Filtered annotations without removing results - django

Consider a model and a query using annotations, for example the following example from the Django documentation:
http://docs.djangoproject.com/en/dev/topics/db/aggregation/
Publisher.objects.filter(book__rating__gt=3.0).annotate(num_books=Count('book'))
The result of this query will only contain objects matching the filter (i.e. has a book_rating greater than 3.0), and these objects has been annotated. But what if I want the query to contain all objects, but only annotate objects which matches a filter (or for example annotate them with 0)? Or is this even possible?

No, you can't do that - because that's not how the underlying SQL works.
The only thing I can think of is to do two queries, one with the filter/annotation and one without, then iterate through them in Python, appending the annotation to the matching objects from the non-filtered list.

Related

Is it possible to query multiple AWS Cloudsearch fields for the same value without repeating?

Using AWS Cloudsearch, I need to query 2 separate fields for the same value using a structured (compound) query e.g.
(and (or name:'john smith') (or curr_addr:'123 someplace' other_addr:'123 someplace'))
This query works, but I'm wondering if it's necessary to repeat the value for each field that I want to search against. Is there some way to specify the value only once e.g. curr_addr+other_addr:'123 someplace'
That is the correct way to structure your compound query. From the AWS documentation, you'll see that they structure their example query the same way:
(and title:'star' (or actors:'Harrison Ford' actors:'William Shatner')(not actors:'Zachary Quinto'))
From Constructing Compound Queries
You may be able to get around this by listing the more repetitive fields in the query options (q.options), and then specify the field for the rest of the fields. The fields list is sort of a fallback for when you don't specify which field you are searching in a compound query. So if you list the address fields there, and then only specify the name field in your query, you may get close to the behavior you're looking for.
Query options
q.options={fields: ['curr_addr','other_addr']}
Query
(and (or name:'john smith') (or '123 someplace'))
But this approach would only work for one set of repetitive fields, so it's not a silver bullet by any means.
From Search API Reference (see q.options => fields)

How to order django query set filtered using '__icontains' such that the exactly matched result comes first

I am writing a simple app in django that searches for records in database.
Users inputs a name in the search field and that query is used to filter records using a particular field like -
Result = Users.objects.filter(name__icontains=query_from_searchbox)
E.g. -
Database consists of names- Shiv, Shivam, Shivendra, Kashiva, Varun... etc.
A search query 'shiv' returns records in following order-
Kahiva, Shivam, Shiv and Shivendra
Ordered by primary key.
My question is how can i achieve the order -
Shiv, Shivam, Shivendra and Kashiva.
I mean the most relevant first then lesser relevant result.
It's not possible to do that with standard Django as that type of thing is outside the scope & specific to a search app.
When you're interacting with the ORM consider what you're actually doing with the database - it's all just SQL queries.
If you wanted to rearrange the results you'd have to manipulate the queryset, check exact matches, then use regular expressions to check for partial matches.
Search isn't really the kind of thing that is best suited to the ORM however, so you may which to consider looking at specific search applications. They will usually maintain an index, which avoids database hits and may also offer a percentage match ordering like you're looking for.
A good place to start may be with Haystack

How to parameterize django aggregation?

I want to do something like
query.annotate(Count('foreign_model_relation', somefield_from_foreign_model=some_value))
That means, i want to count, how many objects from another queryset are pointing to this object. The difference between using something like filter(in=other_queryset) is, that i would like to combine this in one query, to avoid generating one query per object.
Simplified Models:
Group
Object
group (Group)
Vote
object (Object)
up (Boolean)
Now i want to query the up/down count of all Objects for one Group, with one or two queries, not with one/two queries per Object.
You can do this with two queries:
YourObject.objects.filter(vote__up=True, group=some_group).annotate(total_votes_up=Count('vote'))
YourObject.objects.filter(vote__up=False, group=some_group).annotate(total_votes_down=Count('vote'))
But I think that should exist some more elegante way to do this.

Django - How to annotate QuerySet using multiple field values?

I have a model called "Story" that has two integer fields called "views" and "votes". When I retrieve all the Story objects I would like to annotate the returned QuerySet with a "ranking" field that is simply "views"/"votes". Then I would like to sort the QuerySet by "ranking". Something along the lines of...
Story.objects.annotate( ranking=CalcRanking('views','votes') ).sort_by(ranking)
How can I do this in Django? Or should it be done after the QuerySet is retrieved in Python (like creating a list that contains the ranking for each object in the QuerySet)?
Thanks!
PS: In my actual program, the ranking calculation isn't as simple as above and depends on other filters to the initial QuerySet, so I can't store it as another field in the Story model.
In Django, the things you can pass to annotate (and aggregate) must be subclasses of django.db.models.aggregates.Aggregate. You can't just pass arbitrary Python objects to it, since the aggregation/annotation actually happens inside the database (that's the whole point of aggregate and annotate). Note that writing custom aggregations is not supported in Django (there is no documentation for it). All information available on it is this minimal source code: https://code.djangoproject.com/browser/django/trunk/django/db/models/aggregates.py
This means you either have to store the calculations in the database somehow, figure out how the aggregation API works or use raw sql (raw method on the Manager) to do what you do.

How to limit columns returned by Django query?

That seems simple enough, but all Django Queries seems to be 'SELECT *'
How do I build a query returning only a subset of fields ?
In Django 1.1 onwards, you can use defer('col1', 'col2') to exclude columns from the query, or only('col1', 'col2') to only get a specific set of columns. See the documentation.
values does something slightly different - it only gets the columns you specify, but it returns a list of dictionaries rather than a set of model instances.
Append a .values("column1", "column2", ...) to your query
The accepted answer advising defer and only which the docs discourage in most cases.
only use defer() when you cannot, at queryset load time, determine if you will need the extra fields or not. If you are frequently loading and using a particular subset of your data, the best choice you can make is to normalize your models and put the non-loaded data into a separate model (and database table). If the columns must stay in the one table for some reason, create a model with Meta.managed = False (see the managed attribute documentation) containing just the fields you normally need to load and use that where you might otherwise call defer(). This makes your code more explicit to the reader, is slightly faster and consumes a little less memory in the Python process.