C++ initializing constants and inheritance - c++

I want to initialize constant in child-class, instead of base class. And use it to get rid of dynamic memory allocation (I know array sizes already, and there will be a few child-classes with different constants).
So I try:
class A {
public:
const int x;
A() : x(0) {}
A(int x) : x(x) {}
void f() {
double y[this->x];
}
};
class B : A {
B() : A(2) {}
};
Pretty simple, but compiler says:
error C2057: expected constant expression
How can I say to compiler, that it is really a constant?

It isn't a constant though. It can still be modified by the constructor. Only a compile time constant is allowed for the size of an array. When the compiler says "constant expression", it is not meaning an expression which returns a constant value, but an constant, such as "52" or "45" or something along those lines.
Use std::vector instead.
EDIT: In response to "I know array sizes already, and there will be a few child-classes with different constants"
The only way to do that is to use a template.
template<size_t x>
class A {
public:
void f() {
double y[x];
}
};
typedef A<2> B;

The behaviour you expect could be achieved using the following template.
Note that this is actually unreliable, disgusting and could be used only as "a sample". Use std::vector instead.
template <size_t a = 0>
class A {
public:
A() { }
void f() {
int y[a];
y[0] = 5;
}
};
class B : A<2> {
B() { }
};
void main() {
A<1> a;
a.f();
// Undefined behaviour - creating an array of size 0
// At least, MSVS2008 treats it as an error :)
// A<0> a_;
}

There's "constant", and then there's "constant". If you want to allocate an array on the stack like that, the compiler needs the length of the array at compile time, and based on what you've given there it can't figure that out. Interestingly, gcc supports an extension (not supported in standard C++) that allows for stack allocation for variable lengths.

I don't know if it will work for your purposes, but one possibility would be to make it a template parameter:
template <int size>
class A {
double y[size];
};
In this case, you'd probably want to create an instance of A in B instead of using inheritance.
The other obvious possibility would be to use a tr1::array object instead. This is is also a template, so the idea is pretty much the same, but it's already written, tested and working so you can avoid all that. If your compiler doesn't supply TR1 classes, Boost has a mostly conforming implementation (boost::array).

