I use this snippet to show several fields in my admin backend as readonly, but as noticed in the comments, it does not work on stackedinline/tabularinline. Is there any other way to achieve this? I have a list of objects attached to a model and just want to show it in the model's details view without the possibility to change values.
If you are running Django 1.3 or later; there's an attribute named ModelAdmin.readonly_fields which you could use.
InlineModelAdmin inherits from ModelAdmin, so you should be able to use it from your inline subclass.
I've encountered the same problem today. Here is my solution. This is example of read-only field for the ForeignKey value:
class MySelect(forms.Select):
def render(self, name, value, attrs=None, choices=()):
s = Site.objects.get(id=value)
return s.name
class UserProfileInlineForm(forms.ModelForm):
site = forms.ModelChoiceField(queryset=Site.objects.all(), widget=MySelect)
class UserProfileInline(admin.StackedInline):
model = UserProfile
form = UserProfileInlineForm
As is the case with JQuery, it seems you can achieve this by changing an attr called "disabled" (works in my Safari, OK we're now in 2013 :-) ).
Example below:
def get_form(self, request, obj=None, **kwargs):
result = super(<your ModelAdmin class here>, self).get_form(request, obj=obj, **kwargs)
result.base_fields[<the select field you want to disable>].widget.attrs['disabled'] = 'disabled'
return result
Related
To show just the just the related Projects in a ForeignKey Selectbox in Django AdminForm, i customized my ActionAdmin Model with a ActionAdminForm class. to preselect values i used a class like posted here https://stackoverflow.com/a/9191583/326905. Thanks a lot, this works really fine.
But when user does not navigate form Customer -> Project -> Action and navigates directly to Actions in django admin i want to display the values in the selectbox for foreignkey project in ActionAdmin Form formatted like this:
Customername1 - Projectname1
Customername1 - Projectname2
Customername2 - Projectname3
My question is, how could i override self.fields["project"]
in the else case in the code below, so that i get selectbox values concatenated from Project.customer.name and Project.name?
class ActionAdminForm(ModelForm):
def __init__(self, *args, **kwargs):
self.request = kwargs.pop('request', None)
super(ActionAdminForm, self).__init__(*args, **kwargs)
if self.request.GET.get('project'):
prj = Project.objects.get(id=self.request.GET.get('project'))
self.fields["project"].queryset = Project.objects.filter(customer = prj.customer)
else:
self.fields["project"] = ProjectModelChoiceField(Project.objects.all().order_by('name'))
class Meta:
model = Action
I got the solution. Yeah. First i got always error when i tried to use just self.fields["project"], but now it works. I put it into else and wrote a ProjectModelChoiceField like below, influenced by this description: http://bradmontgomery.blogspot.de/2009/01/custom-form-for-djangos-automatic-admin.html
class ProjectModelChoiceField(ModelChoiceField):
def label_from_instance(self, obj):
return "%s - %s"%(obj.customer.name, obj.name)
I want to have additional fields regarding value of one field. Therefor I build a custom admin form to add some new fields.
Related to the blogpost of jacobian 1 this is what I came up with:
class ProductAdminForm(forms.ModelForm):
class Meta:
model = Product
def __init__(self, *args, **kwargs):
super(ProductAdminForm, self).__init__(*args, **kwargs)
self.fields['foo'] = forms.IntegerField(label="foo")
class ProductAdmin(admin.ModelAdmin):
form = ProductAdminForm
admin.site.register(Product, ProductAdmin)
But the additional field 'foo' does not show up in the admin. If I add the field like this, all works fine but is not as dynamic as required, to add the fields regarding the value of another field of the model
class ProductAdminForm(forms.ModelForm):
foo = forms.IntegerField(label="foo")
class Meta:
model = Product
class ProductAdmin(admin.ModelAdmin):
form = ProductAdminForm
admin.site.register(Product, ProductAdmin)
So is there any initialize method that i have to trigger again to make the new field working? Or is there any other attempt?
Here is a solution to the problem. Thanks to koniiiik i tried to solve this by extending the *get_fieldsets* method
class ProductAdmin(admin.ModelAdmin):
def get_fieldsets(self, request, obj=None):
fieldsets = super(ProductAdmin, self).get_fieldsets(request, obj)
fieldsets[0][1]['fields'] += ['foo']
return fieldsets
If you use multiple fieldsets be sure to add the to the right fieldset by using the appropriate index.
The accepted answer above worked in older versions of django, and that's how I was doing it. This has now broken in later django versions (I am on 1.68 at the moment, but even that is old now).
The reason it is now broken is because any fields within fieldsets you return from ModelAdmin.get_fieldsets() are ultimately passed as the fields=parameter to modelform_factory(), which will give you an error because the fields on your list do not exist (and will not exist until your form is instantiated and its __init__ is called).
