qt example from the book - c++

I have this snippet of the code:
#include <QApplication>
#include <QFont>
#include <QPushButton>
#include <QWidget>
class MyWidget : public QWidget
{
public:
MyWidget(QWidget *parent = 0);
};
MyWidget::MyWidget(QWidget *parent)
: QWidget(parent)
{
setFixedSize(200, 120);
QPushButton *quit = new QPushButton(tr("Quit"), this);
quit->setGeometry(62, 40, 75, 30);
quit->setFont(QFont("Times", 18, QFont::Bold));
connect(quit, SIGNAL(clicked()), qApp, SLOT(quit()));
}
int main(int argc, char *argv[])
{
QApplication app(argc, argv);
MyWidget widget;
widget.show();
return app.exec();
}
can somebody please explain what exactly is going on in this line
MyWidget(QWidget *parent = 0);
a little bit difficult understand what is this parent, thanks in advance

That is an argument to the constructor with a default argument (NULL since NULL is defined as 0 as per the c++ standard). Default meaning passing no parameter is the same as passing NULL.
Since Qt's widgets are arranged in a hierarchal system (parent -> child relationships) parent is the widget which is the "owner" or "container" of the current one (NULL means no parent aka a root widget of sorts). For GUI items a widget will often have the widget it is contained in as its parent.
This is advantageous since when a parent is deleted, it will delete any children is has automatically removing the need for much of the memory management that comes with c++.

The parent argument is for giving parents to new widgets. When given, it is useful for Qt to manage the object tree. (To automatically delete child objects.) It also has the concrete visible effect of "attaching" a new widget to another widget (ie, the parent). In your code however, the parent argument is not ever given, causing the widget to appear as a top level window and not to be deleted by Qt automatically. (It would not require deletion by Qt anyway in that code though.)

Its a 0 pointer (think NULL without the type), or in Qt terms, "no parent".

Related

Qt: parent-child widgets. Does closing of a single child widget imply closing of other children?

I have the following problem with the test Qt application, which contains one parent widget and two child widgets, which are separate windows. If the parent widget is hidden, then closing a single child widget implies closing the second child as well as closing the whole application.
Is it the normal behavior of the parent/child widgets in Qt? Is there a way to keep the second child widget visible and the application running?
#include <QApplication>
#include <QtWidgets>
class MyWidget : public QWidget {
public:
MyWidget(const QString& title = "", QWidget *parent = nullptr) :
QWidget(parent) {
setWindowTitle(title);
setWindowFlags(windowFlags() | Qt::Window);
setVisible(true);
}
};
int main(int argc, char *argv[])
{
QApplication a(argc, argv);
MyWidget parent("Parent");
MyWidget *child1 = new MyWidget("Child1", &parent);
MyWidget *child2 = new MyWidget("Child2", &parent);
QTimer::singleShot(5000, [&](){parent.hide();});
return a.exec();
}
There're three widgets of simple class MyWidget:
the parent one 'parent' with two childs 'child1' and 'child2'.
After 5 sec the parent widget is hidden by the QTimer::singleShot.
After that, if I close, e.g. child1 window, the second window child2
is also automatically closed and the application is finished.
I'd expect that child1 and child2 are independent, and closing one of them shouldn't close another one.
Usually children in Qt are independant of another just like you want them to. However when the last primary window is closed in (see QApplication::lastWindowClosed) the application closes as a whole. Likely thats whats happening here. I am unsure why, though.
What you could try is manually define closeEvents for your windows. Still your behaviour is weird, as I remember reading that hiding a parent window should also hide its children here: (https://www.qtcentre.org/threads/61708-Multiple-windows-hide-parent-when-child-shown-unhide-when-child-closed).

Why are QWidgets accessed by pointers?