Related

C++ - initializing variables in header vs with constructor

Regarding the following, are there any reasons to do one over the other or are they roughly equivalent?
class Something
{
int m_a = 0;
};
vs
class Something
{
int m_a;
Something(int p_a);
};
Something::Something(int p_a):m_a(p_a){ ... };
The two code snippets you posted are not quite equal.
class Something
{
int m_a = 0;
};
Here you specify the value with which to initialise, i.e. 0, at compile time.
class Something
{
int m_a;
Something(int p_a);
};
Something::Something(int p_a):m_a(p_a){ ... };
And here you do it at run time (or possibly at run time), with the value p_a not known until the constructor is called.
The following piece of code comes closer to your first example:
class Something
{
int m_a;
Something();
};
Something::Something() : m_a(0) { /* ... */ };
What you have to consider here is that in the first case, the value appears directly in the class definition. This may create an unnecessary dependency. What happens if you need to change your 0 to 1 later on? Exposing the value directly in the class definition (and thus, usually, in a header file) may cause recompilation of a lot of code in situations where the other form of initialisation would avoid it, because the Something::Something() : m_a(0) part will be neatly encapsulated in a source file and not appear in a header file:
// Something.h - stable header file, never changed
class Something
{
int m_a;
Something();
};
// Something.cpp - can change easily
Something::Something() : m_a(0) { /* ... */ };
Of course, the benefits of in-class initialisation may vastly outweigh this drawback. It depends. You just have to keep it in mind.
The first form is more convenient if you have more than one constructor (and want them all to initialise the member in the same way), or if you don't otherwise need to write a constructor.
The second is required if the initialiser depends on constructor arguments, or is otherwise too complicated for in-class initialisation; and might be better if the constructor is complicated, to keep all the initialisation in one place. (And it's also needed if you have to support pre-C++11 compilers.)
The first form is new to C++11 and so at this point isn't terribly well supported, especially if you need to support a variety of older compilers.
Otherwise they should be roughly equivalent when a C++11 compiler is available.
Elaborating on Christian Hackl's answer.
The first form allows to initialize m_a and have a default c'tor at the same time. Or you can even be explicit in your code and define a constructor with the default keyword:
class Something
{
int m_a = 0;
// explicitly tell the compiler to generate a default c'tor
Something() = default;
};
With the second form, an auto-generated default c'tor would leave m_a uninitialized, so if you want to initialize to a hard-coded value, you have to write your own default c'tor:
class Something
{
int m_a;
// implement your own default c'tor
Something() : m_a(0) {}
};
class Something
{
int m_a = 0;
};
is equivalent to
class Something
{
int m_a(0);
};
So, doing
class Something
{
int m_a;// (0) is moved to the constructor
public:
Something(): m_a(0){}
};
yields a uniform syntax for initialization that requires or does not require run-time input.
Personally I don't like the first form because it looks like an "declaration then assignment", which is complete misconception.
If you change the code like what Christian did to make them do the same thing. Now it is a tradeoff between compile-time optimization (which Christian explained completely) and run-time optimization.
class Foo{
public:
Vector<double> vec1;
.
.
.
Vector<double> vecN;
}
Imagine you have to initialize each vector by some predefined doubles. If the program must instantiate many and many objects of this class, it is better to initialize the vectors in the header file to make the user happy by reducing the run-time!
Even though it's supported, this type of initialization will create bugs that will be pretty hard to track down. It's the type of "aesthetic optimization" that you will regret a couple months down the road.
See the example below:
class_x_1.h:
class X
{
private:
int x = 10;
public:
int GetX();
};
class_x_2.h:
class X
{
private:
int x = 20;
public:
int GetX();
};
class_x.cpp:
#include "class_x_1.h" // implementation uses the version that initializes x with 10
int X::GetX()
{
return x;
}
main.cpp:
#include "class_x_2.h" // main includes definition that initializes x with 20
#include <iostream>
int main()
{
X x;
std::cout << x.GetX() << std::endl;
return 0;
}
Output:
20
As expected, it will return 20 because this is the version that initializes x with 20. However, if you go to the implementation of X, you might expected it to be 10.

Safety of reinterpret_cast on pointer to template aggregate type

I would like to know if my following use of reinterpret_cast is undefined behaviour.
Given a template aggregate such as ...
template<typename T>
struct Container
{
Container(T* p) : ptr(p) { }
...
T* ptr;
};
... and a type hierarchy like ...
struct A { };
struct B : A { };
Is the following cast safe, given that B is a dynamic type of A ...
Container<B>* b = new Container<B>( new B() );
Container<A>* a = reinterpret_cast<Container<A>*>(b);
... in so far as that I can now safely use a->ptr and its (possibly virtual) members?
The code where I use this compiles and executes fine (Clang, OS X) but I'm concerned that I've placed a ticking bomb. I guess every instance of Container<T> shares the same layout and size so it shouldn't be a problem, right?
Looking at what cppreference.com says about reinterpret_cast, there seems to be a statement for legal use that covers what I'm trying to do ...
Type aliasing
When a pointer or reference to object of type T1 is reinterpret_cast (or C-style cast) to a pointer or reference to object of a different type T2, the cast always succeeds, but the resulting pointer or reference may only be accessed if both T1 and T2 are standard-layout types and one of the following is true:
...
T2 is an aggregate type or a union type which holds one of the aforementioned types as an element or non-static member (including, recursively, elements of subaggregates and non-static data members of the contained unions): this makes it safe to cast from the first member of a struct and from an element of a union to the struct/union that contains it.
I appreciate that it looks like I'm going the wrong way about this. That's not what I'm concerned about. I'd just like to know if what I'm doing is safe / legal or not. Thanks in advance for any help.
there seems to be a statement for legal use that covers what I'm trying to do ...
That's not what that exception says or means. That exception says that given
struct S { int i; } s;
you can use *reinterpret_cast<int *>(&s) to access s.i.
There is no similar exception for what you're trying to do. What you're trying to do is simply not valid in C++. Even the below is invalid:
struct S { int i; };
struct T { int i; };
int f(S s) { return ((T &) s).i; }
and compilers optimise based on the assumption that you don't write code like that.
For an actual example that fails at run-time with a current compiler:
#include <cstdlib>
struct S { int i; };
struct T { int i; };
void f(S *s, T *t) { int i = s->i; t->i++; if (s->i == i) std::abort(); }
Here, GCC optimises away the check s->i == i (GCC 4.9.2, with -O2 in the command-line options), and unconditionally calls std::abort(), because the compiler knows that s and t cannot possibly point to the same region of memory. Even though you might try to call it as
int main() { S s = { 0 }; f(&s, reinterpret_cast<T *>(&s)); }
Whether or not the type aliasing is legal according to the standard, you may have other issues.
I guess every instance of Container<T> shares the same layout and
size so it shouldn't be a problem, right?
Actually, not every instance of Container<T> shares the same layout! As explained in this question, template members are only created if they are used, so your Container<A> and Container<B> might have different memory layouts if different members are used for each type.

