why my program Time Limited Error?
because of the sort?
this is the question
link text
#include <cstdio>
#include <cstring>
using namespace std;
int map[22][44];
int book[22];
int total;
int sum;
int way[22];
int tails[22];
int tail;
void init()
{
memset(map,0,sizeof(map));
memset(book,0,sizeof(book));
sum =0;
memset(way,0,sizeof(way));
way[1]=1;
memset(tails,0,sizeof(tails));
}
void sort()
{
int t;
for (int i=1;i<=22;i++)
{
if (tails[i]==0)
break;
else
{
for (int j=1;j<=tails[i]-1;j++)
for (int k=j+1;k<=tails[i];k++)
{
if (map[i][j] > map[i][k])
{
t = map[i][j];
map[i][j]=map[i][k];
map[i][k]=t;
}
}
}
}
}
void dfs(int x,int y)
{
if ((x < 1)||(x > 22))
return;
if (book[x]==1)
return;
//printf("%d \n",x);
if (x == total)
{
sum++;
for (int i=1;i<=y-1;i++)
{
printf("%d ",way[i]);
}
printf("%d",total);
printf("\n");
return;
}
tail = tails[x];
for (int i=1;i<=43;i++)
{
book[x]=1;
way[y]=x;
dfs(map[x][i],y+1);
book[x]=0;
}
}
int main()
{
int temp1,temp2;
//freopen("ex.in","r",stdin);
//freopen("ex.out","w",stdout);
int c = 0;
while(scanf("%d",&total)!=EOF)
{
c++;
printf("CASE ");
printf("%d",c);
printf(":");
printf("\n");
init();
for (;;)
{
scanf("%d%d",&temp1,&temp2);
if ((temp1 == 0)&&(temp2 == 0))
break;
else
{
tails[temp1]++;
tail = tails[temp1];
map[temp1][tail]=temp2;
tails[temp2]++;
tail = tails[temp2];
map[temp2][tail]=temp1;
}
}
sort();
dfs(1,1);
printf("There are ");printf("%d",sum);printf(" routes from the firestation to streetcorner ");printf("%d",total);printf(".");
printf("\n");
}
return 0;
}
Because your sorting algoritm is in worst-case O(n*n), you can use InnoSort for better worst-case complexity O(n*log(n)).
You are using C++ then use sort function from <algorithm> header to do this simplest.
Documentation you can find at http://www.sgi.com/tech/stl/sort.html
For a start, you're accessing tails and map past the end. C++ arrays are zero-indexed, so the first element is 0, and the last valid elements are tails[21] and map[21][43].
Related
I have to make a program with a hash table that maps single random characters into the table. The program kind of works but sometimes it crashes, also it doesn't map every element. Some of them just won't get inside the table and there are always spare spaces in the table. I don't know what to do to solve these 2 problems. I used 3 versions of open adressing and each of them causes the same 2 problems. Sorry for my bad English. Thank you in advance.
Edited. Of course, I forgot about dynamic allocation. But the problem isn't solved.
