I am looking for a C/C++ implementation of a multi threaded job dispatcher.
Boss thread (the main function) reads the job (eg executing msgrcv in a while(1) loop).
The boss reads the new job and depending on the destination dispatches the job to the
corresponding thread. The worker thread executes the job.
I don't have the time to build it from scratch, I am looking a ready solution.
UPDATE: I cannot use boost. It must be in pthreads (Linux)
Your simplest option is to have the worker threads waiting on a condition variable which gets signalled when a job comes in for them to read.
You would need a mutex that gets locked whilst you check the condition. When you wait on the condition variable it automatically unlocks the associated mutex until the condition gets signalled at which point your thread will have it. You should check your condition again.
You could have one condition variable for each queue or one for all the threads, it depends on how you are scaled.
Sound like you're after a thread pool. One can be found here (it requires boost). I'm sure Googling for "thread pool" or something similar will yield other posibilities.
Related
I need a threadpool for my application, and I'd like to rely on standard (C++11 or boost) stuff as much as possible. I realize there is an unofficial(!) boost thread pool class, which basically solves what I need, however I'd rather avoid it because it is not in the boost library itself -- why is it still not in the core library after so many years?
In some posts on this page and elsewhere, people suggested using boost::asio to achieve a threadpool like behavior. At first sight, that looked like what I wanted to do, however I found out that all implementations I have seen have no means to join on the currently active tasks, which makes it useless for my application. To perform a join, they send stop signal to all the threads and subsequently join them. However, that completely nullifies the advantage of threadpools in my use case, because that makes new tasks require the creation of a new thread.
What I want to do is:
ThreadPool pool(4);
for (...)
{
for (int i=0;i<something;i++)
pool.pushTask(...);
pool.join();
// do something with the results
}
Can anyone suggest a solution (except for using the existing unofficial thread pool on sourceforge)? Is there anything in C++11 or core boost that can help me here?
At first sight, that looked like what I wanted to do, however I found out that all implementations I have seen have no means to join on the currently active tasks, which makes it useless for my application. To perform a join, they send stop signal to all the threads and subsequently join them. However, that completely nullifies the advantage of threadpools in my use case, because that makes new tasks require the creation of a new thread.
I think you might have misunderstood the asio example:
IIRC (and it's been a while) each thread running in the thread pool has called io_service::run which means that effectively each thread has an event loop and a scheduler. To then get asio to complete tasks you post tasks to the io_service using the io_service::post method and asio's scheduling mechanism takes care of the rest. As long as you don't call io_service::stop, the thread pool will continue running using as many threads as you started running (assuming that each thread has work to do or has been assigned a io_service::work object).
So you don't need to create new threads for new tasks, that would go against the concept of a threadpool.
Have each task class derive from a Task that has an 'OnCompletion(task)' method/event. The threadpool threads can then call that after calling the main run() method of the task.
Waiting for a single task to complete is then easy. The OnCompletion() can perform whatever is required to signal the originating thread, signaling a condvar, queueing the task to a producer-consumer queue, calling SendMessage/PostMessage API's, Invoke/BeginInvoke, whatever.
If an oringinating thread needs to wait for several tasks to all complete, you could extend the above and issue a single 'Wait task' to the pool. The wait task has its own OnCompletion to communicate the completion of other tasks and has a thread-safe 'task counter', (atomic ops or lock), set to the number of 'main' tasks to be issued. The wait task is issued to the pool first and the thread that runs it waits on a private 'allDone' condvar in the wait task. The 'main' tasks are then issued to the pool with their OnCompletion set to call a method of the wait task that decrements the task counter towards zero. When the task counter reaches zero, the thread that achieves this signals the allDone condvar. The wait task OnCompletion then runs and so signals the completion of all the main tasks.
Such a mechansism does not require the continual create/terminate/join/delete of threadpool threads, places no restriction on how the originating task needs to be signaled and you can issue as many such task-groups as you wish. You should note, however, that each wait task blocks one threadpool thread, so make sure you create a few extra threads in the pool, (not usually any problem).
This seems like a job for boost::futures. The example in the docs seems to demonstrate exactly what you're looking to do.
Joining a thread mean stop for it until it stop, and if it stop and you want to assign a new task to it, you must create a new thread. So in your case you should wait for a condition (for example boost::condition_variable) to indicate end of tasks. So using this technique it is very easy to implement it using boost::asio and boost::condition_variable. Each thread call boost::asio::io_service::run and tasks will be scheduled and executed on different threads and at the end, each task will set a boost::condition_variable or event decrement a std::atomic to indicate end of the job! that's really easy, isn't it?
What happens when a thread is put to sleep by other thread, possible by main thread, in the middle of its execution?
assuming I've a function Producer. What if Consumer sleep()s the Producer in the middle of production of one unit ?
Suppose the unit is half produced. and then its put on sleep(). The integrity of system may be in a problem
The thread that sleep is invoked on is put in the idle queue by the thread scheduler and is context switched out of the CPU it is running on, so other threads can take it's place.
