Lately, I've been trying to learn C++ from this website. Unfortunately whenever I try to run one of the code samples, I see that program open for about a half second and then immediately close. Is there a way to stop the program from closing immediately so that I can see the fruits of my effort?
If you are using Visual Studio and you are starting the console application out of the IDE:
pressing CTRL-F5 (start without debugging) will start the application and keep the console window open until you press any key.
Edit: As Charles Bailey rightly points out in a comment below, this won't work if there are characters buffered in stdin, and there's really no good way to work around that. If you're running with a debugger attached, John Dibling's suggested solution is probably the cleanest solution to your problem.
That said, I'll leave this here and maybe someone else will find it useful. I've used it a lot as a quick hack of sorts when writing tests during development.
At the end of your main function, you can call std::getchar();
This will get a single character from stdin, thus giving you the "press any key to continue" sort of behavior (if you actually want a "press any key" message, you'll have to print one yourself).
You need to #include <cstdio> for getchar.
The solution by James works for all Platforms.
Alternatively on Windows you can also add the following just before you return from main function:
system("pause");
This will run the pause command which waits till you press a key and also displays a nice message Press any key to continue . . .
If you are using Microsoft's Visual C++ 2010 Express and run into the issue with CTRL+F5 not working for keeping the console open after the program has terminated, take a look at this MSDN thread.
Likely your IDE is set to close the console after a CTRL+F5 run; in fact, an "Empty Project" in Visual C++ 2010 closes the console by default. To change this, do as the Microsoft Moderator suggested:
Please right click your project name and go to Properties page, please expand Configuration Properties -> Linker -> System, please select Console (/SUBSYSTEM:CONSOLE) in SubSystem dropdown. Because, by default, the Empty project does not specify it.
I usually just put a breakpoint on main()'s closing curly brace. When the end of the program is reached by whatever means the breakpoint will hit and you can ALT-Tab to the console window to view the output.
Why not just run the program from a console ie run the program from cmd.exe if you're using Windows. That way the window stays open after the program finishes.
[EDIT]: When I use KDevelop4 there is a fully fledged instance of Bash (a Linux CLI) running in a tab at the bottom of the IDE. Which is what I use in these sort of circumstances.
Before the end of your code, insert this line:
system("pause");
This will keep the console until you hit a key.
#include <iostream>
#include <string>
using namespace std;
int main()
{
string s;
cout << "Please enter your first name followed by a newline\n";
cin >> s;
cout << "Hello, " << s << '\n';
system("pause"); // <----------------------------------
return 0; // This return statement isn't necessary
}
Call cin.get(); 2 times:
//...
cin.get();
cin.get();
return 0
}
If you run your code from a competent IDE, such as Code::Blocks, the IDE will manage the console it uses to run the code, keeping it open when the application closes. You don't want to add special code to keep the console open, because this will prevent it functioning correctly when you use it for real, outside of the IDE.
I just do this:
//clear buffer, wait for input to close program
std::cin.clear(); std::cin.ignore(INT_MAX, '\n');
std::cin.get();
return 0;
Note: clearing the cin buffer and such is only necessary if you've used cin at some point earlier in your program. Also using std::numeric_limits::max() is probably better then INT_MAX, but it's a bit wordy and usually unnecessary.
Okay I'm guessing you are on Windows using Visual Studio... why? Well because if you are on some sort of Linux OS then you'd probably be running it from the console.
Anyways, you can add crap to the end of your program like others are suggesting, or you can just hit CTRL + F5 (start without debugging) and Visual Studio will leave the console up once complete.
Another option if you want to run the Debug version and not add crap to your code is to open the console window (Start -> Run -> cmd) and navigate to your Debug output directory. Then, just enter the name of your executable and it will run your debug program in the console. You can then use Visual Studio's attach to process or something if you really want to.
Just add the following at the end of your program. It will try to capture some form of user input thus it stops the console from closing automatically.
cin.get();
If you are actually debugging your application in Visual C++, press F5 or the green triangle on the toolbar. If you aren't really debugging it (you have no breakpoints set), press Ctrl+F5 or choose Start Without Debugging on the menus (it's usually on the Debug menu, which I agree is confusing.) It will be a little faster, and more importantly to you, will pause at the end without you having to change your code.
