How do I redefine functions in python? - django

I got a function in a certain module that I want to redefine(mock) at runtime for testing purposes. As far as I understand, function definition is nothing more than an assignment in python(the module definition itself is a kind of function being executed). As I said, I wanna do this in the setup of a test case, so the function to be redefined lives in another module. What is the syntax for doing this?
For example, 'module1' is my module and 'func1' is my function, in my testcase I have tried this (no success):
import module1
module1.func1 = lambda x: return True

import module1
import unittest
class MyTest(unittest.TestCase):
def setUp(self):
# Replace othermod.function with our own mock
self.old_func1 = module1.func1
module1.func1 = self.my_new_func1
def tearDown(self):
module1.func1 = self.old_func1
def my_new_func1(self, x):
"""A mock othermod.function just for our tests."""
return True
def test_func1(self):
module1.func1("arg1")
Lots of mocking libraries provide tools for doing this sort of mocking, you should investigate them as you will likely get a good deal of help from them.

import foo
def bar(x):
pass
foo.bar = bar

Just assign a new function or lambda to the old name:
>>> def f(x):
... return x+1
...
>>> f(3)
4
>>> def new_f(x):
... return x-1
...
>>> f = new_f
>>> f(3)
2
It works also when a function is from another module:
### In other.py:
# def f(x):
# return x+1
###
import other
other.f = lambda x: x-1
print other.f(1) # prints 0, not 2

Use redef: http://github.com/joeheyming/redef
import module1
from redef import redef
rd_f1 = redef(module1, 'func1', lambda x: True)
When rd_f1 goes out of scope or is deleted, func1 will go back to being back to normal

If you want to reload into the interpreter file foo.py that you are editing, you can make a simple-to-type function and use execfile(), but I just learned that it doesn't work without the global list of all functions (sadly), unless someone has a better idea:
Somewhere in file foo.py:
def refoo ():
global fooFun1, fooFun2
execfile("foo.py")
In the python interpreter:
refoo() # You now have your latest edits from foo.py

Related

`setattr()` on Python2 `_sre.SRE_Pattern`

I'm basically attempting py2/3 compatibility by trying to add a a fullmatch method to Python2 re compiled patterns.
I've seen https://stackoverflow.com/a/2982/2694385 on how to add an attribute to an existing instance.
I'm creating the method as given in https://stackoverflow.com/a/30212799/2694385.
Example code
import re
import six
regex = re.compile('some pattern') # Better if we keep this same
if six.PY2:
def fullmatch(self_regex, string, flags=0):
return self_regex.match(string, flags=flags)
regex = re.compile(r'(?:' + regex.pattern + r')\Z', flags=regex.flags)
import types
bound = types.MethodType(fullmatch, regex)
# AttributeError here. None of the following three lines work
regex.fullmatch = bound
regex.__setattr__('fullmatch', bound)
setattr(regex, 'fullmatch', bound)
That ain't gonna work - regex objects are created on the C side and they don't represent your regular instances so you cannot modify their signature from within Python. For example, if you try to extend _sre.SRE_Pattern:
import _sre
class CustomPattern(_sre.SRE_Pattern): pass
You'll get an AttributeError complaining that such object doesn't exist in the _sre module. If you try to cheat it with:
import re
tmp_pattern = re.compile("")
sre_pat = type(tmp_pattern)
class CustomPattern(sre_pat): pass
it will give you a TypeError complaining that _sre.SRE_Pattern (which now 'temporarily' exists as it's being created ad-hoc) is not an acceptable base type.
What you can do instead is to create a full wrapper around the re module (or at least add the missing structures to it) and handle the Python version differences on the Python's side, although I think it's just not worth it.
P.S. If you're not using six anywhere else, there no reason for the overhead just to check your Python version - you can use sys.version_info.major < 3 instead.
See nlpia.regexes.Pattern for something similar to what you want -- a Frankenstein mashup of _sre.Pattern with a fullmatch() method. This monkey-patching "inheritance" approach works in Python 2 and 3.
import re
import regex
class Pattern:
""" "Inherits" _sre.SRE_Pattern and adds .fullmatch() method
>>> pattern = Pattern('Aaron[ ]Swartz')
>>> pattern.match('Aaron Swartz')
<_sre.SRE_Match object; span=(0, 12), match='Aaron Swartz'>
>>> pattern.fullmatch('Aaron Swartz!!')
>>> pattern.match('Aaron Swartz!!')
<_sre.SRE_Match object; span=(0, 12), match='Aaron Swartz'>
"""
def __init__(self, pattern):
self._compiled_pattern = re.compile(pattern)
for name in dir(self._compiled_pattern):
if not name in set(('__class__', '__init__', 'fullmatch')):
attr = getattr(self._compiled_pattern, name)
setattr(self, name, attr)
def fullmatch(self, *args, **kwargs):
return regex.fullmatch(self._compiled_pattern.pattern, *args, **kwargs)

