Why can't I input the integers from a file? - c++

I'm trying to get this C++ code to input a series of numbers from a text file:
int x = 0;
cin >> x;
ifstream iffer;
int numbers[12];
iffer.open("input.txt");
for (int i = 0; i < 12; i++){
iffer >> numbers[i];
}
This doesn't seem to work on the Mac.
Every cell will equal to 0 regardless of the values in the text file. In other words, the ifstream isn't assigning the numbers.
How can I make this work? Is it a Mac issue and if so, how can I get it to work?
Thanks!
Anthony Glyadchenko

Maybe opening the file failed?
You can check if the failbit of iffer is set with fail()
if(iffer.fail())
{
cout << "Failed to open file." << endl;
}

Tried (VC9.0):
#include <iostream>
#include <fstream>
int main()
{
using namespace std;
int x = 0;
cin >> x;
ifstream iffer;
int numbers[12];
iffer.open("input.txt");
for (int i = 0; i < 12; i++){
iffer >> numbers[i];
}
for (int i = 1; i < 12; i++){
numbers[i] = i;
}
return 0;
}
That worked, but the second loop is wrong.

It should work, but be aware, that "get" will always just read one character. This is what I tested, also on Mac OSX, but this has nothing to do with your OS, since it is standard C++:
#include <iostream>
#include <fstream>
using namespace std;
int main(){
ifstream iffer;
iffer.open("input.txt");
char numbers[12];
int i = 0;
while (iffer.good()){
numbers[i] = iffer.get();
i++;
}
for (int n = 0; n < 8; n++){
cout << numbers[n];
}
cout << endl;
iffer.close();
}
The file "input.txt" I am reading in. Make sure this file is in your working directory!:
12345678
While reading the file every character will be stored in your array. So when you have a file like
1 2 3 4 5 6
your array will contain
numbers[0] = '1'
numbers[1] = ' '
numbers[2] = '2'
numbers[3] = ' '
...

I tried your code, slightly modified, on both Linux (g++ 3.4.4) and Mac (g++ 4.0.1) and it works just fine!
With respect to Chuck, if input.txt does not exist, iffer.fail() is true. Since you say that's not the case...
Another possibility is a different input.txt file than what you expected. If it had too few numbers, you'd see zeros (or other garbage values). (You could test with iffer.eof(), though that might be set (appropriately) after reading the last number if there's no trailing whitespace (like a newline). So test eof() before reading!)
Alternatively, you could have a dangling pointer elsewhere in your code trashing something inappropriately. Sometimes adding and removing large chunks of code will permit you to manually "binary search" for where such problems actually lie.
#include <iostream>
#include <fstream>
using namespace std;
#define SHOW(X) cout << # X " = \"" << (X) << "\"" << endl
int main()
{
int x = 0;
cin >> x;
ifstream iffer;
int numbers[12];
iffer.open("input.txt");
SHOW( iffer.fail() );
SHOW( iffer.eof() );
for (int i = 0; i < 12; ++i)
{
SHOW(i);
SHOW(numbers[i]);
iffer >> numbers[i];
SHOW(numbers[i]) << endl;
}
for (int i = 0; i < 12; ++i)
SHOW(numbers[i]);
SHOW( iffer.fail() );
SHOW( iffer.eof() );
}

This sounds like a path issue. You have an "input.txt" file somewhere, but not in the current directory. If this is in a GUI application, keep in mind that the current directory is somewhat unpredictable and you should either give an absolute path or a path relative to some known path (e.g. the path to the current application CFBundle).
Just to test, I just created a Unix program including your precise code wrapped in the following code:
#include <iostream>
#include <fstream>
using namespace std;
int main() {
int x = 0;
// your code
cout << numbers[5] << endl;
return 0;
}
It worked, so if this is in a command-line program and you launched it from the right directory, you must be changing the current directory somewhere in your app.

Related

A C++ program that is abour cerr and clog runs differently in Clion and in terminal

I am trying to get use of cerr and clog instead of cout to give out error message. But I met a problem. Below is a simplified version.
#include <iostream>
using namespace std;
int main() {
for (int i = 0; i < 5; ++i) {
int x;
cin >> x;
cout << "first" << endl;
cerr << "second" << endl;
}
return 0;
}
But the result was
1
first
second
2
second
first
3
second
first
4
first
second
5
second
first
However, if I use g++ on Win10's cmd to compile and run, it was fine.
1
first
second
2
first
second
3
first
second
4
first
second
5
first
second
So I start to doubt that there are some certain settings that make the Clion inner compile&run environment differ from g++. But I am not sure.
Can anybody tell me why?
There are a lot of things under the hood (SPD mentioned some in the comment, but not all - there is a pty-pipe in the middle). But this just work:
#include <iostream>
using namespace std;
int main() {
for (int i = 0; i < 5; ++i) {
int x;
cin >> x;
cout.flush();
cerr.flush();
cout << "first" << endl;
cout.flush();
cerr << "second"<< endl;
cerr.flush();
}
return 0;
}
Read more here.

