I have a modal dialog. I open another modal dialog using DoModal, so that there are now two dialogs, one on top of another. When I then close the top dialog by clicking okay, I get an assertion error for line 896 of mfc90ud.dll. How can I fix this?
Hi probably you did not set parent for your child dialog
CMyDialog dlg(this);
Related
I am closing a modal dialog after I end a task, inside a separate thread from where I created a modal dialog:
void CmodguiApp::_notify_task_end() {
processingDialog->EndDialog(0);
}
This works fine if my application has focus (therefore the modal dialog has focus). But this causes the application to crash if I change window while the modal dialog is on (for instance, if I leave the application processing and switch to Firefox or so).
What could be wrong?
Do not end the dialog with EndDialog. Instead PostMessage with WM_CLOSE or WM_QUIT to the dialog window.
I have a dialog IDD_WINDOW_INFO that has to be opened when the user clicks a button or a menu item in my C++ Win32 application. The method that I use to open the dialog is in the following line:
DialogBox(hInstance, MAKEINTRESOURCE(IDD_WINDOW_INFO), hMainWindow, WindowInfoProc);
but my problem is that when that dialog box opens, the user cannot operate with the main window of my application. So what can I do to have both windows active?
You are calling DialogBox which shows the dialog modally. When a modal dialog is shown, the other owning windows are disabled and only the modal dialog can accept input. That is the very essence and intent of a modal dialog. The idea is that you can interact only with the dialog, and cannot interact with the other windows.
Another answer suggests passing NULL as the hWndParent parameter to DialogBox. That's not the solution. That will result in you having an unowned window. Yes, you will be able to interact with the main window, but when you do so your main window will appear on top of the dialog. That's because the ownership is set incorrectly. I recommend that you read about window ownership to better understand the issue.
The correct solution to your problem is to show a modeless dialog. A modeless dialog allows you to interact with the other windows in your application. And that's exactly what you ask for in the question.
You show modeless dialogs by calling CreateDialog followed by ShowWindow. This MSDN article shows an example: Using Dialog Boxes.
If I recall correctly, you can either pass NULL instead of the handle to the parent window or change the dialogbox type in the resource editor.
That is an easy way to do it, however the following is certainly better - since having an unowned dialog isn't your best choice.
The point is that DialogBox() will create a modal dialog window, while CreateDialog does not. Modal dialogs disable the parent window.
From MSDN: A modeless dialog box neither disables the owner window nor sends messages to it.
That should solve your problem.
CreateDialog(hInstance, MAKEINTRESOURCE(IDD_WINDOW_INFO), hMainWindow, WindowInfoProc);
ShowWindow(hWnd, SW_SHOW);
I have a custom dialog message box that pops-up when a edit control in my main dialog has wrong data.
CDlgError dlgError = new CDlgError(this);
dlgError.Create(CDlgError::IDD, this);
dlgError.m_staticMessage.SetWindowTextA("Error message!");
dlgError.ShowWindow(SW_SHOW);
//more code
I want the rest of the code to be executed only after i press an OK button in my CDlgError pop-up dialog. How can i do that?
Use DoModal instead of Create and ShowWindow to show your error dialog. e.g.
CDlgError dlgError = new CDlgError(this);
dlgError.m_strMessage = "Error message!";
dlgError.DoModal();
As you can see from the code you'll need to pass in the text and THEN set your message label inside CDlgError::OnInitDialog because the control won't be initialized before going modal.
You are creating a dialog using Create which shows a modalless dialog(you can click on other parts of application even dialog is open).
You requirement is for modal dialog where you can not click on any part of application until this dialog is closed.
To do this use DoModal function instead of create.
how can I open a secondary modal dialog in C++ MFC from a dialog without pressing any button?
(If I create a dialog in OnInitDialog(), the first dialog won't appear.)
Just call ShowWindow(SW_SHOW); in your OnInitDialog just before display the secondary dialog.
Had the same problem. The reason was because of a problem in clear case which made the sln folder unreachable. Try close/stop ClearCase and open it again. Browse to the folder from clearcase and open the .sln.
Good Luck
I have a hard time hiding a modal dialog box. What I am doing is - I am trying to design a UI for my own application in MFC, kind of a setup assistant.
In the 1st dialog box I have NEXT button, so when I click that it has to hide the 1st dialog box and move on to the 2nd dialog box, where I have some controls in 2nd dialog box.
How can I achieve that?
I have never tried to hide a Modal dialog...not sure how it can be done.
Anyway, it seems to me you don't need to hide the dialog but destroy the first one and create the second one. You can use EndDialog to terminate a modal dialog.
But MFC has its own mechanism to create your own wizard, have a look at this class CPropertySheet. I am sure you can find thousand of examples, this is one.
Hope it helps.
You can use ShowWindow() function to hide modal
Its default patametet is SW_SHOW which is equal true value 1 and
To hide modal use SW_HIDE value when you click next button
You just use ShowWindow(SW_HIDE) If you make prev button you should use modal pointer
Or next modal should child modal because you cannot have prev modal variable.
I wish you understand me for my english