How to count lines of a file in C++? - c++

How can I count lines using the standard classes, fstream and ifstream?

How about this :-
std::ifstream inFile("file");
std::count(std::istreambuf_iterator<char>(inFile),
std::istreambuf_iterator<char>(), '\n');

You read the file line by line.
Count the number of lines you read.

This is the correct version of Craig W. Wright's answer:
int numLines = 0;
ifstream in("file.txt");
std::string unused;
while ( std::getline(in, unused) )
++numLines;

kernel methods following #Abhay
A complete code I've done :
#include <fstream>
std::size_t count_line(std::istream &is) {
// skip when is not open or got bad
if (!is || is.bad()) { return 0; }
// save state
auto state_backup = is.rdstate();
// clear state
is.clear();
auto pos_backup = is.tellg();
is.seekg(0);
size_t line_cnt;
size_t lf_cnt = std::count(std::istreambuf_iterator<char>(is), std::istreambuf_iterator<char>(), '\n');
line_cnt = lf_cnt;
// if the file is not end with '\n' , then line_cnt should plus 1
// but we should check whether file empty firstly! or it will raise bug
if (is.tellg() != 0) {
is.unget();
if (is.get() != '\n') { ++line_cnt; }
}
// recover state
is.clear() ; // previous reading may set eofbit
is.seekg(pos_backup);
is.setstate(state_backup);
return line_cnt;
}
it will not change the origin file stream state and including '\n'-miss situation processing for the last line.
Thanks #masoomyf for pointing my bug and I was too stupid to figure it out!

int aNumOfLines = 0;
ifstream aInputFile(iFileName);
string aLineStr;
while (getline(aInputFile, aLineStr))
{
if (!aLineStr.empty())
aNumOfLines++;
}
return aNumOfLines;

This works for me:
std::ifstream fin{"source.txt"};
std::count(std::istream_iterator<char>(fin >> std::noskipws), {}, '\n');

int numLines = 0;
ifstream in("file.txt");
//while ( ! in.eof() )
while ( in.good() )
{
std::string line;
std::getline(in, line);
++numLines;
}
There is a question of how you treat the very last line of the file if it does not end with a newline. Depending upon what you're doing you might want to count it and you might not. This code counts it.
See: http://www.cplusplus.com/reference/string/getline/

Divide the file size by the average number of characters per line!

Related

Reading in Floats from Text File and Counting the Columns [duplicate]

How can i read data untill end of line?I have a text file "file.txt" with this
1 5 9 2 59 4 6
2 1 2
3 2 30 1 55
I have this code:
ifstream file("file.txt",ios::in);
while(!file.eof())
{
....//my functions(1)
while(?????)//Here i want to write :while (!end of file)
{
...//my functions(2)
}
}
in my functions(2) i use the data from the lines and it need to be Int ,not char
Don't use while(!file.eof()) as eof() will only be set after reading the end of the file. It does not indicate, that the next read will be the end of the file. You can use while(getline(...)) instead and combine with istringstream to read numbers.
#include <fstream>
#include <sstream>
using namespace std;
// ... ...
ifstream file("file.txt",ios::in);
if (file.good())
{
string str;
while(getline(file, str))
{
istringstream ss(str);
int num;
while(ss >> num)
{
// ... you now get a number ...
}
}
}
You need to read Why is iostream::eof inside a loop condition considered wrong?.
As for reading until the end of the line. there's std::getline.
You have another problem though, and that is that you loop while (!file.eof()) which will most likely not work as you expect. The reason is that the eofbit flag is not set until after you try to read from beyond the end of the file. Instead you should do e.g. while (std::getline(...)).
char eoln(fstream &stream) // C++ code Return End of Line
{
if (stream.eof()) return 1; // True end of file
long curpos; char ch;
curpos = stream.tellp(); // Get current position
stream.get(ch); // Get next char
stream.clear(); // Fix bug in VC 6.0
stream.seekp(curpos); // Return to prev position
if ((int)ch != 10) // if (ch) eq 10
return 0; // False not end of row (line)
else // (if have spaces?)
stream.get(ch); // Go to next row
return 1; // True end of row (line)
} // End function
If you want to write it as function in order to call some where, you can use a vector. This is a function which I use to read such file and return integers element wise.
vector<unsigned long long> Hash_file_read(){
int frames_sec = 25;
vector<unsigned long long> numbers;
ifstream my_file("E:\\Sanduni_projects\\testing\\Hash_file.txt", std::ifstream::binary);
if (my_file) {
//ifstream file;
string line;
for (int i = 0; i < frames_sec; i++){
getline(my_file, line);
numbers.push_back(stoull(line));
}
}
else{
cout << "File can not be opened" << endl;
}
return numbers;
}

Read from file in c++ till end of line?

