I've got a string:
doCall(valA, val.valB);
Using a regex in GVIM I would like to change this to:
valA = doCall(valA, val.valB);
How would I go about doing this? I use %s for basic regex search and replace in GVIM, but this a bit different from my normal usages.
Thanks
You can use this:
%s/\vdoCall\(<(\w*)>,/\1 = doCall(\1,/
\v enables “more magic” in regular expressions – not strictly necessary here but I usually use it to make the expressions simpler. <…> matches word boundaries and the in-between part matches the first parameter and puts it in the first capture group. The replacement uses \1 to access that capture group and insert into the right two places.
Related
I am having an issue with trying to figure out how to insert some text after I perform a regex search. I know there is a replace function, but I am not looking for that option, just inserting. The text editor I am using is Notepad2, but I am willing to try this in other text editors.
Here is the example that I have.
TEST|Test2|Test3|Test4
This is what I am looking for
Test|Test2|PrefixTest3|Test4
Notice that I am trying to insert the the phrase "Prefix" after the 2nd pipe and leave everything else alone.
I can successfully query the result by using this regex:
^[^|]*\|[^|]*|
But then I do not know how I can retain everything prior and after the search point. Any ideas?
You could simply use \K inorder to discard the previously matched characters.
^[^|]*\|[^|]*\|\K
Then replace the match with the string prefix.
DEMO
You may easily do that in Notepad2 using the regex-based Replace feature.
Find: ^\([^|]*|[^|]*|\)
Replace: \1Prefix
Details:
^ - start of a line (Notepad2 never overflows line boundaries!)
\([^|]*|[^|]*|\) - Capturing group 1 matching a sequence of:
[^|]* - zero or more chars other than |
| - a literal (yes, no escaping is necessary, both escaped and unescaped | match a literal |) pipe symbol
[^|]*| - see above, gets to the second |.
The replacement contains a \1 backreference that inserts what was captured with the capturing group 1.
NOTE that Notepad2 regex engine is very limited. Here is what the Notepad2 documentation says:
Notepad2 supports only a limited subset of regular expressions, as provided by built-in engine of the Scintilla source code editing component. The advantage is that it has a very small footprint. There's currently no plans to integrate a more advanced regular expressions engine, but this may be an option for future development.
Note: Regular expression search is limited to single lines, only.
Also, you may refer to the inline comments inside Scintilla RESearch.cxx file describing the supported syntax. Bear in mind that the regex type used in the Notepad2 S&R tool is that of POSIX and not all of the described Scintilla regex features will work in the tool.
Note that Notepad2 does not seem to support alternation and limiting quantifiers (similar to Lua patterns), but \w matches Unicode letters together with ASCII ones. Sadly, I could not make ? quantifier work.
^([^|]*\|[^|]*\|)
Try this.Replace by $1prefix.See demo.Just capture the first group and then use it for replace.The first group can be accessed by $1.
http://regex101.com/r/pQ9bV3/11
How I can get part of SIP URI?
For example I have URI sip:username#sip.somedomain.com, I need get just username and I use [^sip:](.*)[$#]+ expression, but appeared result is username#. How I can exclude from matching #?
this should do the job
(?<=^sip:)(.*)(?=[$#])
Use a lookahead instead of actually matching #:
^sip:(.*?)(?=#|\$)
Either you are using a very strange regex flavor, or your starting character class is a mistake. [^sip:] matches a single character that isn't any of s,i,p or :. I am also not certain what the $ character is for, since that isn't a part of SIP syntax.
If lookaheads are not available in your regex flavour (for instance POSIX regexes lack them), you can still match parts of the string in your regex you don't eventually want to return, if you use capture groups and only grab the contents of some of them.
For example
^sip:(.*?)[$#]+ Then only return the contents of the first capture group
Am i correct to understand, that the definition
:range s[ubstitute]/pattern/string/cgiI
suggests that in the string part indeed only strings are to be used, that is patterns not allowed? What i would like to do is do replacement of say any N symbols at position M with X*N symbols, so i would have liked to use something like this:
:%s/^\(.\{10}\).\{28}/\1X\{28}/g
Which does not work because \{28} is interpreted literally.
Is writing the 28 XXXXX...X in the replace part the only possibility?
You can use expressions in the replacement part via \=. You have to access the match via submatch(), and join it together with the static string, which you can generate via repeat():
:%s/^\(.\{10}\).\{28}/\=submatch(1) . repeat('X',28)/g
The only regex constructs allowed in the replacement part are numbered groups: \1 \2 \3 etc. The repeating construct {28} is not valid there, though it's a clever idea. You'll have to use 28 X's.
Another alternative is using a expression in the replacement part:
:%s/^\(.\{10}\).\{28}/\=submatch(1).repeat("X",28)/g
The first matched group is obtained with submatch(1). For more information see :h sub-replace-expression.
I got a string like this:
PREFIX-('STRING WITH SPACES TO REPLACE')
and i need this:
PREFIX-('STRING_WITH_SPACES_TO_REPLACE')
I'm using Notepad++ for the Regex Search and Replace, but i'm shure every other Editor capable of regex replacements can do it to.
I'm using:
PREFIX-\('(.*)(\s)(.*)'\)
for search and
PREFIX-('\1_\3')
for replace
but that replaces only one space from the string.
The regex search feature in Notepad++ is very, very weak. The only way I can see to do this in NPP is to manually select the part of the text you want to work on, then do a standard find/replace with the In selection box checked.
Alternatively, you can run the document through an external script, or you can get a better editor. EditPad Pro has the best regex support I've ever seen in an editor. It's not free, but it's worth paying for. In EPP all I had to do was this:
search: ((?:PREFIX-\('|\G)[^\s']+)\s+
replace: $1_
EDIT: \G matches the position where the previous match ended, or the beginning of the input if there was no previous match. In other words, the first time you apply the regex, \G acts like \A. You can prevent that by adding a negative lookahead, like so:
((?:PREFIX-\('|(?!\A)\G)[^\s']+)\s+
If you want to prevent a match at the very beginning of the text no matter what it starts with, you can move the lookahead outside the group:
(?!\A)((?:PREFIX-\('|\G)[^\s']+)\s+
And, just in case you were wondering, a lookbehind will work just as well as a lookahead:
((?:PREFIX-\('|(?<!\A)\G)[^\s']+)\s+
You have to keep matching from the beggining of the string untill you can match no more.
find /(PREFIX-\('[^\s']*)\s([^']*'\))/
replace $1_$2
like: while (/(PREFIX-\('[^\s']*)\s([^']*'\))/$1_$2/) {}
How about using Replace all for about 20 times? Or until you're sure no string contains more spaces
Due to nature of regex, it's not possible to do this in one step by normal regular expression.
But if I be in your place, I do such replaces in several steps:
find such patterns and mark them with special character
(Like replacing STRING WITH SPACES TO REPLACE with #STRING WITH SPACES TO REPLACE#
Replace #([^#\s]*)\s to #\1_ server times.
Remove markers!
I studied a little the regex tool in Notepad++ because I didn't know their possibilities.
I conclude that they aren't powerful enough to do what you want.
Your are obliged to learn and use a programming language having a real regex capability. There are a number of them. Personnaly, I use Python. It would take 1 mn to do what you want with it
You'd have to run the replace several times for each space but this regex will work
/(?<=PREFIX-\(')([^\s]+)\s+/g
Replace with
\1_ or $1_
See it working at http://refiddle.com/10z
I just stumbled on a case where I had to remove quotes surrounding a specific regex pattern in a file, and the immediate conclusion I came to was to use vim's search and replace util and just escape each special character in the original and replacement patterns.
This worked (after a little tinkering), but it left me wondering if there is a better way to do these sorts of things.
The original regex (quoted): '/^\//' to be replaced with /^\//
And the search/replace pattern I used:
s/'\/\^\\\/\/'/\/\^\\\/\//g
Thanks!
You can use almost any character as the regex delimiter. This will save you from having to escape forward slashes. You can also use groups to extract the regex and avoid re-typing it. For example, try this:
:s#'\(\\^\\//\)'#\1#
I do not know if this will work for your case, because the example you listed and the regex you gave do not match up. (The regex you listed will match '/^\//', not '\^\//'. Mine will match the latter. Adjust as necessary.)
Could you avoid using regex entirely by using a nice simple string search and replace?
Please check whether this works for you - define the line number before this substitute-expression or place the cursor onto it:
:s:'\(.*\)':\1:
I used vim 7.1 for this. Of course, you can visually mark an area before (onto which this expression shall be executed (use "v" or "V" and move the cursor accordingly)).