#include <time.h>
#include <string>
#include <cstdlib>
using namespace std;
int Liniowo(int i, int proby, int rozmiar) // (open adressing, Linear probing)
{
if(i+proby<rozmiar)
return i+proby;
else
{
return -1;
}
}
int Kwadratowo(int i, int proby, int rozmiar) // (open adressing, Quadratic probing)
{
if (i+proby*proby<rozmiar)
return i+proby*proby;
else
{
return -1;
}
}
int Podwojnie(int i, int proby, int rozmiar, char klucz) // (open adressing, Double hashing)
{
if (i*(klucz*(701%klucz)-klucz%13)<rozmiar&&i*(klucz*(701%klucz)-klucz%13)>0)
return i*(klucz*(701%klucz)-klucz%13);
else
{
return -1;
}
}
int modularnie(char c,int rozmiar) // modular
{
return c%rozmiar;
}
void dodaj(char *tab,int max, char c) // add an element
{
int i=modularnie(c, max);
if (tab[i]== '\0')
tab[i]=c;
else
{
int u=0;
int h;
while (tab[i]!= '\0'&&h!=-1)
{
u++;
// h=Kwadratowo(i, u, max);
h=Podwojnie(i,u,max,c);
}
if (h!=-1)
tab[h]=c;
else
cout << "no niestety, nie udalo sie wstawic " <<endl; //"I couldn't map the element"
}
}
int wyszukaj(char *tab,int max, char c) // search an element
{
int i=modularnie(c, max);
int j=i;
if (tab[i]== '\0')
return -1;
while (tab[i]==c)
{
i=(i+1)%max;
if((i==j)||(tab[i]== '\0'))
return -1;
}
return i;
}
int usun(char *tab,int max, char c) // remove an element
{
int r,j,i=wyszukaj(tab,max,c);
j=i;
if (i==-1)
return -1;
tab[i]= '\0';
while (tab[(++i)%max]!= '\0')
{
i%=max;
r=modularnie(tab[i],max);
if (((i<r)&&(r<=j)) || ((r<=j)&&(j<i)) || ((j<i)&&(i<r)))
{
tab[j]=tab[i];
tab[i]= '\0';
j=i;
continue;
}
}
return 0;
}
int main()
{
srand( time( NULL ) );
int ile;
cout << "podaj wielkosc tablicy: "; //"Type the size of the table"
cin >> ile;
char* tab; // EDITED
tab=new char(ile);
for (int n=0; n<ile; n++)
{
tab[n]= '\0';
}
char e;
for (int i=0; i<ile; i++)
{
e='!'+rand()%127;
dodaj(tab, ile, e);
}
for(int j=0; j<ile; j++)
{
cout << j << ", " << tab[j] << endl;
}
return 0;
}
It's my program to simplify Karnough map. I need to change it from SOP to POS for university project. I changed already signs from + to * and from * to +. All i have to do now is to make it read zero-s from text file instead of one's. i tried everything to solve that problem, but i have no idea. I have got two txt files, one with input and one with output. At this moment i need to put in input 0's instead of 1's and in the other side to, to make it work. Please help me, my life depends of that
#include <iostream>
#include <fstream>
#include <cmath>
#include <windows.h>
using namespace std;
//?????
int pow2(int n) // ??2?????,2^n
{
int result=1
;
while(n>0)
result*=2,n--;
return result;
}
int combination(int n,int r) // ?????C_n^r,? n! / ((n-r)!*(r)!)
{
int fm=1,fz=1;
for(int i=1;i<=r;i++,n--)
{
fm*=i;
fz*=n;
}
return fz/fm;
}
void d2b(int d,char* b,int n) // ???????,??????d???????????b?
{
for(n--;n>=0;n--)
{
b[n]='0'+d%2;
d/=2;
}
}
int ispair(char* a1,char* a2,int n) // ????????????????
{
int x,y=0;
for(int i=0;i<n;i++)
if(a1[i]!=a2[i])
x=i,y++;
if(y==1) return x;
else return-1;
}
bool issame(char* a1,char* a2,int n) // ????
{
for(int i=0;i<n;i++)
if(a1[i]!=a2[i])
return 0;
return 1;
}
int left1(char* a,int N) // ???????????,??????1,??????
{
for(int i=0;i<N;i++)
if(a[i]=='1')
return i;
return -1;
}
void copy(char* a1,char* a2,int n) // ??????
{
for(int i=0;i<n;i++)
a2[i]=a1[i];
}
bool isinside(int x,char* a,int n) // ???x????????a?