In order to fix this, we must override ModelAdmin.get_form() and supply a list of fields that does not include any extra fields that will be added later. The default behavior of get_form is to call get_fieldsets() for this information, and we must prevent that from happening:
# CHOOSE ONE
# newer versions of django use this
from django.contrib.admin.utils import flatten_fieldsets
# if above does not work, use this
from django.contrib.admin.util import flatten_fieldsets
class MyModelForm(ModelForm):
def __init__(self, *args, **kwargs):
super(MyModelForm, self).__init__(*args, **kwargs)
# add your dynamic fields here..
for fieldname in ('foo', 'bar', 'baz',):
self.fields[fieldname] = form.CharField()
class MyAdmin(ModelAdmin):
form = MyModelForm
fieldsets = [
# here you put the list of fieldsets you want displayed.. only
# including the ones that are not dynamic
]
def get_form(self, request, obj=None, **kwargs):
# By passing 'fields', we prevent ModelAdmin.get_form from
# looking up the fields itself by calling self.get_fieldsets()
# If you do not do this you will get an error from
# modelform_factory complaining about non-existent fields.
# use this line only for django before 1.9 (but after 1.5??)
kwargs['fields'] = flatten_fieldsets(self.declared_fieldsets)
# use this line only for django 1.9 and later
kwargs['fields'] = flatten_fieldsets(self.fieldsets)
return super(MyAdmin, self).get_form(request, obj, **kwargs)
def get_fieldsets(self, request, obj=None):
fieldsets = super(MyAdmin, self).get_fieldsets(request, obj)
newfieldsets = list(fieldsets)
fields = ['foo', 'bar', 'baz']
newfieldsets.append(['Dynamic Fields', { 'fields': fields }])
return newfieldsets
This works for adding dynamic fields in Django 1.9.3, using just a ModelAdmin class (no ModelForm) and by overriding get_fields. I don't know yet how robust it is:
class MyModelAdmin(admin.ModelAdmin):
fields = [('title','status', ), 'description', 'contact_person',]
exclude = ['material']
def get_fields(self, request, obj=None):
gf = super(MyModelAdmin, self).get_fields(request, obj)
new_dynamic_fields = [
('test1', forms.CharField()),
('test2', forms.ModelMultipleChoiceField(MyModel.objects.all(), widget=forms.CheckboxSelectMultiple)),
]
#without updating get_fields, the admin form will display w/o any new fields
#without updating base_fields or declared_fields, django will throw an error: django.core.exceptions.FieldError: Unknown field(s) (test) specified for MyModel. Check fields/fieldsets/exclude attributes of class MyModelAdmin.
for f in new_dynamic_fields:
#`gf.append(f[0])` results in multiple instances of the new fields
gf = gf + [f[0]]
#updating base_fields seems to have the same effect
self.form.declared_fields.update({f[0]:f[1]})
return gf
Maybe I am a bit late... However, I am using Django 3.0 and also wanted to dynamically ad some custom fields to the form, depending on the request.
I end up with a solution similar to the one described by #tehfink combined with #little_birdie.
However, just updating self.form.declared_fields as suggested didn't help. The result of this procedure is, that the list of custom fields defined in self.form.declared_fields always grows from request to request.
I solved this by initialising this dictionary first:
class ModelAdminGetCustomFieldsMixin(object):
def get_fields(self, request, obj=None):
fields = super().get_fields(request, obj=None)
self.form.declared_fields = {}
if obj:
for custom_attribute in custom_attribute_list:
self.form.declared_fields.update({custom_attribute.name: custom_attribute.field})
return fields
where custom_attribute.field is a form field instance.
Additionally, it was required to define a ModelForm, wherein during initialisation the custom fields have been added dynamically as well:
class SomeModelForm(forms.ModelForm):
def __init__(self, *args, **kwargs):
super().__init__(*args, **kwargs)
for custom_attribute in custom_attribute_list:
self.fields[custom_attribute.name] = custom_attribute.field
and use this ModelForm in the ModelAdmin.
Afterwards, the newly defined attributes can be used in, e.g., a fieldset.
While Jacob's post might work all right for regular ModelForms (even though it's more than a year and a half old), the admin is a somewhat different matter.
All the declarative way of defining models, forms ModelAdmins and whatnot makes heavy use of metaclasses and class introspection. Same with the admin – when you tell a ModelAdmin to use a specific form istead of creating a default one, it introspects the class. It gets the list of fields and other stuff from the class itself without instantiating it.
Your custom class, however, does not define the extra form field at class level, instead it dynamically adds one after it has been instantiated – that's too late for the ModelAdmin to recognize this change.
One way to go about your problem might be to subclass ModelAdmin and override its get_fieldsets method to actually instantiate the ModelForm class and get the list of fields from the instance instead of the class. You'll have to keep in mind, though, that this might be somewhat slower than the default implementation.
