XSL - Removing the filename from the path string - xslt

Question

I've got a SharePoint problem which I need some help with. I'm creating some custom ItemStyles to format the output of a Content Query Webpart (CQWP) but I need to insert a "view all" button into the output.
View all needs to point to:
http://www.site.com/subsite/doclibrary1/Forms/AllItems.aspx
All the individual files in the document library have the link of:
http://www.site.com/subsite/doclibrary1/FileName.doc
So what I need is some XSL functions to strip FileName.doc from the end of the string.
I've tried using substring-before($variable, '.') to get rid of the .doc, but I then need to find a way to use substring-after to search for the LAST forward slash in the series and truncate the orphaned filename.
Using #Mads Hansen's post, this is the code which resolved the problem:
Template in ItemStyle.xsl
<xsl:template name="ImpDocs" match="Row[#Style='ImpDocs']" mode="itemstyle">
<xsl:variable name="SafeLinkUrl">
<xsl:call-template name="OuterTemplate.GetSafeLink">
<xsl:with-param name="UrlColumnName" select="'LinkUrl'"/>
</xsl:call-template>
</xsl:variable>
<xsl:variable name="ViewAllLink">
<xsl:call-template name="OuterTemplate.getCleanURL">
<xsl:with-param name="path" select="#LinkUrl"/>
</xsl:call-template>
</xsl:variable>
<div class="DocViewAll">
View All
<!--Any other code you need for your custom ItemStyle here-->
</div>
</xsl:template>
Template in ContentQueryMain.xsl
<xsl:template name="OuterTemplate.getCleanURL">
<xsl:param name="path" />
<xsl:choose>
<xsl:when test="contains($path,'/')">
<xsl:value-of select="substring-before($path,'/')" />
<xsl:text>/</xsl:text>
<xsl:call-template name="OuterTemplate.getCleanURL">
<xsl:with-param name="path" select="substring-after($path,'/')" />
</xsl:call-template>
</xsl:when>
<xsl:otherwise />
</xsl:choose>
</xsl:template>

Answer 1

Executing this stylesheet produces: http://www.site.com/subsite/doclibrary1/
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:template match="/">
<xsl:call-template name="getURL">
<xsl:with-param name="path">http://www.site.com/subsite/doclibrary1/FileName.doc</xsl:with-param>
</xsl:call-template>
</xsl:template>
<xsl:template name="getURL">
<xsl:param name="path" />
<xsl:choose>
<xsl:when test="contains($path,'/')">
<xsl:value-of select="substring-before($path,'/')" />
<xsl:text>/</xsl:text>
<xsl:call-template name="getURL">
<xsl:with-param name="path" select="substring-after($path,'/')" />
</xsl:call-template>
</xsl:when>
<xsl:otherwise />
</xsl:choose>
</xsl:template>
</xsl:stylesheet>
The getURL template makes a recursive call to itself when there are "/" characters in the string. While there are still "/" characters, it spits out the values before the slash, and then invokes itself. When it reaches the last one, it stops.

Answer 2

The given solutions are not able to handle url's without filename and extension at the end (Path to folder)
I changed the ideas above to include this aswell...
<xsl:template name="getPath">
<xsl:param name="url" />
<xsl:choose>
<xsl:when test="contains($url,'/')">
<xsl:value-of select="substring-before($url,'/')" />
<xsl:text>/</xsl:text>
<xsl:call-template name="getPath">
<xsl:with-param name="url" select="substring-after($url,'/')" />
</xsl:call-template>
</xsl:when >
<xsl:otherwise>
<xsl:if test="not(contains($url,'.'))">
<xsl:value-of select="$url" />
</xsl:if>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
Btw. Why does MS still not support XSLT 2.0!, i saw people complainin bout that back in 2007 -.-'

Answer 3

If you are using XSLT 2.0 (or more specifically, XPath 2.0), then you should be able to use the replace function, using a regular expression to capture the substring before the last "/":
http://www.w3.org/TR/xpath-functions/#func-replace
Unfortunately, "replace" did not exist in XSLT 1.0, so it depends on what XSLT processor you are using as to whether this will work for you.

Answer 4

This stylesheet:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="url">
<xsl:variable name="vReverseUrl">
<xsl:call-template name="reverse"/>
</xsl:variable>
<xsl:call-template name="reverse">
<xsl:with-param name="pString"
select="substring-after($vReverseUrl,'/')"/>
</xsl:call-template>
</xsl:template>
<xsl:template name="reverse">
<xsl:param name="pString" select="."/>
<xsl:if test="$pString">
<xsl:call-template name="reverse">
<xsl:with-param name="pString" select="substring($pString,2)"/>
</xsl:call-template>
<xsl:value-of select="substring($pString,1,1)"/>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
With this input:
<url>http://www.site.com/subsite/doclibrary1/FileName.doc</url>
Output:
http://www.site.com/subsite/doclibrary1
One line XPath 2.0:
string-join(tokenize(url,'/')[position()!=last()],'/')

Answer 5

See my answer to this question and use the same technique (#Alejandro's answer essentially copies this).