What is the point of function pointers? - c++

I have trouble seeing the utility of function pointers. I guess it may be useful in some cases (they exist, after all), but I can't think of a case where it's better or unavoidable to use a function pointer.
Could you give some example of good use of function pointers (in C or C++)?

Most examples boil down to callbacks: You call a function f() passing the address of another function g(), and f() calls g() for some specific task. If you pass f() the address of h() instead, then f() will call back h() instead.
Basically, this is a way to parametrize a function: Some part of its behavior is not hard-coded into f(), but into the callback function. Callers can make f() behave differently by passing different callback functions. A classic is qsort() from the C standard library that takes its sorting criterion as a pointer to a comparison function.
In C++, this is often done using function objects (also called functors). These are objects that overload the function call operator, so you can call them as if they were a function. Example:
class functor {
public:
void operator()(int i) {std::cout << "the answer is: " << i << '\n';}
};
functor f;
f(42);
The idea behind this is that, unlike a function pointer, a function object can carry not only an algorithm, but also data:
class functor {
public:
functor(const std::string& prompt) : prompt_(prompt) {}
void operator()(int i) {std::cout << prompt_ << i << '\n';}
private:
std::string prompt_;
};
functor f("the answer is: ");
f(42);
Another advantage is that it is sometimes easier to inline calls to function objects than calls through function pointers. This is a reason why sorting in C++ is sometimes faster than sorting in C.

Well, I generally use them (professionally) in jump tables (see also this StackOverflow question).
Jump tables are commonly (but not exclusively) used in finite state machines to make them data driven. Instead of nested switch/case
switch (state)
case A:
switch (event):
case e1: ....
case e2: ....
case B:
switch (event):
case e3: ....
case e1: ....
you can make a 2d array of function pointers and just call handleEvent[state][event]

Examples:
Custom sorting/searches
Different
patterns (like Strategy, Observer)
Callbacks

The "classic" example for the usefulness of function pointers is the C library qsort() function, which implements a Quick Sort. In order to be universal for any and all data structures the user may come up with, it takes a couple of void pointers to sortable data and a pointer to a function that knows how to compare two elements of these data structures. This allows us to create our function of choice for the job, and in fact even allows for choosing the comparison function at run time, e.g. for sorting ascending or descending.

Agree with all of the above, plus....
When you load a dll dynamically at runtime you'll need function pointers to call the functions.

In C, the classic use is the qsort function, where the fourth parameter is pointer to a function to use to perform the ordering within the sort. In C++, one would tend to use functors (objects that look like functions) for this kind of thing.

I am going to go against the current here.
In C, function pointers are the only way to implement customization, because there is no OO.
In C++, you can use either function pointers or functors (function objects) for the same result.
The functors have a number of advantages over raw function pointers, due to their object nature, notably:
They may present several overloads of the operator()
They can have state / reference to existing variables
They can be built on the spot (lambda and bind)
I personally prefer functors to function pointers (despite the boilerplate code), mostly because the syntax for function pointers can easily get hairy (from the Function Pointer Tutorial):
typedef float(*pt2Func)(float, float);
// defines a symbol pt2Func, pointer to a (float, float) -> float function
typedef int (TMyClass::*pt2Member)(float, char, char);
// defines a symbol pt2Member, pointer to a (float, char, char) -> int function
// belonging to the class TMyClass
The only time I have ever seen function pointers used where functors could not was in Boost.Spirit. They have utterly abused the syntax to pass an arbitrary number of parameters as a single template parameter.
typedef SpecialClass<float(float,float)> class_type;
But since variadic templates and lambdas are around the corner, I am not sure we will use function pointers in pure C++ code for long now.

I used function pointers recently to create an abstraction layer.
I have a program written in pure C that runs on embedded systems. It supports multiple hardware variants. Depending on the hardware I am running on, it needs to call different versions of some functions.
At initialization time, the program figures out what hardware it is running on and populates the function pointers. All of the higher-level routines in the program just call the functions referenced by pointers. I can add support for new hardware variants without touching the higher-level routines.
I used to use switch/case statements to select the proper function versions, but this became impractical as the program grew to support more and more hardware variants. I had to add case statements all over the place.
I also tried intermediate function layers to figure out which function to use, but they didn't help much. I still had to update case statements in multiple places whenever we added a new variant. With the function pointers, I only have to change the initialization function.

Function pointers can be used in C to create an interface against which to program. Depending on the specific functionality that is needed at runtime, a different implementation can be assigned to the function pointer.

My main use of them has been CALLBACKS: when you need to save information about a function to call later.
Say you're writing Bomberman. 5 seconds after the person drops the bomb, it should explode (call the explode() function).
Now there's 2 ways to do it. One way is by "probing" all bombs on the screen to see if they're ready to explode in the main loop.
foreach bomb in game
if bomb.boomtime()
bomb.explode()
Another way is to attach a callback to your clock system. When a bomb is planted, you add a callback to make it call bomb.explode() when the time is right.
// user placed a bomb
Bomb* bomb = new Bomb()
make callback( function=bomb.explode, time=5 seconds ) ;
// IN the main loop:
foreach callback in callbacks
if callback.timeToRun
callback.function()
Here callback.function() can be any function, because it is a function pointer.