You can create dynamic fields and fieldset using the form meta class. Sample code is given below. Add the loop logic as per you requirements.
class CustomAdminFormMetaClass(ModelFormMetaclass):
"""
Metaclass for custom admin form with dynamic field
"""
def __new__(cls, name, bases, attrs):
for field in get_dynamic_fields: #add logic to get the fields
attrs[field] = forms.CharField(max_length=30) #add logic to the form field
return super(CustomAdminFormMetaClass, cls).__new__(cls, name, bases, attrs)
class CustomAdminForm(six.with_metaclass(CustomAdminFormMetaClass, forms.ModelForm)):
"""
Custom admin form
"""
class Meta:
model = ModelName
fields = "__all__"
class CustomAdmin(admin.ModelAdmin):
"""
Custom admin
"""
fieldsets = None
form = CustomAdminForm
def get_fieldsets(self, request, obj=None):
"""
Different fieldset for the admin form
"""
self.fieldsets = self.dynamic_fieldset(). #add logic to add the dynamic fieldset with fields
return super(CustomAdmin, self).get_fieldsets(request, obj)
def dynamic_fieldset(self):
"""
get the dynamic field sets
"""
fieldsets = []
for group in get_field_set_groups: #logic to get the field set group
fields = []
for field in get_group_fields: #logic to get the group fields
fields.append(field)
fieldset_values = {"fields": tuple(fields), "classes": ['collapse']}
fieldsets.append((group, fieldset_values))
fieldsets = tuple(fieldsets)
return fieldsets
Stephan's answer is elegant, but when I used in in dj1.6 it required the field to be a tuple.
The complete solution looked like this:
class ProductForm(ModelForm):
foo = CharField(label='foo')
class ProductAdmin(admin.ModelAdmin):
form = ProductForm
def get_fieldsets(self, request, obj=None):
fieldsets = super(ProductAdmin, self).get_fieldsets(request, obj)
fieldsets[0][1]['fields'] += ('foo', )
return fieldsets
not sure why that's not working, but could a possible workaround be to define the field statically (on the form) and then override it in the __init__?
I for a long time could not solve a problem with dynamic addition of fields.
The solution "little_birdie" really works. Thank you Birdie))
The only nuance is:
"Self.declared_fieldsets" should be replaced with "self.fieldsets".
#kwargs['fields'] = flatten_fieldsets(self.declared_fieldsets)
kwargs['fields'] = flatten_fieldsets(self.fieldsets)
I used version 1.10. Perhaps something has changed.
If someone finds an even simpler and elegant solution, show here.
Thanks to all )))
I am wondering how to access a user's profile when creating the
queryset for a ModelChoiceField. I would like to be able to use the
ModelChoiceField to display contacts from another table based on a
parameter saved in the user profile i.e.
who = forms.ModelChoiceField(queryset=Contacts.objects.filter(id__exact=request.user.get_profile().main_company))
Is there a better way to do this (beyond an ajax picker in the
template)?
Greg
For Those interested I was able to come up with a solution from the following SO discussions:
How do I access the request object or any other variable in a form's clean() method?
Django: accessing the model instance from within ModelAdmin?
class InspectionRequestForm(ModelForm):
....
def __init__(self, *args, **kwargs):
self.request = kwargs.pop('request', None)
super(InspectionRequestForm, self).__init__(*args, **kwargs)
companyid = self.request.user.get_profile().main_contactnum.clientid.idflcustomernum
self.fields['who'].queryset = Contacts.objects.filter(clientid__exact=companyid)
My View:
Save Form (Not as necessary to include request=request here, but just in case)
form = InspectionRequestForm(request.POST, request=request)
Or Empty Form
form = InspectionRequestForm(request=request)
Thanks to Daniel Roseman for both of the previous answers.
https://stackoverflow.com/users/104349/daniel-roseman
I am trying to add dynamically new form fields (I used this blog post), for a form used in admin interface :
class ServiceRoleAssignmentForm(forms.ModelForm):
class Meta:
model = ServiceRoleAssignment
def __init__(self, *args, **kwargs):
super(ServiceRoleAssignmentForm, self).__init__(*args, **kwargs)
self.fields['test'] = forms.CharField(label='test')
class ServiceRoleAssignmentAdmin(admin.ModelAdmin):
form = ServiceRoleAssignmentForm
admin.site.register(ServiceRoleAssignment, ServiceRoleAssignmentAdmin)
However, no matter what I try, the field doesn't appear on my admin form ! Could it be a problem related to the way admin works ? Or to ModelForm ?
Thank for any help !
