urls.py
url(r'^some/page/$', views.some_page,
{'template_name': 'some/page.html'},
name='some_page'),
views.py
url = request.build_absolute_uri(reverse('some_page')).lower()
response = HttpResponseRedirect(url)
return response
Question:
Why doesn't this code work?
url = request.build_absolute_uri(reverse('some_page',
kwargs={"template_name": "another/page.html"})).lower()
I'm using django 1.2 on google appengine. Since I get the same error for any kind of typo/mistake, I didn't think it was useful to paste that error message here.
Thanks.
Because reverse expects the arguments to “fill in” regular expressions in the url. So reverse('some_page') should work.
What do you expect it to do?
Related
I have some links that include Persian texts, such as:
http://sample.com/fields/طب%20نظامی
And in the view function I want to access to Persian part, so:
url = request.path_info
key = re.findall('/fields/(.+)', url)[0]
But I get the following error:
IndexError at /fields/
list index out of range
Actually, the problem is with the index zero because it can not see anything there! It should be noted that it is a Django project on IIS Server and I have successfully tested it with other servers and the local server. I think it has some thing related to IIS. Moreover I have tried to slugify the url without success. I can encode urls successfully, but I think it is not the actual answer to this question.
Based on the comments:
I checked the request.path too and the same problem. It contains:
/fields/
I implemented a sample django project in local server and here is my views:
def test(request):
t = request.path
return HttpResponse(t)
The results:
http://127.0.0.1:8000/تست/
/تست/
Without any problem.
Based on the #sytech comment, I have created a middlware.py in my app directory:
from django.core.handlers.wsgi import WSGIHandler
class SimpleMiddleware(WSGIHandler):
def __call__(self, environ, start_response):
print(environ['UNENCODED_URL'])
return super().__call__(environ, start_response)
and in settings.py:
MIDDLEWARE = [
...
'apps.middleware.SimpleMiddleware',
]
But I am getting the following error:
__call__() missing 1 required positional argument: 'start_response'
Assuming you don't have another problem in your rewrite configuration, on IIS, depending on your rewrite configuration, you may need to access this through the UNENCODED_URL variable which will contain the unencoded value.
This can be demonstrated in a simple WSGI middleware:
from django.core.handlers.wsgi import WSGIHandler
class MyHandler(WSGIHandler):
def __call__(self, environ, start_response):
print(environ['UNENCODED_URL'])
return super().__call__(environ, start_response)
You would see the unencoded URL and the path part that's in Persian would be passed %D8%B7%D8%A8%2520%D9%86%D8%B8%D8%A7%D9%85%DB%8C. Which you can then decode with urllib.parse.unquote
urllib.parse.unquote('%D8%B7%D8%A8%2520%D9%86%D8%B8%D8%A7%D9%85%DB%8C')
# طب%20نظامی
If you wanted, you could use a middleware to set this as an attribute on the request object or even override the request.path_info.
You must be using URL rewrite v7.1.1980 or higher for this to work.
You could also use the UNENCODED_URL directly in the rewrite rule, but that may result in headaches with routing.
I can encode urls successfully, but I think it is not the actual answer to this question.
Yeah, that is another option, but may result in other issues like this: IIS10 URL Rewrite 2.1 double encoding issue
You can do this by using python split() method
url = "http://sample.com/fields/طب%20نظامی"
url_key = url.split(sep="/", maxsplit=4)
url_key[-1]
output : 'طب%20نظامی'
in this url is splited by / which occurs 4 time in string so it will return a list like this
['http:', '', 'sample.com', 'fields', 'طب%20نظامی']
then extract result like this url_key[-1] from url_key
you can Split the URL by :
string = http://sample.com/fields/طب%20نظامی
last_part = string. Split("/")[-1]
print(last_part)
output :< طب%20نظامی >
slugify(last_part)
or
slugify(last_part, allow_unicode=True)
I guess This Will Help You :)
I'm trying to use reverse to redirect a user to a login page from a third party App I'm using.
The URL config has:
urlpatterns = [
# authentication / association
url(r'^login/(?P<backend>[^/]+){0}$'.format(extra), views.auth,
name='begin'),
How can I accomplish this? I've tried
return redirect(reverse('social:login'), args=('facebook',))
and
return redirect(reverse('social:login'), kwargs={'backend':fb})
(to get to /login/facebook) but I'm getting a NoReverseMatch
The Django URL system and RegExes are confusing me a bit =(
EDIT: All right, it looks like I was making a mess with these URLs.
A simple solution that works (thank you #Alasdair in the comments):
return redirect('social:begin', backend='facebook')
I have the following URLs:
url(r'^%sdform/' %(URLPREFIX), pv.dform, name='dform'),
url(r'^%sform/(P?<growl>.*)/' %(URLPREFIX), pv.dform, name='dform'),
The view code:
def dform(request, growl = None) is the method signature
The redirect code:
msg = 'test'
return redirect('dform', growl=msg)
Any idea why I get that error? I'm sending the right parameter to the right view method with the right argument name and all that.