Why is this do while loop infinitely executing?

Why is this do while loop infinitely executing?
#include "stdafx.h"
#include <iostream>
using namespace std;
int main()
{
unsigned int base;
cout << "Base: ";
cin >> base;
for (int i = 1; i <= base; i++) {
int j = 0;
do {
cout << "#";
j++;
} while (j = i);
cout << endl;
};
system("pause");
// keep on building up until you reach 'base'
return 0;
}
I am really confused about this. This program is supposed to create a triangle like this
#
##
###
(user inputs bottom number, so in this example the base = 3)
Anybody help fix my rookie mistake?
You might wanna try while (j == i);.
j = i is a variable declaration/assignment which will always be true as long as it succeeds. It seems like you want to compare the two, so use the equal to operator: ==.
Edit: Made a typo and therefore the same mistake as your question shows. Fixed that.

Super basic code: Why is my loop not breaking?

for(int i=0;i<50;i++,size++)
{
cin >> inputnum[i];
cout << size;
if(inputnum[i] == '.')
{
break;
}
}
The break breaks the input stream but the size keeps outputting.
The output of size is 012345678910111213...474849.
I tried putting size++ inside the loop but it made no difference. And size afterwards will be equal to 50, which means it went through the full loop.
I forgot to explain that I added the cout << size within the loop to debug/check why it outputted to 50 after the loop even if I only inputted 3 numbers.
I suspect that inputnum is an array of int (or some other numeric type). When you try to input '.', nothing actually goes into inputnum[i] - the cin >> inputnum[i] expression actually fails and puts cin into a failed state.
So, inputnum[i] is not changed when inputting a '.' character, and the break never gets executed.
Here's an slightly modified version of your code in a small, complete program that demonstrates using !cin.good() to break out of the input loop:
#include <iostream>
#include <ostream>
using namespace std;
int main()
{
int inputnum[50];
int size = 0;
for(int i=0;i<50;i++,size++)
{
cin >> inputnum[i];
if (!cin.good()) {
break;
}
}
cout << "size is " << size << endl;
cout << "And the results are:" << endl;
for (int i = 0; i < size; ++i) {
cout << "inputnum[" << i << "] == " << inputnum[i] << endl;
}
return 0;
}
This program will collect input into the inputnum[] array until it hits EOF or an invalid input.
What is inputnum ? Make sure t's a char[]!! with clang++ this compiles and works perfectly:
#include <iostream>
int main() {
int size = 0;
char inputnum[60];
for(int i=0;i<50;i++,size++) {
std::cin >> inputnum[i];
std::cout << size;
if(inputnum[i] == '.') {
break;
}
}
return 0;
}
(in my case with the following output:)
a
0a
1s
2d
3f
4g
5.
6Argento:Desktop marinos$
Your code seams OK as long as you're testing char against char in your loop and not something else.. Could it be that inputnum is some integral value ? if so, then your test clause will always evaluate to false unless inputnum matches the numerical value '.' is implicitly casted to..
EDIT
Apparently you are indeed trying to put char in a int[]. Try the following:
#include <iostream>
int main() {
using namespace std;
int size = 0;
int inputnum[50];
char inputchar[50];
for(int i=0;i<50;i++,size++) {
cin >> inputchar[i];
inputnum[i] = static_cast<int>(inputchar[i]); // or inputnum[i] = (int)inputchar[i];
cout << size << endl; // add a new line in the end
if(inputchar[i] == '.') break;
}
return 0;
}
Then again this is probably a lab assignment, in a real program I'd never code like this. Tat would depend on the requirements but I'd rather prefer using STL containers and algorithms or stringstreams. And if forced to work at a lower-level C-style, I'd try to figure out to what number '.' translates to (simply by int a = '.'; cout << a;`) and put that number directly in the test clause. Such code however might be simple but is also BAD in my opinion, it's unsafe, implementation specific and not really C++.

Is there a way in C++ to only return the the last instance of a for loop?

