XSLT: number format - xslt

Question

In XSL is function like CONTAIN, that if i have number with simbol like "123112'+:" then doesn't take it.
to be more precise:
<Number>111111</Number>
<Number>123123+</Number>
<Number>222222</Number>
<Number>222222+</Number>
answer:
111111
222222
I'm stuck with xslt 1.0 version

Answer 1

Another approach, exploiting number to boolean conversion.
<xsl:stylesheet
version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text"/>
<xsl:template match="/*">
<xsl:apply-templates select="Number[boolean(number()) or . = 0]"/>
</xsl:template>
<xsl:template match="Number">
<xsl:value-of select="."/>
<xsl:text>
</xsl:text>
</xsl:template>
</xsl:stylesheet>
With input:
<Numbers>
<Number>111111</Number>
<Number>123123+</Number>
<Number>222222</Number>
<Number>222222+</Number>
</Numbers>
Correct result:
111111
222222
Quoting the spec:
The boolean function converts its
argument to a boolean as follows: a
number is true if and only if it is
neither positive or negative zero nor
NaN

Answer 2

Use the following XPath to select all the nodes that contains numbers. It will skip the ones with a plus sign in them.
Number[number(.)=number(.)]
Should work with XSLT 1.0

Answer 3

Yet another solution :)
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="Number[not(.*.+1)]"/>
</xsl:stylesheet>
when this transformation is applied on the following XML document:
<t>
<Number>111111</Number>
<Number>123123+</Number>
<Number>222222</Number>
<Number>222222+</Number>
</t>
the wanted, correct result is produced:
<t>
<Number>111111</Number>
<Number>222222</Number>
</t>
Explanation: All Number elements for wich the expression:
not(.*.+1)
is true() are filtered out by the simple template rule:
<xsl:template match="Number[not(.*.+1)]"/>
This is possible only if the string value of the Number element cannot be converted to a number. In this case .*.+1 evaluates to NaN and boolean(NaN) is false() by definition.
If the string value of the Number element can be converted to a number $num, then the above expression is equivalent to:
not($num*$num+1)
and $num*$num+1 >= 1 for any number $num, so, boolean(.*.+1) in this case is always true().