EDIT:
Based on the answer below, I tried:
url(r'^%sdform/(P?<growl>.*)/' %(URLPREFIX), pv.dform, name='dform_message')
And changed the redirect to:
return redirect('dform_message', growl='Updated Settings')
I still get NoReverseMatch
I think your problem is that you shall not use the same names for different urls (django docu).
I'm getting ready to move an old Classic ASP site to a new Django system. As part of the move we have to setup some of the old URLs to point to the new ones.
For example,
http://www.domainname.com/category.asp?categoryid=105 should 301 to http://www.domainname.com/some-category/
Perhaps I'm regex stupid or something, but for this example, I've included in my URLconf this:
(r'^asp/category\.asp\?categoryid=105$', redirect_to, {'url': '/some-category/'}),
My thinking is that I have to escape the . and the ? but for some reason when I go to test this, it does not redirect to /some-category/, it just 404s the URL as entered.
Am I doing it wrong? Is there a better way?
To elaborate on Daniel Roseman's answer, the query string is not part of the URL, so you'll probably want to write a view function that will grab the category from the query string and redirect appropriately. You can have a URL like:
(r'^category\.asp', category_redirect),
And a view function like:
def category_redirect(request):
if 'categoryid' not in request.GET:
raise Http404
cat_id = request.GET['category']
try:
cat = Category.objects.get(old_id=cat_id)
except Category.DoesNotExist:
raise Http404
else:
return HttpResponsePermanentRedirect('/%s/' % cat.slug)
(Altered to your own tastes and needs, of course.)
Everything after the ? is not part of the URL. It's part of the GET parameters.
N.B This question has been significantly edited before the first answer was given.
Hi,
I'm fairly new to django, so apologies if I'm missing something obvious.
I've got a urls.py file that looks like this:
urlpatterns = patterns(
'',
(r'^$', 'faros.lantern.views.home_page'),
(r'^login/$', 'django.contrib.auth.views.login'),
(r'^logout/$', 'django.contrib.auth.views.logout'),
(r'^about/$', 'faros.lantern.views.about_page_index', {}, 'about_page_index'),
(r'^about/(?P<page_id>([a-z0-9]+/)?)$', 'faros.lantern.views.about_page', {}, 'about_page'),
)
Views that looks like this:
def about_page_index(request):
try:
return render_to_response('lantern/about/index.html', context_instance=RequestContext(request))
except TemplateDoesNotExist:
raise Http404
def about_page(request, page_id):
page_id = page_id.strip('/ ')
try:
return render_to_response('lantern/about/' + page_id + '.html', context_instance=RequestContext(request))
except TemplateDoesNotExist:
raise Http404
And a template that includes this:
Contact
Contact
I'm getting this error message:
Caught an exception while rendering: Reverse for '<function about_page at 0x015EE730>' with arguments '()' and keyword arguments '{'page_id': u'contact'}' not found. The first reverse works fine (about_page_index), generating the correct URL without error messages.
I think this is because the request argument to the about_page view (request) is used, so I need to pass it in when I generate the URL in my template. Problem is, I don't know how to get to it, and searching around isn't getting me anywhere. Any ideas?
Thanks,
Dom
p.s. As an aside, does that method of handling static "about" type pages in an app look horrific or reasonable? I'm essentially taking URLs and assuming the path to the template is whatever comes after the about/ bit. This means I can make the static pages look like part of the app, so the user can jump into the about section and then right back to where they came from. Comments/Feedback on whether this is djangoic or stupid appreciated!
If I guess correctly from the signature of your view function (def about_page(request, page_id = None):), you likely have another URL configuration that points to the same view but that does not take a page_id parameter. If so, the django reverse function will see only one of these, and it's probably seeing the one without the named page_id regex pattern. This is a pretty common gotcha with reverse! :-)
To get around this, assign a name to each of the url patterns (see Syntax of the urlpatterns variable). In the case of your example, you'd do:
(r'^about/(?P<page_id>([a-z]+/)?)$', 'faros.lantern.views.about_page',
{}, 'about_with_page_id')
and then in the template:
Contact
Edit
Thanks for posting the updated urls.py. In the url template tag, using the unqualified pattern name should do the trick (note that I'm deleting the lantern.views part:
Contact
Contact
Edit2
I'm sorry I didn't twig to this earlier. Your pattern is expressed in a way that django can't reverse, and this is what causes the mismatch. Instead of:
r'^about/(?P<page_id>([a-z]+/)?)$'
use:
r'^about/(?P<page_id>[a-z0-9]+)/$'
I created a dummy project on my system that matched yours, reproduced the error, and inserted this correction to success. If this doesn't solve your problem, I'm going to eat my hat! :-)