Some of the GNU library code can be have enhanced debugging if the flag _LIBC is set. While using -D_LIBC when compiling gives the error message
"/usr/include/gnu/stubs.h:7:3: #error Applications may not define the macro _LIBC"
So how do you define this variable?
You'd define it when compiling LibC. It's Open Source, after all.
Related
I am trying to compile a library using clang. The library makes calls to 'unlink', which is not defined by clang:
libmv/src/third_party/OpenExif/src/ExifImageFileWrite.cpp:162:17: error: use of undeclared identifier 'unlink'; did you mean 'inline'?
unlink( mTmpImageFile.c_str() ) ;
My question is, what is the clang equivalent of unlink? As I see it, the path forward would be to #define unlink somewhere with an equivalent routine.
There is no "Clang equivalent". Neither GCC nor Clang have ever been responsible for defining unlink, though they do probably distribute the POSIX headers which do (I don't recall specifically where POSIX headers come from).
Unfortunately, this appears to be a bug with the library you're using; the OpenExif developers failed to include the correct headers. Different C++ implementations may internally #include various headers for their own purposes, which has apparently masked this bug on your previous toolchain.
You can hack your copy and/or submit a patch to add:
#include <unistd.h>
I am using QT Creator to make a C++ program on Ubuntu. The program I had written was compiling fine, until I decided to start using C++11 rather than C++98 (which is the default in QT Creator). I am using my own cmake file, rather than qmake, and so to do this, I included the following line in my CMakeLists.txt file:
set(CMAKE_CXX_FLAGS "-std=c++0x")
Now, part of my code has the following (which was not written by me):
#if (linux && (i386 || __x86_64__))
# include "Linux-x86/OniPlatformLinux-x86.h"
#elif (linux && __arm__)
# include "Linux-Arm/OniPlatformLinux-Arm.h"
#else
# error Unsupported Platform!
#endif
After transferring to C++11, I get an error at the line error Unsupported Platform!. This is because, from what I can see, the variable linux is not defined anywhere, although the variable __x86_64__ is defined.
Therefore, I have two questions:
1) Why is the variable linux not defined, even though I am using Linux?
2) How can I tell C++11 to ignore this error?
Thanks.
The identifier linux is not reserved. A conforming compiler may not predefine it as a macro. For example, this program:
int main() {
int linux = 0;
return linux;
}
is perfectly valid, and a conforming compiler must accept it. Predefining linux causes the declaration to be a syntax error.
Some older compilers (including the compiler you were using, with the options you were giving it) predefine certain symbols to provide information about the target platform -- including linux to indicate a Linux system. This convention goes back to early C compilers, written before there was a distinction between reserved and unreserved identifiers.
The identifier __linux__, since it starts with two underscores, is reserved for use by the implementation, so compilers are allowed to predefine it -- and compilers for Linux systems typically do predefine it as a macro expanding to 1.
Confirm that your compiler predefines __linux__, and then change your code so it tests __linux__ rather than linux. You should also find out what reserved symbol is used instead of i386 (likely __i386__).
Related: Why does the C preprocessor interpret the word "linux" as the constant "1"?
Change your standard-selection flag to -std=gnu++0x instead of c++0x. The gnu flavors provide some non-standard extensions, apparently including predefining the macro linux. Alternatively, check for __linux__ instead.
I am working with Code::Blocks and C++ GNU GCC and trying to port my Visual Studio Project to GNU GCC.
And while I am trying to compile I get stuck with my define macro from a Defines.h file:
#define out &
And when compiling I get this error:
error: expected unqualified-id before '=' token
On this line:
// Open for output. Default for #c ofstream and fstream.
static const openmode out = _S_out;
In ios_base.h
As I know, that file is a part of a libstd library. Can I disable it? If so, how can I do that?
My library doesn't requiring any std c++, just c library.
There are two main options:
Don't define a macro using the word out.
Declare the macro after you include all of your headers.
But seriously, a macro named out that becomes & is a pretty awful macro. It's going to make it difficult to understand the code very quickly.
I try to embed Python in my C++ application, but the linker keeps saying this error:
[ILINK32 Error] Error: Unresolved external '_PyModule_Create2TraceRefs' referenced from E:\CPP PROJECTS\ANDERLICHT\WIN32\DEBUG\ANDERLICHT.OBJ
I'm using Embarcadero C++ Builder XE2, so I converted the python33.lib with coff2omf.exe.