Like Rich said above, it is very usual for functions pointers in Windows to reference some address that stores function.
When you programming in C language on Windows platform you basically load some DLL file in primary memory(using LoadLibrary) and to use the functions stored in DLL you need to create functions pointers and point to these address (using GetProcAddress).
References:
LoadLibrary
GetProcAddress

Use of function pointer
To call function dynamically based on user input.
By creating a map of string and function pointer in this case.
#include<iostream>
#include<map>
using namespace std;
//typedef map<string, int (*)(int x, int y) > funMap;
#define funMap map<string, int (*)(int, int)>
funMap objFunMap;
int Add(int x, int y)
{
return x+y;
}
int Sub(int x, int y)
{
return x-y;
}
int Multi(int x, int y)
{
return x*y;
}
void initializeFunc()
{
objFunMap["Add"]=Add;
objFunMap["Sub"]=Sub;
objFunMap["Multi"]=Multi;
}
int main()
{
initializeFunc();
while(1)
{
string func;
cout<<"Enter your choice( 1. Add 2. Sub 3. Multi) : ";
int no, a, b;
cin>>no;
if(no==1)
func = "Add";
else if(no==2)
func = "Sub";
else if(no==3)
func = "Multi";
else
break;
cout<<"\nEnter 2 no :";
cin>>a>>b;
//function is called using function pointer based on user input
//If user input is 2, and a=10, b=3 then below line will expand as "objFuncMap["Sub"](10, 3)"
int ret = objFunMap[func](a, b);
cout<<ret<<endl;
}
return 0;
}
This way we have used function pointer in our actual company code.
You may write 'n' number of function and call them using this method.
OUTPUT:
Enter your choice( 1. Add 2. Sub 3. Multi) : 1
Enter 2 no :2 4
6
Enter your choice( 1. Add 2. Sub 3. Multi) : 2
Enter 2 no : 10 3
7
Enter your choice( 1. Add 2. Sub 3. Multi) : 3
Enter 2 no : 3 6
18

A different perspective, in addition to other good answers here:
In C, you only use function pointers, not (directly) functions.
I mean, you write functions, but you cant manipulate functions. There's no run-time representation of a function as such which you are able to use. You can't even call "a function". When you write:
my_function(my_arg);
what you're actually saying is "perform a call to the my_function pointer with the specified argument". You're making a call via a function pointer. This decay to function pointer means that the following commands are equivalent to the previous function call:
(&my_function)(my_arg);
(*my_function)(my_arg);
(**my_function)(my_arg);
(&**my_function)(my_arg);
(***my_function)(my_arg);
and so on (thanks #LuuVinhPhuc).
So, you're already using function pointers as values. Obviously you would want to have variables for those values - and here is where all the uses other metion come in: Polymorphism/customization (like in qsort), callbacks, jump tables etc.
In C++ things are a bit more complicated, since we have lambdas, and objects with operator(), and even an std::function class, but the principle is still mostly the same.

I use function pointers extensively, for emulating microprocessors that have 1-byte opcodes. An array of 256 function pointers is the natural way to implement this.

For OO languages, to perform polymorphic calls behind the scenes (this is also valid for C up to some point I guess).
Moreover, they're very useful to inject different behaviour to another function (foo) at runtime. That makes function foo higher-order function. Besides it's flexibility, that makes the foo code more readable since it let's you pull that extra logic of "if-else" out of it.
It enables many other useful things in Python like generators, closures etc.

One use of function pointer could be where we may not want to modify the code where the function is getting called (meaning thereby the call might be conditional and under different conditions, we need to do different sort of processing).
Here the function pointers are very handy, since we do not need to modify the code at the the place where the function is getting called. We simply call the function using the function pointer with appropriate arguments.
The function pointer can be made to point to different functions conditionally. (This can be done somewhere during initialization phase). Moreover the above model is very helpful, if we are not in position to modify the code where it is getting called (suppose it's a library API we can't modify). The API uses a function pointer for calling the appropriate user defined function.

I'll try to give a somewhat comprehensive list here:
Callbacks: Customize some (library) functionality with user supplied code. Prime example is qsort(), but also useful to handle events (like a button calling a callback when it's clicked), or necessary to start a thread (pthread_create()).
Polymorphism: The vtable in a C++ class is nothing but a table of function pointers. And a C program may also choose to provide a vtable for some of its objects:
struct Base;
struct Base_vtable {
void (*destruct)(struct Base* me);
};
struct Base {
struct Base_vtable* vtable;
};
struct Derived;
struct Derived_vtable {
struct Base_vtable;
void (*frobnicate)(struct Derived* me);
};
struct Derived {
struct Base;
int bar, baz;
}
The constructor of Derived would then set its vtable member variable to a global object with the derived's class's implementations of destruct and frobnicate, and code that needed to destruct a struct Base* would simply call base->vtable->destruct(base), which would call the correct version of the destructor, independent of which derived class base actually points to.
Without function pointers, polymorphism would need to be coded out with an army of switch constructs like
switch(me->type) {
case TYPE_BASE: base_implementation(); break;
case TYPE_DERIVED1: derived1_implementation(); break;
case TYPE_DERIVED2: derived2_implementation(); break;
case TYPE_DERIVED3: derived3_implementation(); break;
}
This gets rather unwieldy rather quickly.
Dynamically loaded code: When a program loads a module into memory and tries to call into its code, it must go through a function pointer.
All the uses of function pointers that I've seen fall squarely into one of these three broad classes.