python3 mock.assert_called_once_with on changing list [duplicate]

Consider example:
def func_b(a):
print a
def func_a():
a = [-1]
for i in xrange(0, 2):
a[0] = i
func_b(a)
And test function that tries to test func_a and mocks func_b:
import mock
from mock import call
def test_a():
from dataTransform.test import func_a
with mock.patch('dataTransform.test.func_b', autospec=True) as func_b_mock:
func_a()
func_b_mock.assert_has_calls([call(0), call(1)])
After func_a has executed I try to test if func_a made correct calls to func_b, but since in for loop I am mutating list in the end I get:
AssertionError: Calls not found.
Expected: [call(0), call(1)]
Actual: [call([1]), call([1])]
The following works (the importing mock from unittest is a Python 3 thing, and module is where func_a and func_b are):
import mock
from mock import call
import copy
class ModifiedMagicMock(mock.MagicMock):
def _mock_call(_mock_self, *args, **kwargs):
return super(ModifiedMagicMock, _mock_self)._mock_call(*copy.deepcopy(args), **copy.deepcopy(kwargs))
This inherits from MagicMock, and redefines the call behaviour to deepcopy the arguments and keyword arguments.
def test_a():
from module import func_a
with mock.patch('module.func_b', new_callable=ModifiedMagicMock) as func_b_mock:
func_a()
func_b_mock.assert_has_calls([call([0]), call([1])])
You can pass the new class into patch using the new_callable parameter, however it cannot co-exist with autospec. Note that your function calls func_b with a list, so call(0), call(1) has to be changed to call([0]), call([1]). When run by calling test_a, this does nothing (passes).
Now we cannot use both new_callable and autospec because new_callable is a generic factory but in our case is just a MagicMock override. But Autospeccing is a very cool mock's feature, we don't want lose it.
What we need is replace MagicMock by ModifiedMagicMock just for our test: we want avoid to change MagicMock behavior for all tests... could be dangerous. We already have a tool to do it and it is patch, used with the new argument to replace the destination.
In this case we use decorators to avoid too much indentation and make it more readable:
#mock.patch('module.func_b', autospec=True)
#mock.patch("mock.MagicMock", new=ModifiedMagicMock)
def test_a(func_b_mock):
from module import func_a
func_a()
func_b_mock.assert_has_calls([call([0]), call([1])])
Or:
#mock.patch("mock.MagicMock", new=ModifiedMagicMock)
def test_a():
with mock.patch('module.func_b') as func_b_mock:
from module import func_a
func_a()
func_b_mock.assert_has_calls([call([0]), call([1])])

IronPython strange method calling

Why does calling a method like this in ironPython work?:
from System.Collections.Generic import List
class test:
mem = None
def __init__(self):
# !No Instance created !!!
self.mem = List[int]
def doSomeThing(self):
if self.mem.Contains((List[int](), 123):
pass
I can't get the behaviour of IronPython in this case: self.mem.Contains((List[int](), 123):. Does any one has an explanation for this?
EDIT
Is self.mem only the type, and Contains will always return False? If this is true, it seems to be a nice feature :)
Thank you!
This is true of normal Python classes as well:
class Foo(object):
def bar(self):
pass
f = Foo
f.bar(Foo())
It's the difference between bound (Foo().bar) and unbound (Foo.bar) methods. It's not so much a feature as a side effect of how methods are implemented in Python.
Contains is always false because it is working on an empty list, which contains nothing.

