C++ Hex Parsing - c++

Question

I'm wondering how to convert a hex string to a human readable string (if that makes any sense) this would be my first real encounter with hex values so I'm still learning about them and how to manage them.
I have a program which is reading in data from a file which contains raw packet data (hex) and I need to parse this information so it's human readable.
An example of what I need to do is something like this site does http://home2.paulschou.net/tools/xlate/ where you can put in hex and have it converted to text.

Answer 1

Taken from the C++ String Toolkit Library (StrTk) library, the following should suffice. Note that out should point to a piece of memory half the size of as std::distance(begin,end), and that the values in the range of [begin,end) be 0-9A-F or 0-9a-f
inline bool convert_hex_to_bin(const unsigned char* begin,
const unsigned char* end,
unsigned char* out)
{
if (std::distance(begin,end) % 2)
return false;
static const std::size_t symbol_count = 256;
static const unsigned char hex_to_bin[symbol_count] = {
0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, // 0x00 - 0x07
0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, // 0x08 - 0x0F
0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, // 0x10 - 0x17
0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, // 0x18 - 0x1F
0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, // 0x20 - 0x27
0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, // 0x28 - 0x2F
0x00, 0x01, 0x02, 0x03, 0x04, 0x05, 0x06, 0x07, // 0x30 - 0x37
0x08, 0x09, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, // 0x38 - 0x3F
0x00, 0x0A, 0x0B, 0x0C, 0x0D, 0x0E, 0x0F, 0x00, // 0x40 - 0x47
0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, // 0x48 - 0x4F
0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, // 0x50 - 0x57
0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, // 0x58 - 0x5F
0x00, 0x0A, 0x0B, 0x0C, 0x0D, 0x0E, 0x0F, 0x00, // 0x60 - 0x67
0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, // 0x68 - 0x6F
0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, // 0x70 - 0x77
0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, // 0x78 - 0x7F
0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, // 0x80 - 0x87
0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, // 0x88 - 0x8F
0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, // 0x90 - 0x97
0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, // 0x98 - 0x9F
0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, // 0xA0 - 0xA7
0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, // 0xA8 - 0xAF
0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, // 0xB0 - 0xB7
0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, // 0xB8 - 0xBF
0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, // 0xC0 - 0xC7
0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, // 0xC8 - 0xCF
0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, // 0xD0 - 0xD7
0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, // 0xD8 - 0xDF
0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, // 0xE0 - 0xE7
0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, // 0xE8 - 0xEF
0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, // 0xF0 - 0xF7
0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00 // 0xF8 - 0xFF
};
const unsigned char* itr = begin;
while (end != itr)
{
(*out) = static_cast<unsigned char>(hex_to_bin[*(itr++)] << 4);
(*out) |= static_cast<unsigned char>(hex_to_bin[*(itr++)] );
++out;
}
return true;
}

Answer 2

The C++-ish way to get a string containing the hexadecimal representation of a given number is to use the hex modifier for streams, as in this example:
const int i = 0xdeadbeef;
cout << "0x" << hex << i << endl; // prints "0xdeadbeef"
You can use the same modifier on string streams in case you need to have the hexadecimal representation in a string variable:
const int i = 0xdeadc0de;
ostringstream stream;
stream << "0x" << hex << i;
const string s = stream.str(); // s now contains "0xdeadc0de"
UPDATE:
If your input data is given as a string containing the hexadecimal representation of the characters of a string, you will need to know the encoding of the input string in order to display it correctly. In the simplest case, the string is something like ASCII which maps one byte to one character. So in a given input "414243", every two characters ("41", "42", "43) map to an ASCII value (65, 66, 67), which map to a character ("A", "B", "C").
Here's how to that in C++:
const string hexData = "414243";
assert( hexData.size() % 2 == 0 );
ostringstream asciiStream;
istringstream hexDataStream( hexData );
vector<char> buf( 3 ); // two chars for the hex char, one for trailing zero
while ( hexDataStream.good() ) {
hexDataStream.get( &buf[0], buf.size() );
if ( hexDataStream.good() ) {
asciiStream << static_cast<char>( std::strtol( &buf[0], 0, 16 ) );
}
}
const string asciiData = asciiStream.str(); // asciiData == "ABC"
Using std::strtol from <cstdlib> makes this easy; if you insist on using a template class for this, use std::stringstream to perform the conversion of the single sub strings (like "41") to decimal values (65).

Answer 3

fprintf(file, "%h", thing);
Something along those lines?

Answer 4

Hex is a way of displaying binary data. It is not "raw data" as you say. If the raw data you have contains a string, you should be able to see the string (possibly among other garbage) when you output it to the screen.
Here's a loop to print the ASCII characters in a block of data. To get anything else, you will have to deal with its format.
char *binary_data[ BUFFER_SIZE ];
size_t len = BUFFER_SIZE;
len = get_a_packet( data, len ); // or however you get data
for ( char *text_ptr = binary_data; text_ptr != binary_data + len; ++ text_ptr ) {
if ( * text_ptr <= '~' && * text_ptr >= ' ' ) { // if it's ascii
cerr << * text_ptr; // print it out
}
}
cerr << endl;