They enhance re-use and modularization of code thus making code more maintainable, readable and less prone to errors.
With function pointers:
Note how we have an iterator method that gets passed to it a function pointer. This function pointer tells us what we should do with each elements in the list.
#include <iostream>
#include <vector>
int square(int x) {
return x * x;
}
int root(int x) {
return sqrt(x);
}
int negative(int x) {
return -x;
}
std::vector<int> listIterator(std::vector<int> list, int (*itemOperation)(int)) {
for (int i = 0; i < list.size(); i++) {
list[i] = itemOperation(list[i]);
}
return list;
}
int main() {
std::vector<int> list = { 9, 16, 4, 25 };
for (int i : listIterator(list, square)) {
std::cout << i << ' ';
}
std::cout << std::endl;
for (int i : listIterator(list, root)) {
std::cout << i << ' ';
}
std::cout << std::endl;
for (int i : listIterator(list, negative)) {
std::cout << i << ' ';
}
return 0;
}
Without function pointers:
Without function pointers, you would need to include an iterator in each of the square, root and negative methods.

Related

Significance of passing a function as an argument

I just learn about passing a function of as an argument in c++,
however I wonder what is its significance.
Considering this example,
#include <iostream>
using namespace std;
void argumentFunction(int x) {
cout << x << " is the result.";
}
void myFunction(void (*functionparam) (int), char parameter[80]) {
cout << parameter;
(*functionparam)(1);
}
int main() {
myFunction(&argumentFunction, "I am calling a function with a function.");
cin.ignore(80,'\n');
return 0;
}
why would I need to pass argumentFunction as a parameter in myFunction, which in fact I can directly call it without passing it:
like this:
#include <iostream>
using namespace std;
void argumentFunction(int x) {
cout << x << " is the result.";
}
void myFunction(char parameter[80]) {
cout << parameter;
argumentFunction(1);
}
int main() {
myFunction( "I am calling a function with a function.");
cin.ignore(80,'\n');
return 0;
}
One example is in the C standard library function qsort, which has the signature:
void qsort(void *base, size_t nmemb, size_t size,
int (*compar)(const void *, const void *));
This allows the programmer to pass an arbitrary comparison function to the existing sorting algorithm instead of having to write a whole new sort function for each type of sorting that needs to be done.
If we take a practical example like C's qsort, it doesn't know how to compare your data. After all, it could be string keys you're sorting, integers, floats, pointers, a combo, etc.
It knows how to sort your data, but it doesn't know how to compare one of your keys to another. So passing in a comparator function pointer gives it that missing puzzle piece and allows that code to sort virtually anything (well, except for objects that require C++ semantics since it just shuffles bytes around while ignoring objects).
So a function pointer is a useful mechanism for decoupling. qsort is decoupled from the data types it can potentially sort. That also makes it very generally applicable since you can provide the missing functionality it needs by passing in function pointers.
Another example is, say, you want to build a user interface for a software. Whenever the data in your software changes, some viewport/canvas kind of thingy should be redrawn. If you just called that redraw function directly in every part of your codebase where the data changes, all sorts of parts throughout your system would have to be coupled to the user interface.
Instead, if the system just calls one or more function pointers whenever the data changes, the underlying system doesn't have to be directly coupled to anything in the user interface (also allowing you to swap out the user interface with something newer and more fashionable without breaking that logic). It's sort of like broadcasting a signal out to the world saying, "I have changed!" without caring who is listening, and we can pass in the appropriate function pointers to determine what to do in the case of such events.
With C++ you have more flexible concepts like virtual functions, functionoids using them, function objects that work with templates, ones that can work abstractly using templates to capture specific function object types through static polymorphism to something using dynamic polymorphism that doesn't require templates to then be used, etc. But it's basically the same idea.

