Regex: Check if string contains at least one digit - regex

Question

I have got a text string like this:
test1test
I want to check if it contains at least one digit using a regex.
What would this regex look like?

Answer 1

I'm surprised nobody has mentioned the simplest version:
\d
This will match any digit. If your regular expression engine is Unicode-aware, this means it will match anything that's defined as a digit in any language, not just the Arabic numerals 0-9.
There's no need to put it in [square brackets] to define it as a character class, as one of the other answers did; \d works fine by itself.
Since it's not anchored with ^ or $, it will match any subset of the string, so if the string contains at least one digit, this will match.
And there's no need for the added complexity of +, since the goal is just to determine whether there's at least one digit. If there's at least one digit, this will match; and it will do so with a minimum of overhead.

Answer 2

The regular expression you are looking for is simply this:
[0-9]
You do not mention what language you are using. If your regular expression evaluator forces REs to be anchored, you need this:
.*[0-9].*
Some RE engines (modern ones!) also allow you to write the first as \d (mnemonically: digit) and the second would then become .*\d.*.

Answer 3

In Java:
public boolean containsNumber(String string)
{
return string.matches(".*\\d+.*");
}

Answer 4

you could use look-ahead assertion for this:
^(?=.*\d).+$

Answer 5

Another possible solution, in case you're looking for all the words in a given string, which contain a number
Pattern
\w*\d{1,}\w*
\w* - Matches 0 or more instances of [A-Za-z0-9_]
\d{1,} - Matches 1 or more instances of a number
\w* - Matches 0 or more instances of [A-Za-z0-9_]
The whole point in \w* is to allow not having a character in the beginning or at the end of a word. This enables capturing the first and last words in the text.
If the goal here is to only get the numbers without the words, you can omit both \w*.
Given the string
Hello world 1 4m very happy to be here, my name is W1lly W0nk4
Matches
1 4m W1lly W0nk4
Check this example in regexr - https://regexr.com/5ff7q

Answer 6

Ref this
SELECT * FROM product WHERE name REGEXP '[0-9]'

Answer 7

This:
\d+
should work
Edit, no clue why I added the "+", without it works just as fine.
\d

Answer 8

In perl:
if($testString =~ /\d/)
{
print "This string contains at least one digit"
}
where \d matches to a digit.

Answer 9

If anybody falls here from google, this is how to check if string contains at least one digit in C#:
With Regex
if (Regex.IsMatch(myString, #"\d"))
{
// do something
}
Info: necessary to add using System.Text.RegularExpressions
With linq:
if (myString.Any(c => Char.IsDigit(c)))
{
// do something
}
Info: necessary to add using System.Linq