What is the # doing in the following code? [duplicate]

What does the # symbol do in Python?
An # symbol at the beginning of a line is used for class and function decorators:
PEP 318: Decorators
Python Decorators
The most common Python decorators are:
#property
#classmethod
#staticmethod
An # in the middle of a line is probably matrix multiplication:
# as a binary operator.
Example
class Pizza(object):
def __init__(self):
self.toppings = []
def __call__(self, topping):
# When using '#instance_of_pizza' before a function definition
# the function gets passed onto 'topping'.
self.toppings.append(topping())
def __repr__(self):
return str(self.toppings)
pizza = Pizza()
#pizza
def cheese():
return 'cheese'
#pizza
def sauce():
return 'sauce'
print pizza
# ['cheese', 'sauce']
This shows that the function/method/class you're defining after a decorator is just basically passed on as an argument to the function/method immediately after the # sign.
First sighting
The microframework Flask introduces decorators from the very beginning in the following format:
from flask import Flask
app = Flask(__name__)
#app.route("/")
def hello():
return "Hello World!"
This in turn translates to:
rule = "/"
view_func = hello
# They go as arguments here in 'flask/app.py'
def add_url_rule(self, rule, endpoint=None, view_func=None, **options):
pass
Realizing this finally allowed me to feel at peace with Flask.
In Python 3.5 you can overload # as an operator. It is named as __matmul__, because it is designed to do matrix multiplication, but it can be anything you want. See PEP465 for details.
This is a simple implementation of matrix multiplication.
class Mat(list):
def __matmul__(self, B):
A = self
return Mat([[sum(A[i][k]*B[k][j] for k in range(len(B)))
for j in range(len(B[0])) ] for i in range(len(A))])
A = Mat([[1,3],[7,5]])
B = Mat([[6,8],[4,2]])
print(A # B)
This code yields:
[[18, 14], [62, 66]]
This code snippet:
def decorator(func):
return func
#decorator
def some_func():
pass
Is equivalent to this code:
def decorator(func):
return func
def some_func():
pass
some_func = decorator(some_func)
In the definition of a decorator you can add some modified things that wouldn't be returned by a function normally.
What does the “at” (#) symbol do in Python?
In short, it is used in decorator syntax and for matrix multiplication.
In the context of decorators, this syntax:
#decorator
def decorated_function():
"""this function is decorated"""
is equivalent to this:
def decorated_function():
"""this function is decorated"""
decorated_function = decorator(decorated_function)
In the context of matrix multiplication, a # b invokes a.__matmul__(b) - making this syntax:
a # b
equivalent to
dot(a, b)
and
a #= b
equivalent to
a = dot(a, b)
where dot is, for example, the numpy matrix multiplication function and a and b are matrices.
How could you discover this on your own?
I also do not know what to search for as searching Python docs or Google does not return relevant results when the # symbol is included.
If you want to have a rather complete view of what a particular piece of python syntax does, look directly at the grammar file. For the Python 3 branch:
~$ grep -C 1 "#" cpython/Grammar/Grammar
decorator: '#' dotted_name [ '(' [arglist] ')' ] NEWLINE
decorators: decorator+
--
testlist_star_expr: (test|star_expr) (',' (test|star_expr))* [',']
augassign: ('+=' | '-=' | '*=' | '#=' | '/=' | '%=' | '&=' | '|=' | '^=' |
'<<=' | '>>=' | '**=' | '//=')
--
arith_expr: term (('+'|'-') term)*
term: factor (('*'|'#'|'/'|'%'|'//') factor)*
factor: ('+'|'-'|'~') factor | power
We can see here that # is used in three contexts:
decorators
an operator between factors
an augmented assignment operator
Decorator Syntax:
A google search for "decorator python docs" gives as one of the top results, the "Compound Statements" section of the "Python Language Reference." Scrolling down to the section on function definitions, which we can find by searching for the word, "decorator", we see that... there's a lot to read. But the word, "decorator" is a link to the glossary, which tells us:
decorator
A function returning another function, usually applied as a function transformation using the #wrapper syntax. Common
examples for decorators are classmethod() and staticmethod().
The decorator syntax is merely syntactic sugar, the following two
function definitions are semantically equivalent:
def f(...):
...
f = staticmethod(f)
#staticmethod
def f(...):
...
The same concept exists for classes, but is less commonly used there.
See the documentation for function definitions and class definitions
for more about decorators.
So, we see that
#foo
def bar():
pass
is semantically the same as:
def bar():
pass
bar = foo(bar)
They are not exactly the same because Python evaluates the foo expression (which could be a dotted lookup and a function call) before bar with the decorator (#) syntax, but evaluates the foo expression after bar in the other case.
(If this difference makes a difference in the meaning of your code, you should reconsider what you're doing with your life, because that would be pathological.)
Stacked Decorators
If we go back to the function definition syntax documentation, we see:
#f1(arg)
#f2
def func(): pass
is roughly equivalent to
def func(): pass
func = f1(arg)(f2(func))
This is a demonstration that we can call a function that's a decorator first, as well as stack decorators. Functions, in Python, are first class objects - which means you can pass a function as an argument to another function, and return functions. Decorators do both of these things.
If we stack decorators, the function, as defined, gets passed first to the decorator immediately above it, then the next, and so on.
That about sums up the usage for # in the context of decorators.
The Operator, #
In the lexical analysis section of the language reference, we have a section on operators, which includes #, which makes it also an operator:
The following tokens are operators:
+ - * ** / // % #
<< >> & | ^ ~
< > <= >= == !=
and in the next page, the Data Model, we have the section Emulating Numeric Types,
object.__add__(self, other)
object.__sub__(self, other)
object.__mul__(self, other)
object.__matmul__(self, other)
object.__truediv__(self, other)
object.__floordiv__(self, other)
[...]
These methods are called to implement the binary arithmetic operations (+, -, *, #, /, //, [...]
And we see that __matmul__ corresponds to #. If we search the documentation for "matmul" we get a link to What's new in Python 3.5 with "matmul" under a heading "PEP 465 - A dedicated infix operator for matrix multiplication".
it can be implemented by defining __matmul__(), __rmatmul__(), and
__imatmul__() for regular, reflected, and in-place matrix multiplication.
(So now we learn that #= is the in-place version). It further explains:
Matrix multiplication is a notably common operation in many fields of
mathematics, science, engineering, and the addition of # allows
writing cleaner code:
S = (H # beta - r).T # inv(H # V # H.T) # (H # beta - r)
instead of:
S = dot((dot(H, beta) - r).T,
dot(inv(dot(dot(H, V), H.T)), dot(H, beta) - r))
While this operator can be overloaded to do almost anything, in numpy, for example, we would use this syntax to calculate the inner and outer product of arrays and matrices:
>>> from numpy import array, matrix
>>> array([[1,2,3]]).T # array([[1,2,3]])
array([[1, 2, 3],
[2, 4, 6],
[3, 6, 9]])
>>> array([[1,2,3]]) # array([[1,2,3]]).T
array([[14]])
>>> matrix([1,2,3]).T # matrix([1,2,3])
matrix([[1, 2, 3],
[2, 4, 6],
[3, 6, 9]])
>>> matrix([1,2,3]) # matrix([1,2,3]).T
matrix([[14]])
Inplace matrix multiplication: #=
While researching the prior usage, we learn that there is also the inplace matrix multiplication. If we attempt to use it, we may find it is not yet implemented for numpy:
>>> m = matrix([1,2,3])
>>> m #= m.T
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: In-place matrix multiplication is not (yet) supported. Use 'a = a # b' instead of 'a #= b'.
When it is implemented, I would expect the result to look like this:
>>> m = matrix([1,2,3])
>>> m #= m.T
>>> m
matrix([[14]])
What does the “at” (#) symbol do in Python?
# symbol is a syntactic sugar python provides to utilize decorator,
to paraphrase the question, It's exactly about what does decorator do in Python?
Put it simple decorator allow you to modify a given function's definition without touch its innermost (it's closure).
It's the most case when you import wonderful package from third party. You can visualize it, you can use it, but you cannot touch its innermost and its heart.
Here is a quick example,
suppose I define a read_a_book function on Ipython
In [9]: def read_a_book():
...: return "I am reading the book: "
...:
In [10]: read_a_book()
Out[10]: 'I am reading the book: '
You see, I forgot to add a name to it.
How to solve such a problem? Of course, I could re-define the function as:
def read_a_book():
return "I am reading the book: 'Python Cookbook'"
Nevertheless, what if I'm not allowed to manipulate the original function, or if there are thousands of such function to be handled.
Solve the problem by thinking different and define a new_function
def add_a_book(func):
def wrapper():
return func() + "Python Cookbook"
return wrapper
Then employ it.
In [14]: read_a_book = add_a_book(read_a_book)
In [15]: read_a_book()