{
for(n--;n>=0;n--)
{
if(a[n]!='x' && a[n]!=(char)('0'+x%2))
return 0;
x/=2;
}
return 1;
}
void output(fstream& file,char* a,int n)
{
for(int i=0;i<n;i++)
{
if(i==0)file<<'(';
if(a[i]=='0'||a[i]=='1')
{
if(a[i]=='0') file<<'¬'<<(char)('a'+i);
if(a[i]=='1') file<<(char)('a'+i);
if(a[i+1]=='0'||a[i+1]=='1'||a[i+2]=='0'||a[i+2]=='1'||a[i+3]=='0'||a[i+3]=='1')
{
file<<'+';
}
else{
file<<')';
}
}
else{}
;
}
file<<'*';
}
int count(char* table,char* a,int n,int N) // ??,????????1???????????a?
{
int counter=0;
for(int i=0;i<N;i++)
{
if(table[i]!='1') continue;
if(isinside(i,a,n)) counter++;
}
return counter;
}
void clean(char* table,char* a,int n,int N) // ??????????????????1,???x
{
for(int j=0;j<N;j++)
if(isinside(j,a,n))
table[j]='x';
}
int main()
{
SetConsoleTitle("???-???????????");
system("color 06");
//????
fstream inputFile("input.txt",ios::in); //??????????input.txt
int valNum; //???
inputFile >> valNum; // ???????????
cout<<"\n ????????: "<<valNum;
cout<<"\n ?????????:\n";
int minTermLength=pow2(valNum); // ??????????2^valNum?
char* minTermExpression=new char[minTermLength]; // ???????????????
int lineOff = pow2(ceil(double(valNum)/2));
// ???????
if (inputFile.is_open())
{
for(int i=0;i<minTermLength;i++) // ?????
{
inputFile>>minTermExpression[i];
if(i%lineOff == 0&&(i!=0))
cout<<"\n";
cout<<"\t"<<minTermExpression[i];
}
inputFile.close();
}
// ??????
else{
cout<<"\n ??input.txt??,???????";
return 0;
}
// ?implication????????
char*** implication=new char**[valNum]; // ????
int nonZeroNum=1;
for(int i=0;i<minTermLength;i++)
if(minTermExpression[i]!='0') // ?????ON???DC?????????
nonZeroNum++;
for(int i=0;i<valNum;i++) // i-??,???????3?,i=0???????,i=1???,i=2???
{
if(pow2(i)>nonZeroNum)break;
int x=pow2(i-1)*combination(nonZeroNum,pow2(i));
implication[i]=new char*[x];
for(int j=0;j<x;j++)
implication[i][j]=new char[valNum];
}
//?????????
int* countNum=new int[valNum+1];
countNum[0]=0;
for(int i=0;i<minTermLength;i++)
if(minTermExpression[i]!='0') // ???0?
{
d2b(i,implication[0][countNum[0]],valNum); // ??????????implication[0]???
countNum[0]++;
}
int isOptimal=0;
while(countNum[isOptimal]>0) // ??????????
{
countNum[isOptimal+1]=0;
for(int i=0;i<countNum[isOptimal]-1;i++)
for(int j=i+1;j<countNum[isOptimal];j++)
{
int x=ispair(implication[isOptimal][i],implication[isOptimal][j],valNum); // ??????????
if(x==-1) continue;
copy(implication[isOptimal][i],implication[isOptimal+1][countNum[isOptimal+1]],valNum);// ???implication??
implication[isOptimal+1][countNum[isOptimal+1]][x]='x'; // ??????????,?????????x,???????????
countNum[isOptimal+1]++;
}
for(int i=0;i<countNum[isOptimal+1]-1;i++)
for(int j=i+1;j<countNum[isOptimal+1];j++)
if(issame(implication[isOptimal+1][i],implication[isOptimal+1][j],valNum)) // ??????
