Simulink link by tcpip with C++ application - c++

I am tryng to build a link between my simulink model or just an m file and my C++ application but I'm having an issue. I don't really understand how matlab receives the data, and for simulink in which form should I send the data to the block? I would like to send coordinates like xyz to matlab and with matlab scatter3 the stream of coordinates in real time. Is it possible ?
Here is the C++ extract code : (sorry comments are in french)
/* Démarrage du listage (mode server) */
sock_err = listen(sock, 5);
printf("Listage du port %d...\n", PORT);
/* Si la socket fonctionne */
if(sock_err != SOCKET_ERROR)
{
/* Attente pendant laquelle le client se connecte */
printf("Patientez pendant que le client se connecte sur le port %d...\n", PORT);
csock = accept(sock, (SOCKADDR*)&csin, &recsize);
printf("Un client se connecte avec la socket %d de %s:%d\n", csock, inet_ntoa(csin.sin_addr), htons(csin.sin_port));
// double buff = 25;
mxArray *datasend;
datasend = mxCreateDoubleMatrix(1, 1, mxREAL);
mlfPrintmatrix(datasend);
sock_err = send(csock, T, 3*sizeof(double), 0);
if(sock_err != SOCKET_ERROR)
printf("Send : %s\n", buffer[0]);
//printf("send : [10 20 30]");
else
printf("Erreur de transmission\n");
/* Il ne faut pas oublier de fermer la connexion (fermée dans les deux sens) */
shutdown(csock, 2);
}
Simulink errors:
Error evaluating registered method 'Outputs' of M-S-Function 'stcpiprb' in 'trajectory2/TCP//IP Receive'. The specified amount of data was not returned within the Timeout period.
Please ensure that data is being sent to the specified port or specify a greater timeout value.
The specified amount of data was not returned within the Timeout period.
Please ensure that data is being sent to the specified port or specify a greater timeout value.
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I can't see creating socket and binding to it in your C code. Are you sure that you're binding on 127.0.0.1 and port 80? Are you sure that there's no some apache running on the server on port 80?
http://www.linuxhowtos.org/C_C++/socket.htm
Also:
sock_err = send(csock, T, 3*sizeof(double), 0);
I don't also see T in your code, which is probably not the issue, but it doesn't seem to be the datasend pointer to mxArray.

Related

How to capture multiple instances of the same group in Rust regex?

Here is my text:
hello: 3 32 2 8
I want to capture it with the following regex:
^([a-z]+):( [0-9]+)+$
I'm doing this:
let txt = "hello: 3 32 2 8";
let re = Regex::new("^([a-z]+):( [0-9]+)+$")?;
let caps = re.captures(txt);
println!("{caps:?}");
I'm getting only the last number 8 in the second capture group:
Some(Captures({0: Some("hello: 3 32 2 8"), 1: Some("hello"), 2: Some(" 8")}))
I suspect that it is an expected behavior of captures, but what is the workaround?
I would simply capture the whole sequence of integers.
Since we know this substring has the expected shape, we can split and parse it with confidence (except if one integer has too many digits).
Note that I added some tolerance around white-spaces.
use regex::Regex;
fn detect(txt: &str) -> Result<(&str, Vec<u32>), Box<dyn std::error::Error>> {
let re = Regex::new(r"^\s*([a-z]+)\s*:((\s*[0-9]+)+)\s*$")?;
let caps = re.captures(txt).ok_or("no match")?;
// starting from here, we know that all the expected substrings exist
// thus we can unwrap() the options/errors
let name = caps.get(1).unwrap().as_str();
let values = caps
.get(2)
.unwrap()
.as_str()
.split_ascii_whitespace()
.filter_map(|s| s.parse().ok()) // FIXME: overflow ignored
.collect();
Ok((name, values))
}
fn main() {
for txt in [
"hello: 3 32 2 8",
"hello :\t3 32 2 8",
"\thello :\t3 32 2 8 ",
"hello:",
"hello:9999999999 3",
] {
println!("{:?} ~~> {:?}", txt, detect(txt));
}
}
/*
"hello: 3 32 2 8" ~~> Ok(("hello", [3, 32, 2, 8]))
"hello :\t3 32 2 8" ~~> Ok(("hello", [3, 32, 2, 8]))
"\thello :\t3 32 2 8 " ~~> Ok(("hello", [3, 32, 2, 8]))
"hello:" ~~> Err("no match")
"hello:9999999999 3" ~~> Ok(("hello", [3]))
*/

What regex pattern matches this string?

