GLSL shaders and WebGL problem - glsl

Question

I have created a shader that works perfectly in Firefox, but in Chrome the fragment and vertex shader cannot be linked. They compile just fine, but at the linking part something goes wrong. I have localized the problem at the fallowing bit of code :
else if (uLightType[i] == 1) { //point light
NdotL = dot(n, normalize(lightDir[i]));
if (NdotL > 0.0) {
distance = length(lightDir[i]);
att = (1.0 / (uLightAttenuation[i] * distance * distance));
color += vec3(uLightColor[i] * NdotL * uLightIntensity[i] * att);
}
}
This small piece of code calculates the diffuse color reflected from a point light. It's part of a larger for loop. As it is shown here it won't link at all, but if I remove uLightAttenuation from calculating att, like so :
att = (1.0 / (distance * distance));
it works just fine. If I replace it with any other uniform, say uLightIntensity,
att = (1.0 / (uLightIntensity[i] * distance * distance));
again it won't work. If I replace it with a simple constant value / float variabile, strangely enough it compiles. And what is even more strange is, if I remove att from calculating color, but keep the uniform at it's current position, it runs just fine:
att = (1.0 / (uLightAttenuation[i] * distance * distance));
color += vec3(uLightColor[i] * NdotL * uLightIntensity[i]);
The uniform is a float value, and even if it were a problem with type casting it should fail at compilation, not linking.
Here are the complete shaders, maybe I missed something elsewhere in the code.
Fragment Shader
Vertex Shader

Answer 1

I have managed to make it to work, it turns out I had 2 problems. One is with division by 0 when calculating att. It would let me divide something over a float uniform, so I combined uLightAttenuation and uLightIntensity into a single vec2 uniform, after that that part worked. Secondly, when calculating color I had to reference every component individually (color[0], color[1] etc...) and work only with float variables and not vectors. After that it worked correctly in chrome to.