{
for(int k=j;k<countNum[isOptimal+1]-1;k++)
copy(implication[isOptimal+1][k+1],implication[isOptimal+1][k],valNum);
countNum[isOptimal+1]--;
}
isOptimal++;
}
isOptimal--;
//???????
fstream outputFile("output.txt",ios::out);
outputFile<<"F=";
while(left1(minTermExpression,minTermLength)>=0) //?minTermExpression???1
{
bool flag=0; // ???,????
for(int i=0;i<minTermLength&&flag==0;i++)
{
if(minTermExpression[i]!='1') continue;
int counter=0,recorder;
for(int j=0;j<countNum[isOptimal];j++)
if(isinside(i,implication[isOptimal][j],valNum))
counter++,recorder=j;
if(counter!=1) continue;
output(outputFile,implication[isOptimal][recorder],valNum);
clean(minTermExpression,implication[isOptimal][recorder],valNum,minTermLength);
flag=1;
}
if(flag==1) continue;
int termMaxInclude=0;
int recorder=0;
for(int i=0;i<countNum[isOptimal];i++) // ??????????,???????????1???,??????
if(count(minTermExpression,implication[isOptimal][i],valNum,minTermLength)>termMaxInclude)
termMaxInclude=count(minTermExpression,implication[isOptimal][i],valNum,minTermLength),recorder=i;
if(termMaxInclude==0) {isOptimal--; continue;}
output(outputFile,implication[isOptimal][recorder],valNum);
clean(minTermExpression,implication[isOptimal][recorder],valNum,minTermLength);
}
outputFile.close();
// ?????
outputFile.open("output.txt",ios::in);
char finalExpression[201];
outputFile.getline(finalExpression,200);
outputFile.close();
int termMaxInclude=0;
for(;finalExpression[termMaxInclude]!='\0';termMaxInclude++);
finalExpression[termMaxInclude-1]='\0';
outputFile.open("output.txt",ios::out);
outputFile<<finalExpression;
outputFile.close();
cout<<"\n??????????????";
cout<<"\n ??????,??????!";
cin.get();
return 0;
}
The zeros are simply those not in the ones list.
I have studied the algorithm from Introduction to Algorithm and then
I have written this code. But in my output another value is showing for index 0. and when I use pop function it display 1 instead of 3
#include <iostream>
int top;
void initialise_top(){
top = -1;
}
bool stack_empty(int a[]){
if(top == -1)
return true;
else
return false;
}
void push(int a[], int x, int s){
if(top < s - 1){
top = top + 1;
a[top] = x;
}
else
std::cout << "overflow" << "\n";
}
int pop(int a[]){
if (stack_empty(a) == true)
std::cout << "Underflow" << "\n";
else{
--top;
return a[top+1];
}
}
void display(int a[]){
for(int i = 0;i <= top; i++){
std::cout << a[i] << " ";
}
}
int main()
{
int arr[7];
push(arr,15,7);
push(arr,6,7);
push(arr,2,7);
push(arr,9,7);
push(arr,17,7);
push(arr,3,7);
display(arr);
std::cout << "\n";
int out = pop(arr);
std::cout << pop << "\n";
return 0;
}
Here is the snapshot of the output
enter image description here
In your implementatiton you have "initialise_top()" function.
void initialise_top(){
top=-1;
}
But you don't call it in main function. If you don't call it you can't initialize "top" variable and "top" variable will hold garbage value.
You can read details in here :
Default variable value
And also in theese lines you have some mistakes:
int out=pop(arr);
std::cout<<pop<<"\n";
you must print "out" variable :
std::cout << out << "\n";
You can look to corrected code for your implementation in here :
https://repl.it/JaOd/0
I have this stack array code in C. You can use it as your guide in implementing it to C++.