I am new to Qt5 and I am learning QWidgets to develop an application.
I've noticed in many examples, QWidgets are almost always accessed by pointer. For example:
#include <QApplication>
#include <QWidget>
#include <QFrame>
#include <QGridLayout>
class Cursors : public QWidget {
public:
Cursors(QWidget *parent = 0);
};
Cursors::Cursors(QWidget *parent)
: QWidget(parent) {
QFrame *frame1 = new QFrame(this);
frame1->setFrameStyle(QFrame::Box);
frame1->setCursor(Qt::SizeAllCursor);
QFrame *frame2 = new QFrame(this);
frame2->setFrameStyle(QFrame::Box);
frame2->setCursor(Qt::WaitCursor);
QFrame *frame3 = new QFrame(this);
frame3->setFrameStyle(QFrame::Box);
frame3->setCursor(Qt::PointingHandCursor);
QGridLayout *grid = new QGridLayout(this);
grid->addWidget(frame1, 0, 0);
grid->addWidget(frame2, 0, 1);
grid->addWidget(frame3, 0, 2);
setLayout(grid);
}
int main(int argc, char *argv[]) {
QApplication app(argc, argv);
Cursors window;
window.resize(350, 150);
window.setWindowTitle("Cursors");
window.show();
return app.exec();
}
This is taken from the tutorial: http://zetcode.com/gui/qt5/firstprograms/
Yet, on the same page, I see that we can access the QWidget base class by its object itself:
#include <QApplication>
#include <QWidget>
int main(int argc, char *argv[]) {
QApplication app(argc, argv);
QWidget window;
window.resize(250, 150);
window.setWindowTitle("Simple example");
window.show();
return app.exec();
}
Why is it necessary to access all QWidget derived classes by their pointer? Why isn't it necessary to access QWidget itself by its pointer?
It's all about object's lifetime and shared ownership. If you create an object on stack in function, it will be destroyed when scope ends.
Why isn't it necessary to access QWidget by pointer in your example? Just because when main() 'ends', your program is finished, and widget may be destroyed.
Why is it necessary to access QWidget's children by pointer? Because if you want to ask QWidget to give you access to it's child, it can't give you a value, because it would be just a copy of an object. Moreover, if you pass a large object by value to QWidget, it needs to copy your object.
This is not specific to QWidgets: it is so for every QObjects (Qt fundamental base class, from which everything else is derived).
It is the consequence of a design choice of the Qt framework. Quoting Qt documentation:
QObject has neither a copy constructor nor an assignment operator.
This is by design.
[...]
The main consequence is that you should use
pointers to QObject (or to your QObject subclass) where you might
otherwise be tempted to use your QObject subclass as a value. For
example, without a copy constructor, you can't use a subclass of
QObject as the value to be stored in one of the container classes. You
must store pointers.
Source:
http://doc.qt.io/qt-5.5/qobject.html#no-copy-constructor
The rationale for this choice is explained here:
http://doc.qt.io/qt-5.5/object.html#identity-vs-value
QClasses are larger in size and you don't want to fill up your stack memory by instantiating them in stack memory.
When you instantiate derived class objects it also runs constructor of a base class ( derived class + base class ) memory is required,
On the other hand QWidget only inherits QObject and QPaintDevice as you can see here
So it will be less overhead to create QWidget object on stack memory.
You must be very careful when you are using heap memory, read the answers on memory management
You can study the difference between stack and heap from here

Qt creating MDI document window

I am trying to create a MDI document program. I have a question on creating the subwindow.
This is my mainwindow constructor:
MainWindow::MainWindow(QWidget *parent) :
QMainWindow(parent),
ui(new Ui::MainWindow)
{
ui->setupUi(this);
setWindowTitle(tr("MDI"));
workspace = new QMdiArea;
setCentralWidget(workspace);
//fileNew();
createActions();
createMenus();
createToolbars();
statusBar()->showMessage(tr("Done"));
enableActions();
}
The interesting point is the fileNew(); function. It is a private slot function actually which I want to invoke when "New File" button is triggered. Here is the private slot fileNew() function:
void MainWindow::fileNew()
{
DocumentWindows* document = new DocumentWindows;
workspace->addSubWindow(document);
}
This function works perfectly when I call from the mainwindow constructor. However, there is a problem when I call it from the createActions(); function which uses a signal-slot mechanism.
Here is my createActions()
void MainWindow::createActions()
{
newAction = new QAction(QIcon(":/Image/NewFile.png"),tr("&New"),this);
newAction->setShortcut(tr("Ctrl+N"));
newAction->setToolTip(tr("Open new document"));
connect(newAction, SIGNAL(triggered(bool)), this, SLOT(fileNew()));
}
No subwindow is created even the SLOT is triggered. Subsequently, I find out that if I add document->show();, everything works well.
void MainWindow::fileNew()
{
DocumentWindows* document = new DocumentWindows;
workspace->addSubWindow(document);
document->show();
}
My question is: Why the show() function is needed in a SLOT but not in the constructor?
PS. DocumentWindows is just a class inherits QTextEdit.
This problem has nothing to do with the class of the widgets one is using. It is unrelated to documents, MDI, or the main window. After you add a child widget to a widget that is already visible, you must explicitly show it. Otherwise, the widget will remain hidden.
All widgets are hidden by default. When you initially show the MainWindow, all of its children are recursively shown too. When you later add a child MDI widget, it remains hidden. When widgets are added to layouts, they are shown by default - but your widget is managed by the MDI area, not by a layout.
This is a minimal test case demonstrating your issue:
// https://github.com/KubaO/stackoverflown/tree/master/questions/widget-show-32534931
#include <QtWidgets>
int main(int argc, char ** argv) {
QApplication app{argc, argv};
QWidget w;
w.setMinimumSize(200, 50);
QLabel visible{"Visible", &w};
w.show();
QLabel invisible{"Invisible", &w};
invisible.move(100, 0);
return app.exec();
}

Are destructors necessary in QDialogs?

