I'm creating a custom profile page and I need the user to be able to save or update his profile. For some reason I'm getting the following error when I hit the update profile button:
User matching query does not exist.
Below is the code I have for the forms, models and views files:
forms.py
class ProfileForm(forms.Form):
profile_name = forms.CharField( max_length=50)
models.py
class UserProfile(models.Model):
user = models.ForeignKey(User)
profile_name = models.CharField(blank=True, max_length=50)
def __unicode__(self):
return u'%s %s' % (self.user, self.profile_name)
views.py
def edit_profile(request):
if 'edit_button' in request.POST:
form = ProfileForm(request.POST)
f_user = User.objects.get(username=request.user.id)
f_profile_name = form.cleaned_data['profile_name']
p = UserProfile(user=f_user, profile_name=f_profile_name)
p.save()
else:
form = ProfileForm()
return render_to_response('userprofile_template.html', locals(), context_instance=RequestContext(request))
Any idea what am I not doing right? Thank You!
f_user = User.objects.get(username=request.user.id)
Username is presumabely request.user.username
Or, just user User.objects.get(id=request.user.id)
Actually what is my caffienated ass saying? You have your user object right there!
request.user : )
Related
I'm currently creating a Registration-Page with two parts
One part is about the Username and a Passwort.
The second part is about choosing the own PC-Configuration
After defining everything, the User can register to get to the Main-Page.
Therefore I got a Model called "PC_Configuration" with a bunch of Foreign-Keys to the different Database-Models of the Processors/Graphicscards etc.:
class PC_Configuration(models.Model):
user = models.ForeignKey(User, related_name='user_id', on_delete=models.DO_NOTHING)
processor = models.ForeignKey(Processors, related_name='processor_id', on_delete=models.DO_NOTHING)
graphicscard = models.ForeignKey(Graphicscard, related_name='graphicscard_id', on_delete=models.DO_NOTHING)
os = models.ForeignKey(OS, related_name='os_id', on_delete=models.DO_NOTHING)
ram = models.ForeignKey(RAM, related_name='ram_id', on_delete=models.DO_NOTHING)
harddrive = models.ForeignKey(Harddrive, related_name='harddrive_id', on_delete=models.DO_NOTHING)
Also, there is one ForeignKey to the User to connect the Configuration to the respective User-ID.
Inside views.py, I've been creating a DropdownForm for all the Dropdown-Fields which the User shall choose on his own:
class DropdownForm(forms.ModelForm):
class Meta:
model = models.PC_Configuration
exclude = []
def __init__(self, *args, **kwargs):
super(DropdownForm, self).__init__(*args, **kwargs)
self.fields['processors'].queryset = DropdownForm.objects.all()
self.fields['processors'].label_from_instance = lambda obj: "%s" % obj.name
self.fields['graphicscard'].queryset = DropdownForm.objects.all()
self.fields['graphicscard'].label_from_instance = lambda obj: "%s" % obj.name
self.fields['os'].queryset = DropdownForm.objects.all()
self.fields['os'].label_from_instance = lambda obj: "%s" % obj.name
self.fields['ram'].queryset = DropdownForm.objects.all()
self.fields['ram'].label_from_instance = lambda obj: "%s" % obj.name
self.fields['harddrive'].queryset = DropdownForm.objects.all()
self.fields['harddrive'].label_from_instance = lambda obj: "%s" % obj.name
But regarding the fact, that the User-ID shall be assigned to the Configuration automatically, there's no field for that in here.
It is defined in the register_view(request) - Method:
def register_view(request):
form = DropdownForm()
if request.method == "POST":
form = DropdownForm(request.POST)
username = request.POST.get('username')
password = request.POST.get('password')
myuser = User.objects.create_user(username, None, password)
myuser.save()
auth.login(request, myuser)
#form.user = request.user
print(form.errors)
if form.is_valid():
instance = form.save(commit=False)
instance.user = request.user
instance.save()
messages.success(request, "Account has been created successfully")
return redirect(reverse('gamesearch_view'))
else:
print('Failed')
form = DropdownForm()
render(request, 'register.html', dict(form=form))
return render(request, 'register.html', dict(form=form))
And in here, we got the problem, I guess.