Virtual Methods or Function Pointers

When implementing polymorphic behavior in C++ one can either use a pure virtual method or one can use function pointers (or functors). For example an asynchronous callback can be implemented by:
Approach 1
class Callback
{
public:
Callback();
~Callback();
void go();
protected:
virtual void doGo() = 0;
};
//Constructor and Destructor
void Callback::go()
{
doGo();
}
So to use the callback here, you would need to override the doGo() method to call whatever function you want
Approach 2
typedef void (CallbackFunction*)(void*)
class Callback
{
public:
Callback(CallbackFunction* func, void* param);
~Callback();
void go();
private:
CallbackFunction* iFunc;
void* iParam;
};
Callback::Callback(CallbackFunction* func, void* param) :
iFunc(func),
iParam(param)
{}
//Destructor
void go()
{
(*iFunc)(iParam);
}
To use the callback method here you will need to create a function pointer to be called by the Callback object.
Approach 3
[This was added to the question by me (Andreas); it wasn't written by the original poster]
template <typename T>
class Callback
{
public:
Callback() {}
~Callback() {}
void go() {
T t; t();
}
};
class CallbackTest
{
public:
void operator()() { cout << "Test"; }
};
int main()
{
Callback<CallbackTest> test;
test.go();
}
What are the advantages and disadvantages of each implementation?
Approach 1 (Virtual Function)
"+" The "correct way to do it in C++
"-" A new class must be created per callback
"-" Performance-wise an additional dereference through VF-Table compared to Function Pointer. Two indirect references compared to Functor solution.
Approach 2 (Class with Function Pointer)
"+" Can wrap a C-style function for C++ Callback Class
"+" Callback function can be changed after callback object is created
"-" Requires an indirect call. May be slower than functor method for callbacks that can be statically computed at compile-time.
Approach 3 (Class calling T functor)
"+" Possibly the fastest way to do it. No indirect call overhead and may be inlined completely.
"-" Requires an additional Functor class to be defined.
"-" Requires that callback is statically declared at compile-time.
FWIW, Function Pointers are not the same as Functors. Functors (in C++) are classes that are used to provide a function call which is typically operator().
Here is an example functor as well as a template function which utilizes a functor argument:
class TFunctor
{
public:
void operator()(const char *charstring)
{
printf(charstring);
}
};
template<class T> void CallFunctor(T& functor_arg,const char *charstring)
{
functor_arg(charstring);
};
int main()
{
TFunctor foo;
CallFunctor(foo,"hello world\n");
}
From a performance perspective, Virtual functions and Function Pointers both result in an indirect function call (i.e. through a register) although virtual functions require an additional load of the VFTABLE pointer prior to loading the function pointer. Using Functors (with a non-virtual call) as a callback are the highest performing method to use a parameter to template functions because they can be inlined and even if not inlined, do not generate an indirect call.
Approach 1
Easier to read and understand
Less possibility of errors (iFunc cannot be NULL, you're not using a void *iParam, etc
C++ programmers will tell you that this is the "right" way to do it in C++
Approach 2
Slightly less typing to do
VERY slightly faster (calling a virtual method has some overhead, usually the same of two simple arithmetic operations.. So it most likely won't matter)
That's how you would do it in C
Approach 3
Probably the best way to do it when possible. It will have the best performance, it will be type safe, and it's easy to understand (it's the method used by the STL).
The primary problem with Approach 2 is that it simply doesn't scale. Consider the equivalent for 100 functions:
class MahClass {
// 100 pointers of various types
public:
MahClass() { // set all 100 pointers }
MahClass(const MahClass& other) {
// copy all 100 function pointers
}
};
The size of MahClass has ballooned, and the time to construct it has also significantly increased. Virtual functions, however, are O(1) increase in the size of the class and the time to construct it- not to mention that you, the user, must write all the callbacks for all the derived classes manually which adjust the pointer to become a pointer to derived, and must specify function pointer types and what a mess. Not to mention the idea that you might forget one, or set it to NULL or something equally stupid but totally going to happen because you're writing 30 classes this way and violating DRY like a parasitic wasp violates a caterpillar.
