I'm using this command below to remove the first column of a document:
%s/^[^\t]*\zs\t[^\t]*\ze//g
but it says command not found. Any idea?
Here's the quickest way to remove the first column:
Press gg to go to the first character in the document.
Hit Ctrl+V to enter visual block mode.
Hit G (that is, shift-g) to go to the end of the document
Hit x to delete the first column.
I like the block selection solution of #Peter, but if you want to use substitution you need this command:
:%s/^.//
Let's analyze why this works:
:%s exec a substitution on all the document
/^./ select the first character after the start of the line
/ and replace it with... nothing.
If I understand you correctly, this should do the job:
:%s/^[^\t]//
The command removes all leading characters that are not a tabulator.
Alternatively, if you're editing a tabulator separated values document and want to remove all "columns" before the first tabulator, then this should do it for you:
%s/^[^\t]*\t//
The below command worked for me:
:%s/^\w*//
Related
This is what I have in doc:
1;01878916;BC101;FALSE
16;01978916;BC101;FALSE
17;0195B4E5;BC101;FALSE
19;0197D016;BC101;FALSE
After I run find&replace: ^((1|17);.+?)$ with: empty it leaves
blankrow
16;01978916;BC101;FALSE
blankrow
19;0197D016;BC101;FALSE
and then I have to run find and replace \s+$ in order to remove empty line(s) and manually remove first empty line.
Im weak with regex, tried to combine those 2 commands into one.
How it should be, to remove entirely empty rows, without leaving empty row?
To get
16;01978916;BC101;FALSE
19;0197D016;BC101;FALSE
Thanks in advance. I need to have regex commands in order to run FIND and Replace in all open files, because I'm doing this in 10 files at once. Line operations > Remove blank lines is not an option.
The regex:
^(1|17);.+?\s+
mentioned above works well here as there is no whitespace at the beginning of the lines you want to keep. If that's ever not the case, you can also do:
\s+^(1|17);.+?$
I have a text file as:
0xC1,0x80,
0x63,0x00,
0x3F,0x80,
0x01,0xA0,
I want output as:
Line1: 0xC1,0x63,0x3F,0x01,
Line2: 0x80,0x00,0x80,0xA0,
How to do this using replace function in Notepad++?
You can use the below shortcuts to do the transpose in Notepad ++
Step 1: Ctrl + A: selects all.
Step 2: Ctrl + J: Transpose the Row you selected
Use the box select feature to select the second column text.
Use Alt+Shift+Arraw keys to select the second column.
Copy the selected text to a new file.
Use Find/Replace to remove all the newline characters.
Ctrl+F to open find/replace dialog box.
Select either Extended or Regular Expression Serach mode.
Type \r\n in Find What box.
Keep the Replace with box blank.
Click on Replace All in ALL Open Documents.
Now, the text is brought in single line.
Copy the text from second file and paste it to second line of first file.
Cheers...
There is no built-in function in Notepad++ for transposing a matrix and you can't do it using Replace (as M42 pointed out). Also, I'm not aware of any related plugin. So you will either need a different editor or do it with a script. The simplest solution I guess using a Spreadsheet, eg Excel or OpenOffice, both of them allow you to easily transpose a table.
But, there's still a good alternative without leaving Notepad++. Is to use the Python Script plugin.
Setup Python Script plugin
Install Python Script plugin, from Plugin Manager or from the official website.
When installed, go to Plugins > Python Script > New Script. Choose a filename for your new script (eg transpose.py) and copy the first code block that follows and copy the second one to another script, called for example transpose_uneven.py.