I am following Qt examples (like TabDialog) and I notice that all the UI items are created as pointers - yet I see no delete and no destructor.
Is that right ? Will that not lead to memory leak ?
I am trying to add destructors
~TabDialog()
{
delete tabWidget;
delete buttonBox;
}
and on caller
TabDialog *tabDialog = new TabDialog();
tabDialog->setAttribute(Qt::WA_DeleteOnClose);
tabDialog->exec();
But the program crashes when I close the dialog.
Are the destructors, and delete all pointer items, unnecessary or am I doing it wrong ?
I think that you are confused because of these lines:
tabWidget = new QTabWidget;//and so on
You don't see explicit parent (like new QTabWidget(this);), but it is not necessary here. Take a look here:
QVBoxLayout *mainLayout = new QVBoxLayout;
mainLayout->addWidget(tabWidget);
mainLayout->addWidget(buttonBox);
setLayout(mainLayout);
setLayout will reparent your QVBoxLayout and QVBoxLayout will reparent all widgets inside it, so now your widgets has a parent and they will be destroyed after your dialog.
As doc said:
When you use a layout, you do not need to pass a parent when
constructing the child widgets. The layout will automatically reparent
the widgets (using QWidget::setParent()) so that they are children of
the widget on which the layout is installed.
Note: Widgets in a layout are children of the widget on which the
layout is installed, not of the layout itself. Widgets can only have
other widgets as parent, not layouts.
I'm sorry, but this just doesn't reproduce. The test case is below. You'd probably need to add some extra code to make it reproduce.
Qt's memory management will take care of everything, since all of the widgets end up having parents. Namely:
Tabs are parented as soon as they are passed to addTab.
tabWidget and buttonBox are parented as soon as they are added to the layout.
Since you delete the tabWidget and buttonBox before Qt attempts to delete them, everything is fine. As soon as you delete them, QObject's memory management is informed and they are removed from the TabDialog's child list. I've made this point explicit in the destructor code.
The meaning of Q_ASSERT is: "At this point during runtime, the following must be true". If we're wrong, the debug build will abort. Since it doesn't, the assertions are correct. Thus, before delete tabWidget, the dialog has both QTabWidget and QDialogButtonBox children. After delete tabWidget, the dialog should not have any QTabWidget children anymore. And so on.
#include <QApplication>
#include <QDialog>
#include <QTabWidget>
#include <QDialogButtonBox>
#include <QVBoxLayout>
class TabDialog : public QDialog
{
QTabWidget *tabWidget;
QDialogButtonBox *buttonBox;
public:
TabDialog() :
tabWidget(new QTabWidget),
buttonBox(new QDialogButtonBox(QDialogButtonBox::Ok |
QDialogButtonBox::Cancel))
{
tabWidget->addTab(new QWidget, tr("General"));
tabWidget->addTab(new QWidget, tr("Permissions"));
tabWidget->addTab(new QWidget, tr("Applications"));
QVBoxLayout *layout = new QVBoxLayout;
layout->addWidget(tabWidget);
layout->addWidget(buttonBox);
setLayout(layout);
connect(buttonBox, SIGNAL(accepted()), this, SLOT(accept()));
connect(buttonBox, SIGNAL(rejected()), this, SLOT(reject()));
}
~TabDialog() {
Q_ASSERT(findChild<QTabWidget*>());
Q_ASSERT(findChild<QDialogButtonBox*>());
delete tabWidget;
Q_ASSERT(! findChild<QTabWidget*>());
Q_ASSERT(findChild<QDialogButtonBox*>());
delete buttonBox;
Q_ASSERT(! findChild<QTabWidget*>());
Q_ASSERT(! findChild<QDialogButtonBox*>());
}
};
int main(int argc, char *argv[])
{
QApplication a(argc, argv);
TabDialog *tabDialog = new TabDialog();
tabDialog->setAttribute(Qt::WA_DeleteOnClose);
tabDialog->exec();
return 0;
}
The only way it'd crash is if you tried the following:
int main(int argc, char *argv[])
{
QApplication a(argc, argv);
TabDialog *tabDialog = new TabDialog();
tabDialog->setAttribute(Qt::WA_DeleteOnClose);
tabDialog->exec();
// At this point `tabDialog` is a dangling pointer.
delete tabDialog; // crash
return 0;
}
Unfortunately, Qt examples are a case of pointless premature pessimization. Qt's classes utilize the PIMPL idiom extensively. Thus the size of, say a QTabWidget is not much larger than that of QObject (48 vs. 16 bytes on my 64 bit platform). By allocating the fixed members of your class on the heap, you're performing two heap allocations: a small one for the QObject-derived class, and then another one for its PIMPL. You're doubling the number of allocations for no good reason.
Here's how to avoid this pessimization:
#include <QApplication>
#include <QDialog>
#include <QTabWidget>
#include <QDialogButtonBox>
#include <QVBoxLayout>
class TabDialog : public QDialog
{
QVBoxLayout m_layout;
QTabWidget m_tabWidget;
QDialogButtonBox m_buttonBox;
QWidget m_generalTab, m_permissionsTab, m_applicationsTab;
public:
TabDialog() :
m_layout(this),
m_buttonBox(QDialogButtonBox::Ok | QDialogButtonBox::Cancel)
{
m_tabWidget.addTab(&m_generalTab, tr("General"));
m_tabWidget.addTab(&m_permissionsTab, tr("Permissions"));
m_tabWidget.addTab(&m_applicationsTab, tr("Applications"));
m_layout.addWidget(&m_tabWidget);
m_layout.addWidget(&m_buttonBox);
connect(&m_buttonBox, &QDialogButtonBox::accepted, this, &QDialog::accept);
connect(&m_buttonBox, &QDialogButtonBox::rejected, this, &QDialog::reject);
}
};
int main(int argc, char *argv[])
{
QApplication app(argc, argv);
auto tabDialog = new TabDialog();
tabDialog->setAttribute(Qt::WA_DeleteOnClose);
tabDialog->show(); // NOT tabDialog->exec()!!
return app.exec();
}
The less explicit heap allocations, the better. This way you can't even be tempted to delete anything in the destructor, since there are no pointers involved. The compiler generates necessary destructor calls for you automatically.
Furthermore, if you're showing only one window in main, there's no point to explicit heap allocation either:
int main(int argc, char *argv[])
{
QApplication app(argc, argv);
TabDialog tabDialog;
tabDialog.show();
return app.exec();
}
Memory handling on Qt
Qt handles the widgets as a tree, every widget has a parent and every parent has
the obligation to free the children memory, if a widget has no parent you should delete it manually with the operator delete.