Been scratching my head on this for hours to no avail! I need to match 3 different parts of this string, in 3 different patterns. So one regex pattern matches the first, etc.
Here is the string:
{
"jsonrpc": "2.0",
"result": [
{
"marketId": "1.123485047",
"isMarketDataDelayed": false,
"status": "OPEN",
"betDelay": 0,
"bspReconciled": false,
"complete": true,
"inplay": false,
"numberOfWinners": 1,
"numberOfRunners": 3,
"numberOfActiveRunners": 3,
"lastMatchTime": "2016-03-18T23:21:14.211Z",
"totalMatched": 47663.09,
"totalAvailable": 140527.57,
"crossMatching": true,
"runnersVoidable": false,
"version": 1259153627,
"runners": [
{
"selectionId": 48224,
"handicap": 0.0,
"status": "ACTIVE",
"lastPriceTraded": 1.57,
"totalMatched": 37408.96,
"ex": {
"availableToBack": [
{
"price": 1.56,
"size": 1344.78
},
{
"price": 1.55,
"size": 642.45
},
{
"price": 1.54,
"size": 1034.4
}
],
"availableToLay": [
{
"price": 1.57,
"size": 303.34
},
{
"price": 1.58,
"size": 2368.34
},
{
"price": 1.59,
"size": 1220.99
}
],
"tradedVolume": []
}
},
{
"selectionId": 1141,
"handicap": 0.0,
"status": "ACTIVE",
"lastPriceTraded": 7.0,
"totalMatched": 5863.62,
"ex": {
"availableToBack": [
{
"price": 7.0,
"size": 286.85
},
{
"price": 6.8,
"size": 552.02
},
{
"price": 6.6,
"size": 25.81
}
],
"availableToLay": [
{
"price": 7.2,
"size": 36.05
},
{
"price": 7.4,
"size": 312.79
},
{
"price": 7.6,
"size": 92.63
}
],
"tradedVolume": []
}
},
{
"selectionId": 58805,
"handicap": 0.0,
"status": "ACTIVE",
"lastPriceTraded": 4.5,
"totalMatched": 4390.5,
"ex": {
"availableToBack": [
{
"price": 4.5,
"size": 209.65
},
{
"price": 4.4,
"size": 692.37
},
{
"price": 4.3,
"size": 429.69
}
],
"availableToLay": [
{
"price": 4.6,
"size": 279.02
},
{
"price": 4.7,
"size": 821.2
},
{
"price": 4.8,
"size": 928.88
}
],
"tradedVolume": []
}
}
]
}
],
"id": 1
}
I bolded the 3 parts which need extracting. (in this case they are 1.57, 7.2 and 4.6). These numbers can be integers, have 1 or 2 decimals.
One possible regex to extract 1.57, 7.2 and 4.6 would be :
(?:availableToLay[^\d]+)([\d.]+)
https://regex101.com/r/vP5iH2/1
UPDATE: Just seen the answer from "florentbr" and that is a much tidier answer than mine!
Do you really need RegEx? There's probably many ways of doing this, but breaking down by commas seems to hit the right data. Open up Excel, and dump your data in Cell "A1", then past this code into the VBA editor:
Option Explicit
Sub getYourVals()
Dim dataStr() As String
Dim i As Integer
Dim marker As String
marker = "availableToLay"
dataStr = Split(Range("A" & 1).Value, ",")
For i = 1 To UBound(dataStr)
If Mid(dataStr(i), 2, Len(marker)) = marker Then
Debug.Print Mid(dataStr(i), 28, Len(dataStr(i)) - 27)
End If
Range("A" & i + 1).Value = dataStr(i)
Next i
End Sub
Consider parsing the JSON string altogether, flattening it for needed data. JSON formats can be thought of as an assembly of dictionaries and collections, two data structures VBA maintains. Below uses VBA Tools' VBA-JSON library.
Setup Steps
Import the .bas file in above link into a VBA module in IDE.
Add the VBA Reference for Microsoft Scripting Runtime
VBA Script (loops through the results, runners, and ex collections)
Sub JSONStringData()
Dim jsonStr As String
Dim element As Variant, e As Variant, n As Variant, r As Variant
Dim x As Variant, s As Variant, pr As Variant, dat As Variant
Dim i As Integer, num As Integer
jsonStr = "{""jsonrpc"":""2.0"",""result"":" _
& "[{""marketId"":""1.123485047"",""isMarketDataDelayed"":false,""status"":""OPEN""," _
& """betDelay"":0,""bspReconciled"":false,""complete"":true,""inplay"":false," _
& """numberOfWinners"":1,""numberOfRunners"":3,""numberOfActiveRunners"":3,""lastMatchTime"":" _
& """2016-03-18T23:21:14.211Z"",""totalMatched"":47663.09,""totalAvailable"":140527.57,""crossMatching"":true," _
& """runnersVoidable"":false,""version"":1259153627,""runners"":" _
& "[{""selectionId"":48224,""handicap"":0.0,""status"":""ACTIVE"",""lastPriceTraded"":1.57," _
& """totalMatched"":37408.96,""ex"":{""availableToBack"":[{""price"":1.56,""size"":1344.78}," _