While Testing the Registration, the Testaccounts keep creating and login successfully. But the problem is, that there's no PC-Configuration created because the form is not validating.
With
print(form.errors)
I've been trying to figure out why exactly and it said
<ul class="errorlist"><li>user<ul class="errorlist"><li>This field is required.</li></ul></li></ul>
So it seems like it's necessary to define the "user"-field before checking, if the form is validating and defining the user inside an instance afterwards.
That's why I was trying to do this:
form.user = request.user
But it's still not working and I can't figure out, what's exactly the problem since "user" shouldn't be part of the form-validation.
Can you help me out here?
Thank you in Advance!
You'll have a simpler time with something like this...
Your related_names were somewhat bogus; they're supposed to be the reverse name from the "viewpoint" of the other model. (Also, you never need to add _id to your fields by hand in Django.) If you elide the related_names, they'll implicitly be pc_configuration_set.
on_delete=DO_NOTHING is likely not a good idea. PROTECT is a good default.
It's easier to just handle the username and password as fields in the form.
You were missing exclude = ["user"], so if your template didn't render a field for user, of course it'd be missing. However, you also don't want the POSTer of the form to submit any old user id.
Using a FormView removes most of the boilerplate required to manage forms.
We're using transaction.atomic() to make sure the user doesn't get finally saved to the database if saving the PC Configuration fails.
We assign the created user to form.instance, which is the new but as-of-yet unsaved PC Configuration.
(Of course, imagine these are in separate files.)
from django import forms
from django.db import models, transaction
from django.views.generic import FormView
class PC_Configuration(models.Model):
user = models.ForeignKey(User, on_delete=models.PROTECT)
processor = models.ForeignKey(Processors, on_delete=models.PROTECT)
graphicscard = models.ForeignKey(Graphicscard, on_delete=models.PROTECT)
os = models.ForeignKey(OS, on_delete=models.PROTECT)
ram = models.ForeignKey(RAM, on_delete=models.PROTECT)
harddrive = models.ForeignKey(Harddrive, on_delete=models.PROTECT)
class RegisterAndConfigurePCForm(forms.ModelForm):
username = forms.CharField(required=True)
password = forms.CharField(required=True, widget=forms.PasswordInput())
class Meta:
model = PC_Configuration
exclude = ["user"] # we'll assign this by hand
class RegisterAndConfigureView(FormView):
form_class = RegisterAndConfigurePCForm
template_name = "register.html"
def form_valid(self, form):
with transaction.atomic():
user = User.objects.create_user(form.cleaned_data["username"], None, form.cleaned_data["password"])
form.instance.user = user # assign user to the to-be-created PC configuration
form.save()
return redirect(reverse("gamesearch_view"))
I'm used to collecting the current logged in user in a CreateView and passing it to the form like so:
class MakeFantasyTeam(CreateView):
form_class = MakeFantasyTeamForm
[...]
def form_valid(self, form):
form.instance.team_manager = self.request.user
form.save()
return super(MakeFantasyTeam, self).form_valid(form)
However, this doesn't seem to work when using an InlineFormSetView as provided by django-extra-views. I get an error NOT NULL constraint failed: tournament_invite.invited_by_id and I'm not sure how to get the user.id passed on to the form.
My View:
class InvitePlayersView(InlineFormSetView):
template_name = 'invite_players.html'
model = Tournament
inline_model = Invite
form_class = InvitePlayerForm
pk_url_kwarg = 'tourney_id'
factory_kwargs = {'can_delete': False, 'extra': 1}
def formset_valid(self, formset):
tourney_id = self.kwargs['tourney_id']
formset.instance.invited_for = Tournament.objects.filter(id=tourney_id).get()
formset.instance.invited_by = self.request.user
formset.save()
return super(InvitePlayersView, self).formset_valid(formset)
def get_success_url(self):
return reverse('make_team', kwargs={'tourney_id': self.object.invited_for.id})
My Model:
class Invite(models.Model):
name = models.CharField(max_length=200, blank=True, null=True)
email = models.CharField(max_length=320, null=False, blank=False, validators=[EmailValidator],)
invited_by = models.ForeignKey(get_user_model(), on_delete=models.DO_NOTHING)
invited_for = models.ForeignKey(Tournament, on_delete=models.DO_NOTHING)
created_dt = models.DateTimeField(auto_now_add=True)
def __str__(self):
return self.email
def get_absolute_url(self):
return reverse('home')
My Form:
class InvitePlayerForm(forms.ModelForm):
class Meta:
model = Invite
fields = ('name', 'email',)
Any tips or hints much appreciated!
