I am writing a simple function for downloading a certain file, from the server, to my machine.
The file is unique represented by its id. The file is locatd corectly, and the download is done, but the downloaded file (though named as the one on the server) is empty.
my download function looks like this:
def download_course(request, id):
course = Courses.objects.get(pk = id).course
path_to_file = 'root/cFolder'
filename = __file__ # Select your file here.
wrapper = FileWrapper(file(filename))
content_type = mimetypes.guess_type(filename)[0]
response = HttpResponse(wrapper, content_type = content_type)
response['Content-Length'] = os.path.getsize(filename)
response['Content-Disposition'] = 'attachment; filename=%s/' % smart_str(course)
return response
where can i be wrong? thanks!
I answered this question here, hope it helps.
Looks like you're not sending any data (you don't even open the file).
Django has a nice wrapper for sending files (code taken from djangosnippets.org):
def send_file(request):
"""
Send a file through Django without loading the whole file into
memory at once. The FileWrapper will turn the file object into an
iterator for chunks of 8KB.
"""
filename = __file__ # Select your file here.
wrapper = FileWrapper(file(filename))
response = HttpResponse(wrapper, content_type='text/plain')
response['Content-Length'] = os.path.getsize(filename)
return response
so you could use something like response = HttpResponse(FileWrapper(file(path_to_file)), mimetype='application/force-download').
If you are really using lighttpd (because of the "X-Sendfile" header), you should check the server and FastCGI configuration, I guess.
Try one of these approaches:
1) Disable GZipMiddleware if you are using it;
2) Apply a patch to django/core/servers/basehttp.py described in
https://code.djangoproject.com/ticket/6027
Related
I am learner, and trying to build code to in which user has option to download the zip file that contains multiple .xlm files, which are created on the bases of database.
I have been able to create below code to download single xml file. But struggling to get multiple files packed in zipped format(for each row of database).
import xml.etree.ElementTree as ET
def export_to_xml(request):
listings = mydatabase.objects.all()
root = ET.Element('listings')
for item in listings:
price = ET.Element('price')
price.text = str(item.Name)
offer = ET.Element('offer', attrib={'id': str(item.pk)})
offer.append(price)
root.append(offer)
tree = ET.ElementTree(root)
response = HttpResponse(ET.tostring(tree.getroot()), content_type='application/xhtml+xml')
response['Content-Disposition'] = 'attachment; filename="data.xml"'
return response
Hi Got the solution by using following approach
byteStream = io.BytesIO()
with zipfile.ZipFile(byteStream, mode='w',) as zf:
# your code
zf.writestr()
response = HttpResponse(byteStream.getvalue(), content_type='application/x-zip-compressed')
response['Content-Disposition'] = "attachment; filename=finename.zip"
Hi i'm making my own webserver using django.
i just want to upload local file to django server.
i google every method but i can't get answer.
every method using form or html but i don't want to using form and html
example : from www.localfolder/example.txt to /media/examplefolder.
i don't know how to do.. any help?
this is my code.
#csrf_exempt
def download_file(request, file):
fl_path = 'media/'
filename = str(file)
fl = open(fl_path, 'r')
mime_type, _ = mimetypes.guess_type(fl_path)
response = HttpResponse(fl, content_type=mime_type)
response['Content-Disposition'] = "attachment; filename = %s" % filename
return response
What did you search for when you googled? These were the top 2 results for Django files
https://docs.djangoproject.com/en/3.0/topics/http/file-uploads/
https://docs.djangoproject.com/en/3.0/topics/files/
Seems to have everything you are looking for.
I'm zipping a large number of files in my app, which leads to problems with performance. So now I've decided to zip files in a separate queue, store results in Redis and make available to user as soon as the process is done. I'm storing data in Redis to make it faster, and because I don't need files to be stored on server hard drive.
Here is my task.py:
#shared_task
def zip_files(filenames, key):
compression = zipfile.ZIP_STORED
s = BytesIO()
zf = zipfile.ZipFile(s, mode="w")
for fpath in filenames:
fdir, fname = os.path.split(fpath)
zf.write(fpath, fname, compress_type=compression)
zf.close()
caches['redis'].set(hash_key, {'file':s.getvalue()})
return hash_key
And then here is my simple download view:
def folder_cache(request, folder_hash):
cache_data = caches['redis'].get(folder_hash)
if cache_data:
response = FileResponse(cache_data['file'], content_type="application/x-zip-compressed")
response['Content-Disposition'] = 'attachment; filename=hello.zip'
response['Content-Length'] = len(cache_data['file'])
return response
return HttpResponse("Cache expired.")