& "{""price"":1.55,""size"":642.45},{""price"":1.54,""size"":1034.4}],""availableToLay"":" _
& "[{""price"":1.57,""size"":303.34},{""price"":1.58,""size"":2368.34},{""price"":1.59,""size"":1220.99}]," _
& """tradedVolume"":[]}},{""selectionId"":1141,""handicap"":0.0,""status"":""ACTIVE""," _
& """lastPriceTraded"":7.0,""totalMatched"":5863.62,""ex"":{""availableToBack"":[{""price"":7.0," _
& """size"":286.85},{""price"":6.8,""size"":552.02},{""price"":6.6,""size"":25.81}],""availableToLay"":" _
& "[{""price"":7.2,""size"":36.05},{""price"":7.4,""size"":312.79},{""price"":7.6,""size"":" _
& "92.63}],""tradedVolume"":[]}},{""selectionId"":58805,""handicap"":0.0,""status"":" _
& """ACTIVE"",""lastPriceTraded"":4.5,""totalMatched"":4390.5,""ex"":{""availableToBack"":" _
& "[{""price"":4.5,""size"":209.65},{""price"":4.4,""size"":692.37},{""price"":4.3,""size"":429.69}]" _
& ",""availableToLay"":[{""price"":4.6,""size"":279.02},{""price"":4.7,""size"":821.2}," _
& "{""price"":4.8,""size"":928.88}],""tradedVolume"":[]}}]}],""id"":1}"
' PARSE FILE STRING
Dim p As Object
Set p = ParseJson(jsonStr)
i = 5
For Each element In p
' RESULT COLLECTION OF DICTIONARIES (N = 17)
If element = "result" Then
For Each e In p(element)
For Each n In e
' RUNNERS COLLECTION OF DICTIONARIES (N = 6)
If n = "runners" Then
For Each r In e(n)
For Each x In r
' EX DICTIONARY OF COLLECTIONS (N = 9, 3 PER 3 RUNNERS)
If x = "ex" Then
For Each s In r(x)
num = 1
For Each pr In r(x)(s)
For Each dat In pr
Sheets(1).Range("A" & i) = r("selectionId")
Sheets(1).Range("B" & i) = r("handicap")
Sheets(1).Range("C" & i) = r("status")
Sheets(1).Range("D" & i) = r("lastPriceTraded")
Sheets(1).Range("E" & i) = r("totalMatched")
Sheets(1).Range("F" & i) = s
Sheets(1).Range("G" & i) = num
Sheets(1).Range("H" & i) = dat
Sheets(1).Range("I" & i) = pr(dat)
i = i + 1
Next dat
num = num + 1
Next pr
Next s
End If
Next x
Next r
End If
Next n
Next e
End If
Next element
End Sub
Result (where 1.57, 7.2, and 4.6 are the first prices for availableToLay for each of three runners)
48224 0 ACTIVE 1.57 37408.96 availableToBack 1 price 1.56
48224 0 ACTIVE 1.57 37408.96 availableToBack 1 size 1344.78
48224 0 ACTIVE 1.57 37408.96 availableToBack 2 price 1.55
48224 0 ACTIVE 1.57 37408.96 availableToBack 2 size 642.45
48224 0 ACTIVE 1.57 37408.96 availableToBack 3 price 1.54
48224 0 ACTIVE 1.57 37408.96 availableToBack 3 size 1034.4
48224 0 ACTIVE 1.57 37408.96 availableToLay 1 price 1.57
48224 0 ACTIVE 1.57 37408.96 availableToLay 1 size 303.34
48224 0 ACTIVE 1.57 37408.96 availableToLay 2 price 1.58
48224 0 ACTIVE 1.57 37408.96 availableToLay 2 size 2368.34
48224 0 ACTIVE 1.57 37408.96 availableToLay 3 price 1.59
48224 0 ACTIVE 1.57 37408.96 availableToLay 3 size 1220.99
1141 0 ACTIVE 7 5863.62 availableToBack 1 price 7
1141 0 ACTIVE 7 5863.62 availableToBack 1 size 286.85
1141 0 ACTIVE 7 5863.62 availableToBack 2 price 6.8
1141 0 ACTIVE 7 5863.62 availableToBack 2 size 552.02
1141 0 ACTIVE 7 5863.62 availableToBack 3 price 6.6
1141 0 ACTIVE 7 5863.62 availableToBack 3 size 25.81
1141 0 ACTIVE 7 5863.62 availableToLay 1 price 7.2
1141 0 ACTIVE 7 5863.62 availableToLay 1 size 36.05
1141 0 ACTIVE 7 5863.62 availableToLay 2 price 7.4
1141 0 ACTIVE 7 5863.62 availableToLay 2 size 312.79
1141 0 ACTIVE 7 5863.62 availableToLay 3 price 7.6
1141 0 ACTIVE 7 5863.62 availableToLay 3 size 92.63
58805 0 ACTIVE 4.5 4390.5 availableToBack 1 price 4.5
58805 0 ACTIVE 4.5 4390.5 availableToBack 1 size 209.65
58805 0 ACTIVE 4.5 4390.5 availableToBack 2 price 4.4
58805 0 ACTIVE 4.5 4390.5 availableToBack 2 size 692.37
58805 0 ACTIVE 4.5 4390.5 availableToBack 3 price 4.3
58805 0 ACTIVE 4.5 4390.5 availableToBack 3 size 429.69
58805 0 ACTIVE 4.5 4390.5 availableToLay 1 price 4.6
58805 0 ACTIVE 4.5 4390.5 availableToLay 1 size 279.02
58805 0 ACTIVE 4.5 4390.5 availableToLay 2 price 4.7
58805 0 ACTIVE 4.5 4390.5 availableToLay 2 size 821.2
58805 0 ACTIVE 4.5 4390.5 availableToLay 3 price 4.8
58805 0 ACTIVE 4.5 4390.5 availableToLay 3 size 928.88

