In my HTML I have below tags:
<img src="../images/img.jpg" alt="sometext"/>
Using regex expression I want to remove alt=""
How would I write this?
Update
Its on movable type. I have to write it a like so:(textA is replaced by textB)
regex_replace="textA","textB"
Why don't you just find 'alt=""' and replace it with ' ' ?
On Movable Type try this:
regex_replace="/alt=""/",""
http://www.movabletype.org/documentation/developer/passing-multiple-parameters-into-a-tag-modifier.html
What regex you are asking for ? Straight away remove ..
$ sed 's/alt=""//'
<img src="../images/img.jpg" alt=""/>
<img src="../images/img.jpg" />
This does not requires a regex.
The following expression matches alt="sometext"
alt=".*?"
Note that if you used alt=".*" instead, and you had <img alt="sometext src="../images/img.jpg"> then you would match the whole string alt="sometext src="../images/img.jpg" (from alt=" to the last ").
The .* means: Match as much as you can.
The .*? means: Match as little as you can.
s/ alt="[^"]*"//
This regex_replace modifier should match any IMG tag with an alt attribute and capture everything preceding the alt attribute in group #1. The matched text is then replaced with the contents of group #1, effectively stripping off the alt attribute.
regex_replace='/(<img(?:\s+(?!alt\b)\w+="[^"]*")*)\s+alt="[^"]*"/g','$1'
Is that what you're looking for?
Related
I have an HTML string, e.g. :
<a href=“{{foo.bar}}”>some text “nice” here</a>
I'm trying to find out if any opening/closing double quote (“”, not ") is present inside an html tag (i.e. inside <>, but there could others things also in the tag).
In my example, <a href=“{{foo.bar}}”> should match but “nice” or </a> shouldn't.
What is the right regex for this ?
Actually I don't believe you've found it but you rather you fell into the common trap of regular expressions. You found a pattern which matches what you desire in a specific case.
If you place a < character inside the value of the tag of the link, <a href=“{{foo.bar}}”>some text < “nice” here</a> and your regex will match <a href=“{{foo.bar}}”> and < “nice” here</a>.
So an extra caution needs to be taken when it comes to regular expressions. To match any opening tag of html better use <\w+.*?>. After that extract whatever you find inside “”.
ok, found it : <[^>]*[“”]+[^>]*>
That does not work as you probably expect it to. When you add capturing groups, you'll see which parts of the string are actually matched by which groups:
<([^>]*)([“”]+)([^>]*)>
matches your example in this way:
<a href=“{{foo.bar}}”> a href=“{{foo.bar}} ”
^ Full match ^ 1st group ^ 2nd group ^ 3rd group (nothing)
Building on #Themelis' answer, you probably want to start with something like this:
<(\w+ [^<>“]*)“([^”]+)”([^<>]*)>
matches your example in this way:
<a href=“{{foo.bar}}”> a href= {{foo.bar}}
^ Full match ^ 1st group ^ 2nd group ^ 3rd group (nothing)
I want to extract ID and Name from a single regular expression, but I'm not able to get the correct response
<a href="/profiles/6635/Name"
I have used below regular expression
<a href="/profiles/(.*?)/(.*?)"
As #WiktorStribiżew suggested, you should fix your regular expression to
<a href="/profiles/([^/]+)/([^/]+)"
But also use $1$ and $2$ to get both values in in Template field, for example
$1$$2$
Will save to variable concatenated value - 6635Name
What you use <a href="/profiles/(.*?)/(.*?)" is fine to capture ID and name from <a href="/profiles/6635/Name" because a lazy way (non-greedy) (.*?) you use will match only between profiles/ and the second / same like using [^\/]+ and then between / and " so , check again that you put everything right .
You may need to escape / like this \/so , change it to :
<a href="\/profiles\/(.*?)\/(.*?)"
This is your same regex here DEMO
And if you need to make sure with java tester use this tool :Java regex tester
I need a regex for fetching the value in the </span> tag
<span class="booking-id-value">U166097</span>
value required: U166097
can please someone suggest me. I have tried using
<span class="booking-id-value">(.+?)
but it is not deriving the desired result it display on "U"
I think you need to be more specific about your expected value - below I'll just accept alphabetic and numeric characters as value - and more flexible about your tag, then I can suggest you to use a regex like this:
/<\s*span.+?class\s*=\s*"\s*booking-id-value\s*".*?>/s*([A-Za-z0-9]+)\s*<\//
Regex Demo
? after the .+ makes it ungreedy, tells it to match as little as possible - and that’s just the first U in this case.
Remove the ?, and instead look for the closing </span> after (.*) to terminate what is matched correctly:
<span class="booking-id-value">(.+)<\/span>
https://regex101.com/r/vt4pgN/1/
Regex:
<span.*>(.*)<\/span>
Substitute with:
$1
Result
I have the following text.
<span style="color:#FF0000;">赤色</span><span style="color:#0;">|*|</span><span style="color:#0070C0;">青色</span><span style="color:#0;">|*|</span><span style="color:#00B050;">緑色</span><span style="color:#0;">|*|</span>
I need to remove any span tag that defines color for "|*|" only. That is in this case, I need to remove
<span style="color:#0;">
and
</span>
Can anyone help to do that?
Thanks in advance!
You want something like this:
<span[^>]+style="[^"]*color:[^>]+>(\|\*\|)<\/span>
This matches <span, then one or more non-> characters, then a style attribute that contains color:, then the rest of the tag, then |*|, then </span>.
You would replace with $1 or just |*|.
Here's a demo.
Note: one reason your attempt didn't work is that you escaped the |s, but not the *. You need to escape the * as \*.
I need some help with Regular expression to Search and Replace in Sublime to do the following.
I have HTML-code with links like
href="http://www.example.com/test=123"
href="http://www.example.com/test=6546"
href="http://www.example.com/test=3214"
I want to replace them with empty links:
href=""
href=""
href=""
Please help me to create a Reg. ex. filter to match my case. I guess it would sound like "starts with Quote, following with http:// .... ends with Quote and has digitals and '=' sign", but I'm not very confident of how to write this in Reg. ex. way.
(?<=href=")[^"]*
Try this.Replace by empty string.
See demo.
https://regex101.com/r/sH8aR8/40