Django: ordering numerical value with order_by - django

Question

I'm in a situation where I must output a quite large list of objects by a CharField used to store street addresses.
My problem is, that obviously the data is ordered by ASCII codes since it's a Charfield, with the predictable results .. it sort the numbers like this;
1, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 2, 20, 21....
Now the obvious step would be to change the Charfield the proper field type (IntegerField let's say), however it cannot work since some address might have apartments .. like "128A".
I really don't know how I can order this properly ..

Answer 1

If you're sure there are only integers in the field, you could get the database to cast it as an integer via the extra method, and order by that:
MyModel.objects.extra(
select={'myinteger': 'CAST(mycharfield AS INTEGER)'}
).order_by('myinteger')

Answer 2

Django is trying to deprecate the extra() method, but has introduced Cast() in v1.10. In sqlite (at least), CAST can take a value such as 10a and will cast it to the integer 10, so you can do:
from django.db.models import IntegerField
from django.db.models.functions import Cast
MyModel.objects.annotate(
my_integer_field=Cast('my_char_field', IntegerField())
).order_by('my_integer_field', 'my_char_field')
which will return objects sorted by the street number first numerically, then alphabetically, e.g. ...14, 15a, 15b, 16, 16a, 17...

Answer 3

If you're using PostgreSQL (not sure about MySQL) you can safely use following code on char/text fields and avoid cast errors:
MyModel.objects.extra(
select={'myinteger': "CAST(substring(charfield FROM '^[0-9]+') AS INTEGER)"}
).order_by('myinteger')

Answer 4

Great tip! It works for me! :) That's my code:
revisioned_objects = revisioned_objects.extra(select={'casted_object_id': 'CAST(object_id AS INTEGER)'}).extra(order_by = ['casted_object_id'])

Answer 5

I know that I’m late on this, but since it’s strongly related to the question, and that I had a hard time finding this:
You have to know that you can directly put the Cast in the ordering option of your model.
from django.db import models
from django.db.models.functions import Cast
class Address(models.Model):
street_number = models.CharField()
class Meta:
ordering = [
Cast("street_number", output_field=models.IntegerField()),
]
From the doc about ordering:
You can also use query expressions.
And from the doc about database functions:
Functions are also expressions, so they can be used and combined with other expressions like aggregate functions. 

Answer 6

The problem you're up against is quite similar to how filenames get ordered when sorting by filename. There, you want "2 Foo.mp3" to appear before "12 Foo.mp3".
A common approach is to "normalize" numbers to expanding to a fixed number of digits, and then sorting based on the normalized form. That is, for purposes of sorting, "2 Foo.mp3" might expand to "0000000002 Foo.mp3".
Django won't help you here directly. You can either add a field to store the "normalized" address, and have the database order_by that, or you can do a custom sort in your view (or in a helper that your view uses) on address records before handing the list of records to a template.

Answer 7

In my case i have a CharField with a name field, which has mixed (int+string) values, for example. "a1", "f65", "P", "55" e.t.c ..
Solved the issue by using the sql cast (tested with postgres & mysql),
first, I try to sort by the casted integer value, and then by the original value of the name field.
parking_slots = ParkingSlot.objects.all().extra(
select={'num_from_name': 'CAST(name AS INTEGER)'}
).order_by('num_from_name', 'name')
This way, in any case, the correct sorting works for me.

Answer 8

In case you need to sort version numbers consisting of multiple numbers separated by a dot (e.g. 1.9.0, 1.10.0), here is a postgres-only solution:
class VersionRecordManager(models.Manager):
def get_queryset(self):
return super().get_queryset().extra(
select={
'natural_version': "string_to_array(version, '.')::int[]",
},
)
def available_versions(self):
return self.filter(available=True).order_by('-natural_version')
def last_stable(self):
return self.available_versions().filter(stable=True).first()
class VersionRecord(models.Model):
objects = VersionRecordManager()
version = models.CharField(max_length=64, db_index=True)
available = models.BooleanField(default=False, db_index=True)
stable = models.BooleanField(default=False, db_index=True)
In case you want to allow non-numeric characters (e.g. 0.9.0 beta, 2.0.0 stable):
def get_queryset(self):
return super().get_queryset().extra(
select={
'natural_version':
"string_to_array( "
" regexp_replace( " # Remove everything except digits
" version, '[^\d\.]+', '', 'g' " # and dots, then split string into
" ), '.' " # an array of integers.
")::int[] "
}
)

Answer 9

I was looking for a way to sort the numeric chars in a CharField and my search led me here. The name fields in my objects are CC Licenses, e.g., 'CC BY-NC 4.0'.
Since extra() is going to be deprecated, I was able to do it this way:
MyObject.objects.all()
.annotate(sorting_int=Cast(Func(F('name'), Value('\D'), Value(''), Value('g'), function='regexp_replace'), IntegerField()))
.order_by('-sorting_int')
Thus, MyObject with name='CC BY-NC 4.0' now has sorting_int=40.

Answer 10

All the answeres in this thread did not work for me because they are assuming numerical text. I found a solution that will work for a subset of cases. Consider this model
Class Block(models.Model):
title = models.CharField()
say I have fields that sometimes have leading characters and trailing numerical characters If i try and order normally
>>> Block.objects.all().order_by('title')
<QuerySet [<Block: 1>, <Block: 10>, <Block: 15>, <Block: 2>, <Block: N1>, <Block: N12>, <Block: N4>]>
As expected, it's correct alphabetically, but makes no sense for us humans. The trick that I did for this particular use case is to replace any text i find with the number 9999 and then cast the value to an integer and order by it.
for most cases that have leading characters this will get the desired result. see below
from django.db.models.expressions import RawSQL
>>> Block.objects.all()\
.annotate(my_faux_integer=RawSQL("CAST(regexp_replace(title, '[A-Z]+', '9999', 'g') AS INTEGER)", ''))\
.order_by('my_faux_integer', 'title')
<QuerySet [<Block: 1>, <Block: 2>, <Block: 10>, <Block: 15>, <Block: N1>, <Block: N4>, <Block: N12>]>