QSqlQuery ignoring sort order for SQLite DB

The results returned by my QSqlQuery are always in the same order, regardless of the ORDER BY state:
void Sy_loggingModel::reload()
{
auto query = d_->buildQuery();
query.setForwardOnly( true );
if ( !query.exec() ) {
throw Sy_exception( QObject::tr( "Failed to query logging data: " ) +
query.lastError().text() );
}
beginResetModel();
qDebug() << query.lastQuery()
<< d_->filter_ // First ? param
<< d_->sortedColumn_; // Second ? param
d_->entries_.clear();
while ( query.next() ) {
auto timestamp = query.value( 1 ).toLongLong();
auto level = query.value( 2 ).toInt();
d_->entries_ << Sy_loggingModel_d::Entry{
query.value( 0 ).toLongLong(),
QDateTime::fromMSecsSinceEpoch( timestamp ).toString(),
static_cast< Sy_loggerInterface::DebugLevel >( level ),
query.value( 3 ).toString() };
qDebug() << "\t" << query.value( 0 ).toLongLong()
<< timestamp
<< level
<< query.value( 3 ).toString();
}
endResetModel();
}
Produces this output when alternating between sort orders:
"SELECT rowid, timestamp, debugLevel, message FROM Sy_logger WHERE rowid >= ? AND debugLevel IN ( 0, 1, 2 ) ORDER BY ? DESC;" 0 1
1 1415399097350 0 "Opened database ./logs/Syren2.log"
2 1415399097382 1 "Listening on port 23000"
3 1415399418377 2 "New log rotation settings received, Metric: 0, Interval: 720"
4 1416178611851 2 "Opened database ./logs/Syren2.log"
5 1416178611852 2 "Listening on port 23000"
6 1416178612776 2 "New log rotation settings received, Metric: 0, Interval: 720"
"SELECT rowid, timestamp, debugLevel, message FROM Sy_logger WHERE rowid >= ? AND debugLevel IN ( 0, 1, 2 ) ORDER BY ? ASC;" 0 1
1 1415399097350 0 "Opened database ./logs/Syren2.log"
2 1415399097382 1 "Listening on port 23000"
3 1415399418377 2 "New log rotation settings received, Metric: 0, Interval: 720"
4 1416178611851 2 "Opened database ./logs/Syren2.log"
5 1416178611852 2 "Listening on port 23000"
6 1416178612776 2 "New log rotation settings received, Metric: 0, Interval: 720"
The SQL statement returns the expected result set when used from the command line. Any suggestions? I'm using Qt v5.3.2.
The documentation says:
If the ORDER BY expression is a constant integer K then the expression is considered an alias for the K-th column of the result set.
However, parameters are not considered constants, so the value you use for this parameters is used as an expression that happens to be the same for all rows.
If you want to sort by different columns, you have to construct the SQL statement dynamically.

