I'm attempting to initialise a string variable in C++, and the value is so long that it's going to exceed the 80 character per line limit I'm working to, so I'd like to split it to the next line, but I'm not sure how to do that.
I know that when splitting the contents of a stream across multiple lines, the syntax goes like
cout << "This is a string"
<< "This is another string";
Is there an equivalent for variable assignment, or do I have to declare multiple variables and concatenate them?
Edit: I misspoke when I wrote the initial question. When I say 'next line', I'm just meaning the next line of the script. When it is printed upon execution, I would like it to be on the same line.
You can simply break the line like this:
string longText("This is a "
"very very very "
"long text");
In the C family, whitespaces are insignificant, so you can freely use character literals spanning multiple lines this way.
It can also simply be
cout << "This is a string"
"This is another string";
You can write this:
const char * str = "First phrase, "
"Second phrase, "
"Third phrase";
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Removing leading and trailing spaces from a string
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Closed 2 years ago.
I'm a student so sorry if this is too basic of a question. I want to remove the whitespace at the start of a string, without removing the space between words.
stringstream parser(oneLine) ;
double amount ;
parser >> amount ;
string desc ;
getline(parser, desc) ;
cout << "Amount: $" << amount << " Desc: " << desc << endl ;
For example, I have this function I'm working on. It will read lines in from a text file, which are in the format of ex "10 Streaming Subscription."
The variables are currently: Amount = "10", desc =" Streaming Subscription" but I want desc to be "Streaming Subscription."
You can do it with a search and an erase:
const std::size_t pos = desc.find_first_not_of(' ');
if (pos != std::string::npos)
desc.erase(0, pos);
I wouldn't, though; erasing from the start of a string is not super-trivial, and you don't really need to do it.
I'd put parser.ignore(std::numeric_limits<std::streamsize>::max(), ' ') before your getline call instead, so the spaces never get read in the first place.
Note that if your input file is not formatted as you've described, this line will just keep looking for a space and chucking everything away until it finds one: if you think you may need to be more flexible, it's time to std::getline the whole line in the first place then parse it to an amount and a description after-the-fact.
Note that both solutions only consider space (U+0020) characters; you can expand it to care about e.g. tabspaces if you like. This is easy for the first approach, and slightly more complex for the second approach; in either case, I'll leave it as an exercise to the reader.
Take a look at the following example:
cout << "option 1:
\n option 2:
\n option 3";
I know,it's not the best way to output a string,but the question is why does this cause an error saying that a " character is missing?There is a single string that must go to stdout but it just consists of a lot of whitespace charcters.
What about this:
string x="
string_test";
One may interpret that string as: "\nxxxxxxxxxxxxstring_test" where x is a whitespace character.
Is it a convention?
That's called multiline string literal.
You need to escape the embedded newline. Otherwise, it will not compile:
std::cout << "Hello world \
and stackoverflow";
Note: Backslashes must be immediately before the line ends as they need to escape the newline in the source.
Also you can use the fun fact "Adjacent string literals are concatenated by the compiler" for your advantage by this:
std::cout << "Hello World"
"Stack overflow";
See this for raw string literals. In C++11, we have raw string literals. They are kind of like here-text.
Syntax:
prefix(optional) R"delimiter( raw_characters )delimiter"
It allows any character sequence, except that it must not contain the
closing sequence )delimiter". It is used to avoid escaping of any
character. Anything between the delimiters becomes part of the string.
const char* s1 = R"foo(
Hello
World
)foo";
Example taken from cppreference.
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I am writing a cout statement in C++, but the statement is very big so I pressed enter so that I can start from next line (not want to write full long statement in one line). It was working fine but if \n (new line) is the first character after hitting the enter as you can see the second line of code it was not working. So I just want to ask is there any way to start your code from the next line (continuing the previous line of code) after hitting enter.
cout<<"\nChoose the operation you want to perform :
\n1. To insert a node in the BST and in the tree \n2";
Yes, you can this way:
std::cout << "\nChoose the operation you want to perform:\n"
"1. To insert a node in the BST and in the tree\n"
"2. ...\n";
You cannot have a string on one line that doesn't end with a ", but two properly terminated strings in a row are concatenated. So "foo" "bar" becomes "foobar". Having "foo" and "bar" on separate lines is fine.
As others have mentioned, C++11 supports raw string literals, which do allow strings to be spread out over multiple lines, and avoids having to write \n:
std::cout << R"(
Choose the operation you want to perform:
1. To insert a node in the BST and in the tree
2. ...
)";
You can either use a multiline string literal like
const char* s1 = "\nChoose the operation you want to perform:\n"
"1. To insert a node in the BST and in the tree\n"
"2. some text here";
our you can use raw string literals without any quotes or new line literals (cf, for example, string literals at cppreference.com):
const char* s1 = R"foo(
Choose the operation you want to perform:
1. To insert a node in the BST and in the tree
2. some text here)foo";
These two s1-variants are equivalent. Then write
std::cout << s1;
You have the option:
std::cout << "\nSome text,\n"
"\nsomething else\n";
(which was originally proposed by #G. Sliepen)
I would rather prefer using std::endl.
The code would look like:
std::cout << std::endl << "Some text," << std::endl <<
std::endl << "something else" << std::endl;
Yet another option is to use R prefix (which is used to avoid escaping of any character):
std::cout << R"(
Some text,
something else
)";
My favourite is the last one.
This is how to split string in Unityscript from Unity Wiki. However, I don't recognize " "[0]. Is this regular expression? If so, any reference to it? I'm familiar with regular expressions generally and used them a lot, but this syntax is little confusing.
var qualifiedName = "System.Integer myInt";
var name = qualifiedName.Split(" "[0]);
Wiki Reference
On any string, wether it is a variable or a literal (" "), you can use an indexer to get the char at the nth position.
Your codesample is a very weird way of literally defining a char with a space, and could be simplified by using this:
' '
note the single quotes instead of double quotes
As many have already mentioned, " "[0] is the first character of the " " string (which is a System.String, or an array of System.Chars. The problem with UnityScript is that ' ' is interpreted as a String too, so the only way to provide a Char is by slicing.
" "[0] is the first character of the string " ".
typeof " "[0]; // "string"
Your example is strange, because " "[0] and " " are strictly equal.
" "[0] === " "; // true
Reading reference:
Mono Types When a Mono function requires a char as an input, you can
obtain one by simply indexing a string. E.g. if you wanted to pass the
lowercase a as a char, you'd write: "a"[0]
I suppose it's because UnityScript is implemented in Boo and String is provided by mono.
How do you say something like this?
static const string message = "This is a message.\n
It continues in the next line"
The problem is, the next line isn't being recognized as part of the string..
How to fix that? Or is the only solution to create an array of strings and then initialize the array to hold each line?
Enclose each line in its own set of quotes:
static const string message = "This is a message.\n"
"It continues in the next line";
The compiler will combine them into a single string.
You can use a trailing slash or quote each line, thus
"This is a message.\n \
It continues in the next line"
or
"This is a message."
"It continues in the next line"
In C++ as in C, string litterals separated by whitespace are implicitly concatenated, so
"foo" "bar"
is equivalent to:
"foobar"
So you want:
static const string message = "This is a message.\n"
"It continues in the next line";