I would like to embed front end views in my django admin site at any possible specified locale, maybe in a class or site admin dashboard;anywhere I feel is the best option.. Tried out a few git projects but seems they are not compatible with current django versions..any one offering any idea?!
The Django Admin site is intentionally a separate site, with its own views.
In any app you can make functions that compute various values; but the Admin for that app will need to define its own views, using whatever functions you like.
Im really confused about what is all i need to consider for creating a django aplication with almost similar functionality to it's own admin.
The index page should deploy the list of models the user has access to modify or create...almost the same as when you put admin.site.register(MyModel) but with permission restriction. Im not sure how should i ckeck permissions, and show 1 ,2 or many "ModelAdmis" on my main page.
btw admin users are redirected to the admin index page, non-admins go to my page
Before you consider creating a django admin from scratch, you should read the answers to this question Django Admin app or roll my own?
I couldn't find any resource on how to create a django admin from scratch, but here's what you should do if this is your first time overriding a framework's functionality (in my humble opinion):
Understand and make sure you are comfortable with the django admin app
start from the docs https://docs.djangoproject.com/en/1.7/#the-admin
Head over to the django admin app source code so you can start reading the internals of the functionality you want to implement/override in your new admin app.
source code can be found here https://github.com/django/django/tree/master/django/contrib/admin
(this may involve reading other apps source code too)
After those two steps you should have an idea on how the admin app is implemented and it's dependencies, then you can start creating your custom admin app.
an example on how this may go can be found in this qestion:
How to override Django admin's views?
If you are building something new, try to separate the UI from the backend. You can build your UI using react, angular or whatever and interact with django using the API. To build the API you can use the Django Rest Framework.
Don't use the Django Admin as a public interface. Use that only for the admins!
If you start to use the Django Admin as interface for your public site, you'll fight with the package to tailor and secure the views to avoid destructive actions. What happen if you forget a readonly field? What if the user deleted something ON_CASCADE?
Building the UI you are totally free and you can customise easily everything without fighting the django admin package (it's awesome package but is not provided for public use)
I'm trying to create an account settings page for logged-in users. One of the things users should be able to do is to change their password.
I'm using django-registration and it provides a password change form at site/accounts/password/change by default, and it works. However, I want this function to be available at an Account Settings page instead, along with other administrative functions.
I first tried copying the template code, but it did not work because it includes a special form to create the inputs for the passwords (to handle validation). I don't know how to include this form in my own template.
How can I recreate these forms in my own Account Settings template?
This is the default password change template. I want to reuse form.oldpassword and the others in a separate template.
Django-registration doesn't implement its own password change view, it reuses the one included in Django (django.contrib.auth.views.password_change). It is hooked in through registration.auth_urls which is included in the default and simple registration backends.
By default the view uses django.contrib.auth.forms.PasswordChangeForm (which can be overridden through the password_change_form parameter).
When you only reuse the form (which you can do of course, just import the above form in your custom view), you should be aware that you would still be missing the whole view logic. So unless you have a more complex view in mind, you should consider to reuse it and just override the registration/password_change_form.html and registration/password_change_done.html templates.
a newbie django question
I want to use 3rd party app, but I need to make some mods to it (in this case, the app is django-registration, and I need to change things such as allowing registration without confirmation email)
Initially, I simply installed the app in the general site-packages folder, and changed the code there. Now that I put my code on bitbucket I need a way to be able to keep my mods in the repository in a usable way, and uploading the full python code doesn't sound like a good idea.
I guess the best way would be to keep the 3rd party app in site-packages, and create an app in my project to keep my changes. In my case, I'd create my-django-registration in my project, and then import this when I need it in my code, rather than django-registration.
I also read about virtualenv, but I think that's mostly used for being able to use multiple environments in the same machine (in fact, somewhere it advises against changing the modules installed in the virtualenv), and doesn't help me with keeping my changes in a repository.
Any comments welcome!
Thanks
In general, you should reuse and override the behavior in 3rd party apps and not modify their sources.
What you'll most often encounter is that apps ship models that may not necessarily cover your needs, but do most of the work; you'll have forms that are almost perfect, but need that little something; you'll have views that would be perfect if you can just change one thing; you'll have URLs that are sane, but you need something more from them.
In most cases, that would just require that you create a custom app and rewire everything. Ship your own URLs that map to views that you've extended and overrode methods for custom behavior; supply it with a model form who's Meta is using the new model that you've extended from the original; so forth...
