Pagination in XSLT - xslt

Question

My request is as below . The EmpNumberList will have 250 EmpNumbers separated by space.
<soapenv:Body>
<v1:MRRequestParam>
<v1:EmpNumberList><v1:EmpNumber> 9989071005 2004421004</v1:EmpNumber></v1:EmpNumberList>
</v1:MRRequestParam>
</soapenv:Body>
The XSLT I need to write should count the EmpNumbers from the EmpNumbersList
I need to call stored procedure in my XSLT such that i make 5 calls .
In one call I pass only 50 EmpNumbers.
I make 5 calls in total
First Call will have $EmpNumber1 such that it contains 50 EmpNumbers
$EmpNumber1 = 9989071005 2004421004 (so on 50 EmpNumbers)
<argument type="SQL_VARCHAR" mode="INPUT" nullable="true" precision="0" scale="0" isNull="false"><xsl:value-of select="$EmpNumber1" />
</argument>
When I send back the response I need to club all 5 result set and send at a time.
Please let me know if you have any suggestions

Answer 1

This one is easy:
Use:
string-length(translate(normalize-space(/*/*/*/v1:EmpNumber), '0123456789',''))+1
When applied on this document (the provided one with one more number):
<soapenv:Body xmlns:soapenv="my:soapenv">
<v1:MRRequestParam xmlns:v1="my:v1">
<v1:EmpNumberList>
<v1:EmpNumber> 9989071005 2004421004 1234567890 </v1:EmpNumber>
</v1:EmpNumberList>
</v1:MRRequestParam>
</soapenv:Body>
the wanted, correct result is returned:
3
Here is a complete XSLT 1.0 stylesheet to run and verify that the correct results are always produced:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:soapenv="my:soapenv" xmlns:v1="my:v1">
<xsl:output method="text"/>
<xsl:template match="/">
<xsl:value-of select=
"string-length(
translate(normalize-space(/*/*/*/v1:EmpNumber), '0123456789','')
)+1"/>
</xsl:template>
</xsl:stylesheet>
Do note: You have to specify the correct namespaces in the transformation and in the XML document -- you haven't provided them in your question.
Explanation:
The meaning of this expression:
string-length(
translate(normalize-space(/*/*/*/v1:EmpNumber), '0123456789','')
)+1
is:
normalize-space() . This takes the string and produces a new string from it, in which all leading and trailing whitespace characters are deleted.
What remains are only the numbers with just one intermediate space character between every two numbers. So, if there are N numbers, the number of spaces is N-1.
The translate() function as referenced in the expression, returns a new string in which all digits are gone (replaced by the empty string ''. What remains are only the space characters.
Using the string-length() function we simply get the count of those spaces** (N-1). We add 1 and get the number N of all the numbers in the string.