Approach 3 is only usable when the desired callback is statically knowable.
This leaves Approach 1 as the only usable approach when dynamic method invocation is required.
It's not clear from your example if you're creating a utility class or not. Is you Callback class intended to implement a closure or a more substantial object that you just didn't flesh out?
The first form:
Is easier to read and understand,
Is far easier to extend: try adding methods pause, resume and stop.
Is better at handling encapsulation (presuming doGo is defined in the class).
Is probably a better abstraction, so easier to maintain.
The second form:
Can be used with different methods for doGo, so it's more than just polymorphic.
Could allow (with additional methods) changing the doGo method at run-time, allowing the instances of the object to mutate their functionality after creation.
Ultimately, IMO, the first form is better for all normal cases. The second has some interesting capabilities, though -- but not ones you'll need often.
One major advantage of the first method is it has more type safety. The second method uses a void * for iParam so the compiler will not be able to diagnose type problems.
A minor advantage of the second method is that it would be less work to integrate with C. But if you're code base is only C++, this advantage is moot.
Function pointers are more C-style I would say. Mainly because in order to use them you usually must define a flat function with the same exact signature as your pointer definition.
When I write C++ the only flat function I write is int main(). Everything else is a class object. Out of the two choices I would choose to define an class and override your virtual, but if all you want is to notify some code that some action happened in your class, neither of these choices would be the best solution.
I am unaware of your exact situation but you might want to peruse design patterns
I would suggest the observer pattern. It is what I use when I need to monitor a class or wait for some sort of notification.
For example, let us look at an interface for adding read functionality to a class:
struct Read_Via_Inheritance
{
virtual void read_members(void) = 0;
};
Any time I want to add another source of reading, I have to inherit from the class and add a specific method:
struct Read_Inherited_From_Cin
: public Read_Via_Inheritance
{
void read_members(void)
{
cin >> member;
}
};
If I want to read from a file, database, or USB, this requires 3 more separate classes. The combinations start to be come very ugly with multiple objects and multiple sources.
If I use a functor, which happens to resemble the Visitor design pattern:
struct Reader_Visitor_Interface
{
virtual void read(unsigned int& member) = 0;
virtual void read(std::string& member) = 0;
};
struct Read_Client
{
void read_members(Reader_Interface & reader)
{
reader.read(x);
reader.read(text);
return;
}
unsigned int x;
std::string& text;
};
With the above foundation, objects can read from different sources just by supplying different readers to the read_members method:
struct Read_From_Cin
: Reader_Visitor_Interface
{
void read(unsigned int& value)
{
cin>>value;
}
void read(std::string& value)
{
getline(cin, value);
}
};
I don't have to change any of the object's code (a good thing because it is already working). I can also apply the reader to other objects.
Generally, I use inheritance when I am performing generic programming. For example, if I have a Field class, then I can create Field_Boolean, Field_Text and Field_Integer. In can put pointers to their instances into a vector<Field *> and call it a record. The record can perform generic operations on the fields, and doesn't care or know what kind of a field is processed.
Change to pure virtual, first off. Then inline it. That should negate any method overhead call at all, so long as inlining doesn't fail (and it won't if you force it).
May as well use C, because this is the only real useful major feature of C++ compared to C. You will always call method and it can't be inlined, so it will be less efficient.

