Can I insert one variable into other variable in Xsl? - xslt

<xsl:variable name="id">
<idNum>0607V45621014F</idNum>
</xsl:variable>
<xsl:variable name="pathId" select="Orders/Order[ORD_Num='$id/idNum']"/>
....not select the idNum
an other..not..
<xsl:variable name="XmlFile" select="YG.xml"/>
<xsl:value-of select="document($XmlFile)/aziende/azienda/ragione_sociale"/>
or other...not..
<xsl:variable name="tagName" select="aziende"/>
<xsl:value-of select="document($XmlFile)/$tagName/azienda/ragione_sociale"/>

1)
<xsl:variable name="pathId" select="Orders/Order[ORD_Num='$id/idNum']"/>
You are saying: An Order element wich has at least one ORD_Num child with string value equal to '$id/idNum'.
Replace with:
<xsl:variable name="pathId" select="Orders/Order[ORD_Num=$id]"/>
Because the string value of $id variable (a Result Tree Fragment as you define) is 0607V45621014F.
Note: It would be better if you define $id as a string like select="'0607V45621014F'". Also, you can't (in XSLT 1.0) do: [ORD_Num=$id/idNum] because / operator can't be apply to a RTF.
2)
<xsl:variable name="XmlFile" select="YG.xml"/>
<xsl:value-of select="document($XmlFile)/aziende/azienda/ragione_sociale"/>
Here, you are saying: Let be $XmlFile a node set with all YG.xml elements childs of context node, etc.
Replace (if you want a document with relative uri YG.xml)
<xsl:variable name="XmlFile" select="'YG.xml'"/>
Note: this does not trought an error because document() is very versatile (It's the few ones that take an object as param)
3)
<xsl:variable name="tagName" select="aziende"/>
<xsl:value-of select="document($XmlFile)/$tagName/azienda/ragione_sociale"/>
This does not work because the right expresion of / must be a path (In XSLT 2.0 can be a function as well).
Replace with:
<xsl:variable name="tagName" select="document($XmlFile)/aziende"/>
<xsl:value-of select="$tagName/azienda/ragione_sociale"/>
Or
<xsl:variable name="tagName" select="'aziende'"/>
<xsl:value-of select="document($XmlFile)/*[name()=$tagName]/azienda/ragione_sociale"/>

Related

Populate a variable with a subtree

in a version="2.0" stylesheet:
the following code produces the correct output
<xsl:variable name="obj">
<xsl:choose>
<xsl:when test="t:ReferencedObjectType='Asset'">
<xsl:value-of select="/t:Flow/t:FHeader/t:Producer/t:Repository" />
</xsl:when>
</xsl:choose>
</xsl:variable>
<xsl:choose>
<xsl:value-of select="$obj"/>
but this one does not
<xsl:variable name="obj">
<xsl:choose>
<xsl:when test="t:ReferencedObjectType='Asset'">
<xsl:value-of select="/t:Flow/t:FHeader/t:Producer" />
</xsl:when>
</xsl:choose>
</xsl:variable>
<xsl:choose>
<xsl:value-of select="$obj/t:Repository"/>
How can I get the second code to run as expected ?
If needed, is there a solution in v3 ?
this code does not run either
<xsl:variable name="obj">
<xsl:choose>
<xsl:when test="t:ReferencedObjectType='Asset'">
<xsl:copy-of select="/t:Flow/t:FHeader/t:Producer" />
</xsl:when>
</xsl:choose>
</xsl:variable>
<xsl:choose>
<xsl:value-of select="$obj/t:Repository"/>
relevant xml input
<Flow>
<FHeader>
<Producer>
<Repository>tests.com</Repository>
</Producer>
</FHeader>
</Flow>
You can simply select <xsl:variable name="obj" select="/t:Flow/t:FHeader/t:Producer/t:Repository[current()/t:ReferencedObjectType='Asset']"/>. Or, as Tim already commented, use xsl:copy-of, also taking into account that you then later on need e.g. $obj/t:Producer/t:Repository to select the right level.
Or learn about the as attribute and use e.g. <xsl:variable name="obj" as="element()*">...<xsl:copy-of select="/t:Flow/t:FHeader/t:Producer"/> ...</xsl:variable>, then you later on can use e.g. $obj/t:Repository.
There is also xsl:sequence to select input nodes instead of copying them, in particular with xsl:variable if you use the as attribute. This might consume less memory.
Furthermore XPath 2 and later have if (condition-expression) then expression else expression conditional expressions at the expression level so you might not need XSLT with xsl:choose/xsl:when but could use the <xsl:variable name="obj" select="if (t:ReferencedObjectType='Asset']) then /t:Flow/t:FHeader/t:Producer else if (...) then ... else ()"/>, that way you would select e.g. an input t:Producer element anyway and if you use the variable you can directly select the t:Repository child.

