Perhaps I'm going about this all wrong, but I'm trying to get all the matches in a string for a particular regex pattern. I'm using re-matcher to get a Match object, which I pass to re-find, giving me (full-string-match, grouped-text) pairs. How would I get a sequence of all the matches produced by the Match object?
In Clojuresque Python, it would look like:
pairs = []
match = re-matcher(regex, line)
while True:
pair = re-find(match)
if not pair: break
pairs.append(pair)
Any suggestions?
You probably want to use the built in re-seq and Clojure's built in regex literal. Don't mess with underlying java objects unless you really have too.
(doc re-seq)
clojure.core/re-seq
([re s])
Returns a lazy sequence of successive matches of pattern in string,
using java.util.regex.Matcher.find(), each such match processed with
re-groups.
For example:
user> (re-seq #"the \w+" "the cat sat on the mat")
("the cat" "the mat")
In answer to the follow-up comment, group captures will result in a vector of strings with an element for each part of the group in a match:
user> (re-seq #"the (\w+(t))" "the cat sat on the mat")
(["the cat" "cat" "t"] ["the mat" "mat" "t"])
You can extract a specific element by taking advantage of the elegant fact that vectors are functions of their indices.
user> (defn extract-group [n] (fn [group] (group n)))
#'user/extract-group
user> (let [matches (re-seq #"the (\w+(t))" "the cat sat on the mat")]
(map (extract-group 1) matches))
("cat" "mat")
Or you can destructure the matches (here using a for macro to go over all the matches but this could also be done in a let or function argument binding):
user> (dorun
(for [[m1 m2 m3] (re-seq #"the (\w+(t))" "the cat sat on the mat")]
(do (println "m1:" m1)
(println "m2:" m2)
(println "m3:" m3))))
m1: the cat
m2: cat
m3: t
m1: the mat
m2: mat
m3: t
Related
I am looking for better ways to check if two strings are equal in Clojure!
Given a map 'report' like
{:Result Pass}
, when I evaluate
(type (:Result report))
I get : Java.Lang.String
To write a check for the value of :Result, I first tried
(if (= (:Result report) "Pass") (println "Pass"))
But the check fails.
So I used the compare method, which worked:
(if (= 0 (compare (:Result report) "Pass")) (println "Pass"))
However, I was wondering if there is anything equivalent to Java's .equals() method in Clojure. Or a better way to do the same.
= is the correct way to do an equality check for Strings. If it's giving you unexpected results, you likely have whitespace in the String like a trailing newline.
You can easily check for whitespace by using vec:
(vec " Pass\n")
user=> [\space \P \a \s \s \newline]
As #Carcigenicate wrote, use = to compare strings.
(= "hello" "hello")
;; => true
If you want to be less strict, consider normalizing your string before you compare. If we have a leading space, the strings aren't equal.
(= " hello" "hello")
;; => false
We can then define a normalize function that works for us.
In this case, ignore leading and trailing whitespace and
capitalization.
(require '[clojure.string :as string])
(defn normalize [s]
(string/trim
(string/lower-case s)))
(= (normalize " hellO")
(normalize "Hello\t"))
;; => true
Hope that helps!
I am trying to replace bad characters from a input string.
Characters should be valid UTF-8 characters (tabs, line breaks etc. are ok).
However I was unable to figure out how to replace all found bad characters.
My solution works for the first bad character.
Usually there are none bad characters. 1/50 cases there is one bad character. I'd just want to make my solution foolproof.
(defn filter-to-utf-8-string
"Return only good utf-8 characters from the input."
[input]
(let [bad-characters (set (re-seq #"[^\p{L}\p{N}\s\p{P}\p{Sc}\+]+" input))
filtered-string (clojure.string/replace input (apply str (first bad-characters)) "")]
filtered-string))
How can I make replace work for all values in sequence not just for the first one?
Friend of mine helped me to find workaround for this problem:
I created a filter for replace using re-pattern.
Within let code is currently
filter (if (not (empty? bad-characters))
(re-pattern (str "[" (clojure.string/join bad-characters) "]"))
#"")
filtered-string (clojure.string/replace input filter "")
Here is a simple version:
(ns xxxxx
(:require
[clojure.string :as str]
))
(def all-chars (str/join (map char (range 32 80))))
(println all-chars)
(def char-L (str/join (re-seq #"[\p{L}]" all-chars)))
(println char-L)
(def char-N (str/join (re-seq #"[\p{N}]" all-chars)))
(println char-N)
(def char-LN (str/join (re-seq #"[\p{L}\p{N}]" all-chars)))
(println char-LN)
all-chars => " !\"#$%&'()*+,-./0123456789:;<=>?#ABCDEFGHIJKLMNO"
char-L => "ABCDEFGHIJKLMNO"
char-N => "0123456789"
char-LN => "0123456789ABCDEFGHIJKLMNO"
So we start off with all ascii chars in the range of 32-80. We first print only the letter, then only the numbers, then either letters or numbers. It seems this should work for your problem, although instead of rejecting non-members of the desired set, we keep the members of the desired set.
If I have this set
(def my-set #{"foo.clj" "bar.clj" "baz.clj"})
How can I turn it to this pattern string:
"foo\.clj|bar\.clj|baz\.clj"
My attempt :
(defn set->pattern-str [coll]
(-> (clojure.string/join "|" coll)
(clojure.string/replace #"\." "\\\\.")))