Map functions of a class

Before I was trying to map my classes and namespaces, by using static calls I succeded and now I need to map the functions of my classes because they will be used dynamically.
Firstly I was thinking to hardcode in the constructor so I can assign a std:map with the string of the name of function pointing to the function itself.
for example:
class A{
int B(){
return 1;
}
};
int main(){
A *a = new A();
vector<string, int (*)()> vec;
vector["A.B"] = a.B;
}
By that I have mapped the function B on A class, I know that I only mapped the function the instance and thats B is not static to be globally mapped.
But thats what I need, at somepoint someone will give me a string and I must call the right function of an instance of a class.
My question is if I only can do that by hardcoding at the constructor, since this is a instance scope we are talking or if there is somehow a way to do this in the declaration of the function, like here for namespaces and classes:
Somehow register my classes in a list
If I understand you correctly, you want your map to store a pointer that can be used to call a member function on an instance, the value being chosen from the map at run time. I'm going to assume that this is the right thing to do, and that there isn't a simpler way to solve the same problem. Quite often when you end up in strange C++ backwaters it's a sign that you need to look again at the problem you think you have, and see whether this is the only way to solve it.
The problem with using an ordinary function pointer is that a non-static member function is not an ordinary function. Suppose you could point to a member function with an ordinary function pointer, what would happen when you dereferenced that pointer and called the function? The member function needs an object to operate on, and the syntax doesn't provide a way to pass this object in.
You need a pointer to member, which is a slightly obscure feature with relatively tricky syntax. While an ordinary pointer abstracts an object, a pointer to member abstracts a member on a class; the pointer specifies which class member should be called, but not which object to obtain the member from (that will be specified when the pointer is used). We can use it something like this:
class B;
class A
{
B some_function()
{ /* ... */ }
};
B (A::* myval)() = A::some_function;
Here myval is a variable that indicates one of the members of class A, in this case the member some_function (though it could point to any other member of A of the same type). We can pass myval round wherever we want (e.g. storing it in an STL container, as in your example) and then when we want to call the function, we specify the instance it should be called on in order to locate the function:
A some_a;
B newly_created_b = (some_a.*myval)();
This works for a particular case, but it won't solve your general issue, because member pointers contain the class they refer to as part of the definition. That is, the following two variables are of entirely different types:
B (Foo::* first_variable)() = Foo::some_function;
B (Bar::* second_variable)() = Bar::some_function;
Even though both functions can produce a B when called without arguments, the two values operate on different classes and therefore you can't assign a value of one type to a variable of the other type. This of course rules out storing these different types in a single STL container.
If you're committed to storing these in a container, you'll have to go with a functor-based solution like Charles Salvia proposes.
If I understand you correctly, you're going to have a class like:
struct Foo
{
int bar();
};
And the user will input a string like "Foo::bar", and from that string you need to call the member function Foo::bar?
If so, it's rather awkward to code a flexible solution in C++, due to the static type system. You can use an std::map where the key is a string, and the value is a member function pointer, (or std::mem_fun_t object), but this will only work on a single class, and only on member functions with the same signature.
You could do something like:
#include <iostream>
#include <map>
#include <functional>
struct Foo
{
int bar() { std::cout << "Called Foo::bar!" << std::endl; }
};
int main()
{
std::map<std::string, std::mem_fun_t<int, Foo> > m;
m.insert(std::make_pair("Foo::bar", std::mem_fun(&Foo::bar)));
Foo f;
std::map<std::string, std::mem_fun_t<int, Foo> >::iterator it = m.find("Foo::bar");
std::mem_fun_t<int, Foo> mf = it->second;
mf(&f); // calls Foo::bar
}
just found(using google) a topic to the same question I had with an answer.
What is the simplest way to create and call dynamically a class method in C++?
I didn't try it yet but makes sense, I will ask again later if it doesn't work
ty!
Joe
I must call the right function of an instance of a class.
You need to call a specific method on an existing instance, or you need to create an instance of the appropriate type and call the method?
If it's the former, then you need a std::map or similar that lets you look up instances from their names.
If it's the latter, that's basically what serialization frameworks need to do in order to create the correct type of object when de-serializing, the object that knows how to read the next bit of data. You might take a look at how the Boost serialization library handles it:
boost.org/doc/libs/1_40_0/libs/serialization/doc/serialization.html
Are you doing this in some kind of tight loop where you need the efficiency of a good map? If so, then member function pointers (as you linked to above) is a good way to go. (At least it is after you work around the problem #Tim mentioned of keeping member function pointers to different types in the same collection ... let the language abuse begin!)
On the other hand, if this is in code that's user-driven, it might be more legible to just be totally uncool and write:
if( funcName=="A.b" )
{
A a;
a.b();
} else
// etc etc etc
For the higher-performace case, you can supplement the same approach with a parse step and some integer constants (or an enum) and use a switch. Depending on your compiler, you might actually end up with better performance than using member function pointers in a map:
switch( parse(funcName) )
{
case A_b:
{
A a;
a.b();
}
break;
}
(Of course this breaks down if you want to populate your list of possibilities from different places ... for example if each class is going to register itself during startup. But if you have that kind of object infrastructure then you should be using interfaces instead of pointers in the first place!)