XSLT to convert elements in a concatenated line

I have this situation:
Two variables:
<xsl:variable name="varDep" select="DepAir"/>
<xsl:variable name="varArr" select="ArrAir"/>
Value of variables:
<testa>
<DepAir>SDU</DepAir>
<DepAir>CGH</DepAir>
</testa>
<testb>
<ArrAir>CGH</ArrAir>
<ArrAir>SDU</ArrAir>
</testb>
And I need transform in a concatenated line, like this:
<db:P_IAT>SDU;CGH;CGH;SDU;</db:P_IAT>
How can I do that?
Kind dynamic way will be to put loop for DepAir and ArrAir inside above variables as below:
<xsl:variable name="varDep">
<xsl:for-each select="//DepAir">
<xsl:value-of select="concat(., ';')"/>
</xsl:for-each>
</xsl:variable>
<xsl:variable name="varArr">
<xsl:for-each select="//ArrAir">
<xsl:value-of select="concat(., ';')"/>
</xsl:for-each>
</xsl:variable>
And then use concat inside required node:
<required_node><xsl:value-of select="concat($varDep, $varArr)"/></required_node>
Note! In next questions please put your XSL (what you have tried) to avoid "Down Votes". Hope it will help in your case.

xslt assigning variable value to string literal

I have
<xsl:for-each select="ancestor-or-self::*">
<xsl:variable name="expression" select="name()" ></xsl:variable>
</xsl:for-each>
below I have href and i want to set the value this expression variable in href #######
Delete
I also tried with :
Delete
None of them worked.
Can Anybody help me out how to do that?
Basically my task is to find the expression for current node and send the expression for the same in href?
Adding More Info :
<br/><xsl:for-each select="ancestor-or-self::*">
<xsl:variable name="expression" select="name()" />
</xsl:for-each>
<b>Click Me</b>
when above xsl code is transformed it is giving below error:
Variable or parameter 'expression' is undefined.
In XSLT1.0, you could try setting the variable like so:
<xsl:variable name="expression">
<xsl:for-each select="ancestor-or-self::*">
<xsl:text>/</xsl:text>
<xsl:variable name="name" select="name()"/>
<xsl:value-of select="$name"/>
</xsl:for-each>
</xsl:variable>
So, assuming the following XML structure
<As>
<a>
<Bs>
<b>5</b>
</Bs>
</a>
<a>
<Bs>
<b>9</b>
</Bs>
</a>
<a/>
<a>
<Bs>
<b>12</b>
<b>14</b>
<b>15</b>
</Bs>
</a>
</As>
If you were positioned on the b element with the value of 14, then expression would be set to /As/a/Bs/b
However, this does not take into account multiple nodes with the same name, and so would not be sufficient if you wanted accurate XPath to select the node.
Instead, you could try the following:
<xsl:variable name="expression">
<xsl:for-each select="ancestor-or-self::*">
<xsl:text>/</xsl:text>
<xsl:variable name="name" select="name()"/>
<xsl:value-of select="$name"/>
<xsl:text>[</xsl:text>
<xsl:value-of select="count(preceding-sibling::*[name() = $name]) + 1"/>
<xsl:text>]</xsl:text>
</xsl:for-each>
</xsl:variable>
This would return /As[1]/a[4]/Bs[1]/b[2], which may be what you want.
Very simply, variables are scoped in XSL and exist only within the containing tag. Thus the variable named expression exists only within the for-each block. Also, variables can only be set once. Attempting to set a variable value a second time has no effect.
Therfore you have to declare the variable at or above the level where you want to use it, and put all the code to generate the value inside the variable declaration. If you can use XSLT2, the following will do what you want:
string-join(for $n in ancestor-or-self::* return name($n), '/')
I know it can also be done in XSLT 1 with a recursive template, but I don't have an example handy.

