Except URL regex - regex

Question

Sigh, regex trouble again.
I have following in $text:
[img]http://www.site.com/logo.jpg[/img]
and
[url]http://www.site.com[/url]
I have regex expression:
$text = preg_replace("/(?<!(\[img\]|\[url\]))([http|ftp]+:\/\/)?\S+[^\s.,>)\];'\"!?]\.+[com|ru|net|ua|biz|org]+\/?[^<>\n\r ]+[A-Za-z0-9](?!(\[\/img\]|\[\/url\]))/","there was link",$text);
The point is to replace url only if it's not preceded by [img] or [url] and not followed by [/img] or [/url]. On the output of previous example I get:
there was link
and
there was link
Both, URL and lookbehind and lookforward regexps are working fine separately.
$text = "[img]bash.org/logo.jpg[/img]";
$text = preg_replace("/(?<!(\[img\]|\[url\]))bash.org(?!(\[\/img\]|\[\/url\]))/","there was link",$text);
echo $text leaves everything as is and gives me [img]bash.org/logo.jpg[/img]
I suppose the problem is in combination of lookarounds and URL regex. Where's my mistake?
I WANT TO
replace http://www.google.com with "there was link", but leave as is "[url]http://www.google.com[/url]"
I'M GETTING
http://www.google.com replaced with "there was link" and [url]http://www.google.com[/url] replaced with "there was link"
HERE'S PHP CODE TO TEST
<?php
$text = "[url]http://www.google.com[/url] <br><br> http://www.google.com";
// should NOT be changed //should be changed
$text = preg_replace("/(?<!\[url\])([http|ftp]+:\/\/)?\S+[^\s.,>)\];'\"!?]\.+[com|ru|net|ua|biz|org]+\/?[^<>\n\r ]+[A-Za-z0-9](?!\[\/url\])/","there was link",$text);
echo $text;
echo '<hr width="100%">';
$text = ":) :-) 0:) 0:-) :)) :-))";
$text = preg_replace("/(?<!0):-?\)(?!\))/","smiley",$text);
echo $text; // lookarounds work
echo '<hr width="100%">';
$text = "http://stackoverflow.com/questions/2482921/regexp-exclusion";
$text = preg_replace("/([http|ftp]+:\/\/)?\S+[^\s.,>)\];'\"!?]\.+[com|ru|net|ua|biz|org]+\/?[^<>\n\r ]+[A-Za-z0-9]/","it's a link to stackoverflow",$text);
echo $text; // URL pattern works fine
?>

Answer 1

Assuming I'm understanding you, you wish to replace all URLs in your $input, with the words 'link was here', unless the URL was within either the url or img bbcode tags. The reason the lookaround assertions aren't working is because those parts are actually matching against your very greedy URL pattern (which I'm fairly sure does lots of things you don't mean it to). Writing a pattern that will match any valid URL (including query string) within other text and that will also not match the tags attached to it is not necessarily the simplest of matters. Especially since your current pattern has the http:// or ftp:// as optional.
The only way you are likely to gain any success is to decide on a strict set of rules that constitute a url.

Answer 2

It is tough to fully understand your question, but it looks like you're doing reverse BBcode. So, leave it alone if it's surrounded by tags? If that is the case, then I think you will have an interesting problem on your hands because URL regexes are notoriously complex.
I think you may be making this more complex than it needs to be. Instead, I would change anything that is between the BBcode. Here's what I think needs to happen:
find the string segment "[url]"
capture anything that proceeds it
end the capture when the string segment "[/url]" is seen
That is an easy regex:
$string = "[url]http://www.google.com[/url] <br><br> http://www.google.com";
$replace = "there was link";
$text = preg_replace_all($regex,$replace,$text);
echo $text;
I know this isn't exactly what you asked for (in fact, probably the exact opposite), but it would achieve the same result and be much easier.
You can probably try using negative lookaheads with this regex, but I am not sure it would give you proper results:
$regex = "#(?!\[url\])(.*)(?!\[/url\])#";
One important note: This does not sanitize user input. Make sure you do this, but I would separate the logic so it is very easy to see what you are doing and where you are doing it. I would also use a library to do this because it's easier and probably safer.

Answer 3

Final working regexp looks like:
(?<!\[img\]|\[url\])((^|\s)([\w-]+://|www[.])[^\s()<>]+(?:\([\w\d]+\)|([^[:punct:]\s]|/)))(?!\[\/img\]|\[/url\])
Example:
<?php
$text = "
[img]http://google.com/logo.jpg[/img]
[img]www.google.com/logo.jpg[/img]
[img]http://www.google.com/logo.jpg[/img]
[url]http://google.com/logo.jpg[/url]
[url]www.google.com/logo.jpg[/url]
[url]http://www.google.com/logo.jpg[/url]
www.google.com/logo.jpg
http://google.com/logo.jpg
http://www.google.com/logo.jpg
";
$text = nl2br($text);
$text = preg_replace("'(?<!\[img\]|\[url\])((^|\s)([\w-]+://|www[.])[^\s()<>]+(?:\([\w\d]+\)|([^[:punct:]\s]|/)))(?!\[\/img\]|\[/url\])'i","<font color=\"#ff0000\">link</font>",$text);
echo $text;
?>
outputs:
[img]http://google.com/logo.jpg[/img]
[img]www.google.com/logo.jpg[/img]
[img]http://www.google.com/logo.jpg[/img]
[url]http://google.com/logo.jpg[/url]
[url]www.google.com/logo.jpg[/url]
[url]http://www.google.com/logo.jpg[/url]
link
link
link
The trick is to replace only links starting with ^ or \s . No other way to solve this issue wasn't found.

Answer 4

Where's my mistake?
Well, the worst mistake is the lookbehind. It isn't needed, and it's making the job much harder than it needs to be. Assuming the existing tags are well formed, you needn't bother looking for the opening tag; its presence is implied by the presence of the closing tag.
EDIT: Your regex has several other problems besides the lookbehind, but it didn't seem worthwhile to try and fix it. Instead, I grabbed a regex from RegexBuddy's built-in library of useful regexes, and added the lookahead to it.
Try this regex (or see it in action on ideone):
'_\b(?>
(?>www\.|ftp\.|(?:https?|ftp|file)://) # scheme or subdomain
[-+&##/%=~|$?!:,.\w]*[+&##/%=~|$\w] # everything else
)(?!\[/(?:img|url)\])
_x'
Just because a problem can be described in terms of looking forward or backward, preceding or following, etc., doesn't mean you should design the regex that way. Lookbehind in particular should never be the first tool you reach for.