How can i read data untill end of line?I have a text file "file.txt" with this
1 5 9 2 59 4 6
2 1 2
3 2 30 1 55
I have this code:
ifstream file("file.txt",ios::in);
while(!file.eof())
{
....//my functions(1)
while(?????)//Here i want to write :while (!end of file)
{
...//my functions(2)
}
}
in my functions(2) i use the data from the lines and it need to be Int ,not char
Don't use while(!file.eof()) as eof() will only be set after reading the end of the file. It does not indicate, that the next read will be the end of the file. You can use while(getline(...)) instead and combine with istringstream to read numbers.
#include <fstream>
#include <sstream>
using namespace std;
// ... ...
ifstream file("file.txt",ios::in);
if (file.good())
{
string str;
while(getline(file, str))
{
istringstream ss(str);
int num;
while(ss >> num)
{
// ... you now get a number ...
}
}
}
You need to read Why is iostream::eof inside a loop condition considered wrong?.
As for reading until the end of the line. there's std::getline.
You have another problem though, and that is that you loop while (!file.eof()) which will most likely not work as you expect. The reason is that the eofbit flag is not set until after you try to read from beyond the end of the file. Instead you should do e.g. while (std::getline(...)).
char eoln(fstream &stream) // C++ code Return End of Line
{
if (stream.eof()) return 1; // True end of file
long curpos; char ch;
curpos = stream.tellp(); // Get current position
stream.get(ch); // Get next char
stream.clear(); // Fix bug in VC 6.0
stream.seekp(curpos); // Return to prev position
if ((int)ch != 10) // if (ch) eq 10
return 0; // False not end of row (line)
else // (if have spaces?)
stream.get(ch); // Go to next row
return 1; // True end of row (line)
} // End function
If you want to write it as function in order to call some where, you can use a vector. This is a function which I use to read such file and return integers element wise.
vector<unsigned long long> Hash_file_read(){
int frames_sec = 25;
vector<unsigned long long> numbers;
ifstream my_file("E:\\Sanduni_projects\\testing\\Hash_file.txt", std::ifstream::binary);
if (my_file) {
//ifstream file;
string line;
for (int i = 0; i < frames_sec; i++){
getline(my_file, line);
numbers.push_back(stoull(line));
}
}
else{
cout << "File can not be opened" << endl;
}
return numbers;
}

c++ line from file stored in char array

I want to be able to read a full line into a character array using a function.
example input text is:
Schmidt, Helga
Alvarez, Ruben
Zowkowski, Aaron
Huang, Sun Lee
Einstein, Beverly
However, im not sure how to read a full line of characters into the array. I know the delimiter for >> is whitespace, but I'm not sure if I change that delimiter to '\n' if it'd work?
void buildList(char (*array)[25], ifstream& inputFile){
string line;
for (int i = 0; i < 5; i++)
getline(inputFile, line);
array[i] = line.c_str();
}
Currently this only reads either a last name or first name into my input instead of the whole line. I'm not sure how I can go about changing this. Thanks.
First, you definitely want to use std::string here. Once you
do that, you can use std::getline:
std::vector<std::string>
buildList( istream& input )
{
std::vector<std::string> results;
std::string line
while ( std::getline( input, line ) ) {
results.push_back( line );
}
}
This will make for much simpler and more robust code.
If you have to use such a broken interface, there is a member
function getline:
for ( int i = 0; i != 5; ++ i ) {
input.getline( array[i], maxLength );
}
Also: a function should never take an std::ifstream& as
argument (unless it is going to open or close the file). An
std::istream& should be used.
Use this-
void buildList(char (*array)[25], ifstream& inputFile){
for (int i = 0; i < 5; i++)
std::inputFile.getline(array[i],50);
}
The second parameter of getline is the maximum number of characters to write to the character array.