Out[15]: 'I am reading the book: Python Cookbook'
Tada, you see, I amended read_a_book without touching it inner closure. Nothing stops me equipped with decorator.
What's about #
#add_a_book
def read_a_book():
return "I am reading the book: "
In [17]: read_a_book()
Out[17]: 'I am reading the book: Python Cookbook'
#add_a_book is a fancy and handy way to say read_a_book = add_a_book(read_a_book), it's a syntactic sugar, there's nothing more fancier about it.
If you are referring to some code in a python notebook which is using Numpy library, then # operator means Matrix Multiplication. For example:
import numpy as np
def forward(xi, W1, b1, W2, b2):
z1 = W1 # xi + b1
a1 = sigma(z1)
z2 = W2 # a1 + b2
return z2, a1
Decorators were added in Python to make function and method wrapping (a function that receives a function and returns an enhanced one) easier to read and understand. The original use case was to be able to define the methods as class methods or static methods on the head of their definition. Without the decorator syntax, it would require a rather sparse and repetitive definition:
class WithoutDecorators:
def some_static_method():
print("this is static method")
some_static_method = staticmethod(some_static_method)
def some_class_method(cls):
print("this is class method")
some_class_method = classmethod(some_class_method)
If the decorator syntax is used for the same purpose, the code is shorter and easier to understand:
class WithDecorators:
#staticmethod
def some_static_method():
print("this is static method")
#classmethod
def some_class_method(cls):
print("this is class method")
General syntax and possible implementations
The decorator is generally a named object ( lambda expressions are not allowed) that accepts a single argument when called (it will be the decorated function) and returns another callable object. "Callable" is used here instead of "function" with premeditation. While decorators are often discussed in the scope of methods and functions, they are not limited to them. In fact, anything that is callable (any object that implements the _call__ method is considered callable), can be used as a decorator and often objects returned by them are not simple functions but more instances of more complex classes implementing their own __call_ method.
The decorator syntax is simply only a syntactic sugar. Consider the following decorator usage:
#some_decorator
def decorated_function():
pass
This can always be replaced by an explicit decorator call and function reassignment:
def decorated_function():
pass
decorated_function = some_decorator(decorated_function)
However, the latter is less readable and also very hard to understand if multiple decorators are used on a single function.
Decorators can be used in multiple different ways as shown below:
As a function
There are many ways to write custom decorators, but the simplest way is to write a function that returns a subfunction that wraps the original function call.
The generic patterns is as follows:
def mydecorator(function):
def wrapped(*args, **kwargs):
# do some stuff before the original
# function gets called
result = function(*args, **kwargs)
# do some stuff after function call and
# return the result
return result
# return wrapper as a decorated function
return wrapped
As a class
While decorators almost always can be implemented using functions, there are some situations when using user-defined classes is a better option. This is often true when the decorator needs complex parametrization or it depends on a specific state.
The generic pattern for a nonparametrized decorator as a class is as follows:
class DecoratorAsClass:
def __init__(self, function):
self.function = function
def __call__(self, *args, **kwargs):
# do some stuff before the original
# function gets called
result = self.function(*args, **kwargs)
# do some stuff after function call and
# return the result
return result
Parametrizing decorators
In real code, there is often a need to use decorators that can be parametrized. When the function is used as a decorator, then the solution is simple—a second level of wrapping has to be used. Here is a simple example of the decorator that repeats the execution of a decorated function the specified number of times every time it is called:
def repeat(number=3):
"""Cause decorated function to be repeated a number of times.
Last value of original function call is returned as a result
:param number: number of repetitions, 3 if not specified
"""
def actual_decorator(function):
def wrapper(*args, **kwargs):
result = None
for _ in range(number):
result = function(*args, **kwargs)
return result
return wrapper
return actual_decorator
The decorator defined this way can accept parameters:
>>> #repeat(2)
... def foo():
... print("foo")
...
>>> foo()
foo
foo
Note that even if the parametrized decorator has default values for its arguments, the parentheses after its name is required. The correct way to use the preceding decorator with default arguments is as follows:
>>> #repeat()
... def bar():
... print("bar")
...
>>> bar()
bar
bar
bar
Finally lets see decorators with Properties.
Properties
The properties provide a built-in descriptor type that knows how to link an attribute to a set of methods. A property takes four optional arguments: fget , fset , fdel , and doc . The last one can be provided to define a docstring that is linked to the attribute as if it were a method. Here is an example of a Rectangle class that can be controlled either by direct access to attributes that store two corner points or by using the width , and height properties:
class Rectangle:
def __init__(self, x1, y1, x2, y2):
self.x1, self.y1 = x1, y1
self.x2, self.y2 = x2, y2
def _width_get(self):
return self.x2 - self.x1
def _width_set(self, value):
self.x2 = self.x1 + value
def _height_get(self):
return self.y2 - self.y1
def _height_set(self, value):
self.y2 = self.y1 + value
width = property(
_width_get, _width_set,
doc="rectangle width measured from left"
)
height = property(
_height_get, _height_set,
doc="rectangle height measured from top"
)
def __repr__(self):
return "{}({}, {}, {}, {})".format(
self.__class__.__name__,
self.x1, self.y1, self.x2, self.y2
)
The best syntax for creating properties is using property as a decorator. This will reduce the number of method signatures inside of the class
and make code more readable and maintainable. With decorators the above class becomes:
class Rectangle:
def __init__(self, x1, y1, x2, y2):
self.x1, self.y1 = x1, y1
self.x2, self.y2 = x2, y2
#property
def width(self):
"""rectangle height measured from top"""
return self.x2 - self.x1
#width.setter
def width(self, value):
self.x2 = self.x1 + value
#property
def height(self):
"""rectangle height measured from top"""
return self.y2 - self.y1
#height.setter
def height(self, value):
self.y2 = self.y1 + value
Starting with Python 3.5, the '#' is used as a dedicated infix symbol for MATRIX MULTIPLICATION (PEP 0465 -- see https://www.python.org/dev/peps/pep-0465/)
# can be a math operator or a DECORATOR but what you mean is a decorator.
This code:
def func(f):
return f
func(lambda :"HelloWorld")()
using decorators can be written like:
def func(f):
return f
#func
def name():
return "Hello World"
name()
Decorators can have arguments.
You can see this GeeksforGeeks post: https://www.geeksforgeeks.org/decorators-in-python/
It indicates that you are using a decorator. Here is Bruce Eckel's example from 2008.
Python decorator is like a wrapper of a function or a class. It’s still too conceptual.
def function_decorator(func):
def wrapped_func():
# Do something before the function is executed
func()
# Do something after the function has been executed
return wrapped_func
The above code is a definition of a decorator that decorates a function.
function_decorator is the name of the decorator.
wrapped_func is the name of the inner function, which is actually only used in this decorator definition. func is the function that is being decorated.
In the inner function wrapped_func, we can do whatever before and after the func is called. After the decorator is defined, we simply use it as follows.
#function_decorator
def func():
pass
Then, whenever we call the function func, the behaviours we’ve defined in the decorator will also be executed.
EXAMPLE :
from functools import wraps
def mydecorator(f):
#wraps(f)
def wrapped(*args, **kwargs):
print "Before decorated function"
r = f(*args, **kwargs)
print "After decorated function"
return r
return wrapped
#mydecorator
def myfunc(myarg):
print "my function", myarg
return "return value"
r = myfunc('asdf')
print r
Output :
Before decorated function
my function asdf
After decorated function
return value
To say what others have in a different way: yes, it is a decorator.
In Python, it's like:
Creating a function (follows under the # call)
Calling another function to operate on your created function. This returns a new function. The function that you call is the argument of the #.
Replacing the function defined with the new function returned.
This can be used for all kinds of useful things, made possible because functions are objects and just necessary just instructions.
# symbol is also used to access variables inside a plydata / pandas dataframe query, pandas.DataFrame.query.
Example:
df = pandas.DataFrame({'foo': [1,2,15,17]})
y = 10
df >> query('foo > #y') # plydata
df.query('foo > #y') # pandas