How to store the current path in xsl?

I would like to store the path of the current node so I can reused it in an expression in XSLT. Is it possible?
<!-- . into $path? -->
<xsl:value-of select="$path" />
Hi, I would like to store the path of
the current node so I can reused it in
an expression in XSLT. Is it possible?
It is possible for any given node to construct an XPath expression that, when evaluated, selects exactly this node. In fact more than one XPath expression exists that selects the same node.
See this answer for the exact XSLT code that constructs such an XPath expression.
The problem is that this XPath expression cannot be evaluated during the same transformation in XSLT 1.0 or XSLT 2.0, unless the EXSLT extension function dyn:evaluate is used (and very few XSLT 1.0 processors implement dyn:evaluate() ).
What you want can be achieved in an easier way in XSLT using the <xsl:variable> instruction:
<xsl:variable name="theNode" select="."/>
This variable can be referenced anywhere in its scope as $theNode, and can be passed as parameter when applying or calling templates.
No, this is not possible with vanilla XSLT 1.0. There is no easy way to retrieve an XPath expression string for a given node, and there is definitely no way to evaluate a string that looks like XPath as if it was XPath.
There are extensions that support dynamic evaluation of XPath expressions, but these are not compatible with every XSLT processor.
In any case, if you provide more detail around what you are actually trying to do, there might be another way to do it.
As #Dimitre and #Tomalak have point out, I don't think it has some value in the same transformation to obtain a string representing an XPath expression for a given node, and then select the node "parsing" such string. I could see some value in performing those operations in different transformations.
Besides that, this stylesheet:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes"/>
<xsl:template match="/">
<xsl:for-each select=".|//node()|//#*">
<xsl:variable name="vPath">
<xsl:apply-templates select="." mode="getPath"/>
</xsl:variable>
<xsl:value-of select="concat($vPath,'
')"/>
<xsl:call-template name="select">
<xsl:with-param name="pPath" select="$vPath"/>
</xsl:call-template>
<xsl:text>
</xsl:text>
</xsl:for-each>
</xsl:template>
<xsl:template match="/|node()|#*" mode="getPath" name="getPath">
<xsl:apply-templates select="parent::*" mode="getPath"/>
<xsl:text>/</xsl:text>
<xsl:choose>
<xsl:when test="self::*">
<xsl:value-of select="concat(name(),'[',
count(preceding-sibling::*
[name() =
name(current())]) + 1,
']')"/>
</xsl:when>
<xsl:when test="count(.|../#*)=count(../#*)">
<xsl:value-of select="concat('#',name())"/>
</xsl:when>
<xsl:when test="self::text()">
<xsl:value-of
select="concat('text()[',
count(preceding-sibling::text()) + 1,
']')"/>
</xsl:when>
<xsl:when test="self::comment()">
<xsl:value-of
select="concat('comment()[',
count(preceding-sibling::comment()) + 1,
']')"/>
</xsl:when>
<xsl:when test="self::processing-instruction()">
<xsl:value-of
select="concat('processing-instruction()[',
count(preceding-sibling::
processing-instruction()) + 1,
']')"/>
</xsl:when>
</xsl:choose>
</xsl:template>
<xsl:template name="select">
<xsl:param name="pPath"/>
<xsl:param name="pContext" select="/"/>
<xsl:param name="pInstruction" select="'value-of'"/>
<xsl:variable name="vPosition"
select="number(
substring-before(
substring-after($pPath,
'['),
']'))"/>
<xsl:variable name="vTest"
select="substring-before(
substring-after($pPath,
'/'),
'[')"/>
<xsl:variable name="vPath" select="substring-after($pPath,']')"/>
<xsl:choose>
<xsl:when test="$vPath">
<xsl:call-template name="select">
<xsl:with-param name="pPath" select="$vPath"/>
<xsl:with-param name="pContext"
select="$pContext/*[name()=$vTest]
[$vPosition]"/>
<xsl:with-param name="pInstruction"
select="$pInstruction"/>
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<xsl:variable name="vContext"
select="$pContext/node()
[self::*[name()=$vTest]|
self::comment()[$vTest='comment()']|
self::text()[$vTest='text()']|
self::processing-instruction()
[$vTest =
'processing-instruction()']]
[$vPosition]|
$pContext[$pPath='/']|
$pContext/#*[name() =
substring($pPath,3)]
[not($vTest)]"/>
<xsl:choose>
<xsl:when test="$pInstruction='value-of'">
<xsl:value-of select="$vContext"/>
</xsl:when>
<xsl:when test="$pInstruction='copy-of'">
<xsl:copy-of select="$vContext"/>
</xsl:when>
</xsl:choose>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
</xsl:stylesheet>
With this input:
<?somePI pseudoAttributes?>
<root>
<!-- This is a comment -->
<node attribute="Value">text</node>
</root>
Output:
/
text
/processing-instruction()[1]
pseudoAttributes
/root[1]
text
/root[1]/comment()[1]
This is a comment
/root[1]/node[1]
text
/root[1]/node[1]/#attribute
Value
/root[1]/node[1]/text()[1]
text