Thank you,
Jon
Edit: Just to clarify what I'm trying to do here; I want a user to submit a formset. The data of that formset should be stored in the model, and the userid of the submitting user should also be stored in the model. I don't seem to be able to pass on the userid though.
I am not sure what you exactly want to do here, As per my understanding you want to use the currently logged in user's information. To do so you can append the user's info in the session dictionary. After that you can use the information in templates or in other views too.
In authentication view
def login(request):
#your necessary data
request.session['user_id']=The_user_id
request.session['user_name']=The_userName
To access data in the template
{% request.session.user_id %}
{% request.session.user_name %}
To access data in other views
def myview(request):
user_id= request.session['user_id']
user_name= request.session['user_name']
I'm trying to display a form (ModelForm) with a select field filtered by currently logged in user. The select field in this case contains a list of categories. I want to display only the categories which "belong" to the currently logged in user. The category field is a foreign key to the IngredienceCategory model.
Here is what I've come up with so far but it's giving me an error (unexpected keyword queryset). Any ideas what I'm doing wrong?
# models.py
class IngredienceCategory(models.Model):
name = models.CharField(max_length=30)
user = models.ForeignKey(User, null=True, blank=True)
class Meta:
verbose_name_plural = "Ingredience Categories"
def __unicode__(self):
return self.name
class Ingredience(models.Model):
name = models.CharField(max_length=30)
user = models.ForeignKey(User, null=True, blank=True)
category = models.ForeignKey(IngredienceCategory, null=True, blank=True)
class Meta:
verbose_name_plural = "Ingredients"
def __unicode__(self):
return self.name
class IngredienceForm(ModelForm):
class Meta:
model = Ingredience
fields = ('name', 'category')
# views.py
def home(request):
if request.user.is_authenticated():
username = request.user.username
email = request.user.email
foods = Food.objects.filter(user=request.user).order_by('name')
ingredients = Ingredience.objects.filter(user=request.user).order_by('name')
ingrcat = IngredienceCategory.objects.filter(user=request.user)
if request.method == 'POST':
form = IngredienceForm(request.POST)
if form.is_valid():
# Create an instance of Ingredience without saving to the database
ingredience = form.save(commit=False)
ingredience.user = request.user
ingredience.save()
else:
# How to display form with 'category' select list filtered by current user?
form = IngredienceForm(queryset=IngredienceCategory.objects.filter(user=request.user))
context = {}
for i in ingredients:
context[i.category.name.lower()] = context.get(i.category.name.lower(), []) + [i]
context2 = {'username': username, 'email': email, 'foods': foods, 'ingrcat': ingrcat, 'form': form,}
context = dict(context.items() + context2.items())
else:
context = {}
return render_to_response('home.html', context, context_instance=RequestContext(request))
That's happening because ModelForm does not take a queryset keyword.
You can probably achieve this by setting the queryset on the view:
form = IngredienceForm()
form.fields["category"].queryset =
IngredienceCategory.objects.filter(user=request.user)
See related question here.
Here i have another suggestion to solve the problem. You can pass request object in your form object inside view.
In view.py just pass the request object.
form = IngredienceForm(request)
In your forms.py __init__ function also add request object
from models import IngredienceCategory as IC
class IngredienceForm(ModelForm):
class Meta:
model = Ingredience
fields = ('name', 'category')
def __init__(self, request, *args, **kwargs):
super(IngredienceForm, self).__init__(*args, **kwargs)
self.fields['name'].queryset = IC.objects.filter(user=request.user)
This filter always will be applied whenever you initialize your form .
I'm trying to display a form (ModelForm) with a select field filtered by currently logged in user. The select field in this case contains a list of categories. I want to display only the categories which "belong" to the currently logged in user. The category field is a foreign key to the IngredienceCategory model.
Here is what I've come up with so far but it's giving me an error (unexpected keyword queryset). Any ideas what I'm doing wrong?