c++ Reading numbers from text files, ignoring comments

So I've seen lots of solutions on this site and tutorials about reading in from a text file in C++, but have yet to figure out a solution to my problem. I'm new at C++ so I think I'm having trouble piecing together some of the documentation to make sense of it all.
What I am trying to do is read a text file numbers while ignoring comments in the file that are denoted by "#". So an example file would look like:
#here is my comment
20 30 40 50
#this is my last comment
60 70 80 90
My code can read numbers fine when there aren't any comments, but I don't understand parsing the stream well enough to ignore the comments. Its kind of a hack solution right now.
/////////////////////// Read the file ///////////////////////
std::string line;
if (input_file.is_open())
{
//While we can still read the file
while (std::getline(input_file, line))
{
std::istringstream iss(line);
float num; // The number in the line
//while the iss is a number
while ((iss >> num))
{
//look at the number
}
}
}
else
{
std::cout << "Unable to open file";
}
/////////////////////// done reading file /////////////////
Is there a way I can incorporate comment handling with this solution or do I need a different approach? Any advice would be great, thanks.
If your file contains # always in the first column, then just test, if the line starts with # like this:
while (std::getline(input_file, line))
{
if (line[0] != "#" )
{
std::istringstream iss(line);
float num; // The number in the line
//while the iss is a number
while ((iss >> num))
{
//look at the number
}
}
}
It is wise though to trim the line of leading and trailing whitespaces, like shown here for example: Remove spaces from std::string in C++
If this is just a one of use, for line oriented input like yours, the
simplest solution is just to strip the comment from the line you just
read:
line.erase( std::find( line.begin(), line.end(), '#' ), line.end() );
A more generic solution would be to use a filtering streambuf, something
like:
class FilterCommentsStreambuf : public std::streambuf
{
std::istream& myOwner;
std::streambuf* mySource;
char myCommentChar;
char myBuffer;
protected:
int underflow()
{
int const eof = std::traits_type::eof();
int results = mySource->sbumpc();
if ( results == myCommentChar ) {
while ( results != eof && results != '\n') {
results = mySource->sbumpc(0;
}
}
if ( results != eof ) {
myBuffer = results;
setg( &myBuffer, &myBuffer, &myBuffer + 1 );
}
return results;
}
public:
FilterCommentsStreambuf( std::istream& source,
char comment = '#' )
: myOwner( source )
, mySource( source.rdbuf() )
, myCommentChar( comment )
{
myOwner.rdbuf( this );
}
~FilterCommentsStreambuf()
{
myOwner.rdbuf( mySource );
}
};
In this case, you could even forgo getline:
FilterCommentsStreambuf filter( input_file );
double num;
while ( input_file >> num || !input_file.eof() ) {
if ( ! input_file ) {
// Formatting error, output error message, clear the
// error, and resynchronize the input---probably by
// ignore'ing until end of line.
} else {
// Do something with the number...
}
}
(In such cases, I've found it useful to also track the line number in
the FilterCommentsStreambuf. That way you have it for error
messages.)
An alternative to the "read aline and parse it as a string", can be use the stream itself as the incoming buffer:
while(input_file)
{
int n = 0;
char c;
input_file >> c; // will skip spaces ad read the first non-blank
if(c == '#')
{
while(c!='\n' && input_file) input_file.get(c);
continue; //may be not soooo beautiful, but does not introduce useless dynamic memory
}
//c is part of something else but comment, so give it back to parse it as number
input_file.unget(); //< this is what all the fuss is about!
if(input_file >> n)
{
// look at the nunber
continue;
}
// something else, but not an integer is there ....
// if you cannot recover the lopop will exit
}

Line by line reading in C and C++?

I want to read line by line from a file in C or C++, and I know how to do that when I assume some fixed size of a line, but is there a simple way to somehow calculate or get the exact size needed for a line or all lines in file? (Reading word by word until newline is also good for me if anyone can do it that way.)
If you use a streamed reader, all this will be hidden from you. See getline. The example below is based from the code here.
// getline with strings
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
int main () {
string str;
ifstream ifs("data.txt");
getline (ifs,str);
cout << "first line of the file is " << str << ".\n";
}
In C, if you have POSIX 2008 libraries (more recent versions of Linux, for example), you can use the POSIX getline() function. If you don't have the function in your libraries, you can implement it easily enough, which is probably better than inventing your own interface to do the job.
In C++, you can use std::getline().
Even though the two functions have the same basic name, the calling conventions and semantics are quite different (because the languages C and C++ are quite different) - except that they both read a line of data from a file stream, of course.
There isn't an easy way to tell how big the longest line in a file is - except by reading the whole file to find out, which is kind of wasteful.
I would use an IFStream and use getline to read from a file.
http://www.cplusplus.com/doc/tutorial/files/
int main () {
string line;
ifstream myfile ("example.txt");
if (myfile.is_open())
{
while ( myfile.good() )
{
getline (myfile,line);
cout << line << endl;
}
myfile.close();
}
else cout << "Unable to open file";
return 0;
}
You can't get the length of line until after you read it in. You can, however, read into a buffer repeatedly until you reach the end of line.
For programming in c, try using fgets to read in a line of code. It will read n characters or stop if it encounters a newline. You can read in a small buffer of size n until the last character in the string is the newline.
See the link above for more information.
Here is an example on how to read an display a full line of file using a small buffer:
#include <stdio.h>
#include <string.h>
int main()
{
FILE * pFile;
const int n = 5;
char mystring [n];
int lineLength = 0;
pFile = fopen ("myfile.txt" , "r");
if (pFile == NULL)
{
perror ("Error opening file");
}
else
{
do
{
fgets (mystring , n , pFile);
puts (mystring);
lineLength += strlen(mystring);
} while(mystring[strlen ( mystring)-1] != '\n' && !feof(pFile));
fclose (pFile);
}
printf("Line Length: %d\n", lineLength);
return 0;
}
In C++ you can use the std::getline function, which takes a stream and reads up to the first '\n' character. In C, I would just use fgets and keep reallocating a buffer until the last character is the '\n', then we know we have read the entire line.
C++:
std::ifstream file("myfile.txt");
std::string line;
std::getline(file, line);
std::cout << line;
C:
// I didn't test this code I just made it off the top of my head.
FILE* file = fopen("myfile.txt", "r");
size_t cap = 256;
size_t len = 0;
char* line = malloc(cap);
for (;;) {
fgets(&line[len], cap - len, file);
len = strlen(line);
if (line[len-1] != '\n' && !feof(file)) {
cap <<= 1;
line = realloc(line, cap);
} else {
break;
}
}
printf("%s", line);
getline is only POSIX, here is an ANSI (NO max-line-size info needed!):
const char* getline(FILE *f,char **r)
{
char t[100];
if( feof(f) )
return 0;
**r=0;
while( fgets(t,100,f) )
{
char *p=strchr(t,'\n');
if( p )
{
*p=0;
if( (p=strchr(t,'\r')) ) *p=0;
*r=realloc(*r,strlen(*r)+1+strlen(t));
strcat(*r,t);
return *r;
}
else
{
if( (p=strchr(t,'\r')) ) *p=0;
*r=realloc(*r,strlen(*r)+1+strlen(t));
strcat(*r,t);
}
}
return feof(f)?(**r?*r:0):*r;
}
and now it's easy and short in your main:
char *line,*buffer = malloc(100);
FILE *f=fopen("yourfile.txt","rb");
if( !f ) return;
setvbuf(f,0,_IOLBF,4096);
while( (line=getline(f,&buffer)) )
puts(line);
fclose(f);
free(buffer);
it works on windows for Windows AND Unix-textfiles,
it works on Unix for Unix AND Windows-textfiles
Here is a C++ way of reading the lines, using std algorithms and iterators:
#include <iostream>
#include <iterator>
#include <vector>
#include <algorithm>
struct getline :
public std::iterator<std::input_iterator_tag, std::string>
{
std::istream* in;
std::string line;
getline(std::istream& in) : in(&in) {
++*this;
}
getline() : in(0) {
}
getline& operator++() {
if(in && !std::getline(*in, line)) in = 0;
}
std::string operator*() const {
return line;
}
bool operator!=(const getline& rhs) const {
return !in != !rhs.in;
}
};
int main() {
std::vector<std::string> v;
std::copy(getline(std::cin), getline(), std::back_inserter(v));
}