Aligned storage and standard layout

Consider the following C++11 code:
#include <type_traits>
struct bar
{
virtual void do_bar() const {}
};
struct foo
{
std::aligned_storage<sizeof(bar),alignof(bar)>::type m_storage;
};
bar is not standard layout because of the virtual function do_bar(). However, foo is standard layout as the type provided by std::aligned_storage is a POD type and foo satisfies all the other requirements for standard layout types.
What happens then when I use the m_storage storage with placement new to construct an instance of bar? E.g.,
foo f;
::new(static_cast<void *>(&f.m_storage)) bar();
Is this legal? Can I use this to cheat my way around restrictions about standard layout types?
Here's your code again:
struct bar {
virtual void do_bar() const {}
};
struct foo {
std::aligned_storage<sizeof(bar), alignof(bar)>::type m_storage;
};
This is fine. struct foo is a standard-layout type, and, given an instance foo myFoo, you can construct an object of type bar into myFoo.m_storage.
However, this is completely pointless from the compiler's POV, so why bother with it? As #dyp wisely said in the comments, "Why do you want foo to be standard-layout?"
You handwaved something about unions. Well, that's fine. You can write this:
union DoesntWork {
bar b; // compiler error in C++11 due to non-standard-layout type
int i;
};
union DoesWork {
foo f; // works fine in C++11, of course
int i;
};
However, equally obviously, you cannot expect this to work:
struct car {
int initialsequence;
};
struct bar {
int initialsequence;
virtual void do_bar() const {}
};
struct foo {
std::aligned_storage<sizeof(bar), alignof(bar)>::type m_storage;
bar& asBar() { return *reinterpret_cast<bar*>(&m_storage); }
};
union JustSilly {
foo f;
car c;
} js;
assert(&js.c.initialsequence == // Fails, because no matter how many
&js.f.asBar().initialsequence); // casts you add, bar still has a vptr!
In other words, you're free to lie to the compiler (via type-punning and reinterpret_cast), but that doesn't make your lies true. ;)
See also: XY problem.
Tried in OSX's XCode C++11 compiler option, and seems to work for me. Of course, you probably want to do "::new(static_cast(&f.m_storage)) bar();" in foo's constructor and invoke its destructor in foo's destructor.
When working with aligned quantities
1) It is advisable to specify alignment for the class or struct using declspec(align(16)) or __attribute((aligned(16))). I have encounter some errors when enabling optimization using VS2010, when I didn't do this.
2) I usually avoid overloading new and use the placement operator like you suggest, e.g.
#include <new> // Remember this otherwise the placement operator is not defined
SomeClass* c = (SomeClass*) _mm_malloc(sizeof(SomeClass),16);
new c SomeClass(); // This is perfectly legal
// Some work
_mm_free(c);
3) A good rules of thumb is to place aligned quantities at the start of your struct or class. This way the compiler won't do zero-padding in between members and warn about this.

