Purpose of boost::checked_delete - c++

Question

I don't understand the purpose of boost::checked_delete. The documentation says:
The C++ Standard allows, in 5.3.5/5,
pointers to incomplete class types to
be deleted with a delete-expression.
When the class has a non-trivial
destructor, or a class-specific
operator delete, the behavior is
undefined. Some compilers issue a
warning when an incomplete type is
deleted, but unfortunately, not all
do, and programmers sometimes ignore
or disable warnings.
The supplied function and class
templates can be used to prevent these
problems, as they require a complete
type, and cause a compilation error
otherwise.
So the C++ standard allows you to delete incomplete types, which causes undefined behavior if the type has a non-trivial destructor. What? How can an incomplete type have any destructor at all? Isn't an incomplete type just a prototype?

Answer 1

The most common example of an incomplete type is one that has only been declared:
// this file does not include the definition of foo
class foo;
void bad(foo *f)
{
delete f; // undefined behavior if there exists foo::~foo
}
In reality, the definition of foo may look like this:
class foo
{
public:
~foo() { ... };
};
But if the top code has not 'seen' the class definition and just sees the class declaration, the code will compile.

Answer 2

Consider the following:
Foo.h:
#ifndef Foo_H
#define Foo_H
#include <boost/scoped_ptr.hpp>
#include <boost/utility.hpp>
class Foo : private boost::noncopyable
{
public:
Foo();
~Foo();
void do_something_interesting();
private:
class Impl; // incomplete type
boost::scoped_ptr<Impl> impl;
};
#endif
Foo.cpp:
#include "Foo.h"
#include <string>
#include <iostream>
class Foo::Impl
{
public:
Impl() : name("Foo::Impl")
{}
void say_hi()
{ std::cout << name << " says hi!" << std::endl; }
std::string name;
};
Foo::Foo()
: impl(new Impl)
{}
Foo::~Foo()
{}
void Foo::do_something_interesting()
{ impl->say_hi(); }
Given this (contrived) example, you cannot inline either Foo::Foo or Foo::~Foo because the type is incomplete. By defining both in a context where the type Foo::Impl is a complete type, you can safely delete the type. boost::checked_delete does this safety check for you, and it's purely a compile-time cost. If you either inline Foo::~Foo or omit it entirely, you will get an error from boost::checked_delete wherever you try to destroy a Foo instance.

Answer 3

C++ allows you to use delete on variables that at the time are pointers to incomplete types.
struct S; // incomplete
int main() {
S* s = NULL;
delete s; // legal
}
The compiler doesn't know at that point what S really is. If it turns out S has a non-trivial destructor, then the compiler is not required to detect that problem.
Practically speaking, what probably happens is that when the compiler encounters the delete instruction on an incomplete type, it fills in a call to what it expects will be the type's ordinary compiler-generate default destructor. And if that's what the destructor turns out to be, then everything's fine. But if it turns out that S has a non-trivial destructor, or if it provides its own special method of deletion, then what the compiler filled in earlier will be wrong. The compiler, however, allowed to assume that it correctly compiled the delete instruction and never look back. When that assumption is wrong, you'll get undefined behavior.
The Boost function ensures that it's called only on complete types, thus avoiding the undefined behavior that may occur on incomplete types.