All context (registers, stack pointer, base pointer, etc) are saved on the thread stack, so when it's run next time, it can continue from where it left off.
The OS is constantly doing context switches between threads in order to make your system seem like it's doing multiple things. The OS thread scheduler algorithm takes care of that.
Thread scheduling and threading is a big subject, if you want to really understand it, I suggest you start reading up on it. :)
EDIT: Using sleep for thread synchronization purposes not advised, you should use proper synchronization mechanisms to tell the thread to wait for other threads, etc.
There is no problem associated with this, unless some state is mutated while the thread sleeps, so it wakes up with a different set of values than before going to sleep.
Threads are switched in and out of execution by the CPU all the time, but that does not affect the overall outcome of their execution, assuming no data races or other bugs are present.
It would be unadvisable for one thread to forcibly and synchronously interfere with the execution of another thread. One thread could send an asynchronous message to another requesting that it reschedule itself in some way, but that would be handled by the other thread when it was in a suitable state to do so.
Assuming they communicate using channels that are thread-safe, nothing bad shoudl happen, as the sleeping thread will wake up eventually and grab data from its task queue or see that some semaphore has been set and read the prodced data.
If the threads communicate using nonvolatile variables or direct function calls that change state, that's when Bad Things occur.
I don't know of a way for a thread to forcibly cause another thread to sleep. If two threads are accessing a shared resource (like an input/output queue, which seems likely for you Produce/Consumer example), then both threads may contend for the same lock. The losing thread must wait for the other thread to release the lock if the contention is not the "trylock" variety. The thread that waits is placed into a waiting queue associated with the lock, and is removed from the schedulers run queue. When the winning thread releases the lock, the code checks the queue to see if there are threads still waiting to acquire it. If there are, one is chosen as the winner and is given the lock, and placed in the scheduler run queue.
Situation
I've got a worker thread that's being triggered by a condition_variable to do some work. Basically it is working very good and as supposed.
Problem
However there's one problem: The thread launching the worker thread may get a long enough time slice to feed the data queue and notify the condition_variable when the worker thread is not ready yet, i.e. when it didn't reach the condition_variable.wait() line yet.
Is there any way I can wait for a worker thread until the first call to wait() is made so it's guaranteed that work will be processed when I notify the worker?
There's no reason to do that. When the worker thread is ready, it will do the work. It won't need to be triggered by a condition variable because it won't ever wait.
Waiting for something that has already happened is a coding error. If you might ever even think of doing that, you fundamentally don't understand condition variables.
Before a thread waits on a condition variable, it must make sure that there is something it needs to wait for. That thing must be protected by the mutex associated with the condition variable. And when the thread returns from the condition variable wait, it usually must re-test to see if it needs to wait again.
I have a program that should get the maximum out of my cpu.
It is multithreaded via pthreads that do their job well apart from the fact that they "only" get my cores to about 60% load which is not enough in my opinion.
I am searching for the reason and am asking myself (and hereby you) if the blocking functions mutex_lock/cond_wait are candidates?
What happens when a thread cannot run on in such a function?
Does pthread switch to another thread it handles or
does the thread yield its time to the system and if the latter is the case, can I change this behavior?
Regards,
Nobody
More Information
The setting is one mainthread that fills the taskpool and countless workers that fetch jobs from there and wait on a conditional that is signaled via broadcast when a serialized calculation is done. They go on with the values from this calculation until they are done, deliver their mail and fetch the next job...
On a typical modern pthreads implementation, each thread is managed by the kernel not unlike a separate process. Any blocking call like pthread_mutex_lock or pthread_cond_wait (but also, say, read) will yield its time to the system. The system will then find another eligible thread to schedule, whether in your process or another process, and run it.
If your program is only taking 60% of the CPU, it is more likely blocked on I/O than on pthread operations, unless you have done something way too granular with your pthread operations.
If a thread is waiting on a mutex/condition, it doesn't use resources (well, uses just a tiny amount). Whenever the thread enters waiting state, control switches to other threads. When the mutex is released (or condition variable signalled), the thread wakes up and may acquire the mutex (if no other thread grabs it first), and continue to run. If however some other thread acquires the mutex (this can happen if several threads are waiting for it), the thread returns to sleeping state.
I have a system where my singleton class spawns a thread to do a calculation. If the user requests another calculation while another calculation is still running, I want it to tear down the existing thread and start a new one. But, it should wait for the first thread to exit completely before proceeding. I have all the tear down working but I seem to have an issue with making sure that only one thread runs. My approach is for the StartCalculation function to call mutex->Lock(). And the thread in the destructor releases the lock. It's not working. Am I right in assuming that if Lock() can't get the lock, it spins and keeps trying to reacquire the lock? Can this Lock() be called from my main application thread? Any ideas is helpful. Maybe wxMutex locks are the right mechanism for this.
To wait for a thread you need to create it joinable and simply use wxThread::Wait(). However I agree with the remark above: this is not something you'd normally do at all and definitely not from the main GUI thread as you should never block in it because this freezes the UI.
Consider using a message queue to simply tell the existing thread about the new task it needs to perform instead.