Open your data file and then run Plugins > Python Script > Scripts > transpose.py. This will open a new tab with your data transposed.
transpose.py
delimiter=","
newline="\n"
content=editor.getText()
matrix=[line.split(delimiter) for line in content.rstrip(newline).split(newline)]
transposed=list(map(list, zip(*matrix)))
notepad.new()
for line in transposed:
editor.addText(delimiter.join(line) + newline)
if len(transposed)!=len(matrix[0]):
console.clear()
console.show()
console.write("Warning: some rows are of uneven length. You might consider using the transpose_uneven script instead.")
transpose_uneven.py
import itertools
delimiter=","
newline="\n"
content=editor.getText()
matrix=[line.split(delimiter) for line in content.rstrip(newline).split(newline)]
transposed=list(map(list, itertools.izip_longest(*matrix, fillvalue="")))
notepad.new()
for line in transposed:
editor.addText(delimiter.join(line) + newline)
Examples
The transpose.py script will transpose the following example:
0xC1,0x80,
0x63,0x00,
0x3F,0x80,
0x01,0xA0,
To:
0xC1,0x63,0x3F,0x01
0x80,0x00,0x80,0xA0
,,,
If some of your rows are uneven:
0xC1,0x80,
0x63,0x00,
0x3F,0x80,
0x01,0xA0,
0x02
The uneven columns will be discarded accordingly:
0xC1,0x63,0x3F,0x01,0x02
If this is not desired, use transposed_uneven.py and it will return:
0xC1,0x63,0x3F,0x01,0x02
0x80,0x00,0x80,0xA0,
,,,,
If you really have such a fixed format and need such a fixed output i normally try it with an instant macro.
So my cursor is in the top left corner of the file ready to manipulate and i press the record button (or within the menu bar Macro - Start recording).
In you specific case now press:
End
Del
Pos1
↓
End hit the stop button (or within the menu bar Macro - Stop recording).
Now for a first test hit the playback button (or within the menu bar Macro - Playback) and test if it works. If yes click on Macro - Run a macro multiple times and select Run until the end of file.
I want to delete everything from start of the document upto some regex match, such as _tmm. I wrote the following custom command:
command! FilterTmm exe 'g/^_tmm\\>/,/^$/mo$' | norm /_tmm<CR> | :0,-1 d
This doesn't work as expected. But when I execute these commands directly using the command line, they work.
Do you have any alternative suggestions to accomplish this job using custom commands?
It seems that you want to remove from beginning to the line above the matched line.
/pattern could have offset option. like /pattern/{offset}, :h / for detail, for your needs, you could do (no matter where your cursor is):
ggd/_tmm/-1<cr>
EDIT
I read your question twice, it seems that you want to do it in a single command line.
Your script has problem, normal doesn't support |, that is, it must be the last command.
try this line, if it works for you:
exe 'norm gg'|/_tmm/-1|0,.d
i have a text file in a particular format..
!c_xyz|crby=112|crdate=12jun11|mdby=112|mddate=12jun11|Desc=xyz
asdasda........................................................
asddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddd
!c_abc|crby=112|crdate=12jun11|mdby=112|mddate=12jun11|Desc=xyz...
I need a regular expression to reformat this file using Find and Replace - Visual Studio. The Desc field value has overflowed onto next lines. i need to move them back to the actual line. Final string should be like
!c_xyz|crby=112|crdate=12jun11|mdby=112|mddate=12jun11|Desc=xyzsdasda.........asdddddd..
!c_abc|crby=112|crdate=12jun11|mdby=112|mddate=12jun11|Desc=xyz...
I need an RE for "desc=" followed by anything until the next ! symbol
find Desc=([^\|\r\n]+)[\r\n](([^!\r\n][^\r\n]+[\r\n])*), replace with Desc=\1\2 and repeat until every line starts with ! (you can test this using ^[^!] as a search expr which should find nothing).
alternatively find [\r\n]+, replace with the empty string. thereafter find !, replace with \r\n!. this suggestion has 2 drawbacks. it temporarily produces very long lines which your editor (notably vs) may or may not have difficulties with and processes descriptions containing ! incorrectly.
addendum:
your input seems to be fixed format up to the Desc section. if it is indeed, you can apply alternative #2, step 1, being followed by a search/replace run using (!.{53}\|Desc=)/[\r\n]\1.
As mentioned in the comments by #X3074861X, you can use Notepad++.
Input:
!c_xyz|crby=112|crdate=12jun11|mdby=112|mddate=12jun11|Desc=xyz
asdasda........................................................
asddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddd
!c_abc|crby=112|crdate=12jun11|mdby=112|mddate=12jun11|Desc=xyz...