Alternatively, open a command prompt, navigate to the folder where your exe is, and run it by typing its name. That way when it's finished running the command prompt doesn't close and you can see the output. I prefer both of these methods to adding code that stops the app just as its finished.
Add the following lines before any exit() function or before any returns in main():
std::cout << "Paused, press ENTER to continue." << std::endl;
cin.ignore(100000, "\n");
For Visual Studio (and only Visual Studio) the following code snippet gives you a 'wait for keypress to continue' prompt that truly waits for the user to press a new key explicitly, by first flushing the input buffer:
#include <cstdio>
#include <tchar.h>
#include <conio.h>
_tprintf(_T("Press a key to continue "));
while( _kbhit() /* defined in conio.h */ ) _gettch();
_gettch();
Note that this uses the tchar.h macro's to be compatible with multiple 'character sets' (as VC++ calls them).
Use #include "stdafx.h" & system("pause"); just like the code down below.
#include "stdafx.h"
#include <iostream>
using namespace std;
int main()
{
std::cout << "hello programmer!\n\nEnter 2 numbers: ";
int x, y;
std::cin >> x >> y;
int w = x*y;
std::cout <<"\nyour answer is: "<< w << endl;
system("pause");
}
simply
#include <cstdio>
int main(){
// code...
std::getchar();
std::getchar();
return 0;
}
for some reason there is usually 1 character possible to read with getchar already in stdin when you run a program. so the first getchar reads this character, and the second getchar waits for user (your) input before exiting the program. And after a program exits most of terminals, especially on Windows close terminal immediately.
so what we aim to is a simple way of preventing a program from finishing after it outputs everything.
Of course there are more complex and clean ways to solve this, but this is the simplest.
Similar idea to yeh answer, just minimalist alternative.
Create a batch file with the following content:
helloworld.exe
pause
Then use the batch file.
See if your IDE has a checkbox in project setting to keep the window open after the program terminates. If not, use std::cin.get(); to read a character at the end of main function. However, be sure to use only line-based input (std::getline) or to deal with leftover unread characters otherwise (std::ignore until newline) because otherwise the .get() at the end will only read the garbage you left unread earlier.
This seems to work well:
cin.clear();
cin.ignore(2);
If you clear the buffer first it won't be a problem when you read the next one.
For some reason cin.ignore(1) does not work, it has to be 2.
You could always just create a batch file. For example, if your program is called helloworld.exe, some code would be:
#echo off
:1
cls
call helloworld.exe
pause >nul
goto :1
If you are running Windows, then you can do system("pause >nul"); or system("pause");. It executes a console command to pause the program until you press a key. >nul prevents it from saying Press any key to continue....
I'm putting a breakpoint at the last return 0 of the program. It works fine.
I used cin.get() and that is worked but one day I needed to use another cin.get([Array Variable]) before that to grab a ling string with blank character in middle of. so the cin.get() didn't avoid command prompt window from closing. Finally I found Another way:
Press CTRL+F5 to open in an external window and Visual Studio does not have control over it anymore. Just will ask you about closing after final commands run.
I tried putting a getchar() function at the end. But it didn't work. So what I did was add two getchar() functions one after another. I think the first getchar() absorbs the Enter key you press after the last data input. So try adding two getchar() functions instead of one
Instead of pressing the run button, press CTRL and F5 at the same time, it will give you the press any key to continue message. Or type "(warning use this only for testing not actual programs as an antiviruses don't like it!!!!)" at the end of your main function but: (warning use this only for testing not actual programs as an antiviruses don't like it!!!!)
just use cin.ignore() right before return 0; twice
main()
{
//your codes
cin.ignore();
cin.ignore();
return 0;
}
thats all
you can try also doing this
sleep (50000);
cout << "any text" << endl;
This will hold your code for 50000m, then prints message and closes. But please keep in mind that it will not pause forever.
