I have a block of codes with timestamp in front of each line like this:
12/02/2010 12:20:12 function myFun()
12/02/2010 12:20:13 {....
The first column is a date time value. I would like to comment them out by using Vim, thus:
/*12/02/2010 12:20:12*/ function myFun()
/*12/02/2010 12:20:13*/ {....
I tried to search for date first:
/\d\d\/\d\d\/\d\d\d\d \d\d:\d\d:\d\d
I got all the timestamps marked correctly. However When I tried to replace them by the command:
%s/\d\d\/\d\d\/\d\d\d\d \d\d:\d\d:\d\d/\/*\d\d\/\d\d\/\d\d\d\d \d\d:\d\d:\d\d*\//
I got the following result:
/*dd/dd/dddd dd:dd:dd*/ function myFun()
/*dd/dd/dddd dd:dd:dd*/ {....
I think I need to name the search part and put them back in the replace part. How I can do it?
I suppose I would just do something like:
:%s-^../../.... ..:..:..-/* & */-
I would actually not us a regex to do this. It takes too long to enter the correct formatting. I would instead use a Visual Block. The sequence works out to be something like this.
<C-V>}I/* <ESC>
3f\s
<C-V>I */
I love regex, and don't want to knock the regex solutions, but find when doing things with pre-formatted blocks, that this is easier, and requires less of a diversion from the real task, which isn't figuring out how to write a regex.
%s/\d\d\/\d\d\/\d\d\d\d \d\d:\d\d:\d\d/\/*&*\//
:%s/^\([0-9/]* [0-9:]* \)\(.*\)/\/*\1*\/ \2/
Related
I'm trying to extract the classname from a list of UE4 blueprint paths that look like this:
"Blueprint'/Game/Aberration/CoreBlueprints/Weapons/PrimalItemAmmo_Zipline.PrimalItemAmmo_Zipline'"
The end result needs to be something like this:
PrimalItemAmmo_Zipline_C
I guess the easiest way would be to extract everything between the "." and the apostrophe at the end, before appending the _C. I've tried a few different solutions I've found online, mostly modified from formulas for getting filenames from filepaths, but I can't get any of them to work properly.
What would be the best way to do this?
Assuming the string in A1, try
=substitute(regexextract(A1, "[^.]*$"), char(39)&char(34), "_C")
and see if that works?
try:
=REGEXEXTRACT(A1, "\.(.*)'")&"_C"
for array do:
=ARRAYFORMULA(IFNA(REGEXEXTRACT(A1:A, "\.(.*)'")&"_C"))
I am using an Engineering Program which lets me Code formulas in order to filter out specific lines in a database. I am trying to look for a certain line in the database which contains e.g. "concrete" as a property.
In the Code I can use regular expressions.
The regex I was using so far looked like this:
".*(concrete).*";
so if the line in the database contains concrete, I will get the wanted result.
Now the Problem is: i would like to switch the word concrete with a variable, so that it Looks like this:
".*(#VARIABLE1).*";
(the Syntax with the # works in the program btw.)
the Problem is: if i set the variable as concrete, the program automatically switches it for 'concrete' . Obviously, the word concrete cant be found anymore, since the searchterm now contains the two ' Symbols in the beginning and i the end.
Is there a way to ignore those two characters using the Right regex?
what I want it to do is the following:
If a line in the database contains "25cm concrete in Grey"
I should get a match from the regex.
with the searchterm ".*(concrete).*"; it works, with the variable ".*(#VARIABLE1).*"; it doesnt.
EDIT:
the whole "Formula" in the program Looks like that:
if(Match(QTO(Typ:="Attribut{FloorsLayer_02_MaterialName}");".*(#V_QUALITY).*" ;"regex") ;QTO(Typ:="Attribut{Fläche}");0)
I want the if-condition to be true, when the match inside is true.
the whole QTO function is just the programs Syntax to use a certain Attribute into the match-function, the middle part is my Problem. I really don't know the programming language or anything,I'm new to this. hope it helps!
Thats more of a hack than a real solution and i'm not sure if it even works:
if you use the regex
.*(#VARIABLE1)?).*
and the string ?concrete(
this will result in a regex looking like this:
.*('?concrete(')?).*
which makes the additional characters optional.
This uses the following assumtption:
the string (#VARIABLE1) gets replaced by the ('<content of VARIABLE1>')
I'm trying to change the case of method names for some functions from lowercase_with_underscores to lowerCamelCase for lines that begin with public function get_method_name(). I'm struggling to get this done in a single step.
So far I have used the following
:%s/\(get\)\([a-zA-Z]*\)_\(\w\)/\1\2\u\3/g
However, this only replaces one _ character at a time. What I would like it a search and replace that does something like the following:
Identify all lines containing the string public function [gs]et.
On these lines, perform the following search and replace :s/_\(\w\)/\u\1/g
(
EDIT:
Suppose I have lines get_method_name() and set_method_name($variable_name) and I only want to change the case of the method name and not the variable name, how might I do that? The get_method_name() is more simple of course, but I'd like a solution that works for both in a single command. I've been able to use :%g/public function [gs]et/ . . . as per the solution listed below to solve for the get_method_name() case, but unfortunately not the set_method_name($variable_name) case.
If I've understood you correctly, I don't know why the things you've tried haven't worked but you can use g to perform a normal mode command on lines matchings a pattern.
Your example would be something like:
:%g/public function [gs]et/:s/_\(\w\)/\u\1/g
Update:
To match only the method names, we can use the fact that there will only be method names before the first $, as this looks to be PHP.
