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why doesn't this compile:
enum E { a, b}
typedef struct { int i; E e; } S;
int main(){return 0;}
I get different errors on different system.
You need a semicolon after the enum.
enum E { a, b};
There is no semicolon after the enum.
no semi colon at the end of enum
The enum needs an ; after its }
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Closed 1 year ago.
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My compiler gives me an error when I do this:
strcpy(skin.conclusion[0], "Mel");
My struct looks like this:
struct list{
char conclusion[10][4] = {};
}skin;
What am I doing wrong or is there something else other than strcpy that I'm supposed to use.
Here is the full code that worked for me. Of course, this is C style C++ and not modern C++, there are many reasons to prefer std::string
#include <iostream>
#include <cstring>
struct list{
char conclusion[10][4] = {};
}
skin;
int main()
{
strcpy(skin.conclusion[0], "Mel");
std::cout<<skin.conclusion[0];
return 0;
}
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Closed 3 years ago.
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#include <iostream>
using namespace std;
int main()
{
int* i = new int(75);
double* d = new double(3.14159);
printf("%d\n",*i);
printf("%d\n",*d);
}
In the above code i returns a value of 75 however, d returns 1.
I tried explicitly initializing it as
*d = 3.14159
But the value is still returned as 1.
Can anyone explain what I am doing wrong here?
Use this for printing.
cout<<*i;
cout<<*d
"%f" is the (or at least one) correct format for a double if you want to use printf for printing the value of the double in C++.
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Closed 5 years ago.
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I'm new to C++ and I don't understand why I'm getting a not declared error on this:
int main(){
string listOfColors[5] = {"red","blue","green","yellow","magenta"};
for(int i = 0;i < sizeof listofColors;i++){
cout << listofColors[i] << "\n";
}
return 0;
}
This is my first utilization of an array so far, so I may just not be declaring it correctly. I also had the array declaration before the main function beforehand.
You declared your variable as listOfColors (capital "O"), and then you use it as listofColors in your for loop. All you need to do is to capitalize the "O" when using your variable.
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Closed 9 years ago.
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This simple piece of code causes a core dump. I'm using gcc 4.8.2 in Linux.
template <class T>
class X
{
T c;
};
int main(int argc, char **argv)
{
X<string> *x = new X<string>[7];
delete x;
return 0;
}
I appreciate any help, I'm really confused with this. It doesn't cause a core dump when I use int instead of string.
You called new [] so you need to call delete []:
delete [] x;
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In the following piece of code I get the error mentioned below. Please tell me
Why *p=t gives error here
void reverse (char *p)
{
int length=strlen (p);
int c=0, i=length/2;
char *Temp=p+length-1, t;
while (c<length)
{
t=*Temp;
*Temp=*p
*p=t;
//Gives error as illegal, right operand has type char*
//Why is the error in the above line?
c++;
Temp--;
}
}
There is a semi-colon missing:
t=*Temp;
*Temp=*p ; //--here
*p=t;