an error "has no member named" - c++

Question

I have this snippet of the code
account.cpp
#include "account.h"
#include <iostream>
#include <string>
using namespace std;
Account::Account(string firstName, string lastName, int id)
: strFirstName(firstName), strLastName(lastName), nID(id) {}
void Account::printAccount(){
cout << strFirstName;
}
account.h
#include <string>
using std::string;
class Account{
private:
string strLastName; //Client's last name
string strFirstName; //Client's first name
int nID; //Client's ID number
int nLines; //Number of lines related to account
double lastBill;
public:
Account(string firstName, string lastName, int id);
void printAccount();
};
company.h
#ifndef CELLULAR_COMPANY_H
#define CELLULAR_COMPANY_H
#include <string>
#include <list>
#include <iostream>
#include "account.h"
using namespace std;
class Company {
private:
list<Account> listOfAccounts;
public:
void addAccount(string firstName, string lastName, int id) {
Account newAccount(firstName, lastName, id);
listOfAccounts.push_back(newAccount);
}
void printAccounts(){
for(list<Account>::iterator i = listOfAccounts.begin(); i != listOfAccounts.end(); ++i){
i.printAccount; //here bug
}
}
};
#endif // CELLULAR_COMPANY_H
main.cpp
#include "cellularcompany.h"
int main(){
Company newCompany;
newCompany.addAccount("Pavel", "Nedved", 11111);
newCompany.printAccounts();
return 0;
}
can somebody please explain what does my error mean? thanks in advance (I have it in company.h see comment there)
I have bug 'struct std::_List_iterator<Account>' has no member named 'printAccount'

Answer 1

You forgot the parentheses after printAccount(). Otherwise, it's not a method call. Also, you need to use the -> operator, since it's an iterator.
for(list<Account>::iterator i = listOfAccounts.begin();
i != listOfAccounts.end(); ++i)
{
i->printAccount(); // Note the ()!
// This is equivalent to (*i).printAccount();
}

Answer 2

Try to change i.printAccount; to i->printAccount();