Empty array declaration - strange compiler behavior

I've found a strange looking piece of code in a project I have to maintain. There's an empty array member of a class which doesn't lead to an compiler error. I've tested some variations of such a code with MSVC 10.0:
template<class T> struct A {
int i[];
}; // warning C4200: nonstandard extension used : zero-sized array in struct/union
template<class T> struct B { static int i[]; };
template<class T> int B<T>::i[];
struct C {
int i[];
}; //warning C4200: nonstandard extension used : zero-sized array in struct/union
template<class T> struct D { static int i[]; };
template<class T> int D<T>::i[4];
template<> int D<int>::i[] = { 1 };
int main()
{
A<void> a;
B<void> b;
C c;
D<void> d0;
D<int> d1;
a.i[0] = 0; // warning C4739: reference to variable 'a' exceeds its storage space
b.i[0] = 0; // warning C4789: destination of memory copy is too small
c.i[0] = 0; // warning C4739: reference to variable 'c' exceeds its storage space
int i[]; // error C2133: 'i' : unknown size
d0.i[0] = 0; // ok
d0.i[1] = 0; // ok
return 0;
}
The error message at int i[] is absolutely sensible to me. The code which is shown with class D is well-formed standard C++. But what's about the classes A, B and C? What kind of types are the member variables int i[] in this classes?
EDIT:
your doubt is explained by the definition of the extension to the language, which allows for zero-sized arrays at the end of structs/unions. I have not tried it, but if you declare another member after the zero-sized array, it should fail.
so, if you allocate a variable on the stack, you have to know its size; the exception to the rule is when allocating an array at the end of a struct/union, where some C-typical trickery is possible.
In c++ this raises a warning because the default copy constructor and assignment operator will probably not work.
PREVIOUS ANSWER:
The compiler warns you about the fact that you are trying to define an array with zero size. This is not allowed in standard C/C++.
Let's see the differences class by class.
In class D:
template<class T> struct D { static int i[]; };
it works because you are just declaring the type of a static member variable. For this to link, you need also defining the actual array, in a definition statement like you do:
template<> int D<int>::i[] = { 1 };
here you also specify the size of the array through the initializer.
With class B, you are doing something similar, but the definition is:
template<class T> int B<T>::i[];
i.e., you don't specify the size and get the warning.
With class A, more of the same, you are defining a member variable of type array without the size.
Good one. Just to be certain, you are wondering why the compiler isn't flagging it as an error right? In that case, I think this problem is unpredictable across compilers but I'm aware of this happening on MSVC all the time.
http://support.microsoft.com/kb/98409
Let me see if I can explain it like they did. If I were to declare a struct with an empty array like this,
struct a
{
int x;
char empty[];
};
the compiler might allocate 4 bytes for x and probably another 4 bytes for the char pointer. empty will contain the address 4 bytes past the start of struct a.
Since it is a character array of no length, trying to access it would be an error since there is no trailing 0 to signify the end of the string.
I could choose to initialize the struct later to point to the start of an actual string to overcome this error.
struct a myStruct = { 1, "hello world"}; // empty now points to the start of "hello world"
Since a struct is basically a class, turns out you can do the same thing with a class if you make sure its an aggregate and not a full class.
So there ya go. MSVC compilers treat arrays with no fixed sized as a pointer when declared within a struct/class. Remember that class definitions are merely just declarations. The compiler doesn't allocate space for them until you create an instance for it. When you start to think about it, it sorta makes since. How will the compiler know if you plan to allocate storage for it later. It becomes a run-time artifact but the compiler was still smart enough to warn you about the problem.

Hidden Features of C++? [closed]

