For example,
In this document
< ?xml version="1.0" ? >
< SOAP-ENV:Envelope
xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/"
xmlns:SOAP-ENC="http://schemas.xmlsoap.org/soap/encoding/"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:xsd="http://www.w3.org/2001/XMLSchema"
xmlns:ns1="http://opcfoundation.org/webservices/XMLDA/1.0/"
xmlns:ns2="Service">
< SOAP-ENV:Body id="_0" >
if I need to select the element "Body", I need to know the prefix "SOAP-ENV". How can I get that? getting a root element and slicing the colon (:) off seems a dirty idea to me, I am sure there should be a neat way to do that. Google does not help (may be I am not searching for the right thing).
If you're doing XML processing you shouldn't need to know the prefix.
To select a node in an XML document, you need not know the prefix. You need to know the namespace, not the prefix.
If you are processing a SOAP document, then you know the namespace is http://schemas.xmlsoap.org/soap/envelope/. And that's all you need. In the XML application, you can assign your own namespace prefix.
Related
I loaded an XML file via the "Import XML definition" and everything worked fine. But the XML needs the following added to it
Here is my question,
I just have the XML but not the xsd.
How do I add the xmlns and xsi string into the root node?
For the elements, how do I add the tag like 'common' and 'udf' before the column name like common:abbreviation or udf:name or udf:value?
Basically is there an easy and quick way to do this? Do I need to reimport the files with new xsd?
Thanks
<MyRoot
xmlns:udf="http://www.url.com/xx/XXXX/type1"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:common="http://www.url.com/xx/XXXX/common"
xmlns="http://www.url.com/ws/v410/NewPerson"
xsi:schemaLocation="http://www.url.com/xx/XXXX/NewPerson NewPerson.xsd"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
<common:ID>NNNNNNNNNN</common:ID>
<UDF>
<udf:name>Name Content</udf:name>
<udf:value></udf:value>
</UDF>
</MyRoot>
I've written a post about adding ports to XML transformation. See if this helps: http://powercenternotes.blogspot.com/2013/03/adding-port-to-existing-xml-parser.html
What would be a straightforward way to transform a source XML document into a destination XML document. There are only small differences between source and destination: Specifically I want to delete the first UnitIDRecord-Node within each UnitIDGroup-Node.
What would be the appropriate model for this task DOM or SAX?
What XML-library would best fit this problem (which guarantees that the source and destination only differs in the deleted nodes, no missing namespace, attributes, encoding, ...)?
I read about XSLT, could this be an option?
The XML document looks like following:
<?xml version="1.0" encoding="UTF-8"?>
<ExPostInformationRealGeneration xmlns="http://schemas.seven2one.de/EEX/TransparencyPlatform" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://schemas.seven2one.de/EEX/TransparencyPlatform EEXTransparencyPlatform.xsd">
<DispatcherID>XYZ</DispatcherID>
<CreationDateTime>2012-05-22T13:57:00Z</CreationDateTime>
<MessageText>1 - Positiv - Meldung mit Quality-Tag - L000</MessageText>
<UnitIDGroup>
<UnitID>E110200-001</UnitID>
<UnitIDRecord><Quantity>16.9</Quantity><Starttime>2008-04-30T22:00:00Z</Starttime><Period>PT1H</Period><MessageText></MessageText></UnitIDRecord>
<UnitIDRecord><Quantity>16.6</Quantity><Starttime>2008-04-30T23:00:00Z</Starttime><Period>PT1H</Period><MessageText></MessageText></UnitIDRecord>
<UnitIDRecord><Quantity>16.4</Quantity><Starttime>2008-05-01T00:00:00Z</Starttime><Period>PT1H</Period><MessageText></MessageText></UnitIDRecord>
</UnitIDGroup>
<UnitIDGroup>
<UnitID>E110200-002</UnitID>
<UnitIDRecord><Quantity>16.9</Quantity><Starttime>2008-04-30T22:00:00Z</Starttime><Period>PT1H</Period><MessageText></MessageText></UnitIDRecord>
<UnitIDRecord><Quantity>16.6</Quantity><Starttime>2008-04-30T23:00:00Z</Starttime><Period>PT1H</Period><MessageText></MessageText></UnitIDRecord>
<UnitIDRecord><Quantity>16.4</Quantity><Starttime>2008-05-01T00:00:00Z</Starttime><Period>PT1H</Period><MessageText></MessageText></UnitIDRecord>
</UnitIDGroup>
<UnitIDGroup>
<UnitID>E110201-001</UnitID>
<UnitIDRecord><Quantity>7.0</Quantity><Starttime>2008-04-30T22:00:00Z</Starttime><Period>PT1H</Period><MessageText></MessageText></UnitIDRecord>
<UnitIDRecord><Quantity>7.1</Quantity><Starttime>2008-04-30T23:00:00Z</Starttime><Period>PT1H</Period><MessageText></MessageText></UnitIDRecord>
<UnitIDRecord><Quantity>7.1</Quantity><Starttime>2008-05-01T00:00:00Z</Starttime><Period>PT1H</Period><MessageText></MessageText></UnitIDRecord>
</UnitIDGroup>
<!-- other UnitIDGroup elements -->
</ExPostInformationRealGeneration>
I would consider the possibility of reading the file in as strings and writing the string out to another file if it matches your criteria. That's a 5 line program and avoids any parsing etc. It will run quickly and is simple. But, it is specific to this problem and not reusable. I offer this therefore as a suggestion not the correct solution!
