Remove '\n.\n' C++ - c++

Question

If i have a string as such
"I am not here... \n..Hello\n.\n....Whats happening"
I want to replace the above string so:
"I am not here... \n..Hello\n. \n....Whats happening"
^ Space added
Just a bit of a background on what im doing. Im using sendmail in C++ and \n.\n is End Of Message Equivalent of sendmail. I just created a class that uses sendmail to send mails. but obviously if the user from the outsite gives sendmail that command i want it to be removed. Here is my message function just incase.:
//Operator to add to the message
void operator<<(string imessage){
if (imessage != ""){ message += imessage; }
}
How would i go about doing this. Thanks in advance :D

Answer 1

This is my last version :)
This code handles the case mentioned by #Greg Hewgill
string& format_text(string& str)
{
const string::size_type dot_offset = 2;
string::size_type found_at_start = str.find("\n.\n"),
found_at = str.find("\n.\n");
if(found_at_start != string::npos)
str.insert(0, " ");
while(found_at != string::npos)
{
str.insert(found_at+dot_offset+1, " ");
found_at = str.find("\n.\n", found_at+1);
}
return str;
}
int main()
{
string text = ".\nn\n.\nn";
std::cout << format_text(text);
}

Answer 2

Look up String.find and String.replace
For example (not tested)
string endOfMessage = "\n.\n";
string replacement = "\n. \n";
size_t position;
while (position = message.find(endOfMessage))
{
message.replace(position, endOfMessage.length(), replacement);
}

Answer 3

This is derived from Dan McG's answer so upvote him ;)
string endOfMessage = "\n.\n";
string replacement = "\n. \n";
size_t position;
while (position = message.find(endOfMessage, position) != message.npos)
{
message.replace(position, endOfMessage.length(), replacement);
position += replacement.length();
}

Answer 4

Boost has Boost.Regex (a regular expression module). Might be overkill if this is the only replacement you need to do.

Answer 5

Use std::search and the insert method of sequence containers such as string, deque, or whatever you use to store the message text.
typedef std::string::iterator SIter; // or whatever container you use
static const char *end_seq = "\n.\n";
for ( SIter tricky_begin = msg.begin();
tricky_begin = std::search( tricky_begin, msg.end(), end_seq, end_seq+3 ),
tricky_begin != msg.end(); ) {
tricky_begin = msg.insert( tricky_begin + 2, ' ' );
}