > pivot )
{
// Find the highest bound number to swap
end--;
}
// Do the swap
swap(begin,end);
}
// Partition left
myQSort(0, pivotIndex-1, myArray);
// Partiion right
myQSort(pivotIndex+1,max, myArray);
}
EDIT--
Code for Swap:
void swap(int* num, int* num2)
{
int temp = *num;
*num = *num2;
*num2 = temp;
}

Answer 1

// sort interval [begin, end)
void myQSort(int* begin, int* end)
{
if(end - begin < 2)
return;
int* l = begin;
int* r = end - 1;
// Initially find a random pivot
int* pivot = l + rand() % (r - l + 1);
while(l != r)
{
// Find the lowest bound number to swap
while(*l < *pivot) ++l;
while(*r >= *pivot && l < r) --r;
// Do the swap
if(pivot == l) { pivot = r; }
std::swap(*l, *r);
}
// Here l == r and numbers in the interval [begin, r) are lower and in the interval [l, end) are greater or equal than the pivot
// Move pivot to the position
std::swap(*pivot, *l);
// Sort left
myQSort(begin, l);
// Sort right
myQSort(l + 1, end);
}

Answer 2

You're not using the min parameter in your code, anywhere. You need to set begin and your pivot value using that.

Answer 3

I tried working out the codes above. But, they don't compile.
#Mihran: Your solution is correct algorithmically but the following line generates an error:
myQSort(min, begin - myArray, myArray);
This is because begin is of type int* and myArray is of type long, following which the compiler shows this error message:
implicit conversion loses integer precision
Here's a working solution in C++:
#include <iostream>
using namespace std;
void mySwap(int& num1, int& num2){
int temp = num1;
num1 = num2;
num2 = temp;
}
void myQsort(int myArray[], int min, int max){
int pivot = myArray[(min + max) / 2];
int left = min, right = max;
while (left < right) {
while (myArray[left] < pivot) {
left++;
}
while (myArray[right] > pivot) {
right--;
}
if (left <= right) {
mySwap(myArray[left], myArray[right]);
left++;
right--;
}
}
if (min < right) {
myQsort(myArray, min, right);
}
if (left < max) {
myQsort(myArray, left, max);
}
}
int main()
{
int myArray[] = {1, 12, -5, 260, 7, 14, 3, 7, 2};
int min = 0;
int max = sizeof(myArray) / sizeof(int);
myQsort(myArray, min, max-1);
for (int i = 0; i < max; i++) {
cout<<myArray[i]<<" ";
}
return 0;
}

Answer 4

Here's a clear C++ implementation, for reference:
#include <iostream>
#include <vector>
using namespace std;
int partition(std::vector<int>& arr, int low, int high) {
// set wall index
int wall_index = low;
int curr_index = low;
int pivot_elem = arr[high]; // taking last element as pivot_element
// loop through the entire received arr
for (int i = curr_index; i < high; ++i) {
// if element is less than or equal to pivot_elem
// swap the element with element on the right of the wall
// i.e swap arr[i] with arr[wall_index]
if (arr[i] <= pivot_elem) {
// swap
int temp = arr[wall_index];
arr[wall_index] = arr[i];
arr[i] = temp;
// move the wall one index to the right
wall_index++;
curr_index++;
} else {
// if the element is greater than the pivot_element
// then keep the wall at the same point and do nothing
curr_index++;
}
}
// need to swap the pivot_elem i.e arr[high] with the element right of the wall
int temp = arr[wall_index];
arr[wall_index] = arr[high];
arr[high] = temp;
return wall_index;
}
void quick_sort(std::vector<int>& arr, int low, int high) {
if (low < high) { // element with single arr always have low >= high
int split = partition(arr, low, high);
quick_sort(arr, low, split-1);
quick_sort(arr, split, high);
}
}
int main() {
std::vector<int> data = {6,13,8,4,2,7,16,3,8};
int N = data.size();
quick_sort(data, 0, N-1);
for (int i : data) {
cout << i << " ";
}
return 0;
}

Answer 5

I don't see a clean implementation of Quicksort on SO, so here is my easy to understand implementation
PLEASE DONT USE IN PRODUCTION CODE
This is only for your understanding
// Swap position a with b in an array of integer numbers
void swap(int *numbers, int a, int b){
int temp = numbers[a];
numbers[a] = numbers[b];
numbers[b] = temp;
}
static int partition(int *data, int low, int high) {
int left = low, right = high, pivot = data[low];
while (left < right) {
// Everthing on the left of pivot is lower than the pivot
while ((left <= right) && data[left] <= pivot) // <= is because left is the pivot initially
left++;
// Everything on the right of the pivot is greater than the pivot
while((left <= right) && data[right] > pivot)
right--;
if (left < right)
swap(data, left, right);
}
// Put the pivot in the 'rigthful' place
swap(data, low, right);
return right;
}
// Quicksort
static void quick_sort(int *numbers, int low, int high)
{
if (high > low) {
int p_index = partition(numbers, low, high);
quick_sort(numbers, low , p_index - 1);
quick_sort(numbers, p_index + 1, high);
}
}