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No C++ love when it comes to the "hidden features of" line of questions? Figured I would throw it out there. What are some of the hidden features of C++?
Most C++ programmers are familiar with the ternary operator:
x = (y < 0) ? 10 : 20;
However, they don't realize that it can be used as an lvalue:
(a == 0 ? a : b) = 1;
which is shorthand for
if (a == 0)
a = 1;
else
b = 1;
Use with caution :-)
You can put URIs into C++ source without error. For example:
void foo() {
http://stackoverflow.com/
int bar = 4;
...
}
Pointer arithmetics.
C++ programmers prefer to avoid pointers because of the bugs that can be introduced.
The coolest C++ I've ever seen though? Analog literals.
I agree with most posts there: C++ is a multi-paradigm language, so the "hidden" features you'll find (other than "undefined behaviours" that you should avoid at all cost) are clever uses of facilities.
Most of those facilities are not build-in features of the language, but library-based ones.
The most important is the RAII, often ignored for years by C++ developers coming from the C world. Operator overloading is often a misunderstood feature that enable both array-like behaviour (subscript operator), pointer like operations (smart pointers) and build-in-like operations (multiplying matrices.
The use of exception is often difficult, but with some work, can produce really robust code through exception safety specifications (including code that won't fail, or that will have a commit-like features that is that will succeed, or revert back to its original state).
The most famous of "hidden" feature of C++ is template metaprogramming, as it enables you to have your program partially (or totally) executed at compile-time instead of runtime. This is difficult, though, and you must have a solid grasp on templates before trying it.
Other make uses of the multiple paradigm to produce "ways of programming" outside of C++'s ancestor, that is, C.
By using functors, you can simulate functions, with the additional type-safety and being stateful. Using the command pattern, you can delay code execution. Most other design patterns can be easily and efficiently implemented in C++ to produce alternative coding styles not supposed to be inside the list of "official C++ paradigms".
By using templates, you can produce code that will work on most types, including not the one you thought at first. You can increase type safety,too (like an automated typesafe malloc/realloc/free). C++ object features are really powerful (and thus, dangerous if used carelessly), but even the dynamic polymorphism have its static version in C++: the CRTP.
I have found that most "Effective C++"-type books from Scott Meyers or "Exceptional C++"-type books from Herb Sutter to be both easy to read, and quite treasures of info on known and less known features of C++.
Among my preferred is one that should make the hair of any Java programmer rise from horror: In C++, the most object-oriented way to add a feature to an object is through a non-member non-friend function, instead of a member-function (i.e. class method), because:
In C++, a class' interface is both its member-functions and the non-member functions in the same namespace
non-friend non-member functions have no privileged access to the class internal. As such, using a member function over a non-member non-friend one will weaken the class' encapsulation.
This never fails to surprise even experienced developers.
(Source: Among others, Herb Sutter's online Guru of the Week #84: http://www.gotw.ca/gotw/084.htm )
One language feature that I consider to be somewhat hidden, because I had never heard about it throughout my entire time in school, is the namespace alias. It wasn't brought to my attention until I ran into examples of it in the boost documentation. Of course, now that I know about it you can find it in any standard C++ reference.
namespace fs = boost::filesystem;
fs::path myPath( strPath, fs::native );
Not only can variables be declared in the init part of a for loop, but also classes and functions.
for(struct { int a; float b; } loop = { 1, 2 }; ...; ...) {
...
}
That allows for multiple variables of differing types.
The array operator is associative.
A[8] is a synonym for *(A + 8). Since addition is associative, that can be rewritten as *(8 + A), which is a synonym for..... 8[A]
You didn't say useful... :-)
One thing that's little known is that unions can be templates too:
template<typename From, typename To>
union union_cast {
From from;
To to;
union_cast(From from)
:from(from) { }
To getTo() const { return to; }
};
And they can have constructors and member functions too. Just nothing that has to do with inheritance (including virtual functions).
C++ is a standard, there shouldn't be any hidden features...
C++ is a multi-paradigm language, you can bet your last money on there being hidden features. One example out of many: template metaprogramming. Nobody in the standards committee intended there to be a Turing-complete sublanguage that gets executed at compile-time.