This is my code in main.cpp:
#include "anderlicht.c"
#pragma comment(lib, "python33_omf.lib")
// In main():
PyImport_AppendInittab("anderlicht",PyInit_anderlicht);
Py_SetProgramName(programName.w_str());
Py_Initialize();
In anderlicht.c the Python.h is included. What do I have to do to fix this error?
I had the same problem, but I found a solution that doesn't need rebuild.
If you are developing a new application, you are in debug mode: the compiler defines _DEBUG. In the file "pyconfig.h" (near line 336 for python 3.6.3) you can find:
#ifdef _DEBUG
#define Py_DEBUG
#endif
=> Remove this code.
If you leave that code,you are in Py_Debug mode, so in object.h triggers this:
#if defined(Py_DEBUG) && !defined(Py_TRACE_REFS)
#define Py_TRACE_REFS
#endif
That in modsupport.h defines this alias:
#ifdef Py_TRACE_REFS
/* When we are tracing reference counts, rename module creation functions so
modules compiled with incompatible settings will generate a
link-time error. */
#define PyModule_Create2 PyModule_Create2TraceRefs
#define PyModule_FromDefAndSpec2 PyModule_FromDefAndSpec2TraceRefs
#endif
So your compiler needs a custom version of Python.
Now enjoy your standard embedded python.
The problem is most likely that you're using different compiler flags in building your code than were used in building the Python DLL. In particular, PyModule_Create2TraceRefs is only defined if you have -DPy_TRACE_REFS (which usually passed in via EXTRA_CFLAGS in the make command on Unix; I have no idea how you do it with Embarcadero C++ Builder on Windows). Usually, this isn't defined—in particular, if you're using a DLL from a pre-build Python binary, it won't have it defined.
So, if you want to have custom flags in building your code, you need to rebuild Python itself with the same flags. Otherwise, you need to get the flags that were used to build Python, and use the same ones when building your code.
On Unix, this is trivial: Just call python3.3-config --cflags and python3.3-config --ldflags to get the flags to pass to your compile and link steps. On Windows, it's less trivial. The Building C and C++ Extensions on Windows chapter in the docs explains how to do it when you're using the same toolchain used to build Python itself (usually MSVC), and if you're using mingw with its MSVC-compat features there's documentation elsewhere on how to do that… but if you're using a different toolchain, you will need to figure some of it out yourself.
When I compile a program using just
gcc code.c
There are no messages, and an output file is generated successfully. The outputted file works. However, when I try to the same cygwin installation's gcc compiler in an IDE (I've tried Netbeans and Dev-C++), I get the following errors
main.cpp:27: error: `exit' undeclared (first use this function)
main.cpp:27: error: (Each undeclared identifier is reported only once for each function it appears in.)
main.cpp:77: error: `write' undeclared (first use this function)
main.cpp:78: error: `close' undeclared (first use this function)
I don't see what's different. Why does it not compile?
OK, the issue was that in the IDE, the file had a .cpp extension, whereas when I was compiling from a terminal, it had a .c extension. So, my new question is why does it not compile when it's treated as a c++ file. Isn't C a subset of C++?
C++ is stricter then C. Where C allows you to call a function without a prototype, C++ does not allow this.
To solve the problem, you want to add:
#include <stdlib.h>
Also, when compiling at the command line. Make sure to use the -Wall flag so you'll get important warnings:
gcc -Wall code.c
The IDE is using fussier options to the compiler. You need to include some headers:
#include <stdlib.h> // exit()
#include <unistd.h> // close(), write()
The default options allow almost anything that might be C to compile. By the looks of it, the IDE sets '-Wmissing-prototypes' as one of the compiler options.
If you compile code with a C++ compiler, you must ensure that all functions are declared before use. C is sloppier (or can be sloppier) about that - it is recommended practice to ensure all functions are declared before being defined or referenced, but it is not mandatory. In C++ it is not optional.
There is a subset of C that is also a subset of C++; there are bits of C that are not C++, and there are many bits of C++ that are not C. In particular, an arbitrary C program is not, in general, a C++ program. For example, a C program may not declare 'exit()' and yet it can both use it and still compile. A C++ program must declare 'exit()' before it can user it and compile.
You will have to use g++ for compiling .cpp files.
One possible reason may be that the IDE is unable to access the include files, the cygwin gcc compiler may be expecting it in /usr/include(not sure), and the dev-cpp may not be able to access it.