To do that, we can use a negative lookbehind, #<!:
:%g/public function [gs]et/:s/\(\$.\+\)\#<!_\(\w\)/\u\2/g
This will look behind #<! for any $ followed by any number of characters and only match _\(\w\) if no $s are found.
Bonus points(?):
To do this for multiple buffers stick a bufdo in front of the %g
You want to use a substitute with an expression (:h sub-replace-expression)
Match the complete string you want to process then pass that string to a second substitute command to actually change the string
:%s/\(get\|set\)\zs_\w\+/\=substitute(submatch(0), '_\([A-Za-z]\)', '\U\1', 'g')
Running the above on
get_method_name($variable_name)
set_method_name($variable_name)
returns
getMethodName($variable_name)
setMethodName($variable_name)
To have vi do replace sad with happy, on all lines, in a file:
:1, $ s/sad/happy/g
(It is the :1, $ before the sed command that instructs vi to execute the command on every line in the file.)
I have a txt file with content
$NETS
P3V3_AUX_LGATE; PQ6.8 PU37.2
U335_PIN1; R3328.1 U335.1
$END
need to be updated in this format, and save back to another txt file
$NETS
'P3V3_AUX_LGATE'; PQ6.8 PU37.2
'U335_PIN1'; R3328.1 U335.1
$END
NOTE: number of lines may go up to 10,000 lines
My current solution is to read the txt file line by line, detect the presence of the ";" and newline character and do the changes.
Right now i have a variable that holds ALL the lines, is there other way something like Replace via RegEx to do the changes without looping thru each line, this way i can readily print the result
and follow up question, which one is more efficient?
Try
ResultString = Regex.Replace(SubjectString, "^([^;\r\n]+);", "'$1';", RegexOptions.Multiline)
on your multiline string.
This will find any string (length one or more) at the start of a line up until the first semicolon if there is one and replace it with its quoted equivalent.
It should be more efficient than looping through the string line by line as you're doing now, but if you're in doubt, you'd have to profile it.
You could probably find all the matches using something like \w+; but I don't know how you'd be able to do a replace on that using Regex.Replace to add the 's but keep the original match.
However, if you already have it as one variable, you don't have to read the file again, either you could make your code find all ;s and then find the previous newline for each, or you could use a String.Split on newlines to split the variable you've already got into lines.
And if you want to get it back to one variable you can just use String.Join.
Personally I'd normally use the String.Split (and possibly the String.Join if needed) method, since I think that would make the code easy to read.
I would say Yes! this can be done with Regular expressions. Make sure you got the "multiline" option turned on and craft your regular expression using some capture groups to ease the work.
I can however say this will NOT be the optimal one. Since you mention the amount of lines you could be processing, it seems 'resource wise' smarter to use a streaming approach instead of the in memory approach.
Taking the Regex approach (and this took 15 mins so please don't think this is an optimal solution, just prove it would work)
private static Regex matcher = new Regex(#"^\$NETS\r\n(?<entrytitle>.[^;]*);\s*(?<entryrest>.*)\r\n(?<entrytitle2>.[^;]*);\s*(?<entryrest2>.*)\r\n\$END\r\n", RegexOptions.Compiled | RegexOptions.Multiline);
static void Main(string[] args)
{
string newString = matcher.Replace(ExampleFileContent, new MatchEvaluator(evaluator));
}
static string evaluator(Match m)
{
return String.Format("$NETS\r\n'{0}'; {1}\r\n'{2}'; {3}\r\n$END\r\n",
m.Groups["entrytitle"].Value,
m.Groups["entryrest"].Value,
m.Groups["entrytitle2"].Value,
m.Groups["entryrest2"].Value);
}
Hope this helps,
I have a txt file that I’m trying to import as flat file into SQL2008 that looks like this:
“123456”,”some text”
“543210”,”some more text”
“111223”,”other text”
etc…
The file has more than 300.000 rows and the text is large (usually 200-500 chars), so scanning the file by hand is very time consuming and prone to error. Other similar (and even more complex files) were successfully imported.
The problem with this one, is that “some lines” contain quotes in the text… (this came from an export from an old SuperBase DB that didn’t let you specify a text quantifier, there’s nothing I can do with the file other than clear it and try to import it).
So the “offending” lines look like this:
“123456”,”this text “contains” a quote”
“543210”,”And the “above” text is bad”
etc…
You can see the problem here.
Now, 300.000 is not too much if I could perform a search using a text editor that can use regex, I’d manually remove the quotes from each line. The problem is not the number of offending lines, but the impossibility to find them with a simple search. I’m sure there are less than 500, but spread those in a 300.000 lines txt file and you know what I mean.
Based upon that, what would be the best regex I could use to identify these lines?
My first thought is: Tell me which lines contain more than 4 quotes (“).
But I couldn’t come up with anything (I’m not good at Regex beyond the basics).
this pattern ^("[^"]+){4,} will match "lines containing more than 4 quotes"
you can experiment with replacing 4 with 5 or more, depending on your data.
I think that you can be more direct with a Regex than you're planning to be. Depending on your dialect of Regex, something like this should do it:
^"\d+",".*".*"
You could also use a regex to remove the outside quotes and use a better delimeter instead. For example, search for ^"([0-9]+)","(.*)"$ and replace it with \1+++++DELIM+++++\2.
Of course, this doesn't directly answer your question, but it might solve the problem.