Another hidden feature that doesn't work in C is the functionality of the unary + operator. You can use it to promote and decay all sorts of things
Converting an Enumeration to an integer
+AnEnumeratorValue
And your enumerator value that previously had its enumeration type now has the perfect integer type that can fit its value. Manually, you would hardly know that type! This is needed for example when you want to implement an overloaded operator for your enumeration.
Get the value out of a variable
You have to use a class that uses an in-class static initializer without an out of class definition, but sometimes it fails to link? The operator may help to create a temporary without making assumptins or dependencies on its type
struct Foo {
static int const value = 42;
};
// This does something interesting...
template<typename T>
void f(T const&);
int main() {
// fails to link - tries to get the address of "Foo::value"!
f(Foo::value);
// works - pass a temporary value
f(+Foo::value);
}
Decay an array to a pointer
Do you want to pass two pointers to a function, but it just won't work? The operator may help
// This does something interesting...
template<typename T>
void f(T const& a, T const& b);
int main() {
int a[2];
int b[3];
f(a, b); // won't work! different values for "T"!
f(+a, +b); // works! T is "int*" both time
}
Lifetime of temporaries bound to const references is one that few people know about. Or at least it's my favorite piece of C++ knowledge that most people don't know about.
const MyClass& x = MyClass(); // temporary exists as long as x is in scope
A nice feature that isn't used often is the function-wide try-catch block:
int Function()
try
{
// do something here
return 42;
}
catch(...)
{
return -1;
}
Main usage would be to translate exception to other exception class and rethrow, or to translate between exceptions and return-based error code handling.
Many know of the identity / id metafunction, but there is a nice usecase for it for non-template cases: Ease writing declarations:
// void (*f)(); // same
id<void()>::type *f;
// void (*f(void(*p)()))(int); // same
id<void(int)>::type *f(id<void()>::type *p);
// int (*p)[2] = new int[10][2]; // same
id<int[2]>::type *p = new int[10][2];
// void (C::*p)(int) = 0; // same
id<void(int)>::type C::*p = 0;
It helps decrypting C++ declarations greatly!
// boost::identity is pretty much the same
template<typename T>
struct id { typedef T type; };
A quite hidden feature is that you can define variables within an if condition, and its scope will span only over the if, and its else blocks:
if(int * p = getPointer()) {
// do something
}
Some macros use that, for example to provide some "locked" scope like this:
struct MutexLocker {
MutexLocker(Mutex&);
~MutexLocker();
operator bool() const { return false; }
private:
Mutex &m;
};
#define locked(mutex) if(MutexLocker const& lock = MutexLocker(mutex)) {} else
void someCriticalPath() {
locked(myLocker) { /* ... */ }
}
Also BOOST_FOREACH uses it under the hood. To complete this, it's not only possible in an if, but also in a switch:
switch(int value = getIt()) {
// ...
}
and in a while loop:
while(SomeThing t = getSomeThing()) {
// ...
}
(and also in a for condition). But i'm not too sure whether these are all that useful :)
Preventing comma operator from calling operator overloads
Sometimes you make valid use of the comma operator, but you want to ensure that no user defined comma operator gets into the way, because for instance you rely on sequence points between the left and right side or want to make sure nothing interferes with the desired action. This is where void() comes into game:
for(T i, j; can_continue(i, j); ++i, void(), ++j)
do_code(i, j);
Ignore the place holders i put for the condition and code. What's important is the void(), which makes the compiler force to use the builtin comma operator. This can be useful when implementing traits classes, sometimes, too.
Array initialization in constructor.
For example in a class if we have a array of int as:
class clName
{
clName();
int a[10];
};
We can initialize all elements in the array to its default (here all elements of array to zero) in the constructor as:
clName::clName() : a()
{
}
Oooh, I can come up with a list of pet hates instead:
Destructors need to be virtual if you intend use polymorphically
Sometimes members are initialized by default, sometimes they aren't
Local clases can't be used as template parameters (makes them less useful)
exception specifiers: look useful, but aren't
function overloads hide base class functions with different signatures.
no useful standardisation on internationalisation (portable standard wide charset, anyone? We'll have to wait until C++0x)
On the plus side
hidden feature: function try blocks. Unfortunately I haven't found a use for it. Yes I know why they added it, but you have to rethrow in a constructor which makes it pointless.
It's worth looking carefully at the STL guarantees about iterator validity after container modification, which can let you make some slightly nicer loops.
Boost - it's hardly a secret but it's worth using.