Rally Rest Api: Get defect by Formatted Id

Hi I am having a web service.
https://rally1.rallydev.com/slm/webservice/v2.x/defect/objectId
What I want to do is instead of objectId search defect by using Formatted Id.
How can I do it?
You can find appropriate objectId by formattedID using Rally Lookback API request.
For example: I need search objectId of Test Case named TC12345. So I must send following GET query:
https://rally1.rallydev.com/analytics/v2.0/service/rally/workspace/WORKSPACE_ID/artifact/snapshot/query.js?find={"_UnformattedID":12345,"_TypeHierarchy":"TestCase"}&fields=["ObjectID"]
Where:
WORKSPACE_ID is the your workspace personal number which you can obtain on this page https://rally1.rallydev.com/slm/doc/webservice/objectModel.sp
UnformattedID = 12345 = numerial part of TC12345
Output can be (see searched "ObjectID: 22697085352" at the very end):
{
_rallyAPIMajor: "2"
_rallyAPIMinor: "0"
Errors: [0]
Warnings: [0]
ThreadStats: {
cpuTime: "10.0"
waitTime: "0"
blockedTime: "1"
waitCount: "1"
blockedCount: "2"
}-
Timings: {
preProcess: 0
findEtlDate: 36
allowedValuesDisambiguation: 1
mongoQuery: 9
authorization: 3
formattedId: 0
suppressNonRequested: 0
allowedValuesHydration: 0
compressSnapshots: 0
TOTAL: 49
}-
GeneratedQuery: {
find: {
_UnformattedID: 619
_TypeHierarchy: {
$in: [3]
0: -51012
1: 9467271631
2: 10486304042
-
}-
_ValidFrom: {
$lte: "2014-09-16T14:21:35.731Z"
}-
}-
limit: 100
skip: 0
fields: {
ObjectID: 1
Project: 1
}-
}-
TotalResultCount: 1
StartIndex: 0
PageSize: 100
ETLDate: "2014-09-16T14:21:35.731Z"
Results: [1]
0: {
ObjectID: 22697085352
}-
-
}
It is easier if you use "query" parameter over defect entity directly like:
https://eu1.rallydev.com/slm/webservice/v2.0/defect?query=(FormattedID = DEXXXXX)&fetch=Name,ObjectID
Regards.

IF function; struggling with format of 3 times greater section

Excel 2002: Write an IF function for cell J8 that assigns the text "OK" if the value in cell L9 is three times greater than the value in cell M6; otherwise, have the IF function assign the text "Not OK" to cell J8. would it be: =if(L9*3>m6, "OK", "Not OK")
That would be
=IF(L9>=M6*3,"OK", "Not OK")
further examples:
A B C Formula
-------------------------------------------------
1 2 No OK IF(B2 >= A2*3,"OK", "Not OK")
2 6 OK IF(B3 >= A3*3,"OK", "Not OK")
3 8 No OK IF(B4 >= A4*3,"OK", "Not OK")