That's just the tip of the iceberg of what you can do, there's more ways when your creative. I can give you an example of how I've used the RegistrationProfile model, but shipped my own URL patterns and a custom class-based view that handled the registration process.
Now, where virtualenv comes into play is that you'll most likely be using pip to specify and supply your required dependencies in the requirements file format. That's when you want to say: "I've extended the django-registration app, but it won't work cleanly with just any version. It has to be of release X", or , "a checkout from the repository of commit Y".
This blog post that adresses this issue is extremely helpful. For convenience I copy-paste it here:
You don’t touch external app code
You are not supposed to edit the code from an external app. Unless you fork it first on github.
So, how to override without forking:
Overriding a template
If you want to override templates/userena/activate_fail.html, then all you have to do is create your own templates/userena directory and make your own activate_fail.html in it.
Overriding a url
Probably the first thing you should check in an external app is its urls.py. Views that are properly coded should support plenty of arguments. For example, userena has a signup view with such a signature (at the time of writing):
def signup(request, signup_form=SignupForm,
template_name='userena/signup_form.html', success_url=None,
extra_context=None):
This means that you can replace the form used by the signup view. To do so, open your urls.py, add what we are going to need at the top:
from userena import views as userena_views
from yourforms import YourSignupForm
Then, find the include the external app’s urls, something like:
url(r'^userena/', include('userena.urls')),
Before that, add your url override:
url(r'^userena/signup/$', userena_views.signup, {'signup_form': YourSignupForm}, name='userena_signup'),
url(r'^userena/', include('userena.urls')),
Now, your custom url definition will be the first to be hit when a visitor hits /userena/signup/. Which means that /userena/signup/ will use YourSignupForm instead of userena’s signup form.
This trick works with any view argument. The ones you should see the most often are:
template_name: lets you change the template name
extra_context: lets you add a dict that will be added to the
context
Almost every view should have these arguments.
Overriding a view
Overriding a view requires to override the url of the view you want to replace. If you want your own signup view to be used, then just override the url:
import yourviews
# ...
url(r'^userena/signup/$', yourviews.yoursignup, name='userena_signup'),
url(r'^userena/', include('userena.urls')),
Decorating a view
Decorating a view is like overriding a view, but reuses the external app’s view. Basically, it’s the same than overriding a view (see above), but your view will look like this
from userena import views as userena_views
def yoursignup(request):
# do stuff before userena signup view is called
# call the original view
response = userena_views.signup(request)
# do stuff after userena signup view is done
# return the response
return response
Forking an app
If you are not familiar with pip and virtualenv first, please read the post about using pip and virtualenv first.
For example:
You installed django-userena as such: pip install django-userena
First you should uninstall it: pip uninstall django-userena
Then go on the app’s github page
Click on the fork button
This will make you a repository with a copy of django-userena
Install it as such: pip install -e
git+git#github.com:your-username/django-userena.git#egg=django-userena
Then you can edit the code in yourenv/src/django-userena
Push your commits
Credits to the post writer!
I think the neatest way to accomplish what you look for would be to fork django-registration, and in your app use the fork instead of the original project.
That being said, you can have a non-email registration in django-registration without changing the code of the app. I've done it by creating a custom registration backend that sets the users as activated upon creation. Here you can see other ways to do the same.
I'm new to Django and in bouncing around the framework over the past few days I haven't been able to figure out how to properly install the django.contrib.auth app in my project.
Well, installing is probably not the right word, but configuring it for my purposes.
What I'm truly hoping to do is extend the built-in classes to simply create registration and login forms, since my User class is working just fine from terminal.
In settings.py I have django.contrib.auth in my INSTALLED_APPS.
I also have installed the Authentication Middleware and Sessions Middleware.
I can also clearly see in Django.contrib.auth.views and Django.contrib.auth.forms where the registration and authentication handlers are.
My problem, it seems, since I'm new to the framework, is properly including these files in my project and generating the HTML forms for registration and login.
(As in, do I need to include these Auth files in my app's forms.py? What do I need to model that hasn't already been modeled for me? And finally, since I can see in Django.contrib.auth.views a need for a registration directory with HTML templates, how can I get these all communicating with each other properly?)
Figured out the problem. Just needed to follow Django's URL Conf conventions. Example: (r'^accounts/login/$', 'django.contrib.auth.views.login'),
James Bennet's django-registration is an excellent helper application used for a common registration / login pattern.