Why would one use function pointers to member method in C++?

A lot of C++ books and tutorials explain how to do this, but I haven't seen one that gives a convincing reason to choose to do this.
I understand very well why function pointers were necessary in C (e.g., when using some POSIX facilities). However, AFAIK you can't send them a member function because of the "this" parameter. But if you're already using classes and objects, why not just use an object oriented solution like functors?
Real world examples of where you had to use such function pointers would be appreciated.
Update: I appreciate everyone's answers. I have to say, though, that none of these examples really convinces me that this is a valid mechanism from a pure-OO perspective...
Functors are not a priori object-oriented (in C++, the term “functor” usually means a struct defining an operator () with arbitrary arguments and return value that can be used as syntactical drop-in replacements to real functions or function pointers). However, their object-oriented problem has a lot of issues, first and foremost usability. It's just a whole lot of complicated boilerplate code. In order for a decent signalling framework as in most dialog frameworks, a whole lot of inheritance mess becomes necessary.
Instance-bound function pointers would be very beneficial here (.NET demonstrates this amply with delegates).
However, C++ member function pointers satisfy another need still. Imagine, for example, that you've got a lot of values in a list of which you want to execute one method, say its print(). A function pointer to YourType::size helps here because it lets you write such code:
std::for_each(lst.begin(), lst.end(), std::mem_fun(&YourType::print))
In the past, member function pointers used to be useful in scenarios like this:
class Image {
// avoid duplicating the loop code
void each(void(Image::* callback)(Point)) {
for(int x = 0; x < w; x++)
for(int y = 0; y < h; y++)
callback(Point(x, y));
}
void applyGreyscale() { each(&Image::greyscalePixel); }
void greyscalePixel(Point p) {
Color c = pixels[p];
pixels[p] = Color::fromHsv(0, 0, (c.r() + c.g() + c.b()) / 3);
}
void applyInvert() { each(&Image::invertPixel); }
void invertPixel(Point p) {
Color c = pixels[p];
pixels[p] = Color::fromRgb(255 - c.r(), 255 - r.g(), 255 - r.b());
}
};
I've seen that used in a commercial painting app. (interestingly, it's one of the few C++ problems better solved with the preprocessor).
Today, however, the only use for member function pointers is inside the implementation of boost::bind.
Here is a typical scenario we have here. We have a notification framework, where a class can register to multiple different notifications. When registering to a notification, we pass the member function pointer. This is actually very similar to C# events.
class MyClass
{
MyClass()
{
NotificationMgr::Register( FunctionPtr( this, OnNotification ) );
}
~MyClass()
{
NotificationMgr::UnRegister( FunctionPtr( this, OnNotification ) );
}
void OnNotification( ... )
{
// handle notification
}
};
I have some code I'm working on right now where I used them to implement a state machine. The dereferenced member functions implement the states, but since they are all in the class they get to share a certian amount of data that is global to the entire state machine. That would have been tough to accomplish with normal (non-member) function pointers.
I'm still undecided on if this is a good way to implement a state machine though.
It is like using lambdas. You always can pass all necessary local variables to a simple function, but sometimes you have to pass more then one of them.
So using member functions will save you from passing all necessary member fields to a functor. That's all.
You asked specifically about member functions, but there are other uses for function pointers as well. The most common reason why I need to use function pointers in C++ is when I want to load a DLL ar runtime using LoadLibrary(). This is in Windows, obviously. In applications that use plugins in the form of optional DLLs, dynamic linking can't be used at application startup since the DLL will often not be present, and using delayload is a pain.
After loading the library, you have to get a pointer to the functions you want to use.
I have used member function pointers parsing a file. Depending on specific strings found in the file the same value was found in a map and the associated function called. This was instead of a large if..else if..else statement comparing strings.
The single most important use of member pointers is creating functors. The good news is that you hardly even need to use it directly, as it is already solved in libraries as boost::bind, but you do have to pass the pointers to those libs.
class Processor
{
public:
void operation( int value );
void another_operation( int value );
};
int main()
{
Processor tc;
boost::thread thr1( boost::bind( &Processor::operation, &tc, 100 ) );
boost::thread thr2( boost::bind( &Processor::another_operation, &tc, 5 ) );
thr1.join();
thr2.join();
}
You can see the simplicity of creating a thread that executes a given operation on a given instance of a class.
The simple handmade approach to the problem above would be on the line of creating a functor yourself:
class functor1
{
public:
functor1( Processor& o, int v ) : o_(o), v_(v) {}
void operator()() {
o_.operation( v_ ); // [1]
}
private:
Processor& o_;
int v_;
};
and create a different one for each member function you wish to call. Note that the functor is exactly the same for operation and for another_operation, but the call in [1] would have to be replicated in both functors. Using a member function pointer you can write a simple functor:
class functor
{
public:
functor( void (*Processor::member)(int), Processor& p, int value )
: member_( member ), processor_(p), value_( value ) {}
void operator()() {
p.*member(value_);
}
private:
void (*Processor::member_)(int);
Processor& processor_;
int value;
};
and use it:
int main() {
Processor p;
boost::thread thr1( functor( &Processor::operation, p, 100 ) );
boost::thread thr2( functor( &Processor::another_operation, p, 5 ) );
thr1.join();
thr2.join();
}
Then again, you don't need to even define that functor as boost::bind does it for you. The upcoming standard will have its own version of bind along the lines of boost's implementation.
A pointer to a member function is object-agnostic. You need it if you want to refer to a function by value at run-time (or as a template parameter). It comes into its own when you don't have a single object in mind upon which to call it.
So if you know the function, but don't know the object AND you wish to pass this knowledge by value, then point-to-member-function is the only prescribed solution. Iraimbilanja's example illustrates this well. It may help you to see my example use of a member variable. The principle is the same.
I used a function pointer to a member function in a scenario where I had to provide a function pointer to a callback with a predefined parameter list (so I couldn't pass arbitrary parameters) to some 3rd-party API object.
I could not implement the callback in the global namespace because it was supposed to handle incoming events based on state of the object which made use of the 3rd party API which had triggered the callback.
So I wanted the implementation of the callback to be part of the class which made use of the 3rd-party object. What I did is, I declared a public and static member function in the class I wanted to implement the callback in and passed a pointer to it to the API object (the static keyword sparing me the this pointer trouble).
The this pointer of my object would then be passed as part of the Refcon for the callback (which luckily contained a general purpose void*).
The implementation of the dummy then used the passed pointer to invoke the actual, and private, implementation of the callback contained in the class = ).
It looked something like this:
public:
void SomeClass::DummyCallback( void* pRefCon ) [ static ]
{
reinterpret_cast<SomeClassT*>(pRefCon)->Callback();
}
private:
void class SomeClass::Callback() [ static ]
{
// some code ...
}

Why override operator()?

