Error in django url.py? - django

I am new in django. I try to practice and run the wiki application (i found tutorial at http://showmedo.com/videotutorials/video?name=1100000&fromSeriesID=110">Learn django), In url.py file i write the following urls...
urlpatterns = patterns('',
(r'^wikicamp/(?p<page_name>[^/]+)/edit/$','wikiapp.wiki.views.edit_page'),
(r'^wikicamp/(?p<page_name>[^/]+)/save/$','wikiapp.wiki.views.save_page'),
(r'^wikicamp/(?p<page_name>[^/]+)/$','wikiapp.wiki.views.view_page'),
)
But there is errror which i cant understand.
sre_Constants.error:Unexpected end of pattern.
(r'^wikicamp/(?p<page_name>[^/]+)/$','wikiapp.wiki.views.view_page'),
I use the Django-1.0.2-final.tar.gz

You need to use an uppercase P to capture named regexp groups:
urlpatterns = patterns('',
(r'^wikicamp/(?P<page_name>[^/]+)/edit/$','wikiapp.wiki.views.edit_page'),
(r'^wikicamp/(?P<page_name>[^/]+)/save/$','wikiapp.wiki.views.save_page'),
(r'^wikicamp/(?P<page_name>[^/]+)/$','wikiapp.wiki.views.view_page'),
)

Related

How can I use a catch all route using `path` or `re_path` so that Django passes all unmatched requests to my index view?

My url patterns look like this:
urlpatterns = [
path('admin/', admin.site.urls),
path('api/', include('api.urls')),
re_path('.*', IndexView.as_view()),
]
This works but it matches all URLs, including those prefixed with admin and api. I want those URLs to still match, and for any unmatched URLs to render IndexView.
Before 2.0 I used this regex for this purpose. I tried using it in re_path but that didn't work, which is what led me to trying the above.
url(r'^(?P<path>.*)/$', HtmlView.as_view())
Use case is a SPA where I handle 404s client side.
Many thanks in advance.
You can use two entries (one for '/', another one for anything else), but using path for both of them, which should be (slightly) more efficient:
urlpatterns = [
path('', IndexView.as_view(), {'resource': ''}),
path('<path:resource>', IndexView.as_view())
]
In this case, I'm using <path:resource> because path catches all resource names, inluding that with / in them. But it does not capture the main index resource, /. That's why the first entry. The dictionary as last argument for it is because we need to provide a resource parameter if we want to use the same view than in the second entry.
That view, of course, should have 'resource' as a paremeter:
def as_view(request, resource):
...
So as I said in the question description, trying the regex I was using before Django 2.0 in re_path did not work. It would basically match for all requests except / (i.e., index path). I fixed this by using both that regex and a second path matching / specifically. Here's the code:
urlpatterns = [
re_path(r'^(?P<path>.*)/$', IndexView.as_view()),
path('', IndexView.as_view()),
]
With these changes my other routes would match and these two routes would account for all other urls.
One Idea to go about this is let the django catch 404.
url.py
from django.conf.urls import handler404
handler404 = 'app_name.views.bad_request'
and in your views.py
views.py
def bad_request(request):
return redirect(reverse('home'))
You can always do some regex thingy to catch unmatched urls. but hey this gets the job done. :)

Django: formats of urlpatterns in urls.py

I noticed that in Django there are two formats of urlpatterns in file urls.py:
urlpatterns = [
url(...),
url(...),
]
and
urlpatterns = pattern('',
url(...),
url(...),
)
The first is a list of url instances, and the second invokes the pattern module with an empty string and a number of url instances as parameters.
What is the difference between the two?
What is the purpose of an empty string in the second format?
Which one is recommended to use?
In Django 1.8+, urlpatterns should simply be a list of url()s. This new syntax actually works in 1.7 as well.
urlpatterns = [
url(...),
url(...),
]
The old syntax using pattern is deprecated in Django 1.8, and is removed in Django 1.10.
urlpatterns = pattern('',
url(...),
url(...),
)
With the old syntax, you could provide a prefix. The example given in the docs is
urlpatterns = patterns('news.views',
url(r'^articles/([0-9]{4})/$', 'year_archive'),
url(r'^articles/([0-9]{4})/([0-9]{2})/$', 'month_archive'),
url(r'^articles/([0-9]{4})/([0-9]{2})/([0-9]+)/$', 'article_detail'),
)
However, using strings arguments for the view is now deprecated as well, and you should provide the callable instead.
Per the documentation, patterns is:
A function that takes a prefix, and an arbitrary number of URL
patterns, and returns a list of URL patterns in the format Django
needs.
The first argument to patterns() is a string prefix.
It also provides an example of why you might want to use it:
from django.conf.urls import patterns, url
urlpatterns = patterns('',
url(r'^articles/([0-9]{4})/$', 'news.views.year_archive'),
url(r'^articles/([0-9]{4})/([0-9]{2})/$', 'news.views.month_archive'),
url(r'^articles/([0-9]{4})/([0-9]{2})/([0-9]+)/$', 'news.views.article_detail'),
)
In this example, each view has a common prefix – 'news.views'.
Instead of typing that out for each entry in urlpatterns, you can
use the first argument to the patterns() function to specify a
prefix to apply to each view function.
With this in mind, the above example can be written more concisely as:
from django.conf.urls import patterns, url
urlpatterns = patterns('news.views',
url(r'^articles/([0-9]{4})/$', 'year_archive'),
url(r'^articles/([0-9]{4})/([0-9]{2})/$', 'month_archive'),
url(r'^articles/([0-9]{4})/([0-9]{2})/([0-9]+)/$', 'article_detail'),
)
However, note that this function is deprecated:
Deprecated since version 1.8:
urlpatterns should be a plain list of django.conf.urls.url() instances instead.
Note that the explanation as to why includes (with good reason, clearly!):
Thus patterns() serves little purpose and is a burden when teaching
new users (answering the newbie’s question "why do I need this empty
string as the first argument to patterns()?").