Like for example:
#include <iostream>
using namespace std;
int main()
{
for (int n=10; n>0; n--){
cout<< n <<", ";}
}
This will output the numbers 10,9,8,7,6,5,4,3,2,1
So is there a new way so I just get the last instance of the loop, the 1?
I new at this and google isn't giving me any answers.
There is no direct way to detect whether the current iteration of a for loop is the last one. But if the behavior of the loop is predictable, you can usually write code that can detect when you're on the last iteration.
In this case, you could do something like:
if (n == 1) {
cout << n << "\n";
}
in the body of the loop. (Of course it would be simpler in this case to replace the entire loop with cout << "1\n";, but I presume this is an example of something more complex.)
In more complicated cases, you can save whatever information you need in the body of the loop:
int value_to_print:
for ( ... ) {
value_to_print = i;
}
std::cout << value_to_print << "\n";
On each iteration, value_to_print is replaced by the current value of i. The final value is the value of i on the last iteration.
You could create a variable (outside the loop) to hold the "current" value of n; whatever happens to the loop (exit condition reached, break, an exception is thrown...) the value will stay there:
int last_n;
for (int n=10; n>0; n--) {
last_n = n;
cout<< n <<", ";
if (something) {
break; // works in this case
} else if (something else) {
throw some_random_error; // works in this case too
}
}
cout << "The last value of 'n' was " << last_n << endl;
You can use a simple if statement for that.
int main()
{
for (int n=10; n>0; n--) {
cout << n << ", ";
if( n == 1 ) {
return n;
}
}
}
The simplest way to accomplish this is: -
#include <iostream>
using namespace std;
int main()
{
int x;
for (int n = 10; n > 0; n--){
x = n;
}
cout << x;
return 0;
}
I'm new to programming too and was trying to figure out something which will allow me to get the last instance of my loop as output.
I tried something and got the output, see if it can help you (if there's a mistake please let me know).
Here user input string is being replaced by "*" and instead of giving output of every instance i have made so only last instance is given as output.
#include <iostream>
#include <string>
using namespace std;
int main()
{
string str;
int string_length;//string length
cout<<"Enter your Email-ID: ";
cin>>str;
string_length = str.length(); //to give the length of input string and use it for the loop
cout<<"lentgh of the string: "<<string_length <<endl;
for(int x = 0; x <= string_length; x++){
str[x] = '*';
while(x==string_length) //string_length is the last instance of the loop
{
cout<<"Here's your Encrypted Email-ID: " <<str<<endl;
break;
}
}
return 0;
}