In the Boost Signals library, they are overloading the () operator.
Is this a convention in C++? For callbacks, etc.?
I have seen this in code of a co-worker (who happens to be a big Boost fan). Of all the Boost goodness out there, this has only led to confusion for me.
Any insight as to the reason for this overload?
One of the primary goal when overloading operator() is to create a functor. A functor acts just like a function, but it has the advantages that it is stateful, meaning it can keep data reflecting its state between calls.
Here is a simple functor example :
struct Accumulator
{
int counter = 0;
int operator()(int i) { return counter += i; }
}
...
Accumulator acc;
cout << acc(10) << endl; //prints "10"
cout << acc(20) << endl; //prints "30"
Functors are heavily used with generic programming. Many STL algorithms are written in a very general way, so that you can plug-in your own function/functor into the algorithm. For example, the algorithm std::for_each allows you to apply an operation on each element of a range. It could be implemented something like that :
template <typename InputIterator, typename Functor>
void for_each(InputIterator first, InputIterator last, Functor f)
{
while (first != last) f(*first++);
}
You see that this algorithm is very generic since it is parametrized by a function. By using the operator(), this function lets you use either a functor or a function pointer. Here's an example showing both possibilities :
void print(int i) { std::cout << i << std::endl; }
...
std::vector<int> vec;
// Fill vec
// Using a functor
Accumulator acc;
std::for_each(vec.begin(), vec.end(), acc);
// acc.counter contains the sum of all elements of the vector
// Using a function pointer
std::for_each(vec.begin(), vec.end(), print); // prints all elements
Concerning your question about operator() overloading, well yes it is possible. You can perfectly write a functor that has several parentheses operator, as long as you respect the basic rules of method overloading (e.g. overloading only on the return type is not possible).
It allows a class to act like a function. I have used it in a logging class where the call should be a function but i wanted the extra benefit of the class.
so something like this:
logger.log("Log this message");
turns into this:
logger("Log this message");
Many have answered that it makes a functor, without telling one big reason why a functor is better than a plain old function.
The answer is that a functor can have state. Consider a summing function - it needs to keep a running total.
class Sum
{
public:
Sum() : m_total(0)
{
}
void operator()(int value)
{
m_total += value;
}
int m_total;
};
You may also look over the C++ faq's Matrix example. There are good uses for doing it but it of course depends on what you are trying to accomplish.
The use of operator() to form functors in C++ is related to functional programming paradigms that usually make use of a similar concept: closures.
A functor is not a function, so you cannot overload it.
Your co-worker is correct though that the overloading of operator() is used to create "functors" - objects that can be called like functions. In combination with templates expecting "function-like" arguments this can be quite powerful because the distinction between an object and a function becomes blurred.
As other posters have said: functors have an advantage over plain functions in that they can have state. This state can be used over a single iteration (for example to calculate the sum of all elements in a container) or over multiple iterations (for example to find all elements in multiple containers satisfying particular criteria).
Start using std::for_each, std::find_if, etc. more often in your code and you'll see why it's handy to have the ability to overload the () operator. It also allows functors and tasks to have a clear calling method that won't conflict with the names of other methods in the derived classes.
Functors are basically like function pointers. They are generally intended to be copyable (like function pointers) and invoked in the same way as function pointers. The main benefit is that when you have an algorithm that works with a templated functor, the function call to operator() can be inlined. However, function pointers are still valid functors.
One strength I can see, however this can be discussed, is that the signature of operator() looks and behaves the same across different types. If we had a class Reporter which had a member method report(..), and then another class Writer, which had a member method write(..), we would have to write adapters if we would like to use both classes as perhaps a template component of some other system. All it would care about is to pass on strings or what have you. Without the use of operator() overloading or writing special type adapters, you couldn't do stuff like
T t;
t.write("Hello world");
because T has a requirement that there is a member function called write which accepts anything implicitly castable to const char* (or rather const char[]). The Reporter class in this example doesn't have that, so having T (a template parameter) being Reporter would fail to compile.
However, as far I can see this would work with different types
T t;
t("Hello world");
though, it still explicitly requires that the type T has such an operator defined, so we still have a requirement on T. Personally, I don't think it's too wierd with functors as they are commonly used but I would rather see other mechanisms for this behavior. In languages like C# you could just pass in a delegate. I am not too familiar with member function pointers in C++ but I could imagine you could achieve the same behaviour there aswell.
Other than syntatic sugar behaviour I don't really see the strengths of operator overloading to perform such tasks.
I am sure there are more knowingly people who have better reasons than I have but I thought I'd lay out my opinion for the rest of you to share.
Another co-worker pointed out that it could be a way to disguise functor objects as functions. For example, this:
my_functor();
Is really:
my_functor.operator()();
So does that mean this:
my_functor(int n, float f){ ... };
Can be used to overload this as well?
my_functor.operator()(int n, float f){ ... };
Other posts have done a good job describing how operator() works and why it can be useful.
I've recently been using some code that makes very extensive use of operator(). A disadvantage of overloading this operator is that some IDEs become less effective tools as a result. In Visual Studio, you can usually right-click on a method call to go to the method definition and/or declaration. Unfortunately, VS isn't smart enough to index operator() calls. Especially in complex code with overridden operator() definitions all over the place, it can be very difficult to figure out what piece of code is executing where. In several cases, I found I had to run the code and trace through it to find what was actually running.
Overloading operator() can make the class object calling convention easier. Functor is one of the applications of operator() overloading.
It is easy to get confused between Functor and user-defined conversion function.
Below 2 examples show the difference between
1. Functor
2. User-defined conversion function
1. Functor:
struct A {
int t = 0;
int operator()(int i) { return t += i; } // must have return type or void
};
int main() {
A a;
cout << a(3); // 3
cout << a(4); // 7 (Not 4 bcos it maintaines state!!!)
}
2. User-defined conversion function:
struct A {
int t = 3;
operator int() { return t; } // user-defined conversion function
// Return type is NOT needed (incl. void)
};
int main() {
cout << A(); // 3 - converts the object{i:3} into integer 3
A a;
cout << a; // 3 - converts the object{i:3} into integer 3
}