is there any way to automatically use correct EOL character depending on the OS used?
I was thinking of something like std::eol?
I know that it is very easy to use preprocessor directives but curious if that is already available.
What I am interested in is that I usually have some messages in my applications that I combine later into a single string and I want to have them separated with a EOL. I know that I could use std::stringstream << endl but it seems to be an overkill sometimes instead of a regular append.
std::endl is defined to do nothing besides write '\n' to the stream and flush it (§27.6.2.7). Flushing is defined to do nothing for a stringstream, so you're left with a pretty way of saying mystringstream << '\n'. The standard library implementation on your OS converts \n appropriately, so that's not your concern.
Thus endl is already the ultimate in performance and portability, and the only other thing you could want is << '\n' if you are trying to efficiently write to a file (not a stringstream). Well, << '\n' does also eliminate the pointless virtual call to stringbuf::flush. Unless profiling shows that empty function call to be taking time, don't think about it.
If you want to write a line separator to a stream:
std::cout << '\n';
or
std::cout << "\n";
or
std::cout << "whatever you were going to say anyway\n";
If the stream is text mode and the OS uses anything other than LF as a separator, it will be converted.
If you want to write a line separator and flush the stream:
std::cout << std::endl;
If you have binary-mode output for whatever reason, and you want to write a platform-specific line break, then I think you might have to do it indirectly (write '\n' to a text stream and then examine it in binary mode to see what you get). Possibly there's some way to directly get the line break sequence from the implementation, that I'm not aware of. It's not a great idea, anyway: if you're writing or reading a file in binary mode then it should be in a format which defines line breaks independently of the OS, or which doesn't have lines at all. That's what binary mode is for.
Just open a file in text mode
FILE *fp = fopen( "your_file.txt", "w+t" );
and then
fprintf( fp, "some string and integer %d\n", i );
fclose(fp);
and the OS will take care of the EOL accordingly to its standards.
Well, the STL has std::endl, which you can use as
std::cout << "Hi five!" << std::endl;
Note that besides adding an endline, std::endl also flushes the buffer, which may have undesirable performance consequences.
Files, even text files, are often transferred between machines, so "os-specific new line character" is an oxymoron.
It is though true that operating systems have a say on that matter, particularly one operating systems aka Windows, although many windows programs will read \n-spaced files correctly, even though the winapi multiline edit control would not. I suggest you consider twice what is the right for you: it's not necessarily what your OS recommends. If your files are ever to be stored on removable media, do not use OS standard. Use global standard, 0xA.
Related
Can someone please explain (preferably using plain english) how std::flush works?
What is it?
When would you flush a stream?
Why is it important?
Thank you.
Since it wasn't answered what std::flush happens to be, here is some detail on what it actually is. std::flush is a manipulator, i.e., a function with a specific signature. To start off simple, you can think of std::flush of having the signature
std::ostream& std::flush(std::ostream&);
The reality is a bit more complex, though (if you are interested, it is explained below as well).
The stream class overload output operators taking operators of this form, i.e., there is a member function taking a manipulator as argument. The output operator calls the manipulator with the object itself:
std::ostream& std::ostream::operator<< (std::ostream& (*manip)(std::ostream&)) {
(*manip)(*this);
return *this;
}
That is, when you "output" std::flush with to an std::ostream, it just calls the corresponding function, i.e., the following two statements are equivalent:
std::cout << std::flush;
std::flush(std::cout);
Now, std::flush() itself is fairly simple: All it does is to call std::ostream::flush(), i.e., you can envision its implementation to look something like this:
std::ostream& std::flush(std::ostream& out) {
out.flush();
return out;
}
The std::ostream::flush() function technically calls std::streambuf::pubsync() on the stream buffer (if any) which is associated with the stream: The stream buffer is responsible for buffering characters and sending characters to the external destination when the used buffer would overflow or when the internal representation should be synced with the external destination, i.e., when the data is to be flushed. On a sequential stream syncing with the external destination just means that any buffered characters are immediately sent. That is, using std::flush causes the stream buffer to flush its output buffer. For example, when data is written to a console flushing causes the characters to appear at this point on the console.