Here's a problem, not so obvious. Somehow I had added a debug breakpoint at the very last line of my program. } Not sure how I did that, perhaps with an erroneous mouse click while jumping between different screens. I'm working in VS Code.
And when I go to debug, the system jumps immediately to that breakpoint. No error message, no interim output, nothing. I'm like, how did the program rush thru all my set breakpoints? This took too long to figure out.
Apparently the system sees that last line breakpoint as a "first" stop. The simple fix? Delete that breakpoint, doh! (insert forehead slap here.)
All you have to do set a variable for x then just type this in before the return 0;
cout<<"\nPress any key and hit enter to end...";
cin>>x;
In C++, when writing to and taking information from the console using cout / cin, is it possible to do something like
ENTER YOUR DATA HERE --> __ <-- ENTER YOUR DATA HERE
With the user input cursor where the underscores are located, and output located on either side of the cursor, and then the user's typed input appearing between those two bits of output before being returned to cin?
If so how would I got about doing that?
I hope that between my title and explanation here that it's clear what I'm asking, if not I can try to explain further.
Ideally I'd like to do this using iostream / cin & cout, because those are what I've used in the past. If the solution is to use... printf or similar I'll do that but may need a bit of additional explanation since I'm not really experienced in using that for output.
NOTE: I tried to find an answer for this problem and I can't say for sure that there wasn't one, it was mostly just a matter of finding a huge amount of other input/output-related questions.
EDIT: This is using the DOS shell on Windows 7, compiling from the Windows Visual Studio 2012 command-line compiler.
If Windows, use the Console API. http://msdn.microsoft.com/en-us/library/windows/desktop/ms682073(v=vs.85).aspx
If Linux, use the curses library: http://en.wikipedia.org/wiki/Ncurses
If you are using windows you have the option to use the conio.h.
#include<iostream.h>
#include<conio.h>
int main()
{
clrscr();
gotoxy(5,3);
cout<<"HELLO WORLD";
gotoxy(60,10);
cout<<"HELLO WORLD";
gotoxy(35,20);
cout<<"HELLO WORLD";
getch();
return 0;
}
If you wish to use ANSI libraries only, you can try to take a look at this discussion:
http://www.cplusplus.com/forum/lounge/78225/
In both cases all you have to do is print the first text, then use gotoxy, then you print seconde text, gotoxy again where you want the input to happens, and read the user input.
I use the following lines to output my simulation's progress info in my c++ program,
double N=0;
double percent=0;
double total = 1000000;
for (int i; i<total; ++i)
{
percent = 100*i/total;
printf("\r[%6.4f%%]",percent);
}
It works fine!
But the problem is I see the terminal cursor keeps blinking cyclically through the numbers, this is very annoying, anyone knows how to get rid of this?
I've seen some programs like wget or ubuntu apt, they use progress bar or percentages too, but they seems no blinking cursor issue, I am wondering how did they do that?
Thanks!
You can hide and show the cursor using the DECTCEM (DEC text cursor enable mode) mode in DECSM and DECRM:
fputs("\e[?25l", stdout); /* hide the cursor */
fputs("\e[?25h", stdout); /* show the cursor */
Just a guess: try to use a proper number of '\b' (backspace) characters instead of '\r'.
== EDIT ==
I'm not a Linux shell wizard, but this may work:
system("setterm -cursor off");
// ...display percentages...
system("setterm -cursor on");
Don't forget to #include <cstdlib> or <iostream>.
One way to avoid a blinking cursor is (as suggested) to hide the cursor temporarily.
However, that is only part of the solution. Your program should also take this into account:
after hiding the cursor and modifying the screen, before showing the cursor again move it back to the original location.
hiding/showing the cursor only keeps the cursor from noticeably blinking when your updates take only a small amount of time. If you happened to mix this with some time-consuming process, your cursor will blink.
The suggested solution using setterm is not portable; it is specific to the Linux console. And running an executable using system is not really necessary. But even running
system("tput civis");
...
system("tput cnorm");
is an improvement over using setterm.