# models.py
class IngredienceCategory(models.Model):
name = models.CharField(max_length=30)
user = models.ForeignKey(User, null=True, blank=True)
class Meta:
verbose_name_plural = "Ingredience Categories"
def __unicode__(self):
return self.name
class Ingredience(models.Model):
name = models.CharField(max_length=30)
user = models.ForeignKey(User, null=True, blank=True)
category = models.ForeignKey(IngredienceCategory, null=True, blank=True)
class Meta:
verbose_name_plural = "Ingredients"
def __unicode__(self):
return self.name
class IngredienceForm(ModelForm):
class Meta:
model = Ingredience
fields = ('name', 'category')
# views.py
def home(request):
if request.user.is_authenticated():
username = request.user.username
email = request.user.email
foods = Food.objects.filter(user=request.user).order_by('name')
ingredients = Ingredience.objects.filter(user=request.user).order_by('name')
ingrcat = IngredienceCategory.objects.filter(user=request.user)
if request.method == 'POST':
form = IngredienceForm(request.POST)
if form.is_valid():
# Create an instance of Ingredience without saving to the database
ingredience = form.save(commit=False)
ingredience.user = request.user
ingredience.save()
else:
# How to display form with 'category' select list filtered by current user?
form = IngredienceForm(queryset=IngredienceCategory.objects.filter(user=request.user))
context = {}
for i in ingredients:
context[i.category.name.lower()] = context.get(i.category.name.lower(), []) + [i]
context2 = {'username': username, 'email': email, 'foods': foods, 'ingrcat': ingrcat, 'form': form,}
context = dict(context.items() + context2.items())
else:
context = {}
return render_to_response('home.html', context, context_instance=RequestContext(request))
That's happening because ModelForm does not take a queryset keyword.
You can probably achieve this by setting the queryset on the view:
form = IngredienceForm()
form.fields["category"].queryset =
IngredienceCategory.objects.filter(user=request.user)
See related question here.
Here i have another suggestion to solve the problem. You can pass request object in your form object inside view.
In view.py just pass the request object.
form = IngredienceForm(request)
In your forms.py __init__ function also add request object
from models import IngredienceCategory as IC
class IngredienceForm(ModelForm):
class Meta:
model = Ingredience
fields = ('name', 'category')
def __init__(self, request, *args, **kwargs):
super(IngredienceForm, self).__init__(*args, **kwargs)
self.fields['name'].queryset = IC.objects.filter(user=request.user)
This filter always will be applied whenever you initialize your form .
I have question regarding how to attach additional form to logged in users in Django.
I want that additional form belongs to logged in user and the data I enter in the form should goes under logged in user table. I am new to Django and python please have patience I hope i can explain correctly what i want to do with this
Data I shall enter for this view shall go under logged in user only basically i want to attach this view to the logged in user only Error I am getting is
Exception Value:
registration_todos.user_id may not be NULL
#models
class userProfile(models.Model):
user = models.OneToOneField(User)
birth =models.DateField()
name = models.CharField(max_length=100)
def __unicode__(self):
return self.name
class todos(models.Model):
user = models.ForeignKey(User)
title = models.CharField(max_length=100)
created = models.DateField()
time = models.TimeField()
def __unicode__(self):
return unicode(self.user)
#forms additional form for todos
class formtodos(ModelForm):
title = forms.CharField(label=(u'Todo'))
created = forms.DateField(label=(u'Date'))
time = forms.TimeField(label=(u'Time'))
#user = forms.CharField(label=(u'username'))
class Meta:
model = todos
exclude=('user',)
#view
def modeltodo(request):
if request.user.is_authenticated():
todos.objects.filter(user=request.user)
if request.method == 'POST':
form =formtodos(request.POST)
if form.is_valid():# All validation rules pass
todoss = form.save(commit=False)
todoss.created_by = request.user
form.save()
return HttpResponseRedirect('/profile/')
else:
form = formtodos() # An unbound form
context = {'form':form}
return render_to_response('todo.html', context, context_instance=RequestContext(request))
you've specified exclude = ('user',) in your form. This means that when you try to save the form there is no user_id present which causes the error. You probably want to put this before the save() call: todoss.user = request.user