How to read a txt file into a 2d array

Hey guys I am new to reading txt files to arrays, so I need to read this txt file temperature.txt to a two dimensional array. Here is the file I need to read, and the code I tried writing up it complies but Im not sure if it is reading it correctly
T(F) R1 R2 R3 R4
95.0 95.20 66.10 43.10 29.00
96.0 96.10 67.60 43.50 31.20
97.0 97.40 67.00 43.70 30.50
98.0 97.20 69.10 44.10 30.70
99.0 98.90 68.00 44.70 32.80
100.0 99.50 71.10 45.10 31.50
101.0 101.00 71.20 45.30 31.60
102.0 101.60 71.00 45.70 30.50
103.0 101.80 73.10 46.30 32.50
104.0 103.70 73.50 46.60 32.70
105.0 105.60 72.80 47.10 33.60
UPDATE I re did this again without looking at your answers but will this work ?
using namespace std;
#include<fstream>
#include<iostream>
#include<cmath>
#include<iomanip>
#include<stdlib.h>
int main ()
{
char temp[11] [5];
ifstream tempin ("c:\\mydoc2\\temperaturedata.txt");
tempin>>temp[0]>>temp[1]>>temp[2]>>temp[3]>>temp[4]>>temp[5]>>temp[6]>>temp[7]>>temp[8]
>>temp[9]>>temp[10];
while(!tempin.fail())
{
cout<< temp[0] << " " << temp[1] << " " << temp[2] << " " << temp[3]<< " " << temp[4]<< " " << temp[5] << " " << temp [6] <<
" " << temp [7] << " " << temp[8] << " " << temp[9] << " " << temp[10];
tempin>>temp[0]>>temp[1]>>temp[2]>>temp[3]>>temp[4]>>temp[5]>>temp[6]>>temp[7]
>>temp[8]>>temp[9]>>temp[10];
}
cout << endl << endl;
system("pause");
return 0;
}
You have a string myArray[5]; but you're reading 55 elements - that should not work!
There are lots of errors in your code.
1) You have written a read function but you never call it, so it never executes.
2) There is no 2D array in your code. 2D arrays look like this double myArray[10][10];. (that's a 10 by 10 2D array of doubles).
3) You're trying to read floating point numbers, but your array is an array of strings.
4) Your array is size 5 but you try and read 55 items into it.
5) After you open the file you have an infinite loop which just prints out "No file\n". Not sure why you want to print out error messages in a loop. Normally you just print an error message once.
I could go on, but I think the main point is that you're a beginner, and you currently aren't able to write three lines of code without introducing an error (sorry to be harsh but based on the above that is true). So the important lesson is that you should not try to write more than three lines of code at once.
Try something like this
a) Write some code which opens a file, test it and check that it does open the file
b) Add some code to a) to read one number, test it and check that it does read one number.
c) Replace the read one number code with code that reads a 1D array of numbers. Test it and check that it works.
etc. etc.
The point is to build up gradually to the program you want, and test each stage as you go. I can't emphasise how important that is. Every professional programmer works like this, but because you're a beginner the steps you have to take are much smaller than an experienced programmer.
Try something like this:
#include <stdlib.h>
#include <fstream>
#include <sstream>
#include <string>
#include <iostream>
using namespace std;
int main() {
string line;
ifstream myfile ("C:/temps.txt");
int dim_x = 12;
int dim_y = 5;
double temps[dim_x][dim_y] ;
//init the array if neccesary
for(int x = 0;x<dim_x;x++)
for(int y = 0; y<dim_y;y++)
temps[x][y]=0;
if (myfile.is_open()){
for ( int x=0; getline (myfile,line); x++ ){
int y=0;
istringstream iss(line);
while(iss){
string sub;
iss >> sub;
temps[x][y] = ::atof(sub.c_str());
y++;
}
}
myfile.close();
}
cout << "TEMPS:" << endl;
for(int x = 0;x<dim_x;x++){
for(int y = 0; y<dim_y;y++)
cout<<temps[x][y]<<" ";
cout<<endl;
}
return 0;
}
I made some improvements
#include <fstream>
#include <iostream>
#include <string>
#include <iomanip>
using namespace std;
void read ();
int main ()
{
read();
return 0;
}
void read()
{
ifstream indata(".\\temperaturedata.txt");
if(indata == NULL)
{
cout<< "Opening file failed."<< endl;
return;
}
const int columns = 5;
const int rows = 11;
double myArray[rows][columns];
string tmp;
getline(indata, tmp);
for(int i = 0; i < rows; ++i)
{
for (int j = 0; j < columns; ++j)
{
cout << "\t" << flush;
indata >> myArray[i][j];
cout.setf(ios::fixed);
cout << setprecision(2) << myArray[i][j] <<flush;
}
cout << endl;
}
indata.close();
}
If the content of your file is like this:
95.0 95.20 66.10 43.10 29.00
96.0 96.10 67.60 43.50 31.20
97.0 97.40 67.00 43.70 30.50
98.0 97.20 69.10 44.10 30.70
99.0 98.90 68.00 44.70 32.80
100.0 99.50 71.10 45.10 31.50
101.0 101.00 71.20 45.30 31.60
102.0 101.60 71.00 45.70 30.50
103.0 101.80 73.10 46.30 32.50
104.0 103.70 73.50 46.60 32.70
105.0 105.60 72.80 47.10 33.60
then, it's quite easy for you to get these values. But there are some errors in your code:
while(!indata.fail()) : This line will cause a dead loop. Use if(!indata) instead.
You will need a 2-dimension array of type double instead of string
Here is what could work:
#include<fstream>
#include<iostream>
#include<cmath>
#include<iomanip>
#include<stdlib.h>
using namespace std;
void read ();
int main ()
{
read();
system("PAUSE");
return 0;
}
void read()
{
ifstream indata("E:\\temperature.txt"); //that's my path,you should use yours.
if(!indata)
{
cout<<"No file."<< endl;
}
if(indata.is_open())
{
double myArray[11][5];
for(int i = 0; i < 11; ++i)
{
for(int j = 0; j < 5; ++j)
{
indata >> myArray[i][j];
//cout<<myArray[i][j]<<"\t";
}
//cout<<endl;
}
}
}
This could work when your txt file doesn't include the first line:T(F) R1 R2 R3 R4, if this line did exit,you should use getline() to move your file pointer to the second line, where you could read the data.