Return value optimisation (not obvious, but it's specifically allowed by the standard)
Functors aka function objects aka operator(). This is used extensively by the STL. not really a secret, but is a nifty side effect of operator overloading and templates.
You can access protected data and function members of any class, without undefined behavior, and with expected semantics. Read on to see how. Read also the defect report about this.
Normally, C++ forbids you to access non-static protected members of a class's object, even if that class is your base class
struct A {
protected:
int a;
};
struct B : A {
// error: can't access protected member
static int get(A &x) { return x.a; }
};
struct C : A { };
That's forbidden: You and the compiler don't know what the reference actually points at. It could be a C object, in which case class B has no business and clue about its data. Such access is only granted if x is a reference to a derived class or one derived from it. And it could allow arbitrary piece of code to read any protected member by just making up a "throw-away" class that reads out members, for example of std::stack:
void f(std::stack<int> &s) {
// now, let's decide to mess with that stack!
struct pillager : std::stack<int> {
static std::deque<int> &get(std::stack<int> &s) {
// error: stack<int>::c is protected
return s.c;
}
};
// haha, now let's inspect the stack's middle elements!
std::deque<int> &d = pillager::get(s);
}
Surely, as you see this would cause way too much damage. But now, member pointers allow circumventing this protection! The key point is that the type of a member pointer is bound to the class that actually contains said member - not to the class that you specified when taking the address. This allows us to circumvent checking
struct A {
protected:
int a;
};
struct B : A {
// valid: *can* access protected member
static int get(A &x) { return x.*(&B::a); }
};
struct C : A { };
And of course, it also works with the std::stack example.
void f(std::stack<int> &s) {
// now, let's decide to mess with that stack!
struct pillager : std::stack<int> {
static std::deque<int> &get(std::stack<int> &s) {
return s.*(pillager::c);
}
};
// haha, now let's inspect the stack's middle elements!
std::deque<int> &d = pillager::get(s);
}
That's going to be even easier with a using declaration in the derived class, which makes the member name public and refers to the member of the base class.
void f(std::stack<int> &s) {
// now, let's decide to mess with that stack!
struct pillager : std::stack<int> {
using std::stack<int>::c;
};
// haha, now let's inspect the stack's middle elements!
std::deque<int> &d = s.*(&pillager::c);
}
Another hidden feature is that you can call class objects that can be converted to function pointers or references. Overload resolution is done on the result of them, and arguments are perfectly forwarded.
template<typename Func1, typename Func2>
class callable {
Func1 *m_f1;
Func2 *m_f2;
public:
callable(Func1 *f1, Func2 *f2):m_f1(f1), m_f2(f2) { }
operator Func1*() { return m_f1; }
operator Func2*() { return m_f2; }
};
void foo(int i) { std::cout << "foo: " << i << std::endl; }
void bar(long il) { std::cout << "bar: " << il << std::endl; }
int main() {
callable<void(int), void(long)> c(foo, bar);
c(42); // calls foo
c(42L); // calls bar
}
These are called "surrogate call functions".
Hidden features:
Pure virtual functions can have implementation. Common example, pure virtual destructor.
If a function throws an exception not listed in its exception specifications, but the function has std::bad_exception in its exception specification, the exception is converted into std::bad_exception and thrown automatically. That way you will at least know that a bad_exception was thrown. Read more here.
function try blocks
The template keyword in disambiguating typedefs in a class template. If the name of a member template specialization appears after a ., ->, or :: operator, and that name has explicitly qualified template parameters, prefix the member template name with the keyword template. Read more here.
function parameter defaults can be changed at runtime. Read more here.
A[i] works as good as i[A]
Temporary instances of a class can be modified! A non-const member function can be invoked on a temporary object. For example:
struct Bar {
void modify() {}
}
int main (void) {
Bar().modify(); /* non-const function invoked on a temporary. */
}
Read more here.
If two different types are present before and after the : in the ternary (?:) operator expression, then the resulting type of the expression is the one that is the most general of the two. For example:
void foo (int) {}
void foo (double) {}
struct X {
X (double d = 0.0) {}
};
void foo (X) {}
int main(void) {
int i = 1;
foo(i ? 0 : 0.0); // calls foo(double)
X x;
foo(i ? 0.0 : x); // calls foo(X)
}
map::operator[] creates entry if key is missing and returns reference to default-constructed entry value. So you can write:
map<int, string> m;
string& s = m[42]; // no need for map::find()
if (s.empty()) { // assuming we never store empty values in m