For the find and replace, select the mode as Regular expression with the options as follows:
Find what: \r\n[^!]
Leave Replace with blank.
Output:
!c_xyz|crby=112|crdate=12jun11|mdby=112|mddate=12jun11|Desc=xyzsdasda........................................................sddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddd
!c_abc|crby=112|crdate=12jun11|mdby=112|mddate=12jun11|Desc=xyz...
Screenshot:
I have a file containing (hundreds) of blocks of numbers like below;
This one is fine (16x20, correct number of rows and columns)
11111111111111111110
16666616666666661110
16111616111111162610
16111646111663132610
16162616261623132610
16162313261623132610
16162313261623132610
16162313261623132610
16162313261623132610
16162313261623132610
16162313261623132610
16162313261626132610
16166313661116632610
16111111111116132610
16666666666666136610
11111111111111111110
This one needs to be padded with trailing zeroes so it is (16x20)
111111111111111111
166616666666663661
166611111111111661
166666366663661661
113161111111161611
1316166666616161
1616162262616161
11616166112616161
16616166116616161
16616162262616161
16616166266616161
16616111161116161
1661666666666616111
1661666166163366661
1641666166166613661
1111111111111111111
I would like to pad them with zeroes so they are all like the first example. I'm aware of the regular expressions feature in notepad++ but am struggling to get it to work. I appreciate any help given.
You could do it via a macro.
First append a large number of zeroes to the end of each line using a macro.
Caret on the first entry
click record macro
press end
type out 20 zeroes
press down arrow
click stop recording
play the macro until all lines look like this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...
Caret on first line
click record
press home key
press the right arrow key 20 times
hold shift and press end key
press delete key
press down arrow
click stop recording
play the macro until all lines are processed
You could save the entire process as a single macro so its just a single click in the future.
I can give you a macro solution
go to the beginning of your text
select Macro/Start Recording
press end, press 0 16 times then press Home and down arrow key
select Macro/End Recording
You now have a macro to add sixteen zeros to the end of all lines.
Playback this macro on all lines.
You now have appended zeroes to all lines.
Pressing Alt key and using mouse select the required block(columns) of text you want and paste it into another empty notepad tab
help on column mode editing is there inside notepad ? / help contents menu
Good luck
You can use the plugin ConyEdit to do this.
With ConyEdit running in the background, follow these steps:
use the command line cc.aal 00000000000000000000 to append after lines with twenty zero character.
use the command line cc.gc 1/\d{20}/ to get the first column of regex match.
Looking to do this manualy and not progomaticly ?
Open Findreplace
Copy from the last to rhe first WITHOUT NUMBERS on a line so...
in this example
111111111111111111 <---from here
to here ---> 166616666666663661
166611111111111661
paste that into the fine ( yes your effecticly copying the return wich some applications allow you to manualy input others wont )
then in the replace box, type '0' then your return
Hit that magic replace all :D
This will then add a 0 every time it hits a new line, then add a new... new line....
edit : quickly reviewing another method a second to recover for alternate options :P give me 10
edit 2:
Ah ok somthing like this will work :P just tested it.
use [0-9] in the find replace. so if im looking for 123123123123 ( wich is 12 long ) and i need to buff i up to 20,
Your FIND must be in ()
so..
the find would be
([0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9] )
and the replace is referd to as \1 no the regex, this was my mistake
\100000000
tested and confirmed !dont forget YOU NEED MATCH ALL on, WRAP off!
And so on for your other numbers, Not sure if you can loop this with macros nd stuff :P but hope it helps more than you have now
two good resources.
http://blog.creativeitp.com/posts-and-articles/editors/understanding-regex-with-notepad/comment-page-1/
http://regexpal.com/
base on OP's comment: you could try an editor called vim/gvim
open your file in vim, then type:
:%s/.*/\=printf("%-20s",getline("."))/|%s/ *$/\=substitute(submatch(0)," ","0","g")/
don't forget pressing <Enter> after the above typing.
then you will see the text has been changed into what you want.
of course vim macro can work as well, however, I feel command better... :)