Django error with (CRUD) urls.py

as part of my continuing want to do well on my Uni course, I'm doing a bit of web-dev in Python(2.7) using Django. I had followed Django's tutorial and now I am following this tutorial. However, I get a somewhat inexplicable error when I add in the urls.py part to give me some viewing models. The project is called 'practice' and the app is called 'orders'. Within 'orders' are the models (which all validate)
The (relevant part of) urls.py is:
'django.views.generic.list_details',
url(r'^orders/$', 'object_list', {'queryset': 'orders.Product.objects.all()'}),
url(r'^orders(?P<slug>[-\W]+)/$', 'object_detail', {'queryset': 'orders.Product.objects.all()'})
I've double checked ROOT_URLCONF is correctly set so the error appears to be somewhere within 'django.views.generic.list_details' as a use.
The error message is:
AttributeError: 'str' object has no attribute resolve
A good Google didn't seem to produce anything reasonable so any chance of a hand please guys?
Thanks!
Did you forget "patterns"?
urlpatterns = patterns('',
(r'^$', ...),
# ...
Also I've noticed a slash missing:
url(r'^orders(?P<slug>[-\W]+)/$', 'object_detail', {'queryset': 'orders.Product.objects.all()'})
url(r'^orders/(?P<slug>[-\W]+)/$', 'object_detail', {'queryset': 'orders.Product.objects.all()'})
The AttributeError suggests to me that the string 'django.views.generic.list_details' is being treated as a url to be resolved. However, you've omitted too much of your urls.py to say for sure.
Make sure the prefix string is the first argument to django.conf.urls.patterns. If you want to break up your urls and use different prefix strings, invoke patterns multiple times as described in the documentation:
urlpatterns = patterns('myapp.views',
url(r'^$', 'app_index'),
url(r'^(?P<year>\d{4})/(?P<month>[a-z]{3})/$','month_display'),
)
urlpatterns += patterns('weblog.views',
url(r'^tag/(?P<tag>\w+)/$', 'tag'),
)
You've quoted the value in the arguments dictionary in each pattern, so it's being treated as a string. It should be:
url(r'^orders/$', 'object_list', {'queryset': orders.Product.objects.all()})
Not that you'll need to import orders - except I doubt that will work, because Product will be defined in the models file inside orders. It would be easier to just import Product and refer to it directly.

Django url regexp not working

I'm trying to get my head around regexp in Django urls. I'm currently developing locally and I want to be able to direct a request such as http://localhost:8000/options/items/item-string-1121/ to the 'details' view in my app called 'options', passing in the final number part of the request string (1121) as a parameter 'id' to the view function.
The signature for details in options/views.py is as follows, taking id=1 as default:
def details(request, id=1):
...
I have the following in my root urls.py:
...
urlpatterns += patterns('',
url(r'^options/, include(options.urls')),
)
and in options/urls.py:
urlpatterns = patterns('options.views',
url(r'^items/(.+)(P<id>\d+)/$', 'details'),
...
)
Now when I try to request the above URL the dev server says it tried to match against the pattern ^options/ ^items/(.+)(P<id>\d+)/$ but it doesn't match.
Can anyone see the problem?
You need a non-greedy quantifier on the (.+), so r'^items/(.+?)(P\d+)/$'. Otherwise that first glob happily eats until the end of the string, preventing the ID from ever matching.
You are missing quotes.
urlpatterns += patterns('',
url(r'^options/, include(options.urls')),
)
Should be
urlpatterns += patterns('',
url(r'^options/', include('options.urls')),
)
I'm not too sure of your expression, might try this:
urlpatterns = patterns('options.views',
url(r'^items/(?<=-)(?P<id>\d+)/$', 'details'),
...
)

Django - Url dispatch No match from application

I have a simple url that doesn't match into one of my applications (plaq)
main url.py:
urlpatterns = patterns('',
#...
url(r'^content/', include('content.urls')),
url(r'^$', include('content.urls')),
url(r'^plaq/', include('plaq.urls')),
#...
)
plaq url.py:
urlpatterns = patterns('',
(r'^$', pres),
(r'pres^$', pres),
(r'about^$', about),
(r'privacy^$', privacy),
)
Trying to access to my_host/plaq/pres gives me
Using the URLconf defined in my_project.urls, Django tried these URL patterns, in this order:
...
12. ^content/
13. ^plaq/ ^$
14. ^plaq/ pres^$
15. ^plaq/ about^$
16. ^plaq/ privacy^$
...
The current URL, plaq/pres/, didn't match any of these.
While my_host/plaq displays the good pres view
Why can't I access to my_host/plaq/pres ?
Firstly, you need to learn a bit about regexes: ^ means beginning of string, but for some reason you have it at the end.
Secondly, your URLs end in slashes, so your urlconfs must too.
urlpatterns = patterns('',
(r'^$', pres),
(r'^pres/$', pres),
(r'^about/$', about),
(r'^privacy/$', privacy),
)
carets (^) match the beginning of a string. i think you want e.g. (r'^pres$', pres), (caret moved to front)