Using xsl:variable in a xsl:foreach select statement

I'm trying to iterate through an xml document using xsl:foreach but I need the select=" " to be dynamic so I'm using a variable as the source. Here's what I've tried:
...
<xsl:template name="SetDataPath">
<xsl:param name="Type" />
<xsl:variable name="Path_1">/Rating/Path1/*</xsl:variable>
<xsl:variable name="Path_2">/Rating/Path2/*</xsl:variable>
<xsl:if test="$Type='1'">
<xsl:value-of select="$Path_1"/>
</xsl:if>
<xsl:if test="$Type='2'">
<xsl:value-of select="$Path_2"/>
</xsl:if>
<xsl:template>
...
<!-- Set Data Path according to Type -->
<xsl:variable name="DataPath">
<xsl:call-template name="SetDataPath">
<xsl:with-param name="Type" select="/Rating/Type" />
</xsl:call-template>
</xsl:variable>
...
<xsl:for-each select="$DataPath">
...
The foreach threw an error stating: "XslTransformException - To use a result tree fragment in a path expression, first convert it to a node-set using the msxsl:node-set() function."
When I use the msxsl:node-set() function though, my results are blank.
I'm aware that I'm setting $DataPath to a string, but shouldn't the node-set() function be creating a node set from it? Am I missing something? When I don't use a variable:
<xsl:for-each select="/Rating/Path1/*">
I get the proper results.
Here's the XML data file I'm using:
<Rating>
<Type>1</Type>
<Path1>
<sarah>
<dob>1-3-86</dob>
<user>Sarah</user>
</sarah>
<joe>
<dob>11-12-85</dob>
<user>Joe</user>
</joe>
</Path1>
<Path2>
<jeff>
<dob>11-3-84</dob>
<user>Jeff</user>
</jeff>
<shawn>
<dob>3-5-81</dob>
<user>Shawn</user>
</shawn>
</Path2>
</Rating>
My question is simple, how do you run a foreach on 2 different paths?
Try this:
<xsl:for-each select="/Rating[Type='1']/Path1/*
|
/Rating[Type='2']/Path2/*">
Standard XSLT 1.0 does not support dynamic evaluation of xpaths. However, you can achieve your desired result by restructuring your solution to invoke a named template, passing the node set you want to process as a parameter:
<xsl:variable name="Type" select="/Rating/Type"/>
<xsl:choose>
<xsl:when test="$Type='1'">
<xsl:call-template name="DoStuff">
<xsl:with-param name="Input" select="/Rating/Path1/*"/>
</xsl:call-template>
</xsl:when>
<xsl:when test="$Type='2'">
<xsl:call-template name="DoStuff">
<xsl:with-param name="Input" select="/Rating/Path2/*"/>
</xsl:call-template>
</xsl:when>
</xsl:choose>
...
<xsl:template name="DoStuff">
<xsl:param name="Input"/>
<xsl:for-each select="$Input">
<!-- Do stuff with input -->
</xsl:for-each>
</xsl:template>
The node-set() function you mention can convert result tree fragments into node-sets, that's correct. But: Your XSLT does not produce a result tree fragment.
Your template SetDataPath produces a string, which is then stored into your variable $DataPath. When you do <xsl:for-each select="$DataPath">, the XSLT processor chokes on the fact that DataPath does not contain a node-set, but a string.
Your entire stylesheet seems to be revolve around the idea of dynamically selecting/evaluating XPath expressions. Drop that thought, it is neither possible nor necessary.
Show your XML input and specify the transformation your want to do and I can try to show you a way to do it.