(set->pattern-str my-set)
=> "foo\\.clj|baz\\.clj|bar\\.clj" ;I get the double backslash
Better ideas?
In case your set of strings might have other metacharacters than just . in them, a more general approach is to ask the underlying java.util.regex.Pattern implementation to escape everything for us:
(import 'java.util.regex.Pattern)
(defn set->pattern-str [coll]
(->> coll
(map #(Pattern/quote %))
(clojure.string/join \|)
re-pattern))
IDEone link here. Remember, IDEone is not a REPL, and you have to tell it to put values on stdout with e.g. println before you can see them.
You were close to the final solution. Double backslash is displayed because it is shown escaped. When you turn it into a seq you will see individual characters:
(seq "foo\\.clj")
;;=> (\f \o \o \\ \. \c \l \j)
And working solution:
(def my-set #{"foo.clj" "bar.clj" "baz.clj"})
(def my-set-pattern
(-> (clojure.string/join "|" my-set)
(clojure.string/replace "." "\\.")
(re-pattern)))
(re-matches my-set-pattern "foo.clj")
;;=> "foo.clj"
(re-matches my-set-pattern "bar.clj")
;;=> "bar.clj"
(re-matches my-set-pattern "baz.clj")
;;=> "baz.clj"
(re-matches my-set-pattern "foo-clj")
;;=> nil
Edit: OK, this one does in fact work. Probably want to break it apart a bit more if it's meant to be long lived code, but this is the simplest way I could find to do it with minimal string munging.
(defn is-matching-file-name [target-string]
(re-matches
(re-pattern (clojure.string/escape (String/join "|" my-set) {\. "\\."}))
target-string))
The clojure.string/escape here takes two arguments: the string to escape, and a mapping of the characters to escape to the replacement strings. The key in this map is the literal \. and the value needs two backslashes since we want to include one backslash preceding any . in the final string to be used as the argument for the re-pattern function.
Can anybody explain what the type below is in the code below which I seen in the clojure docs for string/replace?
(clojure.string/replace "The color is red" #"red" "blue")
I am talking specifically about the #"red" "blue"
Also, if I have an array-map like this:
{"red" "blue"}
How could I transform this array-map into this unknown type?
{"red" "blue"} ;=> #"red" "blue"???
If you have a map {"red" "blue"} and you'd like to use that to drive the replacement, you could do:
;; Generic form of your question - uses re-pattern to create a regex
(defn replace-with [s find replacement]
(clojure.string/replace s (re-pattern find) replacement))
;; Walk through every [find replace] pair in replacements map
;; and repeatedly apply it to string
(defn replace-with-all [s replacements]
(reduce (fn [s [f r]] (replace-with s f r))
s
replacements))
(replace-with-all "foo bar baz" {"foo" "blue" "baz" "red"})
;; "blue bar red"
In Clojure, #"....." is a Regular Expression definition. So you are replacing red with blue.
(replace s match replacement)
Replaces all instance of match with replacement in s.
match/replacement can be:
string / string
char / char
pattern / (string or function of match).
But I didn't understand what do you mean by 'transform this array-map into this unknown type'.
I'm new to Clojure and I'm doing some basic stuff from labrepl, now I want to write a function that will replace certain letters with other letters, for example: elosska → elößkä.
I wrote this:
(ns student.dialect (:require [clojure.string :as str]))
(defn germanize
[sentence]
(def german-letters {"a" "ä" "u" "ü" "o" "ö" "ss" "ß"})
(doseq [[original-letter new-letter] german-letters]
(str/replace sentence original-letter new-letter)))
but it doesn't work as I expect. Could you help me, please?
Here is my take,
(def german-letters {"a" "ä" "u" "ü" "o" "ö" "ss" "ß"})
(defn germanize [s]
(reduce (fn[sentence [match replacement]]
(str/replace sentence match replacement)) s german-letters))
(germanize "elosska")
There are 2 problems here:
doseq doesn't preserve head of list that created by its evaluation, so you won't get any results
str/replace works on separate copies of text, producing 4 different results - you can check this by replacing doseq with for and you'll get list with 4 entries.
You code could be rewritten following way:
(def german-letters {"a" "ä" "u" "ü" "o" "ö" "ss" "ß"})
(defn germanize [sentence]
(loop [text sentence
letters german-letters]
(if (empty? letters)
text
(let [[original-letter new-letter] (first letters)]
(recur (str/replace text original-letter new-letter)
(rest letters))))))
In this case, intermediate results are collected, so all replacements are applied to same string, producing correct string:
user> (germanize "elosska")
"elößkä"
P.S. it's also not recommended to use def in the function - it's better to use it for top-level forms
Alex has of course already correctly answered the question with respect to the original issue using doseq... but I found the question interesting and wanted to see what a more "functional" solution would look like. And by that I mean without using a loop.
I came up with this:
(ns student.dialect (:require [clojure.string :as str]))
(defn germanize [sentence]
(let [letters {"a" "ä" "u" "ü" "o" "ö" "ss" "ß"}
regex (re-pattern (apply str (interpose \| (keys letters))))]
(str/replace sentence regex letters)))
Which yields the same result:
student.dialect=> (germanize "elosska")
"elößkä"
The regex (re-pattern... line simply evaluates to #"ss|a|o|u", which would have been cleaner, and simpler to read, if entered as an explicit string, but I thought it best to have only one definition of the german letters.