How can a script retain its values through different script loading in Lua? - c++

Question

My current problem is that I have several enemies share the same A.I. script, and one other object that does something different. The function in the script is called AILogic. I want these enemies to move independently, but this is proving to be an issue. Here is what I've tried.
1) Calling dofile in the enemy's constructor, and then calling its script function in its Update function which happens in every game loop. The problem with this is that Lua just uses the script of the last enemy constructed, so all of the enemies are running the same script in the Update function. Thus, the object I described above that doesn't use the same script for it's A.I. is using the other enemies' script.
2) Calling dofile in the Update function, and then calling its script function immediately after. The problem with this is that dofile is called in every object's update function, so after the AILogic function runs and data for that script is updated, the whole thing just gets reset when dofile is called again for another enemy. My biggest question here is whether there is some way to retain the values in the script, even when I switch to running a different one.
I've read about function environments in Lua, but I'm not quite sure how to implement them correctly. Is this the right direction? Any advice is appreciated, thanks.
Edit: I've also considered creating a separate place to store that data rather than doing it in the Lua script.
Edit2: Added some sample code. (Just a test to get the functionality working).
-- Slime's Script
local count = 0;
function AILogic( Slime )
--Make the slime move in circles(err a square)
if count < 4 then
Slime:MoveDir( 0 );
elseif count < 8 then
Slime:MoveDir( 2 );
elseif count < 12 then
Slime:MoveDir( 1 );
elseif count < 16 then
Slime:MoveDir( 3 );
else
count = 0;
end
count = count + 1;
end

Answer 1

The lua interpreter runs each line as its own chunk which means that locals have line scope, so the example code can't be run as-is. It either needs to be run all at once (no line breaks), without locals, or run in a do ... end block.
As to the question in the OP. If you want to share the exact same function (that is the same function at runtime) then the function needs to take the data as arguments. If, however, you are ok with using the same code but different (runtime) functions than you can use closures to hold the local/individual data.
local function make_counter()
local count = 0
return function ()
local c = count
count = count + 1
return c
end
end
c1 = make_counter()
c2 = make_counter()
c3 = make_counter()
print(c1())
print(c1())
print(c1())
print(c1())
print(c2())
print(c3())
print(c2())
print(c3())
print(c2())
print(c3())
Alternatively, you could play with the environment of the function each time it is called, but that will only work correctly for some cases (depends on what the internals of the function are).

Answer 2

The canonical reference for this is link text. Explaining this briefly we'll work off the following code from the site:
a = 1
local newgt = {} -- create new environment
setmetatable(newgt, {__index = _G})
setfenv(1, newgt) -- set it
The first line sets up the (global) variable "a". You can view this as setting default values for your code. (Keep in mind that in Lua all variables are global unless you declare them with "local".)
The next line creates a table that will be your new environment. It is local to the function/chunk you're executing in so it won't be trashed by anything else that runs now or later.
The third line is the beginnings of the magic. To understand it you're going to have to understand metamethods In essence, however, you're using Lua's metamagic to ensure that any global names that aren't defined in your soon-to-be function environment get resolved in the context of your old global environment. Basically it means if you use a name that's not in your function environment, Lua will automagically hunt in the global environment you used to have to find the name. (In a word: inheritance.)
The fourth line is where you get what you're looking for. Setfenv(1,...) means that this changes the environment for your current function. (You could use 2 for the calling function, 3 for the calling function's caller, etc. on up the line.) The second parameter is the table you just set up, complete with inheritance of the old behaviour. Your function is now executing in a new global environment. It has all the names and values of the old environment handy (including functions and that global variable "a" you put in). If, however, you WRITE to a name it will not overwrite the global state. It will overwrite your local copy of it.
Consider the following subsequent code:
a = 10
b = 20
What you have done now is made your function environment table look like this:
{a = 10, b=20}
Your "global" environment, in short, contains two variables only: a (value 10) and b (value 20). When you access "a" later you'll get your local copy with 10 -- the old global value stored in your metatable is shadowed now and is still set to 1 -- and if you access "b" you'll get 20, despite the original global state likely not even having a variable "b" to access. And you'll still be able to access all the functions, etc. you've defined before this point as well.
Edited to add test code to debug OP's problem.
I put the following code into "junk.lua":
a = 1
local newgt = {}
setmetatable(newgt, {__index = _G})
setfenv(1, newgt)
print(a)
a = 10
print(a)
print(newgt)
The output of it is as follows:
$ lua junk.lua
1
10
table: 0x976d040
This is using Lua 5.1.4. What is the output you're seeing?