Problem is that I can only download a part of the file, then the download is stopped by "Network connection was lost" message. The downloaded file seems to contain a set of numbers (not binary data). But I don't know, maybe I use FileResponse wrong? Or I need to serialize data before / after putting it to Redis cache?
I also tried same code in shell, it works when I use fopen and write data from Redis cache directly to server hard drive.
Finally, I found out that I only had to wrap file data into ContentFile class. So here is the latest working code:
def folder_cache(request, folder_hash):
cache_data = caches['redis'].get(folder_hash)
if cache_data:
if (cache_data['status'] == 'complete'):
...
response = FileResponse(ContentFile(cache_data['file']), content_type="application/x-zip-compressed")
response['Content-Disposition'] = 'attachment; filename={}'.format(filename)
response['Content-Length'] = len(cache_data['file'])
return response
I want to download a csv file with custom filename in a django project, but somehow the downloaded filename just display as "download.csv" instead of using the value of filename in Content-Disposition. I also tried to print csv_response['Content-Disposition'] out, but I'm getting a very strange string =?utf-8?b?YXR0YWNobWVudDsgZmlsZW5hbWU9Iuivvueoi+aKpeWQjeaDheWGtV8yMDE5MTEyODA3NDI0Ny5jc3Yi?=
the code snippet is :
#action(detail=False, methods=['GET'])
def download(self, request):
registrations = self.filter_queryset(self.get_queryset())
csv_response = HttpResponse(content_type='text/csv')
csv_response['Content-Disposition'] = 'attachment; filename="some_custom_name_{time}.csv"'.format(
time=time.strftime("%Y%m%d%H%M%S", time.localtime())
)
writer = csv.writer(csv_response)
writer.writerow([
some content,
])
for registration in registrations:
term_title = '{order} th'.format(order=registration.term.order)
course_title = registration.course.title
writer.writerow([
registration.user.email,
course_title,
term_title,
str(registration.confirmation_code),
str(registration.payment_due),
str(registration.payment_paid),
str(registration.source),
str(registration.created_at),
str(registration.updated_at),
str(registration.payment_source),
])
return csv_response
the django I am using is 2.2
any ideas why this is happening? I am a newb.
Thx in advance
The response header in chrome Dev tools:
I resolved the problem, by following the answer in the below post:
HttpResponse Django does not change file name
I guess that it is that because the string of Content-Disposition needs to be encoded, and if no, then somehow cannot operate on that, by using urlquote, it is solved.
Explanation about urlquote is here
UPDATE:
Also, a simpler way to resolve this without importing urlquote is to add encode(), like below:
csv_response['Content-Disposition'] = 'attachment; filename="some_custom_name_{time}.csv"'.format(
time=time.strftime("%Y%m%d%H%M%S", time.localtime())
).encode()
Change to this:
csv_response['Content-Disposition'] = 'attachment; filename="some_custom_name_{}.csv"'.format(
time.strftime("%Y%m%d%H%M%S", time.localtime())
)
I have a simple django platform where I can upload text files. Ultimately I want to return a downloadable mp3 audio file made from the text in the uploaded file. My problem currently is that I cannot seem to correctly specify the type of file that the website outputs for download.
I then tried to make the downloadable output of the website an mp3 file:
views.py (code adapted from https://github.com/sibtc/simple-file-upload)
def simple_upload(request):
if request.method == 'POST' and request.FILES['myfile']:
myfile = request.FILES['myfile']
print(str(request.FILES['myfile']))
x=str(myfile.read())
tts = gTTS(text=x, lang='en')
response=HttpResponse(tts.save("result.mp3"),content_type='mp3')
response['Content-Disposition'] = 'attachment;filename=result.mp3'
return response
return render(request, 'core/simple_upload.html')
Upon pressing the upload button, the text-to-speech conversion is successful but the content_type of the response is not definable as 'mp3'. The file that results from the download is result.mp3.txt and it contains 'None'.
Can you try to prepare your response using the sample code below?
I've managed to return CSV files correctly this way so it might help you too.
Here it is:
HttpResponse(content_type='text/plain') # Plain text file type
response['Content-Disposition'] = 'attachment; filename="attachment.txt"' # Plain text file extension
response.write("Hello, this is the file contents.")
return response
There are two problems I can see here. The first is that tts.save() returns None, and that is getting passed directly to the HttpResponse. Secondly, the content_type is set to mp3 and ought to be set to audio/mp3.
After calling tts.save(), open the mp3 and pass the file handle to the HttpResponse, and then also set the content_type correctly - for example:
def simple_upload(request):
if request.method == 'POST' and request.FILES['myfile']:
...
tts.save("result.mp3")
response=HttpResponse(open("result.mp3", "rb"), content_type='audio/mp3')