How do I import a variable when defined in a method

My simple code works like this:
In my_stuffmodule1.py, I have the following:
import sys
def main():
result = 'found stuff here'
return result
if __name__ == '__main__':
main()
I want to use the result returned from my_stuffmodule1 in my next module below, called my_stuffmodule2:
import my_stuffmodule1
result
class Use_stuff(object):
def stuff1(self):
for item in result:
code..
def stuff2(self):
code...
BUT I get errors such as 'result is not defined'. I want to use the items in the result string in my_stuffmodule2
As result is defined in my_stuffmodule1.main, it is only visible inside main(), once you call main(), it will be returned.
So in your second module, you need to do this:
import my_stuffmodule1
result = my_stuffmodule1.main()
Now you'll have the value of result in your second module. If you don't want to do this, then in your first module, you need to make sure main() is called when the module is evaluated (when its imported). To do that, you'll need to put a call to main in the global scope, like this:
def main():
return 'result found here'
result = main()
Now, when you import the module, main() will be called and you can do this:
import my_stuffmodule1
result = my_stuffmodule1.result
Note that you still have to use my_stuffmodule1.result because you are importing the module directly. If you just want to have result shown, you could do this:
from my_stuffmodule1 import result
However, keep in mind that this will overwrite any other result you might have in your second module. Therefore, its better to import the module, then qualify the name with my_stuffmodule1.result.
At a guess, I'd say it's because you're importing the first file, and the result string is only getting set when it's run in the context of 'main'. Also, you are returning the result variable - that variable is being defined within the scope of the main() function, and not in a 'global' scope, as it were.
If you were to simply set the variable result outside of the main() function, does that work?
Alternatively, set the value of result to the return value of the main() function, in the second script.
Below is a working example of the second option..
my_stuffmodule1
import sys
def main():
result = 'found stuff here'
return result
if __name__ == '__main__':
main()
my_stuffmodule2
import my_stuffmodule1
result = my_stuffmodule1.main()
class Use_stuff(object):
def stuff1(self):
for item in result:
code..
def stuff2(self):
code...
if you want the result from the main method of my_stuffmodule1 then you will need to execute that modules main method, in this case.
for example
import my_stuffmodule1
result = my_stuffmodule1.main()
class Use_stuff(object):
def stuff1(self):
for item in result:
code..
def stuff2(self):
code...