Sébastien
PS : I am using django 1.3
When rendering your form in template, fields enumerating from fieldsets variable, not from fields. Sure you can redefine fieldsets in your AdminForm, but then validations will fail as original form class doesn't have such field. One workaround I can propose is to define this field in form definition statically and then redefine that field in form's init method dynamically. Here is an example:
class ServiceRoleAssignmentForm(forms.ModelForm):
test = forms.Field()
class Meta:
model = ServiceRoleAssignment
def __init__(self, *args, **kwargs):
super(ServiceRoleAssignmentForm, self).__init__(*args, **kwargs)
# Here we will redefine our test field.
self.fields['test'] = forms.CharField(label='test2')
I actually have a the same issue which I'm working through at the moment.
While not ideal, I have found a temporary workaround that works for my use case. It might be of use to you?
In my case I have a static name for the field, so I just declared it in my ModelForm. as normal, I then override the init() as normal to override some options.
ie:
def statemachine_form(for_model=None):
"""
Factory function to create a special case form
"""
class _StateMachineBaseModelForm(forms.ModelForm):
_sm_action = forms.ChoiceField(choices=[], label="Take Action")
class Meta:
model = for_model
def __init__(self, *args, **kwargs):
super(_StateMachineBaseModelForm, self).__init__(*args, **kwargs)
actions = (('', '-----------'),)
for action in self.instance.sm_state_actions():
actions += ((action, action),)
self.fields['_sm_action'] = forms.ChoiceField(choices=actions,
label="Take Action")
if for_model: return _StateMachineBaseModelForm
class ContentItemAdmin(admin.ModelAdmin):
form = statemachine_form(for_model=ContentItem)
Now as I mentioned before, this is not entirely 'dynamic', but this will do for me for the time being.
I have the exact same problem that, if I add the field dynamically, without declaring it first, then it doesn't actually exist. I think this does in fact have something to do with the way that ModelForm creates the fields.
I'm hoping someone else can give us some more info.
Django - Overriding get_form to customize admin forms based on request
Try to add the field before calling the super.init:
def __init__(self, *args, **kwargs):
self.fields['test'] = forms.CharField(label='test')
super(ServiceRoleAssignmentForm, self).__init__(*args, **kwargs)
I have a standard admin change form for an object, with the usual StackedInline forms for a ForeignKey relationship. I would like to be able to link each inline item to its corresponding full-sized change form, as the inline item has inlined items of its own, and I can't nest them.
I've tried everything from custom widgets to custom templates, and can't make anything work. So far, the "solutions" I've seen in the form of snippets just plain don't seem to work for inlines. I'm getting ready to try some DOM hacking with jQuery just to get it working and move on.
I hope I must be missing something very simple, as this seems like such a simple task!
Using Django 1.2.
There is a property called show_change_link since Django 1.8.
I did something like the following in my admin.py:
from django.utils.html import format_html
from django.core.urlresolvers import reverse
class MyModelInline(admin.TabularInline):
model = MyModel
def admin_link(self, instance):
url = reverse('admin:%s_%s_change' % (instance._meta.app_label,
instance._meta.module_name),
args=(instance.id,))
return format_html(u'Edit', url)
# … or if you want to include other fields:
return format_html(u'Edit: {}', url, instance.title)
readonly_fields = ('admin_link',)
The currently accepted solution here is good work, but it's out of date.
Since Django 1.3, there is a built-in property called show_change_link = True that addresses this issue.
This can be added to any StackedInline or TabularInline object. For example:
class ContactListInline(admin.TabularInline):
model = ContactList
fields = ('name', 'description', 'total_contacts',)
readonly_fields = ('name', 'description', 'total_contacts',)
show_change_link = True
The result will be something line this:
I had similar problem and I came up with custom widget plus some tweaks to model form. Here is the widget:
from django.utils.safestring import mark_safe
class ModelLinkWidget(forms.Widget):
def __init__(self, obj, attrs=None):
self.object = obj
super(ModelLinkWidget, self).__init__(attrs)
def render(self, name, value, attrs=None):
if self.object.pk:
return mark_safe(
u'<a target="_blank" href="../../../%s/%s/%s/">%s</a>' %\
(
self.object._meta.app_label,
self.object._meta.object_name.lower(),
self.object.pk, self.object
)
)
else:
return mark_safe(u'')
Now since widget for each inline need to get different object in constructor you can't just set it in standard way, but in Form's init method:
class TheForm(forms.ModelForm):
...
# required=False is essential cause we don't
# render input tag so there will be no value submitted.
link = forms.CharField(label='link', required=False)
def __init__(self, *args, **kwargs):
super(TheForm, self).__init__(*args, **kwargs)
# instance is always available, it just does or doesn't have pk.
self.fields['link'].widget = ModelLinkWidget(self.instance)
Quentin's answer above works, but you also need to specify fields = ('admin_link',)
There is a module for this purpose. Check out:
django-relatives
I think: args=[instance.id] should be args=[instance.pk]. It worked for me!