QLabel show command opens new Window

I've created an Application which derives from QWidget. When I create an QLabel and yield the show command, it opens in a separate window. I was deriving my BaseClass from QMainWindow before which worked fine.
#include "widget.h"
#include "ui_widget.h"
#include <iostream>
#include <QDebug>
Widget::Widget(QWidget *parent) :
QWidget(parent),
ui(new Ui::Widget)
{
ui->setupUi(this);
testlabel = new my_qlabel(parent);
QImage myImage = QImage(QString::fromStdString("D:/Lighthouse.jpg"));
testlabel->setParent(parent);
testlabel->name="testName";
testlabel->setPixmap(QPixmap::fromImage(myImage, Qt::AutoColor));
testlabel->setGeometry(QRect(500, 500, 100, 100));
testlabel->show();
std::cout<<"i am in the output "<<std::endl;
qDebug() << QString("init");
}
Widget::~Widget()
{
delete ui;
}
testlabel = new my_qlabel(parent);
The above should probably instead be
testlabel = new my_qlabel(this);
Also make sure that your my_qlabel constructor is passing its QWidget pointer argument up to the superclass's (QLabel?) constructor. If you forgot to do that, then the my_qlabel object will not have a parent widget, which will cause it to show up as top-level window, which would match the behavior you are seeing.
testlabel->show();
Once you have testlabel's parenting problems fixed, this show() command should no longer be necessary (or appropriate), since any child widgets you add to your Widget object will be automatically show()'n when the Widget itself is first show()'n. (The only time you would need to manually call show() is if you had previously called hide() or setVisible(false) on that same widget, and now you wanted to make it re-appear; or if you had added the child widget to its parent widget after the parent widget was already visible on-screen; neither is the case here)