I just set up a basic folder structure for a new project, however I am doing it a bit different than the standard file structure, since my front-end is in React and will be in a separate git repository. The problem is, my virtual environment is installed in the "backend-django" project and when I try to access my package imports (that I installed in my virtual env) in backend/settings.py it does not recognize them.
As an example: I pip installed django-environ into my venv but when I go to settings.py (like I normally do) and import environ, I get a 'no module named environ' error.
This is my first foray into Django (clearly). For reference, I have previously only used Flask for Python projects. Any help is appreciated!
A mockup of my basic folder structure is here:
folder structure
I have already tried from backend-django import environ and from . import environ. I am still getting the same error.
just started using pycharm on a existing project, and having difficulty using the run/debug configurations in order to run the test server. The issue stems from their being no settings.py module as standard in django projects. Instead there is settings_base.py and then two different settings modules (settings_live.py and settings_test.py) that extend it by using 'from settings_base import *'. This causes manage.py to fail when running runserver because it can't find settings.py.
In the Django Support settings I have set the project root, and set Settings to settings_test.py however this has not helped. In the Django server run configuration I have setup I also have...
DJANGO_SETTINGS_MODULE=settings_test
... in the Environment Variables section. However when I use runserver it still says
Error: Can't find the file 'settings.py' in the directory containing '/home/pete/Projects/the_project/manage.py'. It appears you've customized things.
You'll have to run django-admin.py, passing it your settings module.
(If the file settings.py does indeed exist, it's causing an ImportError somehow.)
I tried wrapping the entire settings_test.py module in a try/except to see if it really was an import error, however it did not seem to work. Is there something I am missing?
Maybe you should try adding --settings=settings_test to the "Additional options" in your PyCharm Run configuration and make sure that "Working directory" points to correct path.
I'm trying to set up Pinax and I'm new to everything involved (Django, Pinax, webservers, etc). I'm following http://pinax.readthedocs.org/en/latest/gettingstarted.html
When I generate a project using:
(mysite-env)$ pinax-admin setup_project -b basic mysite
The directory structure I get is:
apps __init__.py manage.py settings.pyc urls.py
dev.db __init__.pyc requirements static urls.pyc
fixtures locale settings.py templates wsgi.py
Which as far as I can tell is missing the deployment folder (when you compare to the directory structure shown here : http://pinax.readthedocs.org/en/latest/starterprojects.html). It doesn't seem to be effecting anything yet, but it makes me nervous. What is going on and is the fact I'm missing the deployment folder going to cause problems in the future?
I'm running Ubuntu and using python 2.7. I had the same behaviour with Windows 7, python 2.6
Thanks!
The new Django versions have made the old pinax pretty much useless. Now Django supports project templates and Pinax is separated into several smaller projects regarding starter projects (such as pinax-project-account) and apps (such as django-user-account).
The current way to use pinax is to choose a starter project, and then running something like:
$ django-admin.py startproject --template=https://github.com/pinax/pinax-project-account/zipball/master <project_name>
and then install requirements:
$ pip install -r requirements.txt
This will create a new Django project using the starter-project as a template, which already includes a few apps (like django-user-account) and templates (with bootstrap!). The project is ready to run, and already includes a bunch of functionality (like user registration, login and management).
Also, Django has changed the project directory structure a bit, so now it doesn't really look like that anymore.
I am a newbie at Django and everytime I try to run
python panel/manage.py startapp %app% (panel is my project) it gives me the error:
Error: '%app%' conflicts with the name of an existing Python module and cannot be used as an app name. Please try another name.
Am I doing something wrong?
Surely companies or contacts or stats is not the name of an existing Python module?
This is a fun one - your project and your app need to have different names. You probably created a project, then tried to startapp with the same name.
I was confused as well, until I realized that a Django project is a container for applications; this sequence makes it a bit clearer:
# first create a Project (container).
django-admin.py startproject Project
# create multiple apps
cd Project
python manage.py startapp polls
python manage.py startapp hello
...
Perhaps you need to
cd panel
python manage.py startapp yourappname
I'm not sure running the command from a directory above your project will work properly.
I had the same issue because I was trying to "restart" my app after carrying out changes, but startapp is meant to be used once to create a new app. To view changes, syncronize app with DB with python manage.py migrate and restart the server with python manage.py runserver instead.
From the django-admin docs
(manage.py does essentially the same thing as django-admin)
startapp <app_label> [destination]
django-admin startapp
Creates a Django app directory structure for
the given app name in the current directory or the given destination.
By default the directory created contains a models.py file and other
app template files. (See the source for more details.) If only the app
name is given, the app directory will be created in the current
working directory.
If the optional destination is provided, Django will use that existing
directory rather than creating a new one. You can use ‘.’ to denote
the current working directory.