I have deployed my webservice into Tomcat.
The WSDL has got some operations like ViewOptions, but when I ran that, I got this error:
This XML file does not appear to have any style information associated with it. The document tree is shown below.
<soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/">
<soap:Body>
<soap:Fault>
<faultcode>soap:Server</faultcode>
<faultstring>1</faultstring>
</soap:Fault>
</soap:Body>
</soap:Envelope>
Why do we get this error?
The message isn't an "error" but rather a warning n need not be solved but ignored. An XML document is a data structure but does not contain any presentation/style information internally. Normally an XML document is used in inter-application communication or as a pure data structure that is then used with additional presentation/style information to display to users.
XML can be applied style by XSLT just as HTML by CSS and the above warning can be eradicated An eg: of applying xls to xml
We don't present xml using xls for RSS, Web Services as they are just used for communication without applying stylesheet rather than meant to be presented to user in browser.
So, everything is fine here.
what worked for my case. I replaced all the links of ... with window.open("...link", "_self") and changed
import {
HashRouter as Router,
} from 'react-router-dom';
Have a source xml document that uses namespace containing prefixes and a default namespace. When I transform it using a XSLT doc, the resulting translated xml document is incorrect, that is, element data from the source xml document is missing.
When I remove the "default namespace" from the source xml document, the transformation works as expected.
Question: is there a way to resolve problem without the need to edit out the default namespace from the source xml document? That is, add the solution to the XSLT document.
XML Document:
<MyElement xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:xsd="http://www.w3.org/2001/XMLSchema"
xmlns="http://www.zolldata.com/UDX">
where the problem default namespace is xmlns="http://www.zolldata.com/UDX"
Specify same default namespace in XSLT document if your selectors do not use prefixes, or use prefixes for all selectors in the XSLT, but don't forget to bind them to the default namespace of your XML document.
My question is this:
If I have the following XML:
<root>
<alpha one="start">
<in>1</in>
</alpha>
</root>
and then I'll add the following path:
<root><alpha one="start"><out>2</out></alpha></root>
which results in
<root>
<alpha one="start">
<in>1</in>
</alpha>
</root>
<root>
<alpha one="start">
<out>2</out>
</alpha>
</root>
I want to be able to convert it into this:
<root>
<alpha one="start">
<in>1</in>
<out>2</out>
</alpha>
</root>
Besides implementing it myself (don't feel like reinventing the wheel today),
is there a specific way in Xerces (2.8,C++) to do it?
If so, at which point of the DOMDocuments life is the node merging done? at each insertion? at the writing of the document, explicitly on demand?
Thanks.
If you use xalan its possible to use an xpath to find the element and directly insert into the correc one.
The following code may be slow but returns all "root" elments with the attribute "one" set to "start".
selectNodes("//root[#one="start"]")
It is probably better to use the full path
selectNodes("/abc/def/.../root[#one="start"]")
or if you already have the parent element work relative
selectNodes("./root[#one="start"]")
I think to get the basic concepts xpath on wikipedia.
Isn't it just a one minute task if you know the names of the container tag where various different tags are present?
In your example, get a pointer to the alpha tag in all the XML documents and put the contents of all of them into a new document's alpha if they're not present there already.
This isn't as bad as reinventing the wheel. I'm not familiar with Xerces, but with libxml++, I would call this an easy task.