Checking the source-code for wget doesn't find any cursor-hiding escape sequences. What you're seeing with its progress bar is that it leaves the cursor in roughly the same place whenever it does something time-consuming. The output to the terminal takes so little time that you do not notice the momentary rewrite of the line (by printing a carriage return, then writing most of the line over again). If it were slower, then hiding the cursor would help — up to a point.
By the way — this cursor-hiding technique is used in the terminal drivers for some editors (vim and vile).
Those apps are probably using ncurses. See mvaddstr
The reason the cursor jumps around is because stdout is buffered, so you don't know actually how many characters are being printed at some point in time. The reason wget does not have a jumping cursor is that they are actually printing to stderr instead, which is unbuffered. Try the following:
fprintf(stderr, "\r[%6.4f%%]", percent);
This also has the advantage of not cluttering the file if you are saving the rest of the output somewhere using a pipe like:
$ ./executable > log.data
Press insert key...if that doesn't work then press the fn key in your keyboard.
This will definitely work
Hope this helps
This is my first post and I'm quite a novice on C++ and compiling in general.
I'm compiling a program which requires some graphs to be drawn. The program create a .dat file and then i should open gnuplot and write plot '.dat'. That's fine.
Is there a way to make gnuplot automatically open and show me the plot I need? I should use some system() function in the code to call gnuplot but how can I make him plot what I need?
Sorry for my non-perfect English :s
Thanks for the attention anyway!
Depending on your OS, you might be able to use popen(). This would let you spawn a gnuplot process and just just write to it like any other FILE*.
If you have datapoints to plot, you can pass them inline with the plot "-" ... option. Similarly, you may want to explore set data style points/lines/linespoints/etc options.
Without pause or persist, gnuplot will terminate upon end-of-input-stream. In your example case, that would be when the end of the file is reached.
To produce (write) an output file (graph), use:
set terminal png small
set output "filename.png"
There's lots of options to set terminal. Png is usually there. If not, perhaps gif, tiff, or jpeg?
Watch out for overwriting the file!
You may want to use set size 2,2 to make a larger graph. Some set terminal variants also allow you to specify the size.
I'm learning this today too. Here is a small example I cooked up.
#include <iostream>
#include <fstream>
using namespace std;
int main(int argc, char **argv) {
ofstream file("data.dat");
file << "#x y" << endl;
for(int i=0; i<10; i++){
file << i << ' ' << i*i << endl;
}
file.close();
return 0;
}
Save that as plot.cpp and compile that with g++:
g++ plot.cpp -o plot
Run the program to create the .dat file:
./plot
Save the following gnuplot script as plot.plt:
set terminal svg enhanced size 1000 1000 fname "Times" fsize 36
set output "plot.svg"
set title "A simple plot of x^2 vs. x"
set xlabel "x"
set ylabel "y"
plot "./data.dat" using 1:2 title ""
Run the script with gnuplot to generate your .svg file:
gnuplot plot.plt
The resulting plot will be in plot.svg. If you leave out the first couple lines that specify the output, it will render in a window. Have fun!
Sometimes it is as easy as one may think
gnuplot file
where file is neither your data nor your result file, but a file with the command you would type in the commandline. Just enter there your commands you need (either constant file you have or generate it).
After executing all commands in that file gnuplot exits.
Yes you can. You can make a file that has the commands you would otherwise type in to set up the plot and open gnuplot running from that file. This link has an article that explains how to do it. You can also output to an EPS or other graphical output formats and display the plot using another widget that reads in the file.
You may need to use the '-persist' flag to the command. I know that on *nix systems, this flag is required if you want the plot window to remain after the gnuplot process has completed and exited.
gnuplot -persist commands.gp
Also, you can put as many gnuplot commands as you like in the file. The file acts sort of like a batch script in this regard.
You might need to add a line
pause -1
This will show the plot until return has been pressed.
What you are probably seeing is that gnuplot runs and exits before the plot has time to be displayed.
You might need to set a terminal type. Read the gnuplot documentation about that.