This may raise the question: Why aren't characters immediately written? The simple answer is that writing characters is generally fairly slow. However, the amount of time it takes to write a reasonable amount of characters is essentially identical to writing just one where. The amount of characters depends on many characteristics of the operating system, file systems, etc. but often up to something like 4k characters are written in about the same time as just one character. Thus, buffering characters up before sending them using a buffer depending on the details of the external destination can be a huge performance improvement.
The above should answer two of your three questions. The remaining question is: When would you flush a stream? The answer is: When the characters should be written to the external destination! This may be at the end of writing a file (closing a file implicitly flushes the buffer, though) or immediately before asking for user input (note that std::cout is automatically flushed when reading from std::cin as std::cout is std::istream::tie()'d to std::cin). Although there may be a few occasions where you explicitly want to flush a stream, I find them to be fairly rare.
Finally, I promised to give a full picture of what std::flush actually is: The streams are class templates capable of dealing with different character types (in practice they work with char and wchar_t; making them work with another characters is quite involved although doable if you are really determined). To be able to use std::flush with all instantiations of streams, it happens to be a function template with a signature like this:
template <typename cT, typename Traits>
std::basic_ostream<cT, Traits>& std::flush(std::basic_ostream<cT, Traits>&);
When using std::flush immediately with an instantiation of std::basic_ostream it doesn't really matter: The compiler deduces the template arguments automatically. However, in cases where this function isn't mentioned together with something facilitating the template argument deduction, the compiler will fail to deduce the template arguments.
By default, std::cout is buffered, and the actual output is only printed once the buffer is full or some other flushing situation occurs (e.g. a newline in the stream). Sometimes you want to make sure that the printing happens immediately, and you need to flush manually.
For example, suppose you want to report a progress report by printing a single dot:
for (;;)
{
perform_expensive_operation();
std::cout << '.';
std::flush(std::cout);
}
Without the flushing, you wouldn't see the output for a very long time.
Note that std::endl inserts a newline into a stream as well as causing it to flush. Since flushing is mildly expensive, std::endl shouldn't be used excessively if the flushing isn't expressly desired.
Here's a short program that you can write to observe what flush is doing
#include <iostream>
#include <unistd.h>
using namespace std;
int main() {
cout << "Line 1..." << flush;
usleep(500000);
cout << "\nLine 2" << endl;
cout << "Line 3" << endl ;
return 0;
}
Run this program: you'll notice that it prints line 1, pauses, then prints line 2 and 3. Now remove the flush call and run the program again- you'll notice that the program pauses and then prints all 3 lines at the same time. The first line is buffered before the program pauses, but because the buffer is never flushed, line 1 is not outputted until the endl call from line 2.
A stream is connected to something. In the case of standard output, it could be the console/screen or it could be redirected to a pipe or a file. There is a lot of code between your program and, for example, the hard disk where the file is stored. For example, the operating system is doing stuff with any file or the disk drive itself might be buffering data to be able to write it in fixed size blocks or just to be more efficient.
When you flush the stream, it tells the language libraries, the os and the hardware that you want to any characters that you have output so far to be forced all the way to storage. Theoretically, after a 'flush', you could kick the cord out of the wall and those characters would still be safely stored.
I should mention that the people writing the os drivers or the people designing the disk drive might are free to use 'flush' as a suggestion and they might not really write the characters out. Even when the output is closed, they might wait a while to save them. (Remember that the os does all sorts of things at once and it might be more efficient to wait a second or two to handle your bytes.)
So a flush is a sort of checkpoint.
One more example: If the output is going to the console display, a flush will make sure the characters actually get all the way out to where the user can see them. This is an important thing to do when you are expecting keyboard input. If you think you have written a question to the console and its still stuck in some internal buffer somewhere, the user doesn't know what to type in answer. So, this is a case where the flush is important.
Many C++ books contain example code like this...
std::cout << "Test line" << std::endl;
...so I've always done that too. But I've seen a lot of code from working developers like this instead:
std::cout << "Test line\n";
Is there a technical reason to prefer one over the other, or is it just a matter of coding style?
The varying line-ending characters don't matter, assuming the file is open in text mode, which is what you get unless you ask for binary. The compiled program will write out the correct thing for the system compiled for.
The only difference is that std::endl flushes the output buffer, and '\n' doesn't. If you don't want the buffer flushed frequently, use '\n'. If you do (for example, if you want to get all the output, and the program is unstable), use std::endl.