#include <stdio.h>
#include <stdlib.h>
void push(void);
void pop(void);
int a[5];
int top = -1;
int counter = 0;
int choice;
main() {
do{
printf("*********************************************\nSTACK\nPress the
corresponding button you desire.\n\nPress 1 to push a number to
stack.\nPress 2 to display the current stack.\nPress 3 to pop the current
stack.\nPress 0 to exit.\n\n");
scanf("%d", &choice);
if(choice == 0){
choice = 0;
}
else if(choice == 1){
push();
}
else if(choice == 2){
int i;
printf("Current Stack:\n");
for(i = 0;i <= 4;i++){
printf("%d", a[i]);
}
printf("\n\n");
}
else if(choice == 3){
pop();
}
}while(choice != 0);
}
void push(){
if(top <= 3){
int input;
printf("Enter number to push: ");
scanf("%d", &input);
top = top + 1;
a[top] = input;
int i;
printf("Current Stack:\n");
for(i = 0;i <= 4;i++){
printf("%d", a[i]);
}
printf("\n\n");
}else{
printf("Out of Bounds\n\n");
exit(0);
}
}
void pop(){
if(top >= 0){
printf("You just popped: ");
printf("%d \n\n", a[top]);
a[top] = 0;
printf("Current Stack:\n");
int i;
for(i = 0;i <= 4;i++){
printf("%d", a[i]);
}
printf("\n\n");
top = top - 1;
}else{
printf("Out of Bounds\n\n");
exit(0);
}
}
#include <iostream>
int top;
void initialise_top(){
top=-1;}
bool stack_empty(int a[]){
if(top==-1)
return true;
else
return false;
}
void push(int a[],int x,int s){
if(top<s-1){
top=top+1;
a[top]=x;
}
else
std::cout<<"overflow"<<"\n";
}
int pop(int a[]){
if (stack_empty(a)==true)
std::cout<<"Underflow"<<"\n";
else{
--top;
return a[top+1];
}
}
void display(int a[]){
for(int i=0;i<=top;i++){
std::cout<<a[i]<<" ";
}
}
int main()
{
**initialise_top();**//this statement initialises top=-1
int arr[7];
//std::cout<<stack_empty(arr)<<"\n";
push(arr,15,7);
push(arr,6,7);
push(arr,2,7);
push(arr,9,7);
push(arr,17,7);
push(arr,3,7);
display(arr);
std::cout<<"\n";
int out=pop(arr);
std::cout<<**out**<<"\n";
return 0;
}
1.In your program the value of top=1 when the first element 15 is inserted. due
to this another value is shown for index 0.
So to have top=0, call the function initialise_top(); in main function.
2.To display 3 instead of 1 use
std::cout<<out<<"\n";
Modifications in the program are bold.
I have tried to improve my code. Please tell me if can improve.
#include <iostream>
#define max 1000
class Stack{
int top;
public:
int a[max];
Stack(){
top=-1;
}
bool stack_empty();
void push(int x);
int pop();
void display();
};
bool Stack::stack_empty(){
if(top==-1)
return true;
else
return false;
}
void Stack::push(int x){
int s=max-1;
if(top<s){
top=top+1;
a[top]=x;
}
else
std::cout<<"overflow"<<"\n";
}
int Stack::pop(){
if (stack_empty()==true)
std::cout<<"Underflow"<<"\n";
else{
--top;
return a[top+1];
}
}
void Stack::display(){
for(int i=0;i<=top;i++){
std::cout<<a[i]<<" ";
}
}
int main()
{
Stack stack1;
stack1.push(15);
stack1.push(6);
stack1.push(2);
stack1.push(9);
stack1.push(3);
stack1.display();
std::cout<<"\n";
std::cout<<stack1.pop()<<"\n";
stack1.display();
return 0;
}
What should be changed in the below code? It shows the following error
ERROR: ld.so: object '/home/bot/funcs.so' from LD_PRELOAD cannot be preloaded (cannot open shared object file): ignored.
Error in `/home/bot/dcb7b4b8f54571a4467c2113b7856878': free(): invalid next size (fast): 0x0000000000c350b0
#include <iostream>
using namespace std;
int merge(int *left,int nl,int *right,int nr,int *a)
{
int i=0,j=0,k=0;
while(i<nl && j<nr)
{
if(left[i]<right[j])
{
a[k]=left[i];
i++;
}
else
{
a[k]=right[j];
j++;
}
k++;
}
while(i<nl)
{
a[k]=left[i];
i++;
}
while(j<nr)
{
a[k]=right[j];
j++;
}
}
int mergesort(int *a,int n)
{
if(n<2) return 0;
int mid=n/2;
int *left=new int[mid];
int *right=new int[n-mid];
for(int i=0;i<=mid-1;i++)
{
left[i]=a[i];
}
for(int i=mid;i<=n-1;i++)
{
right[i]=a[i];
}
mergesort(left,mid);
mergesort(right,n-mid);
merge(left,mid,right,n-mid,a);
delete[]left;
delete[]right;
}
int main() {
//code
int a[]={10,7,8,9,4,2,3,6,5,1};
int n=sizeof(a)/sizeof(a[0]);
mergesort(a,n);
for(int i=0;i<10;i++)
{
cout<<a[i]<<"\t";
}
return 0;
}
Fixes noted in comments, seems to be working now. A one time allocation of a temp array either in main or in a helper function would be faster. Using mutually recursive functions (one merges AtoA, the other merges AtoTemp, they call each other), eliminates having to copy data. I can post an example later if wanted. Bottom up merge sort would be slightly faster.
#include <iostream>
using namespace std;
// fix return type to void
void merge(int *left,int nl,int *right,int nr,int *a)
{
int i=0,j=0,k=0;
while(i<nl && j<nr)
{
if(left[i]<right[j])
{
a[k]=left[i];
i++;
}
else
{
a[k]=right[j];
j++;
}
k++;
}
while(i<nl)
{
a[k]=left[i];
i++;
k++; // fix
}
while(j<nr)
{
a[k]=right[j];
j++;
k++; // fix
}
}
// fix return type to void
void mergesort(int *a,int n)
{
if(n<2) return; // fix: change return type to void
int mid=n/2;
int *left=new int[mid];
int *right=new int[n-mid];
for(int i=0;i<=mid-1;i++)
{
left[i]=a[i];
}
for(int i=mid;i<=n-1;i++)
{
right[i-mid]=a[i]; // fix
}
mergesort(left,mid);
mergesort(right,n-mid);
merge(left,mid,right,n-mid,a);
delete[]left;
delete[]right;
}
int main() {
//code
int a[]={10,7,8,9,4,2,3,6,5,1};
int n=sizeof(a)/sizeof(a[0]);
mergesort(a,n);
for(int i=0;i<10;i++)
{
cout<<a[i]<<"\t";
}
cout << endl; // added this not needed
return 0;
}
Cleanup, changed output to not use tabs:
#include <iostream>
#include <iomanip> // for std::setw()
using namespace std;
void merge(int *left,int nl,int *right,int nr,int *a)
{
int i=0,j=0,k=0;
while(i<nl && j<nr)
{
if(left[i]<right[j])
a[k++]=left[i++];
else
a[k++]=right[j++];
}
while(i<nl)
a[k++]=left[i++];
while(j<nr)
a[k++]=right[j++];
}
void mergesort(int *a,int n)
{
if(n<2)
return;
int mid=n/2;
int *left=new int[mid];
int *right=new int[n-mid];
for(int i=0;i<=mid-1;i++)
left[i]=a[i];
for(int i=mid;i<=n-1;i++)
right[i-mid]=a[i];
mergesort(left,mid);
mergesort(right,n-mid);
merge(left,mid,right,n-mid,a);
delete[]left;
delete[]right;
}
int main() {
int a[]={10,7,8,9,4,2,3,6,5,1};
int n=sizeof(a)/sizeof(a[0]);
mergesort(a,n);
for(int i=0;i<10;i++)
cout<<setw(2)<<a[i]<<" "; // 2 digit field output
cout << endl;
return 0;
}
You should use std::vector instead of raw pointer:
typedef std::vector<int> ivector;
void merge( const ivector &l, const ivector &r, ivector &to )
{
ivector_const::iterator il = l.begin();
ivector_const::iterator ir = r.begin();
ivector::iterator ito = to.begin();
while( true ) {
if( il == l.end() ) {
if( ir == r.end() )
return;
*ito++ = *ir++;
} else {
if( ir == r.end() || *il < *ir )
*ito++ = *il++;
else
*ito++ = *ir++;
}
}
}
void mergesort( ivector &v )
{
if(v.size()<2) return;
ivector::iterator imid = v.begin() + v.size() / 2;
ivector left( v.begin(), imid );
ivector right( imid, v.end() );
mergesort(left);
mergesort(right);
merge( left, right, v );
}
int main() {
//code
ivector a ={10,7,8,9,4,2,3,6,5,1};
mergesort(a);
for(size_t i=0;i<a.size();i++)
{
cout<<a[i]<<"\t";
}
return 0;
}
Note: I did not validate your algorithm just rewrote it with std::vector instead of raw pointer. You can notice how simpler your function become when you use proper data type.
The following is the implementation of http://www.spoj.pl/problems/LITE/ using Segment Tree's with lazy propagation. I am new to segment trees and I cannot understand why I am getting TLE. Could someone please look at it and help me correct my error?
#include <iostream>
#include <iostream>
#include <cstdio>
#include <cstring>
#define MAX 100000
using namespace std;
int M[2*MAX+1];
int flag[2*MAX+1];
int count;
void refresh(int begin,int end,int n)
{
M[n] = end-begin+1 - M[n];
flag[n]=0;
flag[n*2] =!flag[n*2];
flag[n*2+1] =!flag[n*2+1];
}
void update(int begin,int end,int i,int j,int n=1)
{
if(flag[n])
{
refresh(begin,end,n);
}
if(begin>=i && end<=j)
{
if(!flag[n])
{
refresh(begin,end,n);
}
flag[n] = 0;
return;
}
else if(begin>=end)
{
return;
}
else
{
int mid = (begin+end)>>1;
if(i<=mid)
{
update(begin,mid,i,j,n*2);
}
if(j>mid)
{
update(mid+1,end,i,j,n*2+1);
}
if(flag[2*n])
{
refresh(begin,mid,2*n);
}
if(flag[2*n+1])
{
refresh(mid+1,end,2*n+1);
}
M[n] = M[n*2]+ M[n*2+1];
}
}
int query(int begin,int end,int i,int j,int n=1)
{
if(flag[n])
{
refresh(begin,end,n);
}
if(begin>=i && end<=j)
{
return M[n];
}
if(begin>=end)
{
return 0;
}
int mid = (begin+end)>>1;
int l=0,r=0;
if(i<=mid)
{
l = query(begin,mid,i,j,n*2);
}
if(j>mid)
{
r = query(mid+1,end,i,j,n*2+1);
}
if(flag[2*n])
{
refresh(begin,mid,2*n);
}
if(flag[2*n+1])
{
refresh(mid+1,end,2*n+1);
}
M[n] = M[n*2]+ M[n*2+1];
return l+r;
}
int main()
{
memset(M,0,sizeof M);
int n,m,a,b,c;
scanf("%d%d",&n,&m);
for(int i=0; i<m; i++)
{
scanf("%d%d%d",&a,&b,&c);
if(a==0)
{
update(1,n,b,c);
}
else
{
printf("%d\n",query(1,n,b,c));
}
}
return 0;
}
M[node]^=1; might be faster than M[node] = (M[node]==0)?1:0;, and (begin+end)>>1 faster than (begin/end)/2, but not very relevant
LE: Try if making the recursive functions inline will run faster. I think it unravels the recursion a couple of times and works a little bit faster. Maybe sending the parameters as references will make it run faster, try that out. If the test cases are chosen properly you still shouldn't be able to pass the tests with this trickery, but it helps sometimes.