s.assign(...);
}
cout << s;
I'm amazed at how many C++ programmers don't know this.
Putting functions or variables in a nameless namespace deprecates the use of static to restrict them to file scope.
Defining ordinary friend functions in class templates needs special attention:
template <typename T>
class Creator {
friend void appear() { // a new function ::appear(), but it doesn't
… // exist until Creator is instantiated
}
};
Creator<void> miracle; // ::appear() is created at this point
Creator<double> oops; // ERROR: ::appear() is created a second time!
In this example, two different instantiations create two identical definitions—a direct violation of the ODR
We must therefore make sure the template parameters of the class template appear in the type of any friend function defined in that template (unless we want to prevent more than one instantiation of a class template in a particular file, but this is rather unlikely). Let's apply this to a variation of our previous example:
template <typename T>
class Creator {
friend void feed(Creator<T>*){ // every T generates a different
… // function ::feed()
}
};
Creator<void> one; // generates ::feed(Creator<void>*)
Creator<double> two; // generates ::feed(Creator<double>*)
Disclaimer: I have pasted this section from C++ Templates: The Complete Guide / Section 8.4
void functions can return void values
Little known, but the following code is fine
void f() { }
void g() { return f(); }
Aswell as the following weird looking one
void f() { return (void)"i'm discarded"; }
Knowing about this, you can take advantage in some areas. One example: void functions can't return a value but you can also not just return nothing, because they may be instantiated with non-void. Instead of storing the value into a local variable, which will cause an error for void, just return a value directly
template<typename T>
struct sample {
// assume f<T> may return void
T dosomething() { return f<T>(); }
// better than T t = f<T>(); /* ... */ return t; !
};
Read a file into a vector of strings:
vector<string> V;
copy(istream_iterator<string>(cin), istream_iterator<string>(),
back_inserter(V));
istream_iterator
You can template bitfields.
template <size_t X, size_t Y>
struct bitfield
{
char left : X;
char right : Y;
};
I have yet to come up with any purpose for this, but it sure as heck surprised me.
One of the most interesting grammars of any programming languages.
Three of these things belong together, and two are something altogether different...
SomeType t = u;
SomeType t(u);
SomeType t();
SomeType t;
SomeType t(SomeType(u));
All but the third and fifth define a SomeType object on the stack and initialize it (with u in the first two case, and the default constructor in the fourth. The third is declaring a function that takes no parameters and returns a SomeType. The fifth is similarly declaring a function that takes one parameter by value of type SomeType named u.
Getting rid of forward declarations:
struct global
{
void main()
{
a = 1;
b();
}
int a;
void b(){}
}
singleton;
Writing switch-statements with ?: operators:
string result =
a==0 ? "zero" :
a==1 ? "one" :
a==2 ? "two" :
0;
Doing everything on a single line:
void a();
int b();
float c = (a(),b(),1.0f);
Zeroing structs without memset:
FStruct s = {0};
Normalizing/wrapping angle- and time-values:
int angle = (short)((+180+30)*65536/360) * 360/65536; //==-150
Assigning references:
struct ref
{
int& r;
ref(int& r):r(r){}
};
int b;
ref a(b);
int c;
*(int**)&a = &c;
The ternary conditional operator ?: requires its second and third operand to have "agreeable" types (speaking informally). But this requirement has one exception (pun intended): either the second or third operand can be a throw expression (which has type void), regardless of the type of the other operand.
In other words, one can write the following pefrectly valid C++ expressions using the ?: operator
i = a > b ? a : throw something();
BTW, the fact that throw expression is actually an expression (of type void) and not a statement is another little-known feature of C++ language. This means, among other things, that the following code is perfectly valid
void foo()
{
return throw something();
}
although there's not much point in doing it this way (maybe in some generic template code this might come handy).
The dominance rule is useful, but little known. It says that even if in a non-unique path through a base-class lattice, name-lookup for a partially hidden member is unique if the member belongs to a virtual base-class:
struct A { void f() { } };
struct B : virtual A { void f() { cout << "B!"; } };
struct C : virtual A { };
// name-lookup sees B::f and A::f, but B::f dominates over A::f !
struct D : B, C { void g() { f(); } };
I've used this to implement alignment-support that automatically figures out the strictest alignment by means of the dominance rule.
This does not only apply to virtual functions, but also to typedef names, static/non-virtual members and anything else. I've seen it used to implement overwritable traits in meta-programs.