For example:
django-admin startapp myapp /Users/jezdez/Code/myapp
This message is displayed if you run "startapp" twice with the same app name. As pointed out above by the OP it doesn't reload the app, it creates one.
You should choose different names for your project and app in Codes:
django-admin startproject **my_project**
python manage.py startapp **my_app**
You need to create the directory before using the commands. Suppose you want a polls app inside apps folder.
mkdir apps apps/polls
python manage.py startapp polls apps/polls
I guess maybe you have already created the app's dir in panel dir manually. The command 'startapp' is to create an app automatically. If you already have one there, it fails.
I reproduced the issue and there's actually something not working as I expected.
I wonder if we stumbled upon a Django's bug, or a limitation that I don't understand.
Having a project called "project" and an empty folder app/newapp
…I tried:
python manage.py startapp newapp apps/newapp
It returns:
CommandError: 'newapp' conflicts with the name of an existing Python module and cannot be used as an app name. Please try another name.
But if I target ANY other route in which the last folder is not called the same name as the app I'm starting, it works.
So I ended up doing:
python manage.py startapp newapp apps/main
Using Django 2.1.3.
if you want to make an empty directory that will contain your new app
project-dir
└── blog
├── __init__.py
├── ...
├── blog-ext #this empty dir that will contain the new app
└── views.py
so instead of typing :
python manage.py newapp blog/blog-ext
it should be :
django-admin startapp newapp blog/blog-ext
Try classic "mysite" or "myproject". You can delete it anytime you want, so if it will accepted, then all your privious ideas conflict with Python modules.
Edit: I tried all your ideas, there was no error for me. So, if you installed support libraries or modules for django, then some of them can contains such names.
this error is because of the name conflicts between the app name and project name.you had given same name for your app and project .your project and app need to be different name .if you had given the same name the above mentioned error will occur .
understand the difference between app and project
Projects vs. apps
What’s the difference between a project and an app? An app is a Web application that does something – e.g., a Weblog system, a database of public records or a simple poll app. A project is a collection of configuration and apps for a particular Web site. A project can contain multiple apps. An app can be in multiple projects.
first create the project.
then create the app.
NOTE: name for app and project should be different
first create a project with projectname
django-admin.py startproject Projectname .
Then create app with appname. (to create your app make sure you are in the same directory manage.py and type this command)
python manage.py startapp Appname
It's the process how I got my doubt clear.
First, I created a directory inside my project directory and put __init__.py, models.py, admin.py, apps.py & views.py.
Then I ran python manage.py runserver & It work well.
Then as suggested on that page I used startapp command. I got this error :
CommandError: 'ucportal' conflicts with the name of an existing Python
module and cannot be used as an app name. Please try another name.
After that I deleted that directory and ran startapp command with same name and it worked fine.
So 'startapp' command is to create an app automatically. If you already have one there, it fails.
Answer given by #DAG worked for me.
I ran into this issue while trying to set up a Wagtail project.
Before creating the app, I had created and activated a virtualenv (using virtualenvwrapper) with the same name: $APPNAME. When I then ran wagtail start $APPNAME, Django looks for naming conflics in the $PYTHONPATH which in this instance points to /Users/User/.virtualenvs.
Naturally, this results in a conflict as /Users/User/.virtualenvs/$APPNAME already exists.
None of these answers helped me. In the end I ended up creating an app with a different name and then just renaming the directory to the app name I wanted all along. Note that you also will need to change the class name in apps.py to match your app name.
Just Simply Use This command
for Django Project Creation
python -m django startproject name_of_django_Project
for Django App Creation
python -m django startapp App_name
I had the same issue when working with wagtail cms. I got this error even there is no such a created app. This occurs when there is an app already that has the same name you need to create inside the site-packages directory.
Once you get this error, you need to check the following directory,
C:\Users\{user}\AppData\Local\Programs\Python\Python38-32\Lib\site-packages
If there is a package with the name same you want to create then you need to remove that package. Also make sure to check that package is important or not before deleting.
The application directory should be created first.
Example: apps/practice
The command appears to be duplicated, but it is correct.
Example: python manage.py startapp practice ./apps1/practice
I am using django with mod_python (I know it is deprecated -- I am just doing this for an exercise), and am getting the following error --
"Could not import project.views. Error was: No module named app.models"
I am getting the 'No module named app.models" in several other places as well. My syncdb is working fine, and if I go into the manage.py shell I can import the models fine. Why is this occurring and what do I need to change? Thank you.
You should use absolute imports everywhere. If your project is structured like so:
/project/settings.py
/project/app/models.py
/project/app/views.py
In INSTALLED_APPS you would use project.app. In app you'd import your models into views: import project.app.models, etc. Alternately you can try adjusting your PYTHONPATH so your imports work. When you run ./manage.py you are in your project folder, and Python automatically adds it to the PYTHONPATH. This doesn't happen automatically in most deployment scenarios (mod_python or other wise).