The difference can be illustrated by the following:
std::cout << std::endl;
is equivalent to
std::cout << '\n' << std::flush;
So,
Use std::endl If you want to force an immediate flush to the output.
Use \n if you are worried about performance (which is probably not the case if you are using the << operator).
I use \n on most lines.
Then use std::endl at the end of a paragraph (but that is just a habit and not usually necessary).
Contrary to other claims, the \n character is mapped to the correct platform end of line sequence only if the stream is going to a file (std::cin and std::cout being special but still files (or file-like)).
There might be performance issues, std::endl forces a flush of the output stream.
There's another function call implied in there if you're going to use std::endl
a) std::cout << "Hello\n";
b) std::cout << "Hello" << std::endl;
a) calls operator << once.
b) calls operator << twice.
I recalled reading about this in the standard, so here goes:
See C11 standard which defines how the standard streams behave, as C++ programs interface the CRT, the C11 standard should govern the flushing policy here.
ISO/IEC 9899:201x
7.21.3 §7
At program startup, three text streams are predefined and need not be opened explicitly
— standard input (for reading conventional input), standard output (for writing
conventional output), and standard error (for writing diagnostic output). As initially
opened, the standard error stream is not fully buffered; the standard input and standard
output streams are fully buffered if and only if the stream can be determined not to refer
to an interactive device.
7.21.3 §3
When a stream is unbuffered, characters are intended to appear from the source or at the
destination as soon as possible. Otherwise characters may be accumulated and
transmitted to or from the host environment as a block. When a stream is fully buffered,
characters are intended to be transmitted to or from the host environment as a block when
a buffer is filled. When a stream is line buffered, characters are intended to be
transmitted to or from the host environment as a block when a new-line character is
encountered. Furthermore, characters are intended to be transmitted as a block to the host
environment when a buffer is filled, when input is requested on an unbuffered stream, or
when input is requested on a line buffered stream that requires the transmission of
characters from the host environment. Support for these characteristics is
implementation-defined, and may be affected via the setbuf and setvbuf functions.
This means that std::cout and std::cin are fully buffered if and only if they are referring to a non-interactive device. In other words, if stdout is attached to a terminal then there is no difference in behavior.
However, if std::cout.sync_with_stdio(false) is called, then '\n' will not cause a flush even to interactive devices. Otherwise '\n' is equivalent to std::endl unless piping to files: c++ ref on std::endl.
They will both write the appropriate end-of-line character(s). In addition to that endl will cause the buffer to be committed. You usually don't want to use endl when doing file I/O because the unnecessary commits can impact performance.
Not a big deal, but endl won't work in boost::lambda.
(cout<<_1<<endl)(3); //error
(cout<<_1<<"\n")(3); //OK , prints 3
If you use Qt and endl, you could accidentally end up using an incorrect endl which gives you very surprising results. See the following code snippet:
#include <iostream>
#include <QtCore/QtCore>
#include <QtGui/QtGui>
// notice that there is no "using namespace std;"
int main(int argc, char** argv)
{
QApplication qapp(argc,argv);
QMainWindow mw;
mw.show();
std::cout << "Finished Execution!" << endl;
// This prints something similar to: "Finished Execution!67006AB4"
return qapp.exec();
}
Note that I wrote endl instead of std::endl (which would have been correct) and apparently there is a endl function defined in qtextstream.h (which is part of QtCore).
Using "\n" instead of endl completely sidesteps any potential namespace issues.
This is also a good example why putting symbols into the global namespace (like Qt does by default) is a bad idea.
Something that I've never seen anyone say is that '\n' is affected by cout formatting:
#include <iostream>
#include <iomanip>
int main() {
std::cout << "\\n:\n" << std::setw(2) << std::setfill('0') << '\n';
std::cout << "std::endl:\n" << std::setw(2) << std::setfill('0') << std::endl;
}
Output:
\n:
0
std::endl:
Notice, how since '\n' is one character and fill width is set to 2, only 1 zero gets printed before '\n'.
I can't find anything about it anywhere, but it reproduces with clang, gcc and msvc.
I was super confused when I first saw it.
With reference This is an output-only I/O manipulator.
std::endl Inserts a newline character into the output sequence os and flushes it as if by calling os.put(os.widen('\n')) followed by os.flush().
When to use:
This manipulator may be used to produce a line of output immediately,
e.g.
when displaying output from a long-running process, logging activity of multiple threads or logging activity of a program that may crash unexpectedly.
Also
An explicit flush of std::cout is also necessary before a call to std::system, if the spawned process performs any screen I/O. In most other usual interactive I/O scenarios, std::endl is redundant when used with std::cout because any input from std::cin, output to std::cerr, or program termination forces a call to std::cout.flush(). Use of std::endl in place of '\n', encouraged by some sources, may significantly degrade output performance.
Many C++ books contain example code like this...
std::cout << "Test line" << std::endl;
...so I've always done that too. But I've seen a lot of code from working developers like this instead:
std::cout << "Test line\n";
Is there a technical reason to prefer one over the other, or is it just a matter of coding style?
The varying line-ending characters don't matter, assuming the file is open in text mode, which is what you get unless you ask for binary. The compiled program will write out the correct thing for the system compiled for.
The only difference is that std::endl flushes the output buffer, and '\n' doesn't. If you don't want the buffer flushed frequently, use '\n'. If you do (for example, if you want to get all the output, and the program is unstable), use std::endl.
The difference can be illustrated by the following:
std::cout << std::endl;
is equivalent to
std::cout << '\n' << std::flush;
So,
Use std::endl If you want to force an immediate flush to the output.
Use \n if you are worried about performance (which is probably not the case if you are using the << operator).
I use \n on most lines.
Then use std::endl at the end of a paragraph (but that is just a habit and not usually necessary).
Contrary to other claims, the \n character is mapped to the correct platform end of line sequence only if the stream is going to a file (std::cin and std::cout being special but still files (or file-like)).
There might be performance issues, std::endl forces a flush of the output stream.
There's another function call implied in there if you're going to use std::endl
a) std::cout << "Hello\n";
b) std::cout << "Hello" << std::endl;
a) calls operator << once.
b) calls operator << twice.
I recalled reading about this in the standard, so here goes:
See C11 standard which defines how the standard streams behave, as C++ programs interface the CRT, the C11 standard should govern the flushing policy here.
ISO/IEC 9899:201x
7.21.3 §7
At program startup, three text streams are predefined and need not be opened explicitly
— standard input (for reading conventional input), standard output (for writing
conventional output), and standard error (for writing diagnostic output). As initially
opened, the standard error stream is not fully buffered; the standard input and standard
output streams are fully buffered if and only if the stream can be determined not to refer
to an interactive device.
7.21.3 §3
When a stream is unbuffered, characters are intended to appear from the source or at the
destination as soon as possible. Otherwise characters may be accumulated and
transmitted to or from the host environment as a block. When a stream is fully buffered,
characters are intended to be transmitted to or from the host environment as a block when
a buffer is filled. When a stream is line buffered, characters are intended to be
transmitted to or from the host environment as a block when a new-line character is
encountered. Furthermore, characters are intended to be transmitted as a block to the host
environment when a buffer is filled, when input is requested on an unbuffered stream, or
when input is requested on a line buffered stream that requires the transmission of
characters from the host environment. Support for these characteristics is
implementation-defined, and may be affected via the setbuf and setvbuf functions.
This means that std::cout and std::cin are fully buffered if and only if they are referring to a non-interactive device. In other words, if stdout is attached to a terminal then there is no difference in behavior.
However, if std::cout.sync_with_stdio(false) is called, then '\n' will not cause a flush even to interactive devices. Otherwise '\n' is equivalent to std::endl unless piping to files: c++ ref on std::endl.
They will both write the appropriate end-of-line character(s). In addition to that endl will cause the buffer to be committed. You usually don't want to use endl when doing file I/O because the unnecessary commits can impact performance.
Not a big deal, but endl won't work in boost::lambda.
(cout<<_1<<endl)(3); //error
(cout<<_1<<"\n")(3); //OK , prints 3
If you use Qt and endl, you could accidentally end up using an incorrect endl which gives you very surprising results. See the following code snippet:
#include <iostream>
#include <QtCore/QtCore>
#include <QtGui/QtGui>
// notice that there is no "using namespace std;"
int main(int argc, char** argv)
{
QApplication qapp(argc,argv);
QMainWindow mw;
mw.show();
std::cout << "Finished Execution!" << endl;
// This prints something similar to: "Finished Execution!67006AB4"
return qapp.exec();
}
Note that I wrote endl instead of std::endl (which would have been correct) and apparently there is a endl function defined in qtextstream.h (which is part of QtCore).
Using "\n" instead of endl completely sidesteps any potential namespace issues.
This is also a good example why putting symbols into the global namespace (like Qt does by default) is a bad idea.
Something that I've never seen anyone say is that '\n' is affected by cout formatting:
#include <iostream>
#include <iomanip>
int main() {
std::cout << "\\n:\n" << std::setw(2) << std::setfill('0') << '\n';
std::cout << "std::endl:\n" << std::setw(2) << std::setfill('0') << std::endl;
}
Output:
\n:
0
std::endl:
Notice, how since '\n' is one character and fill width is set to 2, only 1 zero gets printed before '\n'.
I can't find anything about it anywhere, but it reproduces with clang, gcc and msvc.
I was super confused when I first saw it.
With reference This is an output-only I/O manipulator.
std::endl Inserts a newline character into the output sequence os and flushes it as if by calling os.put(os.widen('\n')) followed by os.flush().
When to use:
This manipulator may be used to produce a line of output immediately,
e.g.
when displaying output from a long-running process, logging activity of multiple threads or logging activity of a program that may crash unexpectedly.
Also
An explicit flush of std::cout is also necessary before a call to std::system, if the spawned process performs any screen I/O. In most other usual interactive I/O scenarios, std::endl is redundant when used with std::cout because any input from std::cin, output to std::cerr, or program termination forces a call to std::cout.flush(). Use of std::endl in place of '\n', encouraged by some sources, may significantly degrade output performance.
This question already has answers here:
"std::endl" vs "\n"
(10 answers)
Closed 6 years ago.
It was many years now since I stopped using std::endl to end lines when writing to std::cout, and started using "\n" instead.
But now I start seeing more snippets of code using '\n' instead, and I started wonder what might be best.
Besides the obvious that one is a string, and the other a character, is there any advantage to using this:
std::cout << variable << '\n';
Over this:
std::cout << variable << "\n";
Late addition:
When I asked this question I seemed to think that newline '\n' flushed the buffer. Now I know that it depends.
By default std::cin is tied to the old C stdin FILE* stream, and std::cout is tied to stdout. The flushing on newline comes from this tying. By default stdout, if connected to a terminal, is line-buffered. That means a new line will flush its buffers. So when printing a newline using std::cout, that will lead to stdout being flushed.
If stdout is not connected to a terminal (for example the output has been redirected or is piped), or if the tie between std::cout and stdout is broken, then newlines will not flush anything.
Actually, '\n' should be the default. Unless you want to also explicitly flush the stream (and when and why would you want to do that?), there is no need to use std::endl at all.1
Of course, many books and tutorials use std::endl as the default. That is unfortunate and might lead to serious performance bugs.
I suppose there's little difference between using '\n' or using "\n", but the latter is an array of (two) characters, which has to be printed character by character, for which a loop has to be set up, which is more complex than outputting a single character. Of course, when doing IO this rarely matters, but if in doubt, when you want to output one character literal, output a character literal, rather than a whole string literal.
A nice side-effect of doing so is that you communicate in your code that you intended to output only a single character, and not just accidentally did this.
1 Note that std::cout is tied to std::cin by default, which leads to std::cout being flushed before any input operation, so that any prompt will be printed before the user has to input something.
There are no the best. You use what you need :
'\n' - to end the line
"some string\n" - the end the line after some string
std::endl - to end the line and flush the stream
They do different things. "\n" Outputs a newline (in the appropriate platform-specific representation, so it generates a "\r\n" on Windows), but std::endl does the same and flushes the stream. Usually, you don't need to flush the stream immediately and it'll just cost you performance, so for the most part there's no reason to use std::endl.
Edit: I worded my answer poorly, which may have lead people to believe that I thought "\n" actually printed a null character. This is of course wrong :)
Edit 2: Having looked at a C++ reference, chars are passed by reference anyway, so there's no difference there. The only difference is that the cstring will have to be searched for a delimiting character. The below isn't correct due to this fact.
'\n' would be ever so slightly more efficient than "\n", because the latter also contains a null character on the end, which means you're sending a char* to operator<<() (usually 4 bytes on a 32-bit system) as opposed to a single byte for a char.
In practice, this is borderline irrelevant. Personally, I follow the convention that Vladimir outlined.*
std::cout << variable << std::endl;
std::endl output a newline, but it also flushes the output stream. In other words, same effect as
std::cout << variable << '\n'; // output newline
std::cout.flush(); // then flush
std::cout << variable << '\n';
'\n' output a newline for a char, hence ostream& operator<< (ostream& os, char c); will be used.
std::cout << variable << "\n";
"\n" is a const char[2], so ostream& operator<< (ostream& os, const char* s); will be used. We can imagine, this function will contain a loop, we might argue is overkill to just print out a newline.
std::endl flushes the stream. When this something you want to happen -- e.g. because you expect your output to be made visible to the user in a timely fashion -- you should use std::endl instead of writing '\n' to the stream (whether as an isolated character or part of a string).
Sometimes, you can get away without explicitly flushing the stream yourself; e.g. in a linux environment, if cout is synchronized with STDOUT (this is the default) and is writing to a terminal, then by default, the stream will be line buffered and will automatically flush every time you write a new line.
However, it is risky to rely on this behavior. e.g. in the same linux environment, if you decide to run your program with stdout being redirected to a file or piped to another process, then by default, the stream will be block buffered instead.
Similarly, if you later decide to turn off synchronization with stdio (e.g. for efficiency), then implementations will tend to use iostream's buffering mechanisms, which doesn't have a line buffering mode.
I have seen much wasted productivity due to this mistake; if output should be visible when it is written, then you should either use std::endl explicitly (or use std::flush or std::ostream::flush, but I usually find std::endl more convenient), or do something else that ensures flushing happens often enough, such as configuring stdout to be line buffered (assuming that's adequate).
I have a large code base that uses std::cout to generate its output, and it uses std::endl all over the place to generate its newlines. This program seems to generate only linefeeds for the endl, which isn't a huge problem in itself, but for whatever reason, wasn't what I had expected.
So as a reality check, I built a simple program to pump endl's into cout, compiled it with the same compiler and examined the output from that. That program emits both CR and LF for endl.
It doesn't look like the large program plays any games with cout to change the way endl works, at least not that I can recognize, so it seems strange that it should behave differently than the small program. It seems as though the large program must be doing something to change the defaults. What am I missing here?
Both programs were compiled using MinGW gcc 4.5.2 on 32bit windows.
To add to Tomalak Geret'kal's answer: the fact that endl expands to the platform-specific endline is a popular misconception.
Inside a C/C++ application the only "official" newline (at least, as far as streams and stream-related functions are concerned) is '\n'. The translation from '\n' to the platform-specific newline is done inside the streams1 when they are opened in text mode (i.e. without the ios::bin flag).
endl, instead, is used to force a stream flush after the '\n'; this can be useful for console output, but (1) often this is not the case (cout is automatically flushed when input is requested from cin via the tied-stream mechanism) and only wastes CPU time, and (2) you often find it used also on file streams, where it is almost never useful, and results in poor file writing performance.
As discussed in the comments, as far as the standard is concerned the translation could actually happen at any level below the stream (e.g. the stream may translate the presence/absence of ios::bin into a flag for the underlying OS file management functions, and it would be responsibility of the OS to do the translation); in reality, mainstream OSes do not have particular flags for this kind of translation, mainly because their file APIs are content-agnostic (you tell them what to write, they write it without modifications).
std::endl is defined by the C++ Standard to perform the following:
Stream a '\n' character;
Stream the std::flush I/O manipulator.
If you're seeing carriage returns at the other end of the stream, then that's occurring at the file interface (and not in the stream functionality itself); in particular, on Windows, you can expect "\n" to be translated transparently to "\r\n" during text-mode output to files.
So, check that your files are both being opened in text- or binary- mode respectively. There is nothing else in C++ that could affect this behaviour.
This FAQ entry pretty much covers what I just said, too.
When a file is opened in "TEXT" Mode (the default when you create file streams).
The '\n' character is converted into a platform specific "end of line sequence" when you write it to a file. Conversely the "end of line sequence" is converted into a '\n' when you read from the file.
Note if you open a file in "BINARY" Mode this conversion does not happen.
In relation to std::endl
stream << std::endl
Is equivalent to:
stream << '\n' << std::flush;
Thus if your stream is a std::fstream (that was opened normally) then '\n' character will be converted into "end of line sequence" which on some platforms is '\r\n'