Preserving the original axis system while rotating with openGL - opengl

I'm implementing an arcball with openGL (on cpp).
Say, I have an object in the center of the axes system and i want to rotate in several times acording to the original (world) axes.
But, after the first rotation, the axes are changed and all further rotations goes wrong.
Any ideas?
Thanks.

Supply the object with it's own orientation axes (modelview matrix), and then multiply that by the rotation matrices. Check Wikipedia for info on how to construct rotation matrices.

I had to do the same thing myself in an OpenGL ES application, which I describe in a writeup about it here. The original crude approach read the current model view matrix and manipulated it to produce the desired effect:
GLfloat currentModelViewMatrix[16];
glGetFloatv(GL_MODELVIEW_MATRIX, currentModelViewMatrix);
glRotatef(xRotation, currentModelViewMatrix[1], currentModelViewMatrix[5], currentModelViewMatrix[9]);
glGetFloatv(GL_MODELVIEW_MATRIX, currentModelViewMatrix);
glRotatef(yRotation, currentModelViewMatrix[0], currentModelViewMatrix[4], currentModelViewMatrix[8]);
This will work, but be aware that the two glGetFloatv() calls will slow your rendering by halting the pipeline. I've since replaced this code with calculations that I perform on my own internal copy of the model view matrix, then I simply write the internally manipulated model view matrix after each rotation. This removes the need to do the expensive matrix read operations.

Add xAngle and yAngle to the current matrix.
Matrix.rotateM(matrix, 0, xAngleADD, matrix[1], matrix[5], matrix[9]);
Matrix.rotateM(matrix, 0, yAngleADD, matrix[0], matrix[4], matrix[8]);
gl.glMultMatrixf(matrix, 0);

Related

OpenGl rotations and translations

I am building a camera class to look arround a scene. At the moment I have 3 cubes just spread arround to have a good impression of what is going on. I have set my scroll button on a mouse to give me translation along z-axis and when I move my mouse left or right I detect this movement and rotate arround y-axis. This is just to see what happens and play arround a bit. So I succeeded in making the camera rotate by rotating the cubes arround the origin but after I rotate by some angle, lets say 90 degrees, and try to translate along z axis to my surprise I find out that my cubes are now going from left to right and not towards me or away from me. So what is going on here? It seems that z axis is rotated also. I guess the same goes for x axis. So it seems that nothing actually moved in regard to the origin, but the whole coordinate system with all the objects was just rotated. Can anyone help me here, what is going on? How coordinate system works in opengl?
You are most likely confusing local and global rotations. Usual cheap remedy is to change(reverse) order of some of your transformation. However doing this blindly is trial&error and can be frustrating. Its better to understand the math first...
Old API OpeGL uses MVP matrix which is:
MVP = Model * View * Projection
Where Model and View are already multiplied together. What you have is most likely the same. Now the problem is that Model is direct matrix, but View is Inverse.
So if you have some transform matrix representing your camera in oder to use it to transform back you need to use its inverse...
MVP = Model * Inverse(Camera) * Projection
Then you can use the same order of transformations for both Model and Camera and also use their geometric properties like basis vectors etc ... then stuff like camera local movements or camera follow are easy. Beware some tutorials use glTranspose instead of real matrix Inverse. That is correct only if the Matrix contains only unit (or equal sized) orthogonal basis vectors without any offset so no scale,skew,offset or projections just rotation and equal scale along all axises !!!
That means when you rotate Model and View in the same way the result is opposite. So in old code there is usual to have something like this:
// view part of matrix
glMatrixMode(GL_MODELVIEW);
glLoadIdentity();
glRotate3f(view_c,0,0,1); // ugly euler angles
glRotate3f(view_b,0,1,0); // ugly euler angles
glRotate3f(view_a,1,0,0); // ugly euler angles
glTranslatef(view_pos); // set camera position
// model part of matrix
for (i=0;i<objs;i++)
{
glMatrixMode(GL_MODELVIEW);
glPushMatrix();
glTranslatef(obj_pos[i]); // set camera position
glRotate3f(obj_a[i],1,0,0); // ugly euler angles
glRotate3f(obj_b[i],0,1,0); // ugly euler angles
glRotate3f(obj_c[i],0,0,1); // ugly euler angles
//here render obj[i]
glMatrixMode(GL_MODELVIEW);
glPopMatrix();
}
note the order of transforms is opposite (I just wrote it here in editor so its not tested and can be opposite to native GL notation ... I do not use Euler angles) ... The order must match your convention... To know more about these (including examples) not using useless Euler angles see:
Understanding 4x4 homogenous transform matrices
Here is 4D version of what your 3D camera class should look like (just shrink the matrices to 4x4 and have just 3 rotations instead of 6):
reper4D
pay attention to difference between local lrot_?? and global grot_?? functions. Also note rotations are defined by plane not axis vector as axis vector is just human abstraction that does not really work except 2D and 3D ... planes work from 2D to ND
PS. its a good idea to have the distortions (scale,skew) separated from model and keep transform matrices representing coordinate systems orthonormal. It will ease up a lot of things latter on once you got to do advanced math on them. Resulting in:
MVP = Model * Model_distortion * Inverse(Camera) * Projection

Can I rotate the view of glOrtho()?

I'm making a program where I need an orthographic projection.
So, I'm using glOrtho(). I made a zoom function but I was wandering if you can rotate your view?
Because glOrho() only looks parralel to other planes.
Or is there another projection wich can do that.
glLookAt can rotate but it changes dimensions when further from the camera.
I read
How can I make the glOrtho parallelepiped rotating?
but it didn't give me an answer.
What's essential here is that you usually split the operations into two matrices: The (Model)View and The Projection.
While glOrtho() is usually called with glMatrixMode(GL_PROJECTION), all operations regarding moving and rotating the camera (such as glRotate*, glTranslate* and gluLookAt) should be preceeded by glMatrixMode(GL_MODELVIEW).
In fixed pipeline, the final position of the vertex is calculated by multiplying input data by these two matrices, and the projection used (orthographic or perspective or nonlinear whatnot) is separate from camera transformations.

OpenGL define vertex position in pixels

I've been writing a 2D basic game engine in OpenGL/C++ and learning everything as I go along. I'm still rather confused about defining vertices and their "position". That is, I'm still trying to understand the vertex-to-pixels conversion mechanism of OpenGL. Can it be explained briefly or can someone point to an article or something that'll explain this. Thanks!
This is rather basic knowledge that your favourite OpenGL learning resource should teach you as one of the first things. But anyway the standard OpenGL pipeline is as follows:
The vertex position is transformed from object-space (local to some object) into world-space (in respect to some global coordinate system). This transformation specifies where your object (to which the vertices belong) is located in the world
Now the world-space position is transformed into camera/view-space. This transformation is determined by the position and orientation of the virtual camera by which you see the scene. In OpenGL these two transformations are actually combined into one, the modelview matrix, which directly transforms your vertices from object-space to view-space.
Next the projection transformation is applied. Whereas the modelview transformation should consist only of affine transformations (rotation, translation, scaling), the projection transformation can be a perspective one, which basically distorts the objects to realize a real perspective view (with farther away objects being smaller). But in your case of a 2D view it will probably be an orthographic projection, that does nothing more than a translation and scaling. This transformation is represented in OpenGL by the projection matrix.
After these 3 (or 2) transformations (and then following perspective division by the w component, which actually realizes the perspective distortion, if any) what you have are normalized device coordinates. This means after these transformations the coordinates of the visible objects should be in the range [-1,1]. Everything outside this range is clipped away.
In a final step the viewport transformation is applied and the coordinates are transformed from the [-1,1] range into the [0,w]x[0,h]x[0,1] cube (assuming a glViewport(0, w, 0, h) call), which are the vertex' final positions in the framebuffer and therefore its pixel coordinates.
When using a vertex shader, steps 1 to 3 are actually done in the shader and can therefore be done in any way you like, but usually one conforms to this standard modelview -> projection pipeline, too.
The main thing to keep in mind is, that after the modelview and projection transforms every vertex with coordinates outside the [-1,1] range will be clipped away. So the [-1,1]-box determines your visible scene after these two transformations.
So from your question I assume you want to use a 2D coordinate system with units of pixels for your vertex coordinates and transformations? In this case this is best done by using glOrtho(0.0, w, 0.0, h, -1.0, 1.0) with w and h being the dimensions of your viewport. This basically counters the viewport transformation and therefore transforms your vertices from the [0,w]x[0,h]x[-1,1]-box into the [-1,1]-box, which the viewport transformation then transforms back to the [0,w]x[0,h]x[0,1]-box.
These have been quite general explanations without mentioning that the actual transformations are done by matrix-vector-multiplications and without talking about homogenous coordinates, but they should have explained the essentials. This documentation of gluProject might also give you some insight, as it actually models the transformation pipeline for a single vertex. But in this documentation they actually forgot to mention the division by the w component (v" = v' / v'(3)) after the v' = P x M x v step.
EDIT: Don't forget to look at the first link in epatel's answer, which explains the transformation pipeline a bit more practical and detailed.
It is called transformation.
Vertices are set in 3D coordinates which is transformed into a viewport coordinates (into your window view). This transformation can be set in various ways. Orthogonal transformation can be easiest to understand as a starter.
http://www.songho.ca/opengl/gl_transform.html
http://www.opengl.org/wiki/Vertex_Transformation
http://www.falloutsoftware.com/tutorials/gl/gl5.htm
Firstly be aware that OpenGL not uses standard pixel coordinates. I mean by that for particular resolution, ie. 800x600 you dont have horizontal coordinates in range 0-799 or 1-800 stepped by one. You rather have coordinates ranged from -1 to 1 later send to graphic card rasterizing unit and after that matched to particular resolution.
I ommited one step here - before all that you have an ModelViewProjection matrix (or viewProjection matrix in some simple cases) which before all that will cast coordinates you use to an projection plane. Default use of that is to implement a camera which converts 3D space of world (View for placing an camera into right position and Projection for casting 3d coordinates into screen plane. In ModelViewProjection it's also step of placing a model into right place in world).
Another case (and you can use Projection matrix this way to achieve what you want) is to use these matrixes to convert one range of resolutions to another.
And there's a trick you will need. You should read about modelViewProjection matrix and camera in openGL if you want to go serious. But for now I will tell you that with proper matrix you can just cast your own coordinate system (and ie. use ranges 0-799 horizontaly and 0-599 verticaly) to standarized -1:1 range. That way you will not see that underlying openGL api uses his own -1 to 1 system.
The easiest way to achieve this is glOrtho function. Here's the link to documentation:
http://www.opengl.org/sdk/docs/man/xhtml/glOrtho.xml
This is example of proper usage:
glMatrixMode (GL_PROJECTION)
glLoadIdentity ();
glOrtho (0, 800, 600, 0, 0, 1)
glMatrixMode (GL_MODELVIEW)
Now you can use own modelView matrix ie. for translation (moving) objects but don't touch your projection example. This code should be executed before any drawing commands. (Can be after initializing opengl in fact if you wont use 3d graphics).
And here's working example: http://nehe.gamedev.net/tutorial/2d_texture_font/18002/
Just draw your figures instead of drawing text. And there is another thing - glPushMatrix and glPopMatrix for choosen matrix (in this example projection matrix) - you wont use that until you combining 3d with 2d rendering.
And you can still use model matrix (ie. for placing tiles somewhere in world) and view matrix (in example for zooming view, or scrolling through world - in this case your world can be larger than resolution and you could crop view by simple translations)
After looking at my answer I see it's a little chaotic but If you confused - just read about Model, View, and Projection matixes and try example with glOrtho. If you're still confused feel free to ask.
MSDN has a great explanation. It may be in terms of DirectX but OpenGL is more-or-less the same.
Google for "opengl rendering pipeline". The first five articles all provide good expositions.
The key transition from vertices to pixels (actually, fragments, but you won't be too far off if you think "pixels") is in the rasterization stage, which occurs after all vertices have been transformed from world-coordinates to screen coordinates and clipped.

OpenGL glScale and glLoadMatrix

I'm writing an 3D Scanner with a Kinect and i want to display the Point clouds..
The Pointclouds have an additional Transformmatrix from a Trackingsystem..
I use:
scale = 0.0005;
glScaled(scale, scale, scale);
to encounter the Problem, that x,y,z Value ranges from 0 - 10.000 are cut by Opengl due to clipping planes.
when i use glLoadMatrix(trackingtransform); i don't see anything.. even if i use glscale again after the loadmatrix.
glLoadMatrix replaces the matrix that you generated with glScaled.
if you want to combine them, use glMultMatrix instead of glLoadMatrix.
That said, I'd advise to do what datenwolf alludes to. Use the projection matrix to set a coordinate system that maps your usage scenario (i.e. a world in the 0-10000 range), and keep the modelview matrix to move around.
You can directly scale the matrix your points are in, like:
glPushMatrix();
glScale();
-draw all your points...
glPopMatrix();

OpenGL Rotation

I'm trying to do a simple rotation in OpenGL but must be missing the point.
I'm not looking for a specific fix so much as a quick explanation or link that explains OpenGL rotation more generally.
At the moment I have code like this:
glPushMatrix();
glRotatef(90.0, 0.0, 1.0, 0.0);
glBegin(GL_TRIANGLES);
glVertex3f( 1.0, 1.0, 0.0 );
glVertex3f( 3.0, 2.0, 0.0 );
glVertex3f( 3.0, 1.0, 0.0 );
glEnd();
glPopMatrix();
But the result is not a triangle rotated 90 degrees.
Edit
Hmm thanks to Mike Haboustak - it appeared my code was calling a SetCamera function that use glOrtho. I'm too new to OpenGL to have any idea of what this meant but disabling this and rotating in the Z-axis produced the desired result.
Ensure that you're modifying the modelview matrix by putting the following before the glRotatef call:
glMatrixMode(GL_MODELVIEW);
Otherwise, you may be modifying either the projection or a texture matrix instead.
Do you get a 1 unit straight line? It seems that 90deg rot. around Y is going to have you looking at the side of a triangle with no depth.
You should try rotating around the Z axis instead and see if you get something that makes more sense.
OpenGL has two matrices related to the display of geometry, the ModelView and the Projection. Both are applied to coordinates before the data becomes visible on the screen. First the ModelView matrix is applied, transforming the data from model space into view space. Then the Projection matrix is applied with transforms the data from view space for "projection" on your 2D monitor.
ModelView is used to position multiple objects to their locations in the "world", Projection is used to position the objects onto the screen.
Your code seems fine, so I assume from reading the documentation you know what the nature of functions like glPushMatrix() is. If rotating around Z still doesn't make sense, verify that you're editing the ModelView matrix by calling glMatrixMode.
The "accepted answer" is not fully correct - rotating around the Z will not help you see this triangle unless you've done some strange things prior to this code. Removing a glOrtho(...) call might have corrected the problem in this case, but you still have a couple of other issues.
Two major problems with the code as written:
Have you positioned the camera previously? In OpenGL, the camera is located at the origin, looking down the Z axis, with positive Y as up. In this case, the triangle is being drawn in the same plane as your eye, but up and to the right. Unless you have a very strange projection matrix, you won't see it. gluLookat() is the easiest command to do this, but any command that moves the current matrix (which should be MODELVIEW) can be made to work.
You are drawing the triangle in a left handed, or clockwise method, whereas the default for OpenGL is a right handed, or counterclockwise coordinate system. This means that, if you are culling backfaces (which you are probably not, but will likely move onto as you get more advanced), you would not see the triangle as expected. To see the problem, put your right hand in front of your face and, imagining it is in the X-Y plane, move your fingers in the order you draw the vertices (1,1) to (3,2) to (3,1). When you do this, your thumb is facing away from your face, meaning you are looking at the back side of the triangle. You need to get into the habit of drawing faces in a right handed method, since that is the common way it is done in OpenGL.
The best thing I can recommend is to use the NeHe tutorials - http://nehe.gamedev.net/. They begin by showing you how to set up OpenGL in several systems, move onto drawing triangles, and continue slowly and surely to more advanced topics. They are very easy to follow.
Regarding Projection matrix, you can find a good source to start with here:
http://msdn.microsoft.com/en-us/library/bb147302(VS.85).aspx
It explains a bit about how to construct one type of projection matrix. Orthographic projection is the very basic/primitive form of such a matrix and basically what is does is taking 2 of the 3 axes coordinates and project them to the screen (you can still flip axes and scale them but there is no warp or perspective effect).
transformation of matrices is most likely one of the most important things when rendering in 3D and basically involves 3 matrix stages:
Transform1 = Object coordinates system to World (for example - object rotation and scale)
Transform2 = World coordinates system to Camera (placing the object in the right place)
Transform3 = Camera coordinates system to Screen space (projecting to screen)
Usually the 3 matrix multiplication result is referred to as the WorldViewProjection matrix (if you ever bump into this term), since it transforms the